Loop not completing full code in python 2.7 - python

I have made a number guessing game yet when I run it the loop only loops the
guess = raw_input("Guess the number between 1 and 50: ")
so I was wondering if anyone knew a fix. The full code is listed below:
import random
score = 1000
print "Welcome to this number guessing game!"
number = random.randint(1, 50)
while True:
guess = raw_input("Guess the number between 1 and 50: ")
if guess == number:
print "You got it right!"
print "Your score was:" + score
quit()
if guess < number:
print "Too Big"
score = score - 10
if guess > number:
print "Too Small"
score = score - 10

You want to indent your code properly to let the interpreter know what is inside the loop:
import random
score = 1000
print "Welcome to this number guessing game!"
number = random.randint(1, 50)
while True:
guess = raw_input("Guess the number between 1 and 50: ")
if guess == number:
print "You got it right!"
print "Your score was:" + score
quit()
if guess < number:
print "Too Big"
score = score - 10
if guess > number:
print "Too Small"
score = score - 10

AndreyS got it right, but you're comparing different types and thus not getting the expected output.
Here's a simple example of your game working:
import random
score = 1000
print "Welcome to this number guessing game!"
number = random.randint(1, 50)
while True:
guess = raw_input("Guess the number between 1 and 50: ")
if int(guess) == number:
print "You got it right!"
print "Your score was:" + str(score)
quit()
if int(guess) > number:
print "Too Big"
score = score - 10
if int(guess) < number:
print "Too Small"
score = score - 10
Notice that I'm casting the guess variable to an integer in order to get the comparisons right.

Your code had indentation issue
data/integer read from the command line had to be converted into 'int' form
Use 'break' to exit from while loop when condition is met instead of 'quit()'
Here is the working code :
import random
score = 1000
print "Welcome to this number guessing game!"
number = random.randint(1, 50)
print "number is", number
while True:
guess = int(raw_input("Guess the number between 1 and 50: "))
print "number is", guess
if (guess == number):
print "You got it right!"
print "Your score was:", score
break
if (guess < number):
print "Too Small"
score = score - 10
if (guess > number):
print "Too Big"
score = score - 10

Related

I am trying to do the basic number guessing game on python

I am having trouble writing the code of the basic number guessing game in Python. The objective of the game is to correctly guess a number from 1 to 10 picked at random by the program. I also put some help text that tells the users if they guessed too high or too low. I keep getting a syntax error. This is the code i wrote so far:
print "Welcome to the number guessing game"
print "I have my number..."
import random
while True:
random.randint(1, 10)
number = raw_input("What is your guess[1-10]: ")
if number > random.radint(1, 10):
print "sorry you guessed to high"
elif number < random.radint(1, 10):
print "You guessed to low"
elif number == random.radint(1, 10):
print "You guessed right thanks for playing"
break
else: raw_input("What is your guess[1-10]: ")
It is randint not radint. You are creating a new random number for every test; you should assign a variable to a random number outside of the while loop.
r = random.randint(1, 10)
You must indent if: else: blocks - Python is layout sensitive, e.g.
if number > r:
print "sorry you guessed to high"
You are comparing against a str, need to convert the input to an int().
number = int(raw_input("What is your guess[1-10]: "))
You have an unnecessary else: condition at the end.
So putting it all together:
import random
print "Welcome to the number guessing game"
print "I have my number..."
r = random.randint(1, 10)
while True:
number = int(raw_input("What is your guess[1-10]: "))
if number > r:
print "sorry you guessed to high"
elif number < r:
print "You guessed to low"
else:
print "You guessed right thanks for playing"
break
You could change the while loop to cover the condition:
import random
print "Welcome to the number guessing game"
print "I have my number..."
number = 0
r = random.randint(1, 10)
while number != r:
number = int(raw_input("What is your guess[1-10]: "))
if number > r:
print "sorry you guessed to high"
elif number < r:
print "You guessed to low"
print "You guessed right thanks for playing"

Avoid Nesting If Statements? (Python 2.7)

I got the idea for this guessing game from a book, Invent With Python. I didn't like that the original script didn't cover the possibilities of re-guessing a number or incorrectly using a number not in 1 - 20, so I modified it. The program works great, however, I'm just wrapping my head around if/elif/else code blocks.
I'd like to rewrite the script without having to nest and if inside of an if. I can't even begin to wrap my head around how to do that. Can anyone please help me--just one example of how this program could work without nesting would be great!
Here's the little script in its entirety:
from random import randint
from sys import exit
name = raw_input("Hello! What's your name? ")
print "Well %s, I'm thinking of a number between 1 and 20." % name
print "Since I'm a benevolent computer program, I'll give you 6 guesses."
secret_number = randint(1, 20)
guesses_left = 6
already_guessed = []
while guesses_left > 0:
try:
guess = int(raw_input("Take a guess: "))
if guess >= 1 and guess <= 20 and guess not in already_guessed:
already_guessed.append(guess)
guesses_left -= 1
if guess == secret_number:
print "You win! %d was my secret number!" % secret_number
exit(0)
elif guess < secret_number:
print "Your guess is too low!"
elif guess > secret_number:
print "Your guess is too high!"
elif guess in already_guessed:
print "You already guessed that!"
else:
print "Not a number between 1 - 20!"
print "Please try again!"
print "You have %d guesses left!" % guesses_left
except ValueError:
print "Invalid input! Please try again!"
Try it like this, using continue to exit the current iteration of the loop and start again at the top of the loop.
You also had a logic bug here:
if guess <= 1 and guess >= 20 and guess not in already_guessed:
A number cannot possibly be both less than or equal to 1, and greater than or equal to 20. Your and should have been an or like this:
if (guess <= 1 or guess >= 20) and guess not in already_guessed:
Or simpler:
if 1 <= guess <= 20 and guess not in already_guessed:
Also, keep your try/except only around the things that can actually raise an exception (or shouldn't happen if an exception occurs:
from random import randint
import sys
name = raw_input("Hello! What's your name? ")
print "Well {}, I'm thinking of a number between 1 and 20.".format(name)
print "Since I'm a benevolent computer program, I'll give you 6 guesses."
secret_number = randint(1, 20)
guesses_left = 6
already_guessed = []
while guesses_left > 0:
print "You have {} guesses left!".format(guesses_left)
try:
guess = int(raw_input("Take a guess: "))
except ValueError:
print "Invalid input! Please try again!\n"
continue
# If the number is not between 1 and 20...
if not (1 <= guess <= 20):
print "Not a number between 1 - 20!"
print "Please try again!\n"
continue
if guess in already_guessed:
print "You already guessed that!\n"
continue
guesses_left -= 1
already_guessed.append(guess)
if guess == secret_number:
print "You win! {} was my secret number!".format(secret_number)
sys.exit(0)
elif guess < secret_number:
print "Your guess is too low!\n"
elif guess > secret_number:
print "Your guess is too high!\n"
Here's an example run:
Hello! What's your name? :)
Well :), I'm thinking of a number between 1 and 20.
Since I'm a benevolent computer program, I'll give you 6 guesses.
You have 6 guesses left!
Take a guess: 2
Your guess is too low!
You have 5 guesses left!
Take a guess: 2
You already guessed that!
You have 5 guesses left!
Take a guess: 3
Your guess is too low!
You have 4 guesses left!
Take a guess: 7
Your guess is too high!
You have 3 guesses left!
Take a guess: 5
Your guess is too high!
You have 2 guesses left!
Take a guess: 4
You win! 4 was my secret number!
Just change the nested if statements to elif like so:
from random import randint
from sys import exit
name = raw_input("Hello! What's your name? ")
print "Well %s, I'm thinking of a number between 1 and 20." % name
print "Since I'm a benevolent computer program, I'll give you 6 guesses."
secret_number = randint(1, 20)
guesses_left = 6
already_guessed = []
while guesses_left > 0:
try:
guess = int(raw_input("Take a guess: "))
if guess <= 1 and guess >= 20 and guess not in already_guessed:
already_guessed.append(guess)
guesses_left -= 1
elif guess == secret_number:
print "You win! %d was my secret number!" % secret_number
exit(0)
elif guess < secret_number:
print "Your guess is too low!"
elif guess > secret_number:
print "Your guess is too high!"
elif guess in already_guessed:
print "You already guessed that!"
else:
print "Not a number between 1 - 20!"
print "Please try again!"
print "You have %d guesses left!" % guesses_left
except ValueError:
print "Invalid input! Please try again!"
This would be simplest way i see to solve your dilema

Guess the number game, error.

This is a game I am currently trying to make. I am coding this game in python 3.4. it doesn't run.
# this is a guess the number game!
import random
guesses = 0
name = input("what is your name?")
number = random.randint(1, 20)
print = name + ", I am thinking of a number between 1 and 20..."
while guesses << 7:
guess = int(raw_input("Take a guess."))
guesses = guesses + 1
if guess < number:
print ("your guess is too low!")
if guess > number:
print ("your guess is too high!")
if guess == number:
break
if guess == number:
guesses = str(guesses)
print ("Good job," + name + "you guessed my number in" +guesses +"guesses!")
if guess != number:
number = str(number)
print ("Nah dude, better luck next time!")
I think you meant to use < instead of <<. << and >> are bit shift operators to the left and right respectively.
Your last two if conditions are also outside your loop, and don't make much sense. You're already checking if guess == number once and breaking if that condition is met. if guess != number your already checking this by using < and > respectively.
print = ...? print syntax is print(some_stuff, ...). Indentation is also off at the top, but assuming that's just due to posting your first question.
Also, raw_input is for python2 it's just input in python3. You could clean the print statements up some with % formatters or using .format.
Fixed code: (Python 3 version since that's whats tagged in the question...)
import random
name = input("what is your name?")
number = random.randint(1, 20)
#print("%s I am thinking of a number between 1 and 20..." % name)
print(name + " I am thinking of a number between 1 and 20...")
guesses = 0
while guesses < 7:
guess = int(input("Take a guess."))
guesses += 1
if guess < number:
print ("your guess is too low!")
elif guess > number:
print ("your guess is too high!")
else:
#print("Good job %s you guessed my number in %d guesses" % (name, guesses))
print ("Good job, " + name + " you guessed my number in " + str(guesses) + " guesses!")
break
There are many errors in your program. Always include errors you get in your question. Given the syntax error you are making first get your hands dirty on python interpreter by executing simple commands. Below should help. Below is in Python 2, for Python 3 replace, raw_input() with input and print 'something' with print ('something')
1st Solution:
import random
name = raw_input("Hello! What is your name?\n")
print "Well, " + name + ", I am thinking of a number between 1 and 20"
no = random.randint(1,20)
guess = int(raw_input("Take a guess\n"))
count =1
while guess != no:
if guess < no:
print "Your guess is too low."
if guess > no:
print "Your guess is too high"
count +=1
guess = int(raw_input("Take a guess\n"))
print "Good job, %s! You guessed my number in %d guesses!" % (name ,count)
2nd Solution:
import random
def check():
global count # good example of use of global
guess = int(raw_input("Take a guess\n"))
if guess == no:
print "Good job, %s! You guessed my number in %d guesses!" %(name,count)
elif guess < no:
print "Your guess is too low."
count +=1
check()
else:
print "Your guess is too high"
count +=1
check()
name = raw_input("Hello! What is your name?\n")
print "Well, " + name + ", I am thinking of a number between 1 and 20"
no = random.randint(1,20)
global count
count =1
check()
Your code goes good, little changes can make it run!
import random
guesses = 0
name = raw_input("what is your name?") # use input() is using Python 3
number = random.randint(1, 20)
print name + ", I am thinking of a number between 1 and 20..."
while guesses < 7:
guess = int(raw_input("Take a guess."))
guesses = guesses + 1
if guess < number:
print ("your guess is too low!")
if guess > number:
print ("your guess is too high!")
if guess == number:
break
if guesses == number:
print ("Good job,", name, "you guessed my number in", guesses, "guesses!")
if guesses != number:
number = str(number)
print ("Nah dude, better luck next time!", "The number is", number)

Codecademy Loops 8/19

I haven't programmed in a while so I thought I'd continue with my codecademy tutorial to get back into shape. I'm really confused right now because I'm getting all these syntax errors where I'm pretty sure I shouldn't.
Here's my code:
from random import randint
# Generates a number from 1 through 10 inclusive
random_number = randint(1, 10)
guesses_left = 3
# Start your game!
while guesses_left > 0:
guess = int(raw_input("Your guess: ")
if guess == random_number:
print "You win!"
break
guesses_left = guesses_left - 1
else:
print "You lose."
I'm getting a syntax error because of the colon on line 10.
I don't get why, its an if statement, and after an if statement you always have a colon don't you?
I've been getting a bunch of syntax errors today for simple stuff like this and I don't understand why.
Is this a straight copy/paste of your code? Your int() is unclosed
guess = int(raw_input("Your guess: ") <--- missing parenthesis
Also, the decrement of guesses_left is in the wrong place. It should probably be placed after the else block, since it should be decremented every loop, regardless of the result of the if/else
Further, the indentation on your else block doesn't line up with your if. Indentation in python is key.
Slight changes to your code:
from random import randint
# Generates a number from 1 through 10 inclusive
random_number = randint(1, 10)
guesses_left = 3
# Start your game!
while guesses_left > 0:
guesses_left = guesses_left - 1
guess = int(raw_input("Your guess: "))
if guess == random_number:
print "You win!"
break
else:
print "You lose."
This code works and gets you through. The main error I got was that it works but still said there was an error after the game was over. This was due to my else: print 'You lose.' being part of the while operation. Instead have the else: function on the same indentation as the while: , and this is what they wanted to see
from random import randint
# Generates a number from 1 through 10 inclusive
random_number = randint(1, 10)
guesses_left = 3
while guesses_left > 0:
guess = int(raw_input("Your guess: "))
guesses_left -= 1
if guess == random_number:
print "You win!"
break
else:
print "You lose."
Here is how i did it, I've added some extra features just for fun c:
from random import randint
# Generates a number from 1 through 10 inclusive
random_number = randint(1, 10)
print random_number # For debugging
guesses_left = 3 # Amount of guesses left
print "Guess my number! You've got 3 tries left!"
tries = [] # Array for user input
while guesses_left > 0:
guess = int(raw_input("Your guess: ")) # Asks user to enter a number
if guess in tries: # Checks if user entered the same number before
print "You've already guessed this number: ", guess
print "You've got " , int(guesses_left) , " guess(es) left!"
elif guess > 10 or guess < 1: # Checks if user input is between 1 and 10
print "Wrong input! Guess a number between 1 and 10!"
print "You've got " , int(guesses_left) , " guess(es) left!"
elif guess == random_number: # If user input is the same as the random number you win!
print "You win!"
break
else:
guesses_left -= 1 # Decreases the amount of guesses left
print "You've got " , int(guesses_left) , " guess(es) left!"
tries.append(guess) # Saves user input to "tries"
else:
print "You lose!"

Python: Number Guessing Game

Your program chooses the number to be guessed by selecting an integer at random in the range 1 to 1000 (inclusive). If the player's guess is incorrect, your program should loop until the player finally gets the number right. Your program should keep telling the player Too high or Too low to help the player “zero in” on the correct answer. After a game ends, the program should prompt the user to enter "y" to play again or "n" to exit the game.
My problem is how do you generate a new random integer each time they want to play again?
Here's my code.
import random
randomNumber = random.randrange(1, 1000)
def main():
print ""
number = input("I have a number between 1 and 1000. Can you guess my number? Please type your first guess: ")
guess(number)
def guess(number1):
correct = False
while not correct:
if number1 > randomNumber:
print "Too high. Try again."
print ""
elif number1 < randomNumber:
print "Too low. Try again."
print ""
elif number1 == randomNumber:
break
number1 = input ("What number do you guess? ")
if number1 == randomNumber:
playAagain = raw_input ("Excellent! You guessed the number! Would you like to play again (y or n)? ")
if playAagain == "y":
main()
main()
Take this line:
randomNumber = random.randrange(1, 1000)
and place it inside guess:
import random
def main():
print ""
number = input("I have a number between 1 and 1000. Can you guess my number? Please type your first guess: ")
guess(number)
def guess(number1):
#########################################
randomNumber = random.randrange(1, 1000)
#########################################
correct = False
while not correct:
if number1 > randomNumber:
print "Too high. Try again."
print ""
elif number1 < randomNumber:
print "Too low. Try again."
print ""
elif number1 == randomNumber:
break
number1 = input ("What number do you guess? ")
if number1 == randomNumber:
playAagain = raw_input ("Excellent! You guessed the number! Would you like to play again (y or n)? ")
if playAagain == "y":
main()
main()
Now, a new random integer will be created each time the function is called.
Put a loop in main() and initialize randomNumber at the beginning of the loop.
please try this remove four spaces starting from random to starting of while loop
import random
print " welcome to game of guessing "
print "you have 6 attempts"
num1 = random.randint(1,100)
print num1 # this is your computer generated number ( skip while running :only for test purpose)
num2 = num1+random.randint(1,15)
print " hint: number is close to " + str(num2)
count=1
while count<=6:
print " enter the number you think"
inputnum=raw_input()
if inputnum==str(num1):
print "congrats you guess the correct number"
break
elif inputnum<str(num1):
print " number is lower than correct one "
count=count+1
elif inputnum>str(num1):
print "number is greater than correct one"
count=count+1
else:
break
You just have to define your main() function like this.
def main():
global randomNumber
print ""
randomNumber = random.randrange(1, 1000)
number = input("I have a number between 1 and 1000. Can you guess my number? Please type your first guess: ")
guess(number)
And everything will be perfect. Hope this helps.

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