I'm writing a program in pygame in which I want to draw circles on several surfaces, so that when I erase a circle (redraw it with the transparent colorkey) I get the picture that was in the layer below back. However, I seem to be stuck at an early step and can't seem to draw a circle on a surface (as opposed to the background display). Here is a minimal example:
import pygame
pygame.init()
width = 400
height = 400
screen = pygame.display.set_mode((width, height))
surf1 = pygame.Surface((width,height))
surf1.fill((0,255,0))
pygame.draw.circle(surf1, (0,0,0), (200,2000), 5)
screen.blit(surf1, (0,0))
exit = False
while not exit:
for event in pygame.event.get():
if event.type == pygame.QUIT:
exit = True
pygame.display.update()
pygame.quit()
I expected to get a green surface with a black circle in the middle, but I only get a green surface. What am I doing wrong?
Thanks!
You have a typo in the coordinates for the circle, it should be
pygame.draw.circle(surf1, (0,0,0), (200,200), 5)
i.e. a 200 instead of a 2000.
Related
I'm trying to make a game using pygame but I came up with an issue of people getting annoyed of the resolution they're working with, and can't resize window without stretching it.
Here is an example picture of what I'm trying to achieve.
here's what I tried.
window.blit(pg.transform.scale(screen, (window.get_size())), (0, 0)) # The game screen stretching
PS: It's hard to explain so I had to show an image
Use the following algortihm:
Get the bounding rectangle of the image and set the center of the rectangle to the center of the destination rectangle.
Use pygame.Rect.fit() to resize and move the aspect ratio rectangle into the destination rectangle.
Use the size of the new rectangle to scale the image.
blit the image at the position of the rectangle.
def blit_fit(dest_surf, image, dest_rect):
image_rect = image.get_rect(center = dest_rect.center)
fit_rect = image_rect.fit(dest_rect)
scaled_image = pygame.transform.scale(image, fit_rect.size)
dest_surf.blit(scaled_image, fit_rect)
Minimal example:
import pygame
pygame.init()
window = pygame.display.set_mode((300, 300))
clock = pygame.time.Clock()
font = pygame.font.SysFont(None, 100)
image = font.render("Screen", True, (255, 255, 0))
pygame.draw.rect(image, (255, 255, 255), image.get_rect(), 1)
def blit_fit(dest_surf, image, dest_rect):
image_rect = image.get_rect(center = dest_rect.center)
fit_rect = image_rect.fit(dest_rect)
scaled_image = pygame.transform.scale(image, fit_rect.size)
dest_surf.blit(scaled_image, fit_rect)
run = True
while run:
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
window.fill(0)
blit_fit(window, image, window.get_rect())
pygame.display.flip()
clock.tick(100)
pygame.quit()
exit()
I can't get pytmx to render transparent tiles from Tiled correctly in pygame.
On this example you can see that the tile rendered from the tmx file is showing a black background, i would like to have it like the image rendered directly from the image file.
I have tried messing with .convert(), .convert_alpha() or even putting the flag pygame.SCRALPHA but no luck there.
Here is a link to get the assets for reproducing the example : https://filebin.net/yvmr5jz04j889mlx
Here is the code of the example :
import pygame
import pytmx
pygame.init()
gameScreen = pygame.display.set_mode((280, 210))
clock = pygame.time.Clock()
# filling in white to see the lack of alpha
gameScreen.fill((255, 255, 255))
# bliting from tmx file, (the alpha is not recognized)
gameMap = pytmx.load_pygame('test_map.tmx')
for layer in gameMap.visible_layers:
if isinstance(layer, pytmx.TiledTileLayer):
for x, y, gid, in layer:
tile = gameMap.get_tile_image_by_gid(gid)
if tile:
gameScreen.blit(tile, (x * gameMap.tilewidth, y * gameMap.tileheight))
# bliting the image directly from pygame (the alpha is correctly recognized)
rock = pygame.image.load('rock.png')
gameScreen.blit(rock, (140, 70))
def game_loop():
gameExit = False
while not gameExit:
for event in pygame.event.get():
if event.type == pygame.QUIT:
gameExit = True
pygame.display.update()
clock.tick(30)
game_loop()
pygame.quit()
Found the solution !
Turns out that when I created the Tilesets in Tiled I checked the box "use transparency color".
I had a hard time figuring this out because when I looked at the tileset properties in Tiled after the tileset was created, it showed that the transparency color was not set, and the transparency was taken into account in Tiled.
I am making a program with a graph that scrolls and I just need to move a section of the screen.
If I do something like this:
import pygame
screen = pygame.display.set_mode((300, 300))
sub = screen.subsurface((0,0,20,20))
screen.blit(sub, (30,40))
pygame.display.update()
It gives the error message: pygame.error: Surfaces must not be locked during blit
I assume it means the child is locked to its parent surface or something but how else could I go about doing this?
screen.subsurface creates a surface, which reference to the original surface. From documentation:
Returns a new Surface that shares its pixels with its new parent.
To avoid undefined behaviour, the surfaces get locked. You've to .copy the surface, before you can .blit it to its source:
sub = screen.subsurface((0,0,20,20)).copy()
screen.blit(sub, (30,40))
Just don't draw to the screen surface directly. Create a Surface for each part of your game/UI, and blit each of those to the screen.
import pygame
def main():
pygame.init()
screen = pygame.display.set_mode((640, 480))
# create two parts: a left part and a right part
left_screen = pygame.Surface((400, 480))
left_screen.fill((100, 0, 0))
right_screen = pygame.Surface((240, 480))
right_screen.fill((200, 200, 0))
x = 100
while True:
events = pygame.event.get()
for e in events:
if e.type == pygame.QUIT:
return
# don't draw to the screen surface directly
# draw stuff either on the left_screen or right_screen
x += 1
left_screen.fill(((x / 10) % 255, 0, 0))
# then just blit both parts to the screen surface
screen.blit(left_screen, (0, 0))
screen.blit(right_screen, (400, 0))
pygame.display.flip()
if __name__ == '__main__':
main()
So I was testing out pygame and I wanted to draw a simple rectangle. There are no error messages when I run the code but the rectangle doesn't show up in the window. What I see is a blank white Pygame window pop up. Does anyone know why?
Currently using Python3 and Pygame 1.9.4 on my mac.
Here is my code,
import pygame
import pygame.font
pygame.init()
# Colours
BLACK = ( 0, 0, 0)
WHITE = (255,255,255)
GREEN = ( 0,255, 0)
RED = (255, 0, 0)
BLUE = ( 0, 0,255)
# Dimensions of screen
size = (400,500)
WIDTH = 500
HEIGHT = 400
screen = pygame.display.set_mode(size)
# Loop Switch
done = False
# Screen Update Speed (FPS)
clock = pygame.time.Clock()
# ------- Main Program Loop -------
while not done:
# --- Main Event Loop ---
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
pygame.draw.rect(screen,(78,203,245),(0,0,250,500),5)
screen.fill(GREEN)
pygame.display.flip()
#Setting FPS
clock.tick(60)
#Shutdown
pygame.quit()
You do not want to fill the screen with green every 60 ticks
To fix this, simply put screen.fill(GREEN) outside of the Main loop.
The only time you want screen.fill inside your while loop, is when your adding movement into your program.
I strongly suggest you make a function called draw and draw things outside of your while loop.
I have found the problem:
first of, Glitchd is correct, but you forget to update:
import pygame
import pygame.font
pygame.init()
# Colours
BLACK = ( 0, 0, 0)
WHITE = (255,255,255)
GREEN = ( 0,255, 0)
RED = (255, 0, 0)
BLUE = ( 0, 0,255)
# Dimensions of screen
size = (400,500)
WIDTH = 500
HEIGHT = 400
screen = pygame.display.set_mode(size)
# Loop Switch
done = False
# Screen Update Speed (FPS)
clock = pygame.time.Clock()
# ------- Main Program Loop -------
while not done:
# --- Main Event Loop ---
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
screen.fill(GREEN)
pygame.draw.rect(screen,(78,203,245),(0,0,250,500),5)
pygame.display.flip()
pygame.display.update()
#Setting FPS
clock.tick(60)
#Shutdown
pygame.quit()
U are drawing a shape and then covering it up with green, swap
pygame.draw.rect(screen,(78,203,245),(0,0,250,500),5)
screen.fill(GREEN)
Those 2 around
The problem is that you draw the shape and after that you 'fill' (cover) it with green, so try something like that:
screen.fill(GREEN) #first fill the screen with green
pygame.draw.rect(screen,(78,203,245),(0,0,250,500),5) #and after that draw the rectangle
The error is obvious as first you are drawing a shape then covering it with color . Your code is right but need some rearrangement.
screen.fill("your color") # First you should fill the screen with color
pygame.draw.rect(screen,(78,203,245),(0,0,250,500),5) # Then u should draw any shape
Each of the previously given answers fail to properly elaborate why this issue occurs. It is not about the order of drawing, filling operations; it is about your timing on calling the pygame.display.flip function, or shortly: updating the screen. Your code draws a rectangle, fills the screen with green, and then updates the screen. What it should have done instead is draw the rectangle, update the screen and then fill the screen with green. That way the screen is updated after you draw the rectangle before the screen is filled with green, therefore you can see it:
import pygame
import pygame.font
pygame.init()
# Colours
BLACK = ( 0, 0, 0)
WHITE = (255,255,255)
GREEN = ( 0,255, 0)
RED = (255, 0, 0)
BLUE = ( 0, 0,255)
# Dimensions of screen
size = (400,500)
WIDTH = 500
HEIGHT = 400
screen = pygame.display.set_mode(size)
# Loop Switch
done = False
# Screen Update Speed (FPS)
clock = pygame.time.Clock()
# ------- Main Program Loop -------
while not done:
# --- Main Event Loop ---
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
#In each case you draw the rectangle and then fill the screen with green
pygame.draw.rect(screen,(78,203,245),(0,0,250,500),5)
pygame.display.flip()
screen.fill(GREEN)
#Setting FPS
clock.tick(60)
#Shutdown
pygame.quit()
In a nutshell, you should update after you draw the rectangle.
you should add pygame.display.update() in the while not done loop. pygame.display.update updates the screen. You have this problem because you drew all of the drawings but did not update the screen.
You should first cover the screen with green and then draw your shape because otherwise it will get covered.
I am trying two draw two surfaces, one on top of the other, each with a border around it. Both the top surface (topSurf) and the bottom surface (botSurf) appear on the screen.
When I attempt to draw a border around each surface with the pygame.draw.rect command, the rect on the top surface appears, but the rect on the bottom surface does not.
Why does this happen?
Here is the code:
import sys
import pygame
from pygame.locals import *
pygame.init()
RED = (255,0,0)
GREEN = (0,255,0)
BLUE = (0,0,255)
WHITE = (255,255,255)
screen = pygame.display.set_mode((600,600))
#top surface
topRect = pygame.Rect(0,0,600,500)
topSurf = pygame.Surface((600,500))
topSurf = topSurf.convert()
topSurf.fill(BLUE)
#bottom surface
botSurf = pygame.Surface((600,100))
botRect = pygame.Rect(0,500,600,100)
botSurf = botSurf.convert()
botSurf.fill(GREEN)
#rectangle
pygame.draw.rect(topSurf,RED,topRect,10)
pygame.draw.rect(botSurf,WHITE,botRect,10)
### main game loop
while True:
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
screen.blit(topSurf,topRect)
screen.blit(botSurf,botRect)
pygame.display.flip()
Screenshot
You're using the botRect's coordinates to draw the white rect and that means you're drawing it at the surfaces local coordinates (0, 500), outside of the area of the botSurf. You have to draw the rect at (0, 0) first and then move the rect afterwards if you also want to use it as the blit position of the surface.
botSurf = pygame.Surface((600,100))
botSurf.fill(GREEN)
botRect = pygame.Rect(0,0,600,100)
pygame.draw.rect(botSurf,WHITE,botRect,10)
botRect.y = 500