Develop Reference

Python Request returning different result than original page (browser)

I am trying to do a simple WebScrapper to monitor Nike's site here in Brazil.
Basically i want to track products that have stock right now, to check when new products are added.
My problem is that when i navigate to the site https://www.nike.com.br/snkrs#estoque I see different products compared to what I see using python requests method.
Here is the code I am using:
import requests
from bs4 import BeautifulSoup
headers ={
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/87.0.4280.88 Safari/537.36'
}
url = 'https://www.nike.com.br/snkrs#estoque'
page = requests.get(url, headers=headers)
soup = BeautifulSoup(page.content, 'html.parser')
len(soup.find_all(class_='produto produto--comprar'))
This code gives me 40, but using the browser I can see 56 products https://prnt.sc/26jeo1i

The data comes from a different source, within 3 pages.
import requests
from bs4 import BeautifulSoup
headers ={
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/87.0.4280.88 Safari/537.36'
}
productList = []
for p in [1,2,3]:
url = f'https://www.nike.com.br/Snkrs/Estoque?p={p}&demanda=true'
page = requests.get(url, headers=headers)
soup = BeautifulSoup(page.content, 'html.parser')
productList += soup.find_all(class_='produto produto--comprar')
Output:
print(len(productList))
56

BeautifulSoup is returning empty data from website

I am running this code
import requests
from bs4 import BeautifulSoup
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/78.0.3904.108 Safari/537.36'
}
r = requests.get('https://www.bohus.no/spiseplassen/oppbevaring-1/gradino-vitrine-2')
soup = BeautifulSoup(r.content, 'lxml')
print(soup.find('div', class_='price').text)
I am trying to get the price of the product on this site: https://www.bohus.no/spiseplassen/oppbevaring-1/gradino-vitrine-2
All I am getting is empty data when running my code. Am I doing something wrong or does the website do something special to stop me from scaping price?

As stated in the comments, you can get the product data from the store's API.
Here's how:
import requests
from bs4 import BeautifulSoup
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) '
'AppleWebKit/537.36 (KHTML, like Gecko) '
'Chrome/78.0.3904.108 Safari/537.36',
"x-requested-with": "XMLHttpRequest"
}
product_url = "https://www.bohus.no/spiseplassen/oppbevaring-1/gradino-vitrine-2"
page_content = requests.get(product_url).content
soup = BeautifulSoup(page_content, 'lxml')
product_id = soup.find("input", {"name": "d-session-product"})["value"]
payload = {
"debug": "off",
"ajax": "1",
"product_list": product_id,
"action": "init",
"showStockStatusAndShoppingcart": "1",
"enablePickupAtNearbyStores": "yes",
}
endpoint = "https://www.bohus.no/lite.cgi/module/priceAndStock"
product_data = requests.post(endpoint, data=payload, headers=headers).json()
print(product_data["price"][0]["salesPriceNormal"])
Output:
8799

Also, you can use requests-HTML library:
import requests_html
from requests_html import HTMLSession
session = HTMLSession()
r = session.get('https://www.bohus.no/spiseplassen/oppbevaring-1/gradino-vitrine-2')
r.html.render()
sel='div.price-data > div.price'
print(r.html.find(sel, first=True).text)

why can't it print response after making a request to an api/url?

I just found the bestbuyCA api by inspecting the xhr.
aboveurl = 'https://www.bestbuy.ca/ecomm-api/availability/products?accept=application%2Fvnd.bestbuy.simpleproduct.v1%2Bjson&accept-language=en-CA&skus=14962185'
I've tried:：
response= requests.get(aboveurl)
print(response.text)
//
r = requests.get(url).json()
print(r)
When I run my code in vsc, it starts and keeps running but it will not display anything.

You have to add a header to your request to get the request result:
import requests
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/56.0.2924.76 Safari/537.36', "Upgrade-Insecure-Requests": "1","DNT": "1","Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8","Accept-Language": "en-US,en;q=0.5","Accept-Encoding": "gzip, deflate"}
aboveurl = "https://www.bestbuy.ca/ecomm-api/availability/products?accept=application%2Fvnd.bestbuy.simpleproduct.v1%2Bjson&accept-language=en-CA&skus=14962185"
html = requests.get(aboveurl,headers=headers)
print(f'requrest code: {html.status_code}\n request text: {html.text}')

python web scraping,web parser

I just start learning python, and I have problem with scraping.
Code work correctly, but when I scrape , but get only empty list [].
what I do wrong?
I can't find same problem , Thanks for your time!
`import requests
from bs4 import BeautifulSoup as bs4
headers = {
"accept": "text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9",
"user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.198 Safari/537.36"
}
url = "https://www.worldometers.info/geography/alphabetical-list-of-countries/"
session = requests.session()
try:
req = session.get(url, headers=headers)
if req.status_code == 200:
soup = bs4(req.content, "html.parser")
divs = soup.find_all("div", attrs={"style" : "font-weight"})
name = soup.find_all()
print(divs)
except Exception:
print("ERORR IN URL ADRESS")`

You can get the table with class table-condensed and find the data you need. Please check the below code:
import requests
from bs4 import BeautifulSoup
headers = {
"accept": "text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9",
"user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.198 Safari/537.36"
}
url = "https://www.worldometers.info/geography/alphabetical-list-of-countries/"
session = requests.session()
try:
req = session.get(url, headers=headers)
if req.status_code == 200:
soup = BeautifulSoup(req.content, "html.parser")
countries = soup.find("table", {"class": "table-condensed"}).find("tbody").findAll("tr")
for country in countries:
print(country.findAll("td")[1].text)
except Exception:
print("ERORR IN URL ADRESS")

Can't find text from page using Python BS4

I am trying to learn how to use BS4 but I ran into this problem. I try to find the text in the Google Search results page showing the number of results for the search but I can't find no text 'results' neither in the html_page nor in the soup HTML parser. This is the code:
from bs4 import BeautifulSoup
import requests
url = 'https://www.google.com/search?q=stack'
res = requests.get(url)
html_page = res.content
soup = BeautifulSoup(html_page, 'html.parser')
print(b'results' in html_page)
print('results' in soup)
Both prints return False, what am I doing wrong? How to fix that?
EDIT:
Turns out the language of the webpage was a problem, adding &hl=en to the URL almost fixed it.
url = 'https://www.google.com/search?q=stack&hl=en'
The first print is now True but the second is still False.

requests library when returning the response in form of response.content usually returns in a raw format. So to answer your second question, replace the res.content with res.text.
from bs4 import BeautifulSoup
import requests
url = 'https://www.google.com/search?q=stack'
res = requests.get(url)
html_page = res.text
soup = BeautifulSoup(html_page, 'html.parser')
print('results' in soup)
Output: True
Keep in mind, Google is usually very active in handling scrapers. To avoid getting blocked/captcha'ed, you can add a user agent to emulate a browser. :
# This is a standard user-agent of Chrome browser running on Windows 10
headers = { 'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36' }
Example:
from bs4 import BeautifulSoup
import requests
headers={'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36'}
resp = requests.get('https://www.amazon.com', headers=headers).text
soup = BeautifulSoup(resp, 'html.parser')
...
<your code here>
Additionally, you can add another set of headers to pretend like a legitimate browser. Add some more headers like this:
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36',
'Accept' : 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8',
'Accept-Language' : 'en-US,en;q=0.5',
'Accept-Encoding' : 'gzip',
'DNT' : '1', # Do Not Track Request Header
'Connection' : 'close'
}

It's not because res.content should be changed to res.text as 0xInfection mentioned, it would still return the result.
However, in some cases, it will only return bytes content if it's not gzip or deflate transfer-encodings, which are automatically decoded by requests to a readable format (correct me in the comments or edit this answer if I'm wrong).
It's because there's no user-agent specified thus Google will block a request eventually because default requests user-agent is python-requests and Google understands that it's a bot/script. Learn more about request headers.
Pass user-agent into request headers:
headers = {
"User-Agent":
"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.102 Safari/537.36 Edge/18.19582"
}
request.get('YOUR_URL', headers=headers)
Code and example in the online IDE:
import requests, lxml
from bs4 import BeautifulSoup
headers = {
"User-Agent":
"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.102 Safari/537.36 Edge/18.19582"
}
params = {
"q": "fus ro dah definition", # query
"gl": "us", # country to make request from
"hl": "en" # language
}
response = requests.get('https://www.google.com/search',
headers=headers,
params=params).content
soup = BeautifulSoup(response, 'lxml')
number_of_results = soup.select_one('#result-stats nobr').previous_sibling
print(number_of_results)
# About 114,000 results
Alternatively, you can achieve the same thing by using Google Direct Answer Box API from SerpApi. It's a paid API with a free plan.
The difference in your case is that you only need to extract the data you want without thinking about how to extract stuff or figure out how to bypass blocks from Google or other search engines since it's already done for the end-user.
import os
from serpapi import GoogleSearch
params = {
"engine": "google",
"q": "fus ro dah definition",
"api_key": os.getenv("API_KEY"),
}
search = GoogleSearch(params)
results = search.get_dict()
result = results["search_information"]['total_results']
print(result)
# 112000
Disclaimer, I work for SerpApi.