You know how in Linux when you try some Sudo stuff it tells you to enter the password and, as you type, nothing is shown in the terminal window (the password is not shown)?
Is there a way to do that in Python? I'm working on a script that requires so sensitive info and would like for it to be hidden when I'm typing it.
In other words, I want to get the password from the user without showing the password.
Use getpass.getpass():
from getpass import getpass
password = getpass()
An optional prompt can be passed as parameter; the default is "Password: ".
Note that this function requires a proper terminal, so it can turn off echoing of typed characters – see “GetPassWarning: Can not control echo on the terminal” when running from IDLE for further details.
import getpass
pswd = getpass.getpass('Password:')
getpass works on Linux, Windows, and Mac.
This code will print an asterisk instead of every letter.
import sys
import msvcrt
passwor = ''
while True:
x = msvcrt.getch()
if x == '\r':
break
sys.stdout.write('*')
passwor +=x
print '\n'+passwor
Updating on the answer of #Ahmed ALaa
# import msvcrt
import getch
def getPass():
passwor = ''
while True:
x = getch.getch()
# x = msvcrt.getch().decode("utf-8")
if x == '\r' or x == '\n':
break
print('*', end='', flush=True)
passwor +=x
return passwor
print("\nout=", getPass())
msvcrt us only for windows, but getch from PyPI should work for both (I only tested with linux).
You can also comment/uncomment the two lines to make it work for windows.
You can also use the pwinput module which works on both Windows and Linux.
It replaces the char with '*' (by default) and backspace works.
import pwinput
password = pwinput.pwinput(prompt='Password: ')
You can, optionally, pass a different mask character as well.
import pwinput
password = pwinput.pwinput(prompt='Password: ', mask='')
See the pwinput documentation for more information.
Here is my code based off the code offered by #Ahmed ALaa
Features:
Works for passwords up to 64 characters
Accepts backspace input
Outputs * character (DEC: 42 ; HEX: 0x2A) instead of the input character
Demerits:
Works on Windows only
The function secure_password_input() returns the password as a string when called. It accepts a Password Prompt string, which will be displayed to the user to type the password
def secure_password_input(prompt=''):
p_s = ''
proxy_string = [' '] * 64
while True:
sys.stdout.write('\x0D' + prompt + ''.join(proxy_string))
c = msvcrt.getch()
if c == b'\r':
break
elif c == b'\x08':
p_s = p_s[:-1]
proxy_string[len(p_s)] = " "
else:
proxy_string[len(p_s)] = "*"
p_s += c.decode()
sys.stdout.write('\n')
return p_s
Related
You know how in Linux when you try some Sudo stuff it tells you to enter the password and, as you type, nothing is shown in the terminal window (the password is not shown)?
Is there a way to do that in Python? I'm working on a script that requires so sensitive info and would like for it to be hidden when I'm typing it.
In other words, I want to get the password from the user without showing the password.
Use getpass.getpass():
from getpass import getpass
password = getpass()
An optional prompt can be passed as parameter; the default is "Password: ".
Note that this function requires a proper terminal, so it can turn off echoing of typed characters – see “GetPassWarning: Can not control echo on the terminal” when running from IDLE for further details.
import getpass
pswd = getpass.getpass('Password:')
getpass works on Linux, Windows, and Mac.
This code will print an asterisk instead of every letter.
import sys
import msvcrt
passwor = ''
while True:
x = msvcrt.getch()
if x == '\r':
break
sys.stdout.write('*')
passwor +=x
print '\n'+passwor
Updating on the answer of #Ahmed ALaa
# import msvcrt
import getch
def getPass():
passwor = ''
while True:
x = getch.getch()
# x = msvcrt.getch().decode("utf-8")
if x == '\r' or x == '\n':
break
print('*', end='', flush=True)
passwor +=x
return passwor
print("\nout=", getPass())
msvcrt us only for windows, but getch from PyPI should work for both (I only tested with linux).
You can also comment/uncomment the two lines to make it work for windows.
You can also use the pwinput module which works on both Windows and Linux.
It replaces the char with '*' (by default) and backspace works.
import pwinput
password = pwinput.pwinput(prompt='Password: ')
You can, optionally, pass a different mask character as well.
import pwinput
password = pwinput.pwinput(prompt='Password: ', mask='')
See the pwinput documentation for more information.
Here is my code based off the code offered by #Ahmed ALaa
Features:
Works for passwords up to 64 characters
Accepts backspace input
Outputs * character (DEC: 42 ; HEX: 0x2A) instead of the input character
Demerits:
Works on Windows only
The function secure_password_input() returns the password as a string when called. It accepts a Password Prompt string, which will be displayed to the user to type the password
def secure_password_input(prompt=''):
p_s = ''
proxy_string = [' '] * 64
while True:
sys.stdout.write('\x0D' + prompt + ''.join(proxy_string))
c = msvcrt.getch()
if c == b'\r':
break
elif c == b'\x08':
p_s = p_s[:-1]
proxy_string[len(p_s)] = " "
else:
proxy_string[len(p_s)] = "*"
p_s += c.decode()
sys.stdout.write('\n')
return p_s
This question already has answers here:
Getting a hidden password input
(6 answers)
Closed 7 months ago.
This post was edited and submitted for review 3 months ago and failed to reopen the post:
Original close reason(s) were not resolved
Is there a way in Python to convert characters as they are being entered by the user to asterisks, like it can be seen on many websites?
For example, if an email user was asked to sign in to their account, while typing in their password, it wouldn't appear as characters but rather as * after each individual stroke without any time lag.
If the actual password was KermitTheFrog, it would appear as ************* when typed in.
I am not asking about how to disable echoing characters to the screen, which is what Python's getpass.getpass() module does. I specifically want the feature where asterisks appear in response to key presses, which getpass doesn't do.
There is getpass(), a function which hides the user input.
import getpass
password = getpass.getpass()
print(password)
If you want a solution that works on Windows/macOS/Linux and on Python 2 & 3, you can install the pwinput module (formerly called stdiomask):
pip install pwinput
Unlike getpass.getpass() (which is in the Python Standard Library), the pwinput module can display *** mask characters as you type. It is also cross-platform, while getpass is Linux and macOS only.
Example usage:
>>> pwinput.pwinput()
Password: *********
'swordfish'
>>> pwinput.pwinput(mask='X') # Change the mask character.
Password: XXXXXXXXX
'swordfish'
>>> pwinput.pwinput(prompt='PW: ', mask='*') # Change the prompt.
PW: *********
'swordfish'
>>> pwinput.pwinput(mask='') # Don't display anything.
Password:
'swordfish'
Unfortunately this module, like Python's built-in getpass module, doesn't work in IDLE or Jupyter Notebook.
More details at https://pypi.org/project/pwinput/
If you're using Tkinter:
# For Python 2:
from Tkinter import Entry, Tk
# For Python 3
from tkinter import Entry, Tk
master = Tk()
Password = Entry(master, bd=5, width=20, show="*")
Password.pack()
master.mainloop()
In the shell, this is not possible. You can however write a function to store the entered text and report only a string of *'s when called.
Kinda like this, which I did not write. I just Googled it.
You can do this:
# if getch module is available, then we implement our own getpass() with asterisks,
# otherwise we just use the plain boring getpass.getpass()
try:
import getch
def getpass(prompt):
"""Replacement for getpass.getpass() which prints asterisks for each character typed"""
print(prompt, end='', flush=True)
buf = ''
while True:
ch = getch.getch()
if ch == '\n':
print('')
break
else:
buf += ch
print('*', end='', flush=True)
return buf
except ImportError:
from getpass import getpass
first install the library:
pip install stdiomask
note that you install std io mask not studiomask...
And then the code is:
password = stdiomask.getpass() # It will ask to enter password and display * on the screen
print(password)
This is the output:
Password: *****
google
while using getpass in python, nothing is indicated to show a password input.
this can be resolved by this simple solution:
just copy the ‘getpass_ak.py’ module provided in the link to python’s Lib folder.
https://starrernet.wixsite.com/analytix/python-coder
use the following code:
import getpass_ak
a = (getpass_ak.getpass('password: '))
this will add * to your password inputs.
For anyone who would actually want to have asterisks appear, here's an improvement on Tigran Aivazian's answer. This version imports the built-in msvcrt.getch, adds cases for different line endings when hitting 'Enter/Return', and includes logic to support Backspace, as well as Ctrl+C (KeyboardInterrupt):
try:
from msvcrt import getch
def getpass(prompt):
"""Replacement for getpass.getpass() which prints asterisks for each character typed"""
print(prompt, end='', flush=True)
buf = b''
while True:
ch = getch()
if ch in {b'\n', b'\r', b'\r\n'}:
print('')
break
elif ch == b'\x08': # Backspace
buf = buf[:-1]
print(f'\r{(len(prompt)+len(buf)+1)*" "}\r{prompt}{"*" * len(buf)}', end='', flush=True)
elif ch == b'\x03': # Ctrl+C
raise KeyboardInterrupt
else:
buf += ch
print('*', end='', flush=True)
return buf.decode(encoding='utf-8')
except ImportError:
from getpass import getpass
Please feel free to suggest any other changes, or ways to improve this; I hacked the changes together pretty quickly, especially with the Backspace logic.
I have combined the answers of #Tigran Aivazian and #Ahndwoo into fully working solution:
! additional code for the backspace {b'\x08', b'\x7f'}: # Backspace is added
for the Ctrl+C combination the silent return is used. The raise KeyboardInterrupt is commented now, but can be uncommented for raise the error.
# if getch module is available, then we implement our own getpass() with asterisks,
# otherwise we just use the plain boring getpass.getpass()
try:
from getch import getch
def getpass(prompt):
"""Replacement for getpass.getpass() which prints asterisks for each character typed"""
print(prompt, end='', flush=True)
buf = b''
while True:
ch = getch().encode()
if ch in {b'\n', b'\r', b'\r\n'}:
print('')
break
elif ch == b'\x03': # Ctrl+C
# raise KeyboardInterrupt
return ''
elif ch in {b'\x08', b'\x7f'}: # Backspace
buf = buf[:-1]
print(f'\r{(len(prompt)+len(buf)+1)*" "}\r{prompt}{"*" * len(buf)}', end='', flush=True)
else:
buf += ch
print('*', end='', flush=True)
return buf.decode(encoding='utf-8')
except ImportError:
from getpass import getpass
password = getpass('Enter password: ')
print(password)
My own suggestion is -- DO NOT DO IT!
Don't reinvent the wheel, use a password helper if you want 'stars'
Instead do something like the following pseudo-code... If the TTY_ASSPASS environment variable is set -- call that password helper. There are a number available, including "systemd-ask-password" If there is a TTY - fall back to read no echo (getpass.getpass()) If there is no TTY, - fall back just read STDIN with rstrip()
This not only lets the user select a password input program (via an environment variable (or some other confuguration), but also lets them substitute for other sources of passwords, like GUI input, or collecting password from a pre-opened keyring password daemon, or elsewhere
Don't restrict or otherwise limit where passwords come from!
For notes on password helpers see.. https://antofthy.gitlab.io/info/crypto/passwd_input.txt
For a shell script password helper https://antofthy.gitlab.io/software/#askpass_stars
Looks like Andrei Krivoshei answer has already made a start on that, resulting in something very similar, but still in its infancy.
You may want to check getpass function.
Prompt the user for a password without echoing. The user is prompted
using the string prompt, which defaults to 'Password: '. On Unix, the
prompt is written to the file-like object stream. stream defaults to
the controlling terminal (/dev/tty) or if that is unavailable to
sys.stderr (this argument is ignored on Windows).
Note: This module mimics unix password prompts and does not show asterisks.
Usage:
import getpass
getpass.getpass()
You know how in Linux when you try some Sudo stuff it tells you to enter the password and, as you type, nothing is shown in the terminal window (the password is not shown)?
Is there a way to do that in Python? I'm working on a script that requires so sensitive info and would like for it to be hidden when I'm typing it.
In other words, I want to get the password from the user without showing the password.
Use getpass.getpass():
from getpass import getpass
password = getpass()
An optional prompt can be passed as parameter; the default is "Password: ".
Note that this function requires a proper terminal, so it can turn off echoing of typed characters – see “GetPassWarning: Can not control echo on the terminal” when running from IDLE for further details.
import getpass
pswd = getpass.getpass('Password:')
getpass works on Linux, Windows, and Mac.
This code will print an asterisk instead of every letter.
import sys
import msvcrt
passwor = ''
while True:
x = msvcrt.getch()
if x == '\r':
break
sys.stdout.write('*')
passwor +=x
print '\n'+passwor
Updating on the answer of #Ahmed ALaa
# import msvcrt
import getch
def getPass():
passwor = ''
while True:
x = getch.getch()
# x = msvcrt.getch().decode("utf-8")
if x == '\r' or x == '\n':
break
print('*', end='', flush=True)
passwor +=x
return passwor
print("\nout=", getPass())
msvcrt us only for windows, but getch from PyPI should work for both (I only tested with linux).
You can also comment/uncomment the two lines to make it work for windows.
You can also use the pwinput module which works on both Windows and Linux.
It replaces the char with '*' (by default) and backspace works.
import pwinput
password = pwinput.pwinput(prompt='Password: ')
You can, optionally, pass a different mask character as well.
import pwinput
password = pwinput.pwinput(prompt='Password: ', mask='')
See the pwinput documentation for more information.
Here is my code based off the code offered by #Ahmed ALaa
Features:
Works for passwords up to 64 characters
Accepts backspace input
Outputs * character (DEC: 42 ; HEX: 0x2A) instead of the input character
Demerits:
Works on Windows only
The function secure_password_input() returns the password as a string when called. It accepts a Password Prompt string, which will be displayed to the user to type the password
def secure_password_input(prompt=''):
p_s = ''
proxy_string = [' '] * 64
while True:
sys.stdout.write('\x0D' + prompt + ''.join(proxy_string))
c = msvcrt.getch()
if c == b'\r':
break
elif c == b'\x08':
p_s = p_s[:-1]
proxy_string[len(p_s)] = " "
else:
proxy_string[len(p_s)] = "*"
p_s += c.decode()
sys.stdout.write('\n')
return p_s
This question already has answers here:
Getting a hidden password input
(6 answers)
Closed 7 months ago.
I am trying to mask what the user types into IDLE with asterisks so people around them can't see what they're typing/have typed in. I'm using basic raw input to collect what they type.
key = raw_input('Password :: ')
Ideal IDLE prompt after user types password:
Password :: **********
If you want a solution that works on Windows/macOS/Linux and on Python 2 & 3, you can install the pwinput module:
pip install pwinput
Unlike getpass.getpass() (which is in the Python Standard Library), the pwinput module can display *** mask characters as you type.
Example usage:
>>> pwinput.pwinput()
Password: *********
'swordfish'
>>> pwinput.pwinput(mask='X') # Change the mask character.
Password: XXXXXXXXX
'swordfish'
>>> pwinput.pwinput(prompt='PW: ', mask='*') # Change the prompt.
PW: *********
'swordfish'
>>> pwinput.pwinput(mask='') # Don't display anything.
Password:
'swordfish'
Unfortunately this module, like Python's built-in getpass module, doesn't work in IDLE or Jupyter Notebook.
More details at https://pypi.org/project/pwinput/
Note that pwinput is the new name for the stdiomask module.
To solve this I wrote this small module pyssword to mask the user input password at the prompt. It works with windows. The code is below:
from msvcrt import getch
import getpass, sys
def pyssword(prompt='Password: '):
'''
Prompt for a password and masks the input.
Returns:
the value entered by the user.
'''
if sys.stdin is not sys.__stdin__:
pwd = getpass.getpass(prompt)
return pwd
else:
pwd = ""
sys.stdout.write(prompt)
sys.stdout.flush()
while True:
key = ord(getch())
if key == 13: #Return Key
sys.stdout.write('\n')
return pwd
break
if key == 8: #Backspace key
if len(pwd) > 0:
# Erases previous character.
sys.stdout.write('\b' + ' ' + '\b')
sys.stdout.flush()
pwd = pwd[:-1]
else:
# Masks user input.
char = chr(key)
sys.stdout.write('*')
sys.stdout.flush()
pwd = pwd + char
Disclaimer: does not provide the asterix in terminal, but it does so in jupyter notebook.
The below code provides replaces written characters with asterix and allow for deletion of wrongly typed characters. The number of asterixes reflects the number of typed characters.
import getpass
key = getpass.getpass('Password :: ')
And after the user press enter:
Depending on the OS, how you get a single character from user input and how to check for the carriage return will be different.
See this post: Python read a single character from the user
On OSX, for example, you could so something like this:
import sys, tty, termios
def getch():
fd = sys.stdin.fileno()
old_settings = termios.tcgetattr(fd)
try:
tty.setraw(sys.stdin.fileno())
ch = sys.stdin.read(1)
finally:
termios.tcsetattr(fd, termios.TCSADRAIN, old_settings)
return ch
key = ""
sys.stdout.write('Password :: ')
while True:
ch = getch()
if ch == '\r':
break
key += ch
sys.stdout.write('*')
print
print key
I stumbled upon this thread while I was trying to preform the same feat. I know this thread is old, but if anyone else needs this - here is how I did it.
I ended up using readchar package.
Here is my solution, it prints asterisks and also handles backspaces:
import sys, readchar
def passprompt(prompt: str, out = sys.stdout) -> str:
out.write(prompt); out.flush()
password = ""
while True:
ch = str(readchar.readchar(), encoding='UTF-8')
if ch == '\r':
break
elif ch == '\b':
out.write('\b \b')
password = password[0:len(password)-1]
out.flush()
else:
password += ch
out.write('*')
out.flush()
return password
I had to regularly flush stdout for it to work.
My suggestion is -- DO NOT DO IT!
Don't reinvent the wheel, use a password helper if you want 'stars'
See https://stackoverflow.com/a/67327327/701532
I'm writing a console program with Python under Windows.
The user need to login to use the program, when he input his password, I'd like they to be echoed as "*", while I can get what the user input.
I found in the standard library a module called getpass, but it will not echo anything when you input(linux like).
Thanks.
The getpass module is written in Python. You could easily modify it to do this. In fact, here is a modified version of getpass.win_getpass() that you could just paste into your code:
import sys
def win_getpass(prompt='Password: ', stream=None):
"""Prompt for password with echo off, using Windows getch()."""
import msvcrt
for c in prompt:
msvcrt.putch(c)
pw = ""
while 1:
c = msvcrt.getch()
if c == '\r' or c == '\n':
break
if c == '\003':
raise KeyboardInterrupt
if c == '\b':
pw = pw[:-1]
msvcrt.putch('\b')
else:
pw = pw + c
msvcrt.putch("*")
msvcrt.putch('\r')
msvcrt.putch('\n')
return pw
You might want to reconsider this, however. The Linux way is better; even just knowing the number of characters in a password is a significant hint to someone who wants to crack it.
kindall's answer is close, but it has issues with backspace not erasing the asterisks, as well as backspace being able to go back beyond the input prompt.
Try:
def win_getpass(prompt='Password: ', stream=None):
"""Prompt for password with echo off, using Windows getch()."""
if sys.stdin is not sys.__stdin__:
return fallback_getpass(prompt, stream)
import msvcrt
for c in prompt:
msvcrt.putwch(c)
pw = ""
while 1:
c = msvcrt.getwch()
if c == '\r' or c == '\n':
break
if c == '\003':
raise KeyboardInterrupt
if c == '\b':
if pw == '':
pass
else:
pw = pw[:-1]
msvcrt.putwch('\b')
msvcrt.putwch(" ")
msvcrt.putwch('\b')
else:
pw = pw + c
msvcrt.putwch("*")
msvcrt.putwch('\r')
msvcrt.putwch('\n')
return pw
Note mscvrt.putwch does not work with python 2.x, you need to use mscvrt.putch instead.
You can use the getpass module. This doesn't exactly answer the question because the getpass function doesn't output anything to the console except for the prompt. The reason for this is that it's an extra layer of security. If someone is watching over your shoulder, they won't be able to figure out how long your password is.
Here's an example of how to use it:
from getpass import getpass
getpass('Enter your password: ')
This example will display "Enter your password: " and then you can type in your password.