unable to click a perticular cell in web table in python selenium - python

the link is "https://www.psacard.com/smrpriceguide/baseball-card-values/1909-11-t206-white-border/1055/".
My question is: How I will get the index of the particular record of which Description contains "Carolina". Also how can I click the hyperlink(Shop) against that row. Please provide solution with python and selenium only.

With selenium, I usually use xpath searches. I suggest googling xpath, but here's a quick example for your case:
Find a div element who's text is exactly Carolina Brights:
//div[text()="Carolina Brights"]
in selenium:
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.ui import WebDriverWait
browser = webdriver.PhantomJS()
browser.implicitly_wait(10)
my_xpath = '//div[text()="Carolina Brights"]]'
my_div = WebDriverWait(browser, 10).until(
EC.visibility_of_element_located((By.XPATH, my_xpath))
)
my_div.click()
Obviously that particular div has no onClick so no point clicking it, but you get the idea ...

Related

Selenium cant find element on Javascript page

I am still quite new to python and selenium, However have managed to get quite far with what I am doing. But I appear to now be stuck. The page in question is an internal business page. I have tried using ID, name and XPATH with very little success.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver import ActionChains
import time
PATH = r"C:\Users\p819364\Downloads\chromedriver.exe"
options = webdriver.ChromeOptions()
options.add_argument('--ignore-ssl-errors=yes')
options.add_argument('--ignore-certificate-errors')
driver = webdriver.Chrome(PATH, options=options)
driver.get("https://10.47.31.102/3/Login")
driver.implicitly_wait(15)
print (driver.title)
username = driver.find_element(By.NAME, value='j_username')
username.send_keys("username")
password = driver.find_element(By.NAME, value='j_password')
password.send_keys("password")
password.send_keys(Keys.RETURN)
driver.implicitly_wait(20)
Settings = driver.find_element(By.XPATH, value="//*[#id='evo_widget_TBFisheyeItem_4']")
Settings.click()
driver.implicitly_wait(20)
Filter = driver.find_element(By.XPATH, value="//*[#id='tableForm:authenticationPolicyTable:tableActions']")
driver.implicitly_wait(20)
Filter.click()
The problem I am having is with the filter, I think it may be because this is a page within a page. I am sorry I cannot share the page as its internal. But I need to be able to click the filter and click and options
I keep getting the following error
Message: no such element; Unable to locate element: {"method":"css selector","selector":["//*[#id='tableForm:authenticationPolicyTable:tableActions']"
The XPATH is as follows:
//*[#id="tableForm:authenticationPolicyTable:tableActions"]
This is the full XPATH (which I have tried):
/html/body/form[3]/table/thead/tr[1]/th/table/tbody/tr/td[2]/select
I appreciate any help given and I also am not sure if its caused this because the field I want to select is not in view until I scroll. However I cannot seem to scroll as the element is within another as pictured
Thanks
Edit:
The iFrame was stopping it i had to switch to it first
iframe = driver.find_element_by_xpath("//*[#id='consoleCanvas']")
driver.switch_to.frame(iframe)
I think if the page is within page then you need to check if that element is within iframe. If iframe is there then you should first switch to frame and then click on filter. If you can post html code then it will be easy to understand issue.

Element Not Clickable - even though it is there

Hoping you can help. I'm relatively new to Python and Selenium. I'm trying to pull together a simple script that will automate news searching on various websites. The primary focus was football and to go and get me the latest Manchester United news from a couple of places and save the list of link titles and URLs for me. I could then look through the links myself and choose anything I wanted to review.
In trying the the independent newspaper (https://www.independent.co.uk/) I seem to have come up against a problem with element not interactable when using the following approaches:
import time
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome('chromedriver')
driver.get('https://www.independent.co.uk')
time.sleep(3)
#accept the cookies/privacy bit
OK = driver.find_element_by_id('qcCmpButtons')
OK.click()
#wait a few seconds, just in case
time.sleep(5)
search_toggle = driver.find_element_by_class_name('icon-search.dropdown-toggle')
search_toggle.click()
This throws the selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable error
I've also tried with XPATH
search_toggle = driver.find_element_by_xpath('//*[#id="quick-search-toggle"]')
and I also tried ID.
I did a lot of reading on here and then also tried using WebDriverWait and execute_script methods:
element = WebDriverWait(driver, 20).until(EC.presence_of_element_located((By.XPATH, '//*[#id="quick-search-toggle"]')))
driver.execute_script("arguments[0].click();", element)
This didn't seem to error but the search box never appeared, i.e. the appropriate click didn't happen.
Any help you could give would be fantastic.
Thanks,
Pete
Your locator is //*[#id="quick-search-toggle"], there are 2 on the page. The first is invisible and the second is visible. By default selenium refers to the first element, sadly the element you mean is the second one, so you need another unique locator. Try this:
search_toggle = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, '//div[#class="row secondary"]//a[#id="quick-search-toggle"]')))
search_toggle.click()
First you need to open search box, then send search keys:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.chrome.options import Options
import os
chrome_options = Options()
chrome_options.add_argument("--start-maximized")
browser = webdriver.Chrome(executable_path=os.path.abspath(os.getcwd()) + "/chromedriver", options=chrome_options)
link = 'https://www.independent.co.uk'
browser.get(link)
# accept privacy
button = browser.find_element_by_xpath('//*[#id="qcCmpButtons"]/button').click()
# open search box
li = browser.find_element_by_xpath('//*[#id="masthead"]/div[3]/nav[2]/ul/li[1]')
search_tab = li.find_element_by_tag_name('a').click()
# send keys to search box
search = browser.find_element_by_xpath('//*[#id="gsc-i-id1"]')
search.send_keys("python")
search.send_keys(Keys.RETURN)
Can you try with below steps
search_toggle = driver.find_element_by_xpath('//*[#class="row secondary"]/nav[2]/ul/li[1]/a')
search_toggle.click()

Unable to locate element error through Selenium after copying xPath location

Selenium, cannot locate xPath element
I'm a beginner learning Selenium, trying to build a tiny web scraper. First part is to go to the site and click button "Search By Address". I copied the xPath from Inspecting the element in Google Chrome, however, using Selenium to find the element keeps throwing a "unable to locate" error.
from selenium import webdriver
web_Url = 'http://hcad.org/quick-search/'
driver = webdriver.Firefox(executable_path=r'C:\Users\Jaz\Documents\Python\Modules\geckodriver.exe')
driver.implicitly_wait(10) # this lets webdriver wait 10 seconds for the website to load
driver.get(web_Url)
button = driver.find_element_by_xpath("//*[#id='s_addr']").click()
The element you are trying to find is inside iframe. First, switch to iframe using 'driver.switchTo().frame()' command and then try to find the element.
More details on switching to iframe is discussed in this article.
from selenium import webdriver
web_Url = 'http://hcad.org/quick-search/'
driver = webdriver.Firefox(executable_path=r'C:\Users\Jaz\Documents\Python\Modules\geckodriver.exe')
driver.implicitly_wait(10) # this lets webdriver wait 10 seconds for the website to load
driver.get(web_Url)
element = driver.find_element_by_xpath("//div[#class='c-general']/iframe")
driver.switch_to_frame(element)
driver.find_element_by_xpath("//*[#id='s_addr']").click()
driver.switch_to_default_content()
To click() on the element with text as Search By Address as the the desired element is within an <iframe> so you have to:
Induce WebDriverWait for the desired frame to be available and switch to it.
Induce WebDriverWait for the desired element to be clickable.
You can use the following solution:
Code Block:
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
driver = webdriver.Firefox(executable_path=r'C:\Utility\BrowserDrivers\geckodriver.exe')
driver.get("http://hcad.org/quick-search/")
WebDriverWait(driver, 10).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH,"//iframe[#src='https://public.hcad.org/records/quicksearch.asp']")))
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input#s_addr"))).click()
Browser Snapshot:
Here you can find a relevant discussion on Ways to deal with #document under iframe

How to find the Xpath of the element as per the html through Selenium and Python

Tried something like this in python unable I want to click on cross using Selenium.
driver.find_element_by_xpath("//span[contains(#onclick, 'parent.$WZRK_WR.closeIframe('60005','intentPreview');')]").click()
As per the HTML you have shared to click on the element depicted as X, first you need to induce WebDriverWait while switching to the <iframe> and again induce WebDriverWait for the desired element to be clickable and you can use the following solution:
WebDriverWait(driver, 10).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH,"//iframe[#id='wiz-iframe-intent']")))
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//div[#class='CT_Interstitial']//span[#class='CT_InterstitialClose']"))).click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
Open below URL and Click on Add to Chrome button.
Xpath Helper- https://chrome.google.com/webstore/detail/xpath-helper/hgimnogjllphhhkhlmebbmlgjoejdpjl?hl=en
Once plugin added to Chrome. Open your application/webpage and press SHIFT+CTRL+X. Black window will appear on top then you can play with xpath.
If xpath is invalid- then you will get xpath error and if no matches found then it will display NULL.
Note- To check element attribute still you can use F12 that is nothing but default inspect element for all browser then check attribute and create your own xpath and try.
Xpath Syntax
// tagname[#attribute-name=’value1′] and if you are not sure about tag name then no worry you can try with * also
//*[#attribute-name='value1']
You are dealing with an iframe. Follow below steps :
You'll need to switch control to iframe.
Then perform your action (in this case 'Click close').
Switch the control back to default frame.
You can try with this css_selector :
div.CT_InterstitialContents+span.CT_InterstitialClose[onclick]
Xpath would be :
//div[#class='CT_InterstitialContents']/following-sibling::span[#class='CT_InterstitialClose' and onclick]
Try to use this xPath:
//div[#id = 'contentDiv']/div/div/span[#class = 'CT_InterstitialClose']
Code:
close_btn = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//div[#id = 'contentDiv']/div/div/span[#class = 'CT_InterstitialClose']")))
close_btn.click()
Imports:
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver.common.by import By
Explanation:
WebDriverWait is used to wait until element will be clickable, and only then clicks on it. In this example WebDriverWait will wait at least 10 seconds until element will be clickable.
PS: as I see in the screenshot your element is probably in iframe. That means you have to switch to this iframe first, to be able to interact with the elements in it. The code sample for it would be like this:
WebDriverWait(driver, 10).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH, "XPATH_TO_FRAME")))
# do stuff
close_btn = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//div[#id = 'contentDiv']/div/div/span[#class = 'CT_InterstitialClose']")))
close_btn.click()
# switch back to default content
driver.switch_to.default_content()
You can write xpath using class name of span. Please refer an example below.
//span[#class='amountCharged']

Selenium can't locate the element, a search button using xpath

I can't find a solution how this element cannot be found by using a selenium xpath. Other button on other websites always working just fine. Usually what I would normally do is, just open up a page and inspect the element and I would right click it and copy the xpath. Done.
But this website, www.gsc.com.my (a malaysian cinema booking site). Seems not able to find the button. Is it protected by another security layer?
Lets see the code below,
from selenium import webdriver
chromedriver_path = './chromedriver.exe'
driver = webdriver.Chrome(chromedriver_path)
driver.get('https://www.gsc.com.my')
driver.find_element_by_xpath("""//*[#id="btnNext"]""").click()
The error Message:
no such element: Unable to locate element: {"method":"xpath","selector":"//*[#id="btnNext"]"}
Button is located inside an iframe, so you need to switch to that frame before clicking the button:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.webdriver.support import expected_conditions as EC
driver.switch_to.frame('getQuickFilter_ctrl_ifrBox')
wait(driver, 10).until(EC.element_to_be_clickable((By.ID, "btnNext"))).click()
Because there are two elements with id btnNext, you'll have to specify which of them using an index, 1 for the first, 2 for the second.
driver.find_element_by_xpath("""//*[#id="btnNext"][1]""").click()
You can try with this css selector :
div.container input#btnNext
Note that you will need to switch to iframe first , cause the check button is in a iframe.
For switching to iframe :
driver.switch_to.frame(driver.find_element_by_id("getQuickFilter_ctrl_ifrBox"))
and for clicking on check Button
wait = WebDriverWait(driver, 10)
check_button = wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "div.container input#btnNext")))
check_button.click()

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