Access the form that caused a post_save [Django] - python

Is there a way I can access the form that caused a post_save?
The use case is that I have a field (a checkbox) that isn't attached to a particular model, but it's an extra field in the form itself.
I want to know whether the field was checked or unchecked when the form got saved and the model stored, and imho the post_save signal is a good place to put the logic that should process that extra field.
I'm also open to suggestions where else I could put that piece of code.

post_save won't know anything about any form that might have caused the model change.
If you want to access that checkbox value you need to do it in the form class itself. I would probably override the clean() method of the form, and check for the checkbox value in cleaned_data['checkbox_field'] there, and then do whatever you need to with it.

Related

Passing a model instance, not __unicode__ method in django

I've got a django form that contains a join via a foreign key. This is a foreign key to a very large table. On the form, to prevent loading up a massive select that tends to crash browsers, I've got a jQuery autocomplete, which on each keystroke sends off the entered text. This text is then searched in the table and suitable results are returned to be displayed. The id is then passed to a hidden CharField when one is selected. This hidden CharField is the widget for the ForeignKey relation. When I try to save the form, I get an error that I need to be passing a model instance for the related model, which is fair enough. I can't work out how to do this however. I can take that id and do a model.objects.get(pk=id_from_form), but if I replace the POST data with the result of this, I still get an error as I'm just passing the __unicode__ method of the model. I'm sure there's something I'm missing, but I can't see what it is.
Thanks.
Instead of using a CharField to store the id, try using a ModelChoiceField with the widget set as a HiddenInput. The field definition in your form would look something like:
mymodel = forms.ModelChoiceField(widget=forms.HiddenInput, queryset=MyModel.objects.all())

How to use Post_save in Django

I am trying to add points to a User's profile after they submit a comment- using the Django comment framework. I think I need to use a post_save but am not sure to be perfectly honest.
Here is what I have as a method in my models.py:
def add_points(request, Comment):
if Comment.post_save():
request.user.get_profile().points += 2
request.user.get_profile().save()
From the examples of post_save I've found, this is far from what is shown - so I think I am way off the mark.
Thank you for your help.
Unfortunately this makes no sense at all.
Firstly, this can't be a method, as it doesn't have self as the first parameter.
Secondly, it seems to be taking the class, not an instance. You can't save the class itself, only an instance of it.
Thirdly, post_save is not a method of the model (unless you've defined one yourself). It's a signal, and you don't call a signal, you attach a signal handler to it and do logic there. You can't return data from a signal to a method, either.
And finally, the profile instance that you add 2 to will not necessarily be the same as the one you save in the second line, because Django model instances don't have identity. Get it once and put it into a variable, then save that.
The Comments framework defines its own signals that you can use instead of the generic post_save. So, what you actually need is to register a signal handler on comment_was_posted. Inside that handler, you'll need to get the user's profile, and update that.
def comment_handler(sender, comment, request, **kwargs):
profile = request.user.get_profile()
profile.points += 2
profile.save()
from django.contrib.comments.signals import comment_was_posted
comment_was_posted.connect(comment_handler, sender=Comment)

ModelAdmin thread-safety/caching issues

Ultimately, my goal is to extend Django's ModelAdmin to provide field-level permissions—that is, given properties of the request object and values of the fields of the object being edited, I would like to control whether or not the fields/inlines are visible to the user. I ultimately accomplished this by adding a can_view_field() method to the ModelAdmin and modifying the built-in get_form() and get_fieldset() methods to remove/exclude fields+inlines that the user does not have permissions (as determined by can_view_field()) to see. If you'd like to see the code, I placed it in a pastebin, since it's long and only somewhat relevant.
It works great...almost. I appear to have run into some sort of thread-safety or caching issue, where the state of the ModelAdmin object is being leaked from one request to another in a reproducible manner.
I'll illustrate the problem with a simple example. Suppose that I have a model whose ModelAdmin I have extended with the field-level permissions code. This model has two fields:
- public_field, which can be seen/edited by any staff member
- secret_field, which can only be seen/edited by superusers
In this case, the can_view_field() method would look like this:
def can_view_field(self, request, obj, field_name):
"""
Returns boolean indicating whether the user has necessary permissions to
view the passed field.
"""
if obj is None:
return request.user.has_perm('%s.%s_%s' % (
self.opts.app_label,
action,
obj.__class__.__name__.lower()
))
else:
if field_name == "public_field":
return True
if field_name == "secret_field" and request.is_superuser:
return True
return False
Test case 1: with a fresh server restart, if you first view the changelist form as a superuser, you see the form as should happen, with both public_field and secret_field visible. If you log out and view it as a staff member (but not superuser), you only see public_field.
Test case 2: with a fresh server restart, if you log in as a staff member first, you still only see public_field. However, if you then log out and view as a superuser, you do not see secret_field. This is 100% reproducible.
I've done some basic thread-safety diagnostics:
At the end of get_form(), I've printed out the memory address of the ModelForm object. As it should be, it is unique with each request. Therefore, the ModelForm object is not the problem.
Immediately before the admin registration, I tried printing the memory address of the ModelAdmin object. In test case 1, it is unique with both requests. However with test case 2, it does not print at all on the second request.
At this point, I'm clueless. My next point of research will be the admin registration system (which I admittedly know nothing about). The state resets with a server restart, so it seems that the ModelAdmin must be cached? Or is it a thread-safety issue? If I turn it into a factory and return a deepcopy() of the ModelAdmin, would it serve a fresh ModelAdmin with each request? I'm clueless and would appreciate any thoughts. Thanks!
I'm confused about why you think ModelAdmin should be a new instance on each request. The admin objects are instantiated by the admin.site.register(Model) calls in each admin.py, which in turn is called from admin.autodiscover() in urls.py. In other words, this happens on process startup. Given the dynamic multi-process nature of most web serving environments, you may or may not get a new process with any particular request - certainly you won't get one every single time.
Because of this, it's not wise to store or alter state on a global object like ModelAdmin. I haven't looked through your linked code properly, but there was at least one case where you were altering an attribute on self as a result of a method call. Don't do that - you'll need to find some other way of passing dynamic values between methods.

Django ModelForm, having a foreign key as a hidden field

I'm basically building a very trivial form. Let's stick to the books/publisher examples given in the django tutorials and build upon that.
I have a user login to the web app, at which point the first thing they can do is click on a publisher. This publisher then gets saved for their session. Upon that I take them to a create book form. In there I embed the the publisher's id from the database into a hidden field.
Upon the user submitting an HTTP POST, I do something like:
mybookform = BookForm(request.POST)
if mybookform.is_valid():
abook = mybookform.save(commit=False)
abook.publisher_id = request.POST['publisher_id']
mybookform.save()
Yes there's a few naive things done here, such as blindly grabbing the publisher_id and verifying if it's indeed a real publisher id, amongst other security issues. Let's just not pay attention to that for the moment.
My question is, is there a better way of handling this? Although hypothetically this example doesn't make logistical sense, in my particular app the example actually makes sense. The problem is I get a ValueError exception saying publisher_id needs to be a Publisher instance.
Now I can easily retrieve a publisher instance with Publisher.objects.filter(id=..) and use that instead. The question is, is it really necessary? Can I avoid the additional query to the database and somehow update this form instance in a more 'elegant' fashion?
Also, is it possible to somehow embed the publisher in a hidden field so that I do not need to do mybookform.save(commit=False) and just do mybookform = BookForm(request.POST) followed by mybookform.save() immediately?
Retrieving the instance of the publisher does protect against client-side changes that might reference a completely invalid publisher.
To your second question, yes you can include that field as a hidden field by overriding the field in the ModelForm with the approriate form field setting the widget to HiddenInput.
There is no better way to do this.
I would use the get_object_or_404 function for this.
And yes, you can prevent this to be modified by the user by setting the model field to editable=False,

Model and Validation Confusion - Looking for advice

I'm somewhat new to Python, Django, and I'd like some advice on how to layout the code I'd like to write.
I have the model written that allows a file to be uploaded. In the models save method I'm checking if the file has a specific extension. If it has an XML extension I'm opening the file and grabbing some information from the file to save in the database. I have this model working. I've tested it in the built-in administration. It works.
Currently when there's an error (it's not an XML file; the file can't be opened; a specific attribute doesn't exist) I'm throwing an custom "Exception" error. What I would like to do is some how pass these "Exception" error messages to the view (whether that's a custom view or the built-in administration view) and have an error message displayed like if the forms library was being used. Is that possible?
I'm starting to think I'm going to have to write the validation checks again using the forms library. If that's the case, is it possible to still use the built-in administration template, but extend the form it uses to add these custom validations?
Anything to help my confusion would be appreciated.
UPDATE:
Here's my model so far, for those who are asking, "nzb" is the XML file field.
http://dpaste.com/hold/6101/
The admin interface will use the Form you associate with your model; your own views can also use the form.
This is exactly what I'd like to do. However, I don't know how to associate my forms with my models. When ever I've created forms in the past they've always acted as their own entity. I could never get the administration views to use them while using the ModelForm class. Can you shead any light on this?
I've read over the link you gave me and it seams to be what I've done in the past, with no luck.
Getting attributes from the file, should probably be a method.
Sorry, could you please elaborate on this? A method where?
UPDATE:
It seams I've been compleatly missing this step to link a form to the administration view.
http://docs.djangoproject.com/en/dev/ref/contrib/admin/#adding-custom-validation-to-the-admin
This should now allow me to do the validation in a Form. However, I'm still confused about how to actually handle the validation. S.Lott says it should be a method?
The Form errors are automatically part of the administrative view.
See http://docs.djangoproject.com/en/dev/ref/forms/validation/#ref-forms-validation
You're happiest if you validate in a Form -- that's what Forms are for. The admin interface will use the Form you associate with your model; your own views can also use the form.
Getting attributes from the file, should probably be a separate method of the model class. The separate method of the model class can be used by the save() method of the model class or invoked at other times by view functions.
"I could never get the administration views to use them while using the ModelForm class."
http://docs.djangoproject.com/en/dev/ref/contrib/admin/#form
http://docs.djangoproject.com/en/dev/ref/contrib/admin/#adding-custom-validation-to-the-admin
"I'm still confused about how to actually handle the validation. S.Lott says it should be a method?"
Validation in a form is done with a clean() method or a clean_somefield() method.
The "Adding custom validation to the admin" link (above) shows how to add the clean_name method to the "MyArticleAdminForm" form.
If you're still confused, trying actually typing the code from the Django web page and see what it does.
I guess the best way would be to implement a special field class that extends FileField with custom validation of the uploaded file.
The validation is implemented in the field's clean method. It should check the XML file and raise ValidationErrors if it encounters errors. The admin system should then treat your custom errors like any other field errors.
The ImageField class is a good example of special validation like this — I recommend just reading through the source.
You can provide a form that will be used by the admin site. You can then perform validations in the form code that will be displayed in the admin area.
See the docs on the admin site, and in particular the form attribute of ModelAdmin.
"I'm throwing an custom "Exception" error " - Where exactly are you throwing the exception ? In your model or in your view ?
I am confused with your question, so I am assuming that you should be asking 'Where should I catch input errors if any ? ' to yourself.
The Model and View as I see are like pieces in a small assembly line.
View/ Form validation is the first action which should be performed. If there is any issue with the input data through the forms. It should be prevented at the form level using form.is_valid() etc.
The models functionality should be to provide meta information about the entity itself apart from performing CRUD. Ideally it should not be bothered about the data it is getting for the CRUD operations.

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