Azure Python web service fail when open pickle file - python

I start web service on azure, deploy the python project(3), it is successfully started, and some routes like:
#app.route('/')
def OK():
return 'OK!'
working ok.
But when requesting this code:
#app.route('/predict_states/<userRequests>')
def CreatePrediction(userRequests):
predict = Predict([userRequests], model)
return jsonify(predict)
the model is:
with open("model.pkl", 'rb') as f:
model = dill.load(f)
azure return an error 500:
IIS received the request; however, an internal error occurred during the processing of the request. The root cause of this error depends on which module handles the request and what was happening in the worker process when this error occurred.
IIS was not able to access the web.config file for the Web site or application. This can occur if the NTFS permissions are set incorrectly.
IIS was not able to process configuration for the Web site or application.
The authenticated user does not have permission to use this DLL.
The request is mapped to a managed handler but the .NET Extensibility Feature is not installed.
What could be the problem?

Related

Spotipy redirect uri opening on server instead of users browser?

I built a web app using Django and the wrapper for the Spotify api, Spotipy, and deployed it to Heroku. The problem I am facing is that the redirect uri opens on the machine running the code, which in this case is the linux server used by heroku. Because of this, the user never actually sees the page prompting them to authenticate the app and login to their Spotify accounts, resulting in a request timeout from Heroku. This happens when my REDIRECT_URI is set to http://localhost/. I have tried to set the REDIRECT_URI to https://nameofmyapp.herokuapp.com which then resulted in an EOFError from the Spotipy module. I have not been able to find a solution for this. For context, my authentication flow is set up as follows:
def index(request):
cache_handler = spotipy.DjangoSessionCacheHandler(request=request)
auth_manager = spotipy.oauth2.SpotifyOAuth(
env("CLIENT_ID"), env("CLIENT_SECRET"), env("REDIRECT_URI"), scope=env("SCOPE"), cache_handler=cache_handler)
session = spotipy.Spotify(
oauth_manager=auth_manager, requests_session=True)

Trading view alerts to trigger market order through python and Oanda's API

I'm trying to trigger a python module (market order for Oanda) using web hooks(from trading view).
Similar to this
1) https://www.youtube.com/watch?v=88kRDKvAWMY&feature=youtu.be
and this
2)https://github.com/Robswc/tradingview-webhooks-bot
But my broker is Oanda so I'm using python to place the trade. This link has more information.
https://github.com/hootnot/oanda-api-v20
The method is web hook->ngrok->python. When a web hook is sent, the ngrok (while script is also running) shows a 500 internal service error and that the server encountered an internal error and was unable to complete your request. Either the server is overloaded or there is an error in the application.
This is what my script says when its running (see picture);
First says some stuff related the market order then;
running script picture
One thing I noticed is that after Debug it doesn't say Running on... (so maybe my flask is not active?
Here is the python script;
from flask import Flask
import market_orders
# Create Flask object called app.
app = Flask(__name__)
# Create root to easily let us know its on/working.
#app.route('/')
def root():
return 'online'
#app.route('/webhook', methods=['POST'])
def webhook():
if request.method == 'POST':
# Parse the string data from tradingview into a python dict
print(market_orders.myfucn())
else:
print('do nothing')
if __name__ == '__main__':
app.run()
Let me know if there is any other information that would be helpful.
Thanks for your help.
I fixed it!!!! Google FTW
The first thing I learned was how to make my module a FLASK server. I followed these websites to figure this out;
This link helped me set up the flask file in a virtual environment. I also moved my Oanda modules to this new folder. And opened the ngrok app while in this folder via the command window. I also ran the module from within the command window using flask run.
https://topherpedersen.blog/2019/12/28/how-to-setup-a-new-flask-app-on-a-mac/
This link showed me how to set the FLASK_APP and the FLASK_ENV
Flask not displaying http address when I run it
Then I fixed the internal service error by adding return 'okay' after print(do nothing) in my script. This I learned from;
Flask Value error view function did not return a response

Cannot get authentication with google api from python script to work - Error: redirect_uri_mismatch

I am trying to create a trivial python script that allows me to bulk add a list of youtube videos to a playlist of mine.
The problem I am having is getting this script to get authenticated to the google api with my apps credentials.
I am basically just using the sample authentication script at https://developers.google.com/google-apps/calendar/quickstart/python
and this stackoverflow question (Adding youtube video to playlist using Python)
The main stopping point is that I keep getting an Error: redirect_uri_mismatch. Since I am calling the script from the commandline on my laptop, the error is saying: The redirect URI in the request: http://localhost:8080/ did not match a registered redirect URI.
I have set http://localhost:8080 as the JavaScript origins and http://localhost:8080/oauth2callback as the Redirect URIs
And i am using the following (as run from the python shell):
from oauth2client.client import flow_from_clientsecrets
from oauth2client.file import Storage
from oauth2client import tools
from oauth2client.tools import argparser, run_flow
import argparse, sys, os
flow = flow_from_clientsecrets('path to my CLIENT_SECRETS.json file', scope='https://www.googleapis.com/auth/youtube')
store = Storage('config/%s-oauth2.json' % sys.argv[0])
parser = argparse.ArgumentParser(parents=[tools.argparser])
flags = parser.parse_args()
credentials = run_flow(flow, store, flags)
then the terminal opens my browser and in the browser I get the 400 error. The following gets printed to the terminal:
Your browser has been opened to visit:
https://accounts.google.com/o/oauth2/auth?scope=https%3A%2F%2Fwww.googleapis.com%2Fauth%2Fyoutube&redirect_uri=http%3A%2F%2Flocalhost%3A8080%2F&response_type=code&client_id=my-CLIENT-ID&access_type=offline
If your browser is on a different machine then exit and re-run this
application with the command-line parameter
--noauth_local_webserver
I am not sure what I am really supposed to be putting as the redirect URIs and javascript origins, but I don't intend to run this anywhere else other than as a python script from the terminal of my laptop. The documentation provides https://example.com/ and https://example.com/oauth2callback as pre populated values, but clearly that's not where I am running this "app" from and I know that's just placeholder stuff.
UPDATE: not sure why, but i realize that the url the app is sending me to has the redirect_uri parameter set to just http://localhost:8080/, if i add oauth2callback to the uri than i get sent to the screen where it asks me to accept management of the youtube account. so that's odd.
UPDATE 2: and if I change my redirect uris to just http://localhost:8080/ via the developer console, i can get my credentials, but I am sure this is not the best way to be going about this.
If you are just running this through you terminal than you can use the native host by creating a client ID as an installed app and then selecting other. If you are trying to do this using the web app client ID and only want it to be local then you would use these:
JavaScript origins: http://localhost:your_port_here/
Redirect URIs: http://localhost:your_port_here/url_path
where url_path is the place you want google to send you after authentication.
Edit: the tutorial code only works if you are using a native app. If you are indeed planning to create a web app there are separate instructions.
The redirect_uri parameter set to just http://localhost:8080/ is by design. When you call tools.run_flow() it is spinning up a server of it's own behind the scenes and initiating the oauth flow. It is then expecting the redirect_uri to redirect back to the server it spun up (which is listening on port 8080) so that it can use the access_token it receives to create the credentials and put them in storage.

App Engine Backends Configuration (python)

I got timeout error on my GAE server when it tries to send large files to an EC2 REST server. I found Backends Python API would be a good solution to my example but I had some problems on configuring it.
Following some instructions, I have added a simple backends.yaml in my project folder. But I still received the following error, which seems like I failed to create a backend instance.
File "\Google\google_appengine\google\appengine\api\background_thread\background_thread.py", line 84, in start_new_background_thread
raise ERROR_MAP[error.application_error](error.error_detail)
FrontendsNotSupported
Below is my code, and my question is:
Currently, I got timeout error in OutputPage.py, how do I let this script run on a backend instance?
update
Following Jimmy Kane's suggestions, I created a new script przm_batchmodel_backend.py for the backend instance. After staring my GAE, now it I have two ports (a default and a backend) running my site. Is that correct?
app.yaml
- url: /backend.html
script: przm_batchmodel.py
backends.yaml
backends:
- name: mybackend
class: B1
instances: 1
options: dynamic
OutputPage.py
from przm import przm_batchmodel
from google.appengine.api import background_thread
class OutputPage(webapp.RequestHandler):
def post(self):
form = cgi.FieldStorage()
thefile = form['upfile']
#this is the old way to initiate calculations
#html= przm_batchmodel.loop_html(thefile)
przm_batchoutput_backend.przmBatchOutputPageBackend(thefile)
self.response.out.write(html)
app = webapp.WSGIApplication([('/.*', OutputPage)], debug=True)
przm_batchmodel.py
def loop_html(thefile):
#parses uploaded csv and send its info. to the REST server, the returned value is a html page.
data= csv.reader(thefile.file.read().splitlines())
response = urlfetch.fetch(url=REST_server, payload=data, method=urlfetch.POST, headers=http_headers, deadline=60)
return response
przm_batchmodel_backend.py
class BakendHandler(webapp.RequestHandler):
def post(self):
t = background_thread.BackgroundThread(target=przm_batchmodel.loop_html, args=[thefile])
t.start()
app = webapp.WSGIApplication([('/backend.html', BakendHandler)], debug=True)
You need to create an application 'file'/script for the backend to work. Just like you do with the main.
So something like:
app.yaml
- url: /backend.html
script: przm_batchmodel.py
and on przm_batchmodel.py
class BakendHandler(webapp.RequestHandler):
def post(self):
html = 'test'
self.response.out.write(html)
app = webapp.WSGIApplication([('/backend.html', OutputPage)], debug=True)
May I also suggest using the new feature modules which are easier to setup?
Edit due to comment
Possible the setup was not your problem.
From the docs
Code running on a backend can start a background thread, a thread that
can "outlive" the request that spawns it. They allow backend instances
to perform arbitrary periodic or scheduled tasks or to continue
working in the background after a request has returned to the user.
You can only use backgroundthread on backends.
So edit again. Move the part of the code that is:
t = background_thread.BackgroundThread(target=przm_batchmodel.loop_html, args=[thefile])
t.start()
self.response.out.write(html)
To the backend app

Flask file upload limit

I have a file upload handler for multiple file uploads, and have set the MAX_CONTENT_SIZE. The docs mention that Flask throws a 413 exception when the total file size exceeds the limit, so I've also written a 413 error handler with a custom 413 page. However, when testing the file upload, I can see that the 413 error is definitely thrown, but the connection seems to break everytime instead of rendering my error page. FYI, I'm using the Flask dev server currently.
Code:
app.config['MAX_CONTENT_LENGTH'] = 50 * 1024 * 1024 # 50 Mb limit
#app.route('/upload', methods=['POST'])
def upload_files():
if request.method == 'POST':
uploaded_files = request.files.getlist('uploaded_files[]')
# do some stuff with these files
#app.errorhandler(413)
def error413(e):
return render_template('413.html'), 413
UPDATE:
Ok strange, this problem seems to only occur when using the Flask dev server. I'm testing it on Apache, and my 413 error page renders fine.
Use a production WSGI server will solve this problem (e.g. Gunicorn, Waitress). Below is a simple timeline of this issue.
2015
In this snippet (gone) that posted by Armin Ronacher, he said:
You might notice that if you start not accessing .form or .files on incoming POST requests, some browsers will honor this with a connection reset message. This can happen if you start rejecting uploads that are larger than a given size.
Some WSGI servers solve that problem for you, others do not. For instance the builtin Flask webserver is pretty dumb and will not attempt to fix this problem.
2018
I added a tip in the Flask's file uploading docs (flask #2662):
Connection Reset Issue
When using the local development server, you may get a connection reset error instead of a 413 response. You will get the correct status response when running the app with a production WSGI server.
2021
I think/hope it will be fixed in Werkzeug in the near future (werkzeug #1513).

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