Locating Cookiecutter Extensions - python

I'm working on creating my first cookiecutter. By and large, this has gone well, but I now want to add a jinja2 filter of my own.
In line with the comments in this issue, I've created a new Jinja2 extension much like the one here. Full code for this extension is here:
https://github.com/seclinch/sigchiproceedings-cookiecutter/commit/5a314fa7207fa8ab7b4024564cec8bb1e1629cad#diff-f4acf470acf9ef37395ef389c12f8613
However, the following simple example demonstrates the same error:
# -*- coding: utf-8 -*-
from jinja2.ext import Extension
def slug(value):
return value
class PaperTitleExtension(Extension):
def __init__(self, environment):
super(PaperTitleExtension, self).__init__(environment)
environment.filters['slug'] = slug
I've dropped this code into a new jinja2_extensions directory and added a simple __init__.py as follows:
# -*- coding: utf-8 -*-
from paper_title import PaperTitleExtension
__all__ = ['PaperTitleExtension']
Based on this piece of documentation I've also added the following to my `cookiecutter.json' file:
"_extensions": ["jinja2_extensions.PaperTitleExtension"]
However, running this generates the following error:
$ cookiecutter sigchiproceedings-cookiecutter
Unable to load extension: No module named 'jinja2_extensions'
I'm guessing that I'm missing some step here, can anyone help?

Had the same issue, try executing with python3 -m option
My extension in extensions/json_loads.py
import json
from jinja2.ext import Extension
def json_loads(value):
return json.loads(value)
class JsonLoadsExtension(Extension):
def __init__(self, environment):
super(JsonLoadsExtension, self).__init__(environment)
environment.filters['json_loads'] = json_loads
cookiecutter.json
{
"service_name": "test",
"service_slug": "{{ cookiecutter.service_name.replace('-', '_') }}",
...
"_extensions": ["extensions.json_loads.JsonLoadsExtension"]
}
Then I executed with python3 -m cookiecutter . no_input=True timestamp="123" extra_dict="{\"features\": [\"redis\", \"grpc_client\"]}" -f and it works fine.

I ran into a similar error earlier.
Unable to load extension: No module named 'cookiecutter_repo_extensions'
The problem was that in my case there was a dependency to the 'cookiecutter-repo-extension' which I had not installed in my Virtual Environment.

The directory containing your extension needs to be on your PYTHONPATH.
https://github.com/cookiecutter/cookiecutter/issues/1211#issuecomment-522226155
A PR to improve the docs would be appreciated 📖 ✍️ 🙏

Related

create utils.py in AWS lambda

I had a def hello() function in my home/file.py file. I created a home/common/utils.pyfile and moved the function there.
Now, I want to import it in my file file.py.
I imported it like this: from utils import hello and from common.utils import hello and the import in my file doesn't throw an error. However, when I run it on AWS Lambda, I get an error that:
Runtime.ImportModuleError: Unable to import module 'file': No module named 'utils'
How can I fix this? without having to use Ec2 or something...
data "archive_file" "file_zip" {
type = "zip"
source_file = "${path.module}/src/file.py"
output_file_mode = "0666"
output_path = "${path.module}/bin/file.zip"
}
The deployment package that you're uploading only contains your main Python script (file.py). Specifically, it does not include any dependencies such as common/utils.py. That's why the import fails when the code runs in Lambda.
Modify the creation of your deployment package (file.zip) so that it includes all needed dependencies.
For example:
data "archive_file" "file_zip" {
type = "zip"
output_file_mode = "0666"
output_path = "${path.module}/bin/file.zip"
source {
content = file("${path.module}/src/file.py")
filename = "file.py"
}
source {
content = file("${path.module}/src/common/utils.py")
filename = "common/utils.py"
}
}
If all of your files happen to be in a single folder then you can use source_dir instead of indicating the individual files.
Note: I don't use Terraform so the file(...) with embedded interpolation may not be 100% correct, but you get the idea.
First of all, properly follow this standard URL:- https://docs.aws.amazon.com/lambda/latest/dg/python-package.html (refer section with title:- Deployment package with dependencies)
Now, if you notice, in the end of section,
zip -g my-deployment-package.zip lambda_function.py
Follow the same command for your utils file:-
zip -g my-deployment-package.zip common/
zip -g my-deployment-package.zip common/utils.py
Ensure that, in lambda_function, you are using proper import statement like:-
from common.utils import util_function_name
Now, you can upload this zip and test for yourself. It should run.
Hope this helps.

How do I structure a package so that its modules are callable?

I'm very new to Python and am learning how packages and modules work but have run into a snag. Initially I created a very simple package to be deployed as a Lambda function. I have a file in the root directory called lambda.py which contains a handler function, and I put most of my business logic in a separate file. I created a subdirectory - for this example let's say it's called testme - and more specifically put it in __init__.py underneath that subdirectory. Initially this worked great. Inside my lambda.py file I could use this import statement:
from testme import TestThing # TestThing is the name of the class
However, now that the code is growing, I've been splitting things into multiple files. As a result, my code no longer runs; I get the following error:
TypeError: 'module' object is not callable
Here's a simplified version of what my code looks like now, to illustrate the problem. What am I missing? What can I do to make these modules "callable"?
/lambda.py:
#!/usr/bin/env python2
# -*- coding: utf-8 -*-
from testme import TestThing
def handler(event, context):
abc = TestThing(event.get('value'))
abc.show_value()
if __name__ == '__main__':
handler({'value': 5}, None)
/testme/__init__.py:
#!/usr/bin/env python2
# -*- coding: utf-8 -*-
__project__ = "testme"
__version__ = "0.1.0"
__description__ = "Test MCVE"
__url__ = "https://stackoverflow.com"
__author__ = "soapergem"
__all__ = ["TestThing"]
/testme/TestThing.py:
#!/usr/bin/env python2
# -*- coding: utf-8 -*-
class TestThing:
def __init__(self, value):
self.value = value
def show_value(self):
print 'The value is %s' % self.value
Like I said, the reason I'm doing all this is because the real world example has enough code that I want to split it into multiple files inside the subdirectory. And so I left an __init__.py file there to just to serve as an index essentially. But I am very unsure of what the best practices are for package structure, or how to get this working.
You either have to import your class in your __init__ file:
testme/__init__.py:
from .TestThing import TestThing
or import it using the full path:
lambda.py:
from testme.TestThing import TestThing
When you use a __init__.py file, you create a package, and this package (named after the root directory, e.g. testme, may include submodules. Those are accessible via the package.module syntax, but the contents of the submodules are only visible in the root package if you explicitly import them there.

Python Import Linux vs Windows

I am developping a new little project which need to run on Windows and Linux. To explain my problem I will use 3 files.
parser/__init__.py
from .toto import Parser as TotoParser
parser/toto.py
class Variable(object):
def __str__(self):
return "totoVariable"
class Parser(object):
#staticmethod
def parse(data):
return Variable()
main.py
#!/usr/bin/env python3
from parser import TotoParser
def main():
print(TotoParser.parse(""))
if __name__ == '__main__':
main()
In this project. I create several modules(file) into different packages(directory). The thing is I need to change the name of module imported. To do that I use aliasing into __init__ files.
My project run perfectly on Lunix but when I tried it on Windows this problem occurs !
ImportError: cannot import name 'TotoParser'
Sorry for my English, I am learning it...
Please rename init.py to __init__.py, I believe that it is work, case already named as __init__.py ignore this anwser...

How to integrate checking of readme in pytest

I use pytest in my .travis.yml to check my code.
I would like to check the README.rst, too.
I found readme_renderer via this StackO answer
Now I ask myself how to integrate this into my current tests.
The docs of readme_renderer suggest this, but I have not clue how to integrate this into my setup:
python setup.py check -r -s
I think the simplest and most robust option is to write a pytest plugin that replicates what the distutils command you mentioned in you answer does.
That could be as simple as a conftest.py in your test dir. Or if you want a standalone plugin that's distributable for all of us to benefit from there's a nice cookiecutter template.
Ofc there's inherently nothing wrong with calling the check manually in your script section after the call to pytest.
I check it like this now:
# -*- coding: utf-8 -*-
from __future__ import absolute_import, division, unicode_literals, print_function
import os
import subx
import unittest
class Test(unittest.TestCase):
def test_readme_rst_valid(self):
base_dir = os.path.dirname(os.path.dirname(os.path.dirname(__file__)))
subx.call(cmd=['python', os.path.join(base_dir, 'setup.py'), 'check', '--metadata', '--restructuredtext', '--strict'])
Source: https://github.com/guettli/reprec/blob/master/reprec/tests/test_setup.py
So I implemented something but it does require some modifications. You need to modify your setup.py as below
from distutils.core import setup
setup_info = dict(
name='so1',
version='',
packages=[''],
url='',
license='',
author='tarun.lalwani',
author_email='',
description=''
)
if __name__ == "__main__":
setup(**setup_info)
Then you need to create a symlink so we can import this package in the test
ln -s setup.py setup_mypackage.py
And then you can create a test like below
# -*- coding: utf-8 -*-
from __future__ import absolute_import, division, unicode_literals, print_function
import os
import unittest
from distutils.command.check import check
from distutils.dist import Distribution
import setup_mypackage
class Test(unittest.TestCase):
def test_readme_rst_valid(self):
dist = Distribution(setup_mypackage.setup_info)
test = check(dist)
test.ensure_finalized()
test.metadata = True
test.strict = True
test.restructuredtext = True
global issues
issues = []
def my_warn(msg):
global issues
issues += [msg]
test.warn = my_warn
test.check_metadata()
test.check_restructuredtext()
if len(issues) > 0:
assert len(issues) == 0, "\n".join(issues)
Running the test then I get
...
AssertionError: missing required meta-data: version, url
missing meta-data: if 'author' supplied, 'author_email' must be supplied too
Ran 1 test in 0.067s
FAILED (failures=1)
This is one possible workaround that I can think of
Upvoted because checking readme consistence is a nice thing I never integrated in my own projects. Will do from now on!
I think your approach with calling the check command is fine, although it will check more than readme's markup. check will validate the complete metadata of your package, including the readme if you have readme_renderer installed.
If you want to write a unit test that does only markup check and nothing else, I'd go with an explicit call of readme_renderer.rst.render:
import pathlib
from readme_renderer.rst import render
def test_markup_is_generated():
readme = pathlib.Path('README.rst')
assert render(readme.read_text()) is not None
The None check is the most basic test: if render returns None, it means that the readme contains errors preventing it from being translated to HTML. If you want more fine-grained tests, work with the HTML string returned. For example, I expect my readme to contain the word "extensions" to be emphasized:
import pathlib
import bs4
from readme_renderer.rst import render
def test_extensions_is_emphasized():
readme = pathlib.Path('README.rst')
html = render(readme.read_text())
soup = bs4.BeautifulSoup(html)
assert soup.find_all('em', string='extensions')
Edit: If you want to see the printed warnings, use the optional stream argument:
from io import StringIO
def test_markup_is_generated():
warnings = StringIO()
with open('README.rst') as f:
html = render(f.read(), stream=warnings)
warnings.seek(0)
assert html is not None, warnings.read()
Sample output:
tests/test_readme.py::test_markup_is_generated FAILED
================ FAILURES ================
________ test_markup_is_generated ________
def test_markup_is_generated():
warnings = StringIO()
with open('README.rst') as f:
html = render(f.read(), stream=warnings)
warnings.seek(0)
> assert html is not None, warnings.read()
E AssertionError: <string>:54: (WARNING/2) Title overline too short.
E
E ----
E fffffff
E ----
E
E assert None is not None
tests/test_readme.py:10: AssertionError
======== 1 failed in 0.26 seconds ========

How can I get the version defined in setup.py (setuptools) in my package?

How could I get the version defined in setup.py from my package (for --version, or other purposes)?
Interrogate version string of already-installed distribution
To retrieve the version from inside your package at runtime (what your question appears to actually be asking), you can use:
import pkg_resources # part of setuptools
version = pkg_resources.require("MyProject")[0].version
Store version string for use during install
If you want to go the other way 'round (which appears to be what other answer authors here appear to have thought you were asking), put the version string in a separate file and read that file's contents in setup.py.
You could make a version.py in your package with a __version__ line, then read it from setup.py using execfile('mypackage/version.py'), so that it sets __version__ in the setup.py namespace.
Warning about race condition during install
By the way, DO NOT import your package from your setup.py as suggested in another answer here: it will seem to work for you (because you already have your package's dependencies installed), but it will wreak havoc upon new users of your package, as they will not be able to install your package without manually installing the dependencies first.
example study: mymodule
Imagine this configuration:
setup.py
mymodule/
/ __init__.py
/ version.py
/ myclasses.py
Then imagine some usual scenario where you have dependencies and setup.py looks like:
setup(...
install_requires=['dep1','dep2', ...]
...)
And an example __init__.py:
from mymodule.myclasses import *
from mymodule.version import __version__
And for example myclasses.py:
# these are not installed on your system.
# importing mymodule.myclasses would give ImportError
import dep1
import dep2
problem #1: importing mymodule during setup
If your setup.py imports mymodule then during setup you would most likely get an ImportError. This is a very common error when your package has dependencies. If your package does not have other dependencies than the builtins, you may be safe; however this isn't a good practice. The reason for that is that it is not future-proof; say tomorrow your code needs to consume some other dependency.
problem #2: where's my __version__ ?
If you hardcode __version__ in setup.py then it may not match the version that you would ship in your module. To be consistent, you would put it in one place and read it from the same place when you need it. Using import you may get the problem #1.
solution: à la setuptools
You would use a combination of open, exec and provide a dict for exec to add variables:
# setup.py
from setuptools import setup, find_packages
from distutils.util import convert_path
main_ns = {}
ver_path = convert_path('mymodule/version.py')
with open(ver_path) as ver_file:
exec(ver_file.read(), main_ns)
setup(...,
version=main_ns['__version__'],
...)
And in mymodule/version.py expose the version:
__version__ = 'some.semantic.version'
This way, the version is shipped with the module, and you do not have issues during setup trying to import a module that has missing dependencies (yet to be installed).
The best technique is to define __version__ in your product code, then import it into setup.py from there. This gives you a value you can read in your running module, and have only one place to define it.
The values in setup.py are not installed, and setup.py doesn't stick around after installation.
What I did (for example) in coverage.py:
# coverage/__init__.py
__version__ = "3.2"
# setup.py
from coverage import __version__
setup(
name = 'coverage',
version = __version__,
...
)
UPDATE (2017): coverage.py no longer imports itself to get the version. Importing your own code can make it uninstallable, because you product code will try to import dependencies, which aren't installed yet, because setup.py is what installs them.
Your question is a little vague, but I think what you are asking is how to specify it.
You need to define __version__ like so:
__version__ = '1.4.4'
And then you can confirm that setup.py knows about the version you just specified:
% ./setup.py --version
1.4.4
I wasn't happy with these answers... didn't want to require setuptools, nor make a whole separate module for a single variable, so I came up with these.
For when you are sure the main module is in pep8 style and will stay that way:
version = '0.30.unknown'
with file('mypkg/mymod.py') as f:
for line in f:
if line.startswith('__version__'):
_, _, version = line.replace("'", '').split()
break
If you'd like to be extra careful and use a real parser:
import ast
version = '0.30.unknown2'
with file('mypkg/mymod.py') as f:
for line in f:
if line.startswith('__version__'):
version = ast.parse(line).body[0].value.s
break
setup.py is somewhat of a throwaway module so not an issue if it is a bit ugly.
Update: funny enough I've moved away from this in recent years and started using a separate file in the package called meta.py. I put lots of meta data in there that I might want to change frequently. So, not just for one value.
With a structure like this:
setup.py
mymodule/
/ __init__.py
/ version.py
/ myclasses.py
where version.py contains:
__version__ = 'version_string'
You can do this in setup.py:
import sys
sys.path[0:0] = ['mymodule']
from version import __version__
This won't cause any problem with whatever dependencies you have in your mymodule/__init__.py
Create a file in your source tree, e.g. in yourbasedir/yourpackage/_version.py . Let that file contain only a single line of code, like this:
__version__ = "1.1.0-r4704"
Then in your setup.py, open that file and parse out the version number like this:
verstr = "unknown"
try:
verstrline = open('yourpackage/_version.py', "rt").read()
except EnvironmentError:
pass # Okay, there is no version file.
else:
VSRE = r"^__version__ = ['\"]([^'\"]*)['\"]"
mo = re.search(VSRE, verstrline, re.M)
if mo:
verstr = mo.group(1)
else:
raise RuntimeError("unable to find version in yourpackage/_version.py")
Finally, in yourbasedir/yourpackage/__init__.py import _version like this:
__version__ = "unknown"
try:
from _version import __version__
except ImportError:
# We're running in a tree that doesn't have a _version.py, so we don't know what our version is.
pass
An example of code that does this is the "pyutil" package that I maintain. (See PyPI or google search -- stackoverflow is disallowing me from including a hyperlink to it in this answer.)
#pjeby is right that you shouldn't import your package from its own setup.py. That will work when you test it by creating a new Python interpreter and executing setup.py in it first thing: python setup.py, but there are cases when it won't work. That's because import youpackage doesn't mean to read the current working directory for a directory named "yourpackage", it means to look in the current sys.modules for a key "yourpackage" and then to do various things if it isn't there. So it always works when you do python setup.py because you have a fresh, empty sys.modules, but this doesn't work in general.
For example, what if py2exe is executing your setup.py as part of the process of packaging up an application? I've seen a case like this where py2exe would put the wrong version number on a package because the package was getting its version number from import myownthing in its setup.py, but a different version of that package had previously been imported during the py2exe run. Likewise, what if setuptools, easy_install, distribute, or distutils2 is trying to build your package as part of a process of installing a different package that depends on yours? Then whether your package is importable at the time that its setup.py is being evaluated, or whether there is already a version of your package that has been imported during this Python interpreter's life, or whether importing your package requires other packages to be installed first, or has side-effects, can change the results. I've had several struggles with trying to re-use Python packages which caused problems for tools like py2exe and setuptools because their setup.py imports the package itself in order to find its version number.
By the way, this technique plays nicely with tools to automatically create the yourpackage/_version.py file for you, for example by reading your revision control history and writing out a version number based on the most recent tag in revision control history. Here is a tool that does that for darcs: http://tahoe-lafs.org/trac/darcsver/browser/trunk/README.rst and here is a code snippet which does the same thing for git: http://github.com/warner/python-ecdsa/blob/0ed702a9d4057ecf33eea969b8cf280eaccd89a1/setup.py#L34
We wanted to put the meta information about our package pypackagery in __init__.py, but could not since it has third-party dependencies as PJ Eby already pointed out (see his answer and the warning regarding the race condition).
We solved it by creating a separate module pypackagery_meta.py that contains only the meta information:
"""Define meta information about pypackagery package."""
__title__ = 'pypackagery'
__description__ = ('Package a subset of a monorepo and '
'determine the dependent packages.')
__url__ = 'https://github.com/Parquery/pypackagery'
__version__ = '1.0.0'
__author__ = 'Marko Ristin'
__author_email__ = 'marko.ristin#gmail.com'
__license__ = 'MIT'
__copyright__ = 'Copyright 2018 Parquery AG'
then imported the meta information in packagery/__init__.py:
# ...
from pypackagery_meta import __title__, __description__, __url__, \
__version__, __author__, __author_email__, \
__license__, __copyright__
# ...
and finally used it in setup.py:
import pypackagery_meta
setup(
name=pypackagery_meta.__title__,
version=pypackagery_meta.__version__,
description=pypackagery_meta.__description__,
long_description=long_description,
url=pypackagery_meta.__url__,
author=pypackagery_meta.__author__,
author_email=pypackagery_meta.__author_email__,
# ...
py_modules=['packagery', 'pypackagery_meta'],
)
You must include pypackagery_meta into your package with py_modules setup argument. Otherwise, you can not import it upon installation since the packaged distribution would lack it.
This should also work, using regular expressions and depending on the metadata fields to have a format like this:
__fieldname__ = 'value'
Use the following at the beginning of your setup.py:
import re
main_py = open('yourmodule.py').read()
metadata = dict(re.findall("__([a-z]+)__ = '([^']+)'", main_py))
After that, you can use the metadata in your script like this:
print 'Author is:', metadata['author']
print 'Version is:', metadata['version']
Simple and straight, create a file called source/package_name/version.py with the following contents:
#!/usr/bin/env python3
# -*- coding: UTF-8 -*-
__version__ = "2.6.9"
Then, on your file source/package_name/__init__.py, you import the version for other people to use:
#!/usr/bin/env python3
# -*- coding: UTF-8 -*-
from .version import __version__
Now, you can put this on setup.py
#!/usr/bin/env python3
# -*- coding: UTF-8 -*-
import re
import sys
try:
filepath = 'source/package_name/version.py'
version_file = open( filepath )
__version__ ,= re.findall( '__version__ = "(.*)"', version_file.read() )
except Exception as error:
__version__ = "0.0.1"
sys.stderr.write( "Warning: Could not open '%s' due %s\n" % ( filepath, error ) )
finally:
version_file.close()
Tested this with Python 2.7, 3.3, 3.4, 3.5, 3.6 and 3.7 on Linux, Windows and Mac OS. I used on my package which has Integration and Unit Tests for all theses platforms. You can see the results from .travis.yml and appveyor.yml here:
https://travis-ci.org/evandrocoan/debugtools/builds/527110800
https://ci.appveyor.com/project/evandrocoan/pythondebugtools/builds/24245446
An alternate version is using context manager:
#!/usr/bin/env python3
# -*- coding: UTF-8 -*-
import re
import sys
try:
filepath = 'source/package_name/version.py'
with open( filepath ) as file:
__version__ ,= re.findall( '__version__ = "(.*)"', file.read() )
except Exception as error:
__version__ = "0.0.1"
sys.stderr.write( "Warning: Could not open '%s' due %s\n" % ( filepath, error ) )
You can also be using the codecs module to handle unicode errors both on Python 2.7 and 3.6
#!/usr/bin/env python3
# -*- coding: UTF-8 -*-
import re
import sys
import codecs
try:
filepath = 'source/package_name/version.py'
with codecs.open( filepath, 'r', errors='ignore' ) as file:
__version__ ,= re.findall( '__version__ = "(.*)"', file.read() )
except Exception as error:
__version__ = "0.0.1"
sys.stderr.write( "Warning: Could not open '%s' due %s\n" % ( filepath, error ) )
If you are writing a Python module 100% in C/C++ using Python C Extensions, you can do the same thing, but using C/C++ instead of Python.
On this case, create the following setup.py:
#!/usr/bin/env python3
# -*- coding: UTF-8 -*-
import re
import sys
import codecs
from setuptools import setup, Extension
try:
filepath = 'source/version.h'
with codecs.open( filepath, 'r', errors='ignore' ) as file:
__version__ ,= re.findall( '__version__ = "(.*)"', file.read() )
except Exception as error:
__version__ = "0.0.1"
sys.stderr.write( "Warning: Could not open '%s' due %s\n" % ( filepath, error ) )
setup(
name = 'package_name',
version = __version__,
package_data = {
'': [ '**.txt', '**.md', '**.py', '**.h', '**.hpp', '**.c', '**.cpp' ],
},
ext_modules = [
Extension(
name = 'package_name',
sources = [
'source/file.cpp',
],
include_dirs = ['source'],
)
],
)
Which reads the version from the file version.h:
const char* __version__ = "1.0.12";
But, do not forget to create the MANIFEST.in to include the version.h file:
include README.md
include LICENSE.txt
recursive-include source *.h
And it is integrated into the main application with:
#include <Python.h>
#include "version.h"
// create the module
PyMODINIT_FUNC PyInit_package_name(void)
{
PyObject* thismodule;
...
// https://docs.python.org/3/c-api/arg.html#c.Py_BuildValue
PyObject_SetAttrString( thismodule, "__version__", Py_BuildValue( "s", __version__ ) );
...
}
References:
python open file error
Define a global in a Python module from a C API
How to include package data with setuptools/distribute?
https://github.com/lark-parser/lark/blob/master/setup.py#L4
How to use setuptools packages and ext_modules with the same name?
Is it possible to include subdirectories using dist utils (setup.py) as part of package data?
To avoid importing a file (and thus executing its code) one could parse it and recover the version attribute from the syntax tree:
# assuming 'path' holds the path to the file
import ast
with open(path, 'rU') as file:
t = compile(file.read(), path, 'exec', ast.PyCF_ONLY_AST)
for node in (n for n in t.body if isinstance(n, ast.Assign)):
if len(node.targets) == 1:
name = node.targets[0]
if isinstance(name, ast.Name) and \
name.id in ('__version__', '__version_info__', 'VERSION'):
v = node.value
if isinstance(v, ast.Str):
version = v.s
break
if isinstance(v, ast.Tuple):
r = []
for e in v.elts:
if isinstance(e, ast.Str):
r.append(e.s)
elif isinstance(e, ast.Num):
r.append(str(e.n))
version = '.'.join(r)
break
This code tries to find the __version__ or VERSION assignment at the top level of the module return is string value. The right side can be either a string or a tuple.
There's a thousand ways to skin a cat -- here's mine:
# Copied from (and hacked):
# https://github.com/pypa/virtualenv/blob/develop/setup.py#L42
def get_version(filename):
import os
import re
here = os.path.dirname(os.path.abspath(__file__))
f = open(os.path.join(here, filename))
version_file = f.read()
f.close()
version_match = re.search(r"^__version__ = ['\"]([^'\"]*)['\"]",
version_file, re.M)
if version_match:
return version_match.group(1)
raise RuntimeError("Unable to find version string.")
A lot of the other answers are outdated, I believe the standard way to get version information from an installed python 3.10 package is by using importlib.metadata as of PEP-0566
Official docs: https://docs.python.org/3.10/library/importlib.metadata.html
from importlib.metadata import version
VERSION_NUM = version("InstalledPackageName")
This is simple, clean, and no fuss.
This won't work if you are doing something weird in a script that runs during package installation, but if all you are doing is getting the version number for a version check to show the user in through a CLI --help command, about box, or anything else where your package is already installed and just needs the installed version number this seems like the best solution to me.
Cleaning up https://stackoverflow.com/a/12413800 from #gringo-suave:
from itertools import ifilter
from os import path
from ast import parse
with open(path.join('package_name', '__init__.py')) as f:
__version__ = parse(next(ifilter(lambda line: line.startswith('__version__'),
f))).body[0].value.s
Now this is gross and needs some refining (there may even be an uncovered member call in pkg_resources that I missed), but I simply do not see why this doesn't work, nor why no one has suggested it to date (Googling around has not turned this up)...note that this is Python 2.x, and would require requiring pkg_resources (sigh):
import pkg_resources
version_string = None
try:
if pkg_resources.working_set is not None:
disto_obj = pkg_resources.working_set.by_key.get('<my pkg name>', None)
# (I like adding ", None" to gets)
if disto_obj is not None:
version_string = disto_obj.version
except Exception:
# Do something
pass
deploy package to server and file naming convention for indices packages :
example for pip dynamic version conversion:
win:
test_pkg-1.0.0-cp36-cp36m-win_amd64.whl
test_pkg-1.0.0-py3.6-win-amd64.egg
mac:
test_pkg-1.0.0-py3.7-macosx-10.12-x86_64.egg
test_pkg-1.0.0-py3.7-macosx-10.12-x86_64.whl
linux:
test_pkg-1.0.0-cp36-cp36m-linux_x86_64.whl
from setuptools_scm import get_version
def _get_version():
dev_version = str(".".join(map(str, str(get_version()).split("+")[0]\
.split('.')[:-1])))
return dev_version
Find the sample setup.py calls the dynamic pip version matching from git commit
setup(
version=_get_version(),
name=NAME,
description=DESCRIPTION,
long_description=LONG_DESCRIPTION,
classifiers=CLASSIFIERS,
# add few more for wheel wheel package ...conversion
)
For what is worth, I wrote getversion to solve this issue for one of our projects' needs. It relies on a sequence of PEP-compliant strategies to return the version for a module, and adds some strategies for development mode (git scm).
Example:
from getversion import get_module_version
# Get the version of an imported module
from xml import dom
version, details = get_module_version(dom)
print(version)
Yields
3.7.3.final.0
Why was this version found ? You can understand it from the details:
> print(details)
Version '3.7.3.final.0' found for module 'xml.dom' by strategy 'get_builtin_module_version', after the following failed attempts:
- Attempts for module 'xml.dom':
- <get_module_version_attr>: module 'xml.dom' has no attribute '__version__'
- Attempts for module 'xml':
- <get_module_version_attr>: module 'xml' has no attribute '__version__'
- <get_version_using_pkgresources>: Invalid version number: None
- <get_builtin_module_version>: SUCCESS: 3.7.3.final.0
More can be found in the documentation.
I am using an environment variable as below
VERSION=0.0.0 python setup.py sdist bdist_wheel
In setup.py
import os
setup(
version=os.environ['VERSION'],
...
)
For consistency check with packer version, I am using below script.
PKG_VERSION=`python -c "import pkg; print(pkg.__version__)"`
if [ $PKG_VERSION == $VERSION ]; then
python setup.py sdist bdist_wheel
else
echo "Package version differs from set env variable"
fi
I created the regex pattern to find version number from setup.cfg ?:[\s]+|[\s])?[=](?:[\s]+|[\s])?(.*)
import re
with open("setup.cfg", "r") as _file:
data = _file.read()
print(re.findall(r"\nversion(?:[\s]+|[\s])?[=](?:[\s]+|[\s])?(.*)", data))
# -> ['1.1.0']
You can add this code to your __init__.py:
VERSION = (0, 3, 0)
def get_version():
"""Return the VERSION as a string.
For example, if `VERSION == (0, 10, 7)`, return '0.10.7'.
"""
return ".".join(map(str, VERSION))
__version__ = get_version()
And add this to the setup.py:
def get_version(version_tuple):
"""Return the version tuple as a string, e.g. for (0, 10, 7),
return '0.10.7'.
"""
return ".".join(map(str, version_tuple))
init = os.path.join(os.path.dirname(__file__), "your_library", "__init__.py")
version_line = list(filter(lambda line: line.startswith("VERSION"), open(init)))[0]
VERSION = get_version(eval(version_line.split("=")[-1]))
And finally, you can add the version=VERSION, line to the setup:
setup(
name="your_library",
version=VERSION,
)
I've solved this issue in the following way:
Created a version.py inside my module:
setup.py
mymodule/
/ __init__.py
/ version.py
/ myclasses.py
version.py
__version__ = '1.0.0'
setup.py
import sys
sys.path.insert(0, ("./mymodule"))
from version import __version__
I've avoided dependency this way. Of course, I'was inspired by many answers here.
Thank you!

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