DeadLock in Python - python

I'm programing a GUI with tkinter that uses cv2 to extract the video stream from the computer camera. To do that, a Thread reloads the image using a while loop.
I have been using Locks so both Threads (the main one and the auxiliar) end their process as expected. However, i'm not able to do that because of a DeadLock that I can't identify.
The code is the following:
import tkinter as tk
import cv2
import time
import sys
import threading
from PIL import ImageTk, Image
class Application:
gui_root = None
gui_panel = None
frame = None
video_capture = None
stop_event = None
thread = None
thread_lock = None
def __init__(self):
self.gui_root = tk.Tk()
self.gui_root.geometry("640x480")
self.gui_root.resizable(False, False)
self.video_capture = cv2.VideoCapture(0)
self.stop_event = threading.Event()
self.thread_lock = threading.Lock()
self.thread = threading.Thread(target=self.load_frame, args=())
self.thread.start()
self.gui_root.wm_protocol("WM_DELETE_WINDOW", self.on_close)
def start(self):
self.gui_root.mainloop()
def load_frame(self):
print('Starting load_frame')
while self.thread_lock.acquire() and not self.stop_event.is_set():
_, self.frame = self.video_capture.read()
self.frame = cv2.resize(self.frame, (640, 480))
c_image = cv2.cvtColor(self.frame, cv2.COLOR_BGR2RGB)
c_image_tk = ImageTk.PhotoImage(Image.fromarray(c_image))
if self.gui_panel is None:
self.gui_panel = tk.Label(image=c_image_tk)
self.gui_panel.place(width=640, height=480, x=0, y=0)
else:
self.gui_panel.configure(image=c_image_tk)
self.thread_lock.release()
print("End of while")
self.thread_lock.release()
print('End of Process 2')
def on_close(self):
self.stop_event.set()
print("Event set")
with self.thread_lock:
self.video_capture.release()
self.gui_root.destroy()
app = Application()
app.start()

The most likely problem here is that you're attempting to do Tkinter stuff, like creating a new tk.Label, from a background thread, and that's not allowed.
My first guess is that what's happening is that the Tk code on the background thread is just hanging—which isn't really a deadlock, but since you've got a thread hanging forever while holding a lock, nobody else will ever acquire that lock, so it's much the same effect.
The only way to solve this is to have your background thread(s) post messages to a queue requesting GUI stuff to get done for them, and have the main thread poll that queue each time through the event loop (e.g., via an after function).
The old mttkinter project wrapped this up transparently, but unfortunately it was never updated for modern Python. A few years ago, I slapped together a quick port (at https://github.com/abarnert/mttkinter), but I never tested it rigorously, and I don't know if anyone's ever used it for anything serious.
But you could try this at least for a quick test. If it makes no difference, then you've probably ruled out Tk threading issues; if it makes a difference, great (although that difference could be "now it doesn't freeze up, but it crashes 50% of the time—in which case you're not done, and can't trust mttkinter as-is, but at least you know that Tk threading is the thing you have to solve).

Related

tkinter, master window does not loop after I start a thread [duplicate]

My interface is freezing on pressing the button. I am using threading but I am not sure why is still hanging. Any help will be appreciated. Thanks in advance
class magic:
def __init__(self):
self.mainQueue=queue.Queue()
def addItem(self,q):
self.mainQueue.put(q)
def startConverting(self,funcName):
if(funcName=="test"):
while not self.mainQueue.empty():
t = Thread(target = self.threaded_function)
t.start()
t.join()
def threaded_function(self):
time.sleep(5)
print(self.mainQueue.get())
m=magic()
def helloCallBack():
m.addItem("asd")
m.startConverting("test") //this line of code is freezing
B = tkinter.Button(top, text ="Hello", command = helloCallBack)
B.pack()
top.mainloop()
Here's a recipe for doing an asynchronous task with a tkinter-based GUI. I adapted it from a recipe in the cited book. You should be able to modify it to do what you need.
To keep the GUI responsive requires not interfering with its mainloop() by doing something like join()ing a background thread—which makes the GUI "hang" until the thread is finished. This is accomplished by using the universal after() widget method to poll a Queue at regular intervals.
# from "Python Coobook 2nd Edition", section 11.9, page 439.
# Modified to work in Python 2 & 3.
from __future__ import print_function
try:
import Tkinter as tk, time, threading, random, Queue as queue
except ModuleNotFoundError: # Python 3
import tkinter as tk, time, threading, random, queue
class GuiPart(object):
def __init__(self, master, queue, end_command):
self.queue = queue
# Set up the GUI
tk.Button(master, text='Done', command=end_command).pack()
# Add more GUI stuff here depending on your specific needs
def processIncoming(self):
""" Handle all messages currently in the queue, if any. """
while self.queue.qsize():
try:
msg = self.queue.get_nowait()
# Check contents of message and do whatever is needed. As a
# simple example, let's print it (in real life, you would
# suitably update the GUI's display in a richer fashion).
print(msg)
except queue.Empty:
# just on general principles, although we don't expect this
# branch to be taken in this case, ignore this exception!
pass
class ThreadedClient(object):
"""
Launch the main part of the GUI and the worker thread. periodic_call()
and end_application() could reside in the GUI part, but putting them
here means that you have all the thread controls in a single place.
"""
def __init__(self, master):
"""
Start the GUI and the asynchronous threads. We are in the main
(original) thread of the application, which will later be used by
the GUI as well. We spawn a new thread for the worker (I/O).
"""
self.master = master
# Create the queue
self.queue = queue.Queue()
# Set up the GUI part
self.gui = GuiPart(master, self.queue, self.end_application)
# Set up the thread to do asynchronous I/O
# More threads can also be created and used, if necessary
self.running = True
self.thread1 = threading.Thread(target=self.worker_thread1)
self.thread1.start()
# Start the periodic call in the GUI to check the queue
self.periodic_call()
def periodic_call(self):
""" Check every 200 ms if there is something new in the queue. """
self.master.after(200, self.periodic_call)
self.gui.processIncoming()
if not self.running:
# This is the brutal stop of the system. You may want to do
# some cleanup before actually shutting it down.
import sys
sys.exit(1)
def worker_thread1(self):
"""
This is where we handle the asynchronous I/O. For example, it may be
a 'select()'. One important thing to remember is that the thread has
to yield control pretty regularly, be it by select or otherwise.
"""
while self.running:
# To simulate asynchronous I/O, create a random number at random
# intervals. Replace the following two lines with the real thing.
time.sleep(rand.random() * 1.5)
msg = rand.random()
self.queue.put(msg)
def end_application(self):
self.running = False # Stops worker_thread1 (invoked by "Done" button).
rand = random.Random()
root = tk.Tk()
client = ThreadedClient(root)
root.mainloop()
For anyone having a problem with sys.exit(1) in #martineau's code - if you replace sys.exit(1) with self.master.destroy() the program ends gracefully. I lack the reputation to add a comment, hence the seperate answer.

How to check periodically if a thread is finished

I am trying to run a script which runs Asynchronously using threadings. I have run into an issue on how to check periodically if a thread is still alive (under start_thread1). I don't want to use join() as that will freeze the GUI until the threads is finished.
If that is not possible, I am open-minded with any other ways of doing it.
Here is the code I am using - this is a part of part of the code just to outline the "issue" that I have:
from tkinter.constants import LEFT, RIGHT, S
import tkinter.messagebox
from matplotlib import pyplot as plt
import tkinter as tk, time, threading, random, queue
class GuiPart(object):
def __init__(self, master, queue, queue2, client_instance):
self.queue = queue
self.queue2 = queue2
self.x = []
self.y= []
# Set up the GUI
self.Button2 = tk.Button(master, text="Button2", padx=10,
pady=5, fg="white", bg="#263D42", command=client_instance.start_thread1)
self.Button2.pack(side = RIGHT)
def processIncoming(self):
""" Handle all messages currently in the queue, if any. """
while not self.queue.empty():
msg = self.queue.get_nowait()
self.x.append(msg)
print(msg)
while not self.queue2.empty():
msg2 = self.queue2.get_nowait()
self.y.append(msg2)
fig, ax = plt.subplots()
ax.plot(self.x, self.y)
plt.show()
class ThreadedClient(object):
"""
Launch the main part of the GUI and the worker thread. periodic_call()
and end_application() could reside in the GUI part, but putting them
here means that you have all the thread controls in a single place.
"""
def __init__(self, master):
"""
Start the GUI and the asynchronous threads. We are in the main
(original) thread of the application, which will later be used by
the GUI as well. We spawn a new thread for the worker (I/O).
"""
self.master = master
# Create the queue
self.queue = queue.Queue()
self.queue2 = queue.Queue()
self.running=True
# Set up the GUI part
self.gui = GuiPart(master, self.queue, self.queue2, self)
# Set up the thread to do asynchronous I/O
# More threads can also be created and used, if necessary
def start_thread1(self):
thread1=threading.Thread(target=self.worker_thread1)
thread1.start()
# how to check periodically if the thread is finished and when is finished run self.gui.processIncoming()
# if I run it straight away like this the self.gui.processIncoming() will run before the thread will finish and nothing will be plotted
if thread1.is_alive() == False:
self.gui.processIncoming()
def worker_thread1(self):
"""
This is where we handle the asynchronous I/O. For example, it may be
a 'select()'. One important thing to remember is that the thread has
to yield control pretty regularly, be it by select or otherwise.
"""
if self.running:
time.sleep(5) # I am using time.sleep(5) just to simulate a long-running process
for i in range(20):
msg = i
self.queue.put(msg)
for j in range(20):
msg2 = j
self.queue2.put(msg2)
root = tk.Tk()
root.title('Matplotlib threading')
client = ThreadedClient(root)
root.mainloop()
If I understand correctly, you have a tkinter program with a second thread that does some data collection, and you need to get data from that second thread back into the gui. You can't simply wait for the second thread to finish because that would block the tkinter main loop.
One solution is to create a callback function, pass it to the second thread, and call it as the very last step in the second thread. Most tkinter objects aren't threadsafe, so if you're going to update the GUI in the callback function, you have to run the callback in the main thread. To do this, base the callback on tkinter's after_idle function. This causes the callback to occur in tk's event loop, in the main thread, much like a tkinter event handler.
This program does that, and is similar to your program. I changed a few minor things to make my static type checker (pylint) happy. I don't use matplotlib so I took that code out.
The important stuff is in start_thread1. The function f is declared and passed as an argument to the thread. Note that f doesn't call processIncoming, but passes it to after_idle; that instructs the tk main loop to perform the actual call. The function that got passed to worker_thread1 is called as the last step in the thread.
The end result is that processIncoming() is fired into the main thread when the worker thread finishes.
from tkinter.constants import RIGHT
import tkinter as tk
import time
import threading
import queue
class GuiPart:
def __init__(self, master, queue1, queue2, client_instance):
self.queue1 = queue1
self.queue2 = queue2
self.x = []
self.y= []
# Set up the GUI
self.Button2 = tk.Button(master, text="Button2", padx=10,
pady=5, fg="white", bg="#263D42",
command=client_instance.start_thread1)
self.Button2.pack(side = RIGHT)
def processIncoming(self):
""" Handle all messages currently in the queue, if any. """
print(threading.current_thread())
while not self.queue1.empty():
msg = self.queue1.get_nowait()
self.x.append(msg)
print("X", msg)
while not self.queue2.empty():
msg2 = self.queue2.get_nowait()
self.y.append(msg2)
print("Y", msg2)
print("Make a plot now")
class ThreadedClient:
"""
Launch the main part of the GUI and the worker thread. periodic_call()
and end_application() could reside in the GUI part, but putting them
here means that you have all the thread controls in a single place.
"""
def __init__(self, master):
"""
Start the GUI and the asynchronous threads. We are in the main
(original) thread of the application, which will later be used by
the GUI as well. We spawn a new thread for the worker (I/O).
"""
self.master = master
# Create the queue
self.queue1 = queue.Queue()
self.queue2 = queue.Queue()
self.running=True
# Set up the GUI part
self.gui = GuiPart(master, self.queue1, self.queue2, self)
# Set up the thread to do asynchronous I/O
# More threads can also be created and used, if necessary
def start_thread1(self):
def f():
self.master.after_idle(self.gui.processIncoming)
thread1=threading.Thread(target=self.worker_thread1, args=(f, ))
thread1.start()
def worker_thread1(self, callback):
"""
This is where we handle the asynchronous I/O. For example, it may be
a 'select()'. One important thing to remember is that the thread has
to yield control pretty regularly, be it by select or otherwise.
"""
print(threading.current_thread())
if self.running:
time.sleep(1) # simulate a long-running process
for i in range(20):
msg = i
self.queue1.put(msg)
for j in range(20):
msg2 = j
self.queue2.put(msg2)
callback()
root = tk.Tk()
root.title('Matplotlib threading')
client = ThreadedClient(root)
root.mainloop()

Freezing/Hanging tkinter GUI in waiting for the thread to complete

My interface is freezing on pressing the button. I am using threading but I am not sure why is still hanging. Any help will be appreciated. Thanks in advance
class magic:
def __init__(self):
self.mainQueue=queue.Queue()
def addItem(self,q):
self.mainQueue.put(q)
def startConverting(self,funcName):
if(funcName=="test"):
while not self.mainQueue.empty():
t = Thread(target = self.threaded_function)
t.start()
t.join()
def threaded_function(self):
time.sleep(5)
print(self.mainQueue.get())
m=magic()
def helloCallBack():
m.addItem("asd")
m.startConverting("test") //this line of code is freezing
B = tkinter.Button(top, text ="Hello", command = helloCallBack)
B.pack()
top.mainloop()
Here's a recipe for doing an asynchronous task with a tkinter-based GUI. I adapted it from a recipe in the cited book. You should be able to modify it to do what you need.
To keep the GUI responsive requires not interfering with its mainloop() by doing something like join()ing a background thread—which makes the GUI "hang" until the thread is finished. This is accomplished by using the universal after() widget method to poll a Queue at regular intervals.
# from "Python Coobook 2nd Edition", section 11.9, page 439.
# Modified to work in Python 2 & 3.
from __future__ import print_function
try:
import Tkinter as tk, time, threading, random, Queue as queue
except ModuleNotFoundError: # Python 3
import tkinter as tk, time, threading, random, queue
class GuiPart(object):
def __init__(self, master, queue, end_command):
self.queue = queue
# Set up the GUI
tk.Button(master, text='Done', command=end_command).pack()
# Add more GUI stuff here depending on your specific needs
def processIncoming(self):
""" Handle all messages currently in the queue, if any. """
while self.queue.qsize():
try:
msg = self.queue.get_nowait()
# Check contents of message and do whatever is needed. As a
# simple example, let's print it (in real life, you would
# suitably update the GUI's display in a richer fashion).
print(msg)
except queue.Empty:
# just on general principles, although we don't expect this
# branch to be taken in this case, ignore this exception!
pass
class ThreadedClient(object):
"""
Launch the main part of the GUI and the worker thread. periodic_call()
and end_application() could reside in the GUI part, but putting them
here means that you have all the thread controls in a single place.
"""
def __init__(self, master):
"""
Start the GUI and the asynchronous threads. We are in the main
(original) thread of the application, which will later be used by
the GUI as well. We spawn a new thread for the worker (I/O).
"""
self.master = master
# Create the queue
self.queue = queue.Queue()
# Set up the GUI part
self.gui = GuiPart(master, self.queue, self.end_application)
# Set up the thread to do asynchronous I/O
# More threads can also be created and used, if necessary
self.running = True
self.thread1 = threading.Thread(target=self.worker_thread1)
self.thread1.start()
# Start the periodic call in the GUI to check the queue
self.periodic_call()
def periodic_call(self):
""" Check every 200 ms if there is something new in the queue. """
self.master.after(200, self.periodic_call)
self.gui.processIncoming()
if not self.running:
# This is the brutal stop of the system. You may want to do
# some cleanup before actually shutting it down.
import sys
sys.exit(1)
def worker_thread1(self):
"""
This is where we handle the asynchronous I/O. For example, it may be
a 'select()'. One important thing to remember is that the thread has
to yield control pretty regularly, be it by select or otherwise.
"""
while self.running:
# To simulate asynchronous I/O, create a random number at random
# intervals. Replace the following two lines with the real thing.
time.sleep(rand.random() * 1.5)
msg = rand.random()
self.queue.put(msg)
def end_application(self):
self.running = False # Stops worker_thread1 (invoked by "Done" button).
rand = random.Random()
root = tk.Tk()
client = ThreadedClient(root)
root.mainloop()
For anyone having a problem with sys.exit(1) in #martineau's code - if you replace sys.exit(1) with self.master.destroy() the program ends gracefully. I lack the reputation to add a comment, hence the seperate answer.

Python multiprocessing asynchronous callback

I'm writing a program with a GUI using TKinter, in which the user can click a button and a new process is started to perform work using multiprocess.Process. This is necessary so the GUI can still be used while the work is being done, which can take several seconds.
The GUI also has a text box where the status of the program is displayed when things happen. This is often straight forward, with each function calling an add_text() function which just prints text in the text box. However, when add_text() is called in the separate process, the text does not end up in the text box.
I've thought about using a Pipe or Queue, but that would require using some sort of loop to check if anything has been returned from the process and that would also cause the main (GUI) process to be unusable. Is there some way to call a function in one process that will do work in another?
Here's an simple example of what I'm trying to do
import time
import multiprocessing as mp
import tkinter as tk
textbox = tk.Text()
def add_text(text):
# Insert text into textbox
textbox.insert(tk.END, text)
def worker():
x = 0
while x < 10:
add_text('Sleeping for {0} seconds'.format(x)
x += 1
time.sleep(1)
proc = mp.Process(target=worker)
# Usually happens on a button click
proc.start()
# GUI should still be usable here
The asyncronous things actually require loop.
You could attach function to the TkInter's loop by using Tk.after() method.
import Tkinter as tk
class App():
def __init__(self):
self.root = tk.Tk()
self.check_processes()
self.root.mainloop()
def check_processes(self):
if process_finished:
do_something()
else:
do_something_else()
self.after(1000, check_processes)
app=App()
I ended up using a multiprocessing.Pipe by using TKinter's after() method to perform the looping. It loops on an interval and checks the pipe to see if there's any messages from the thread, and if so it inserts them into the text box.
import tkinter
import multiprocessing
def do_something(child_conn):
while True:
child_conn.send('Status text\n')
class Window:
def __init__(self):
self.root = tkinter.Tk()
self.textbox = tkinter.Text()
self.parent_conn, child_conn = multiprocessing.Pipe()
self.process = multiprocessing.Process(target=do_something, args=(child_conn,))
def start(self):
self.get_status_updates()
self.process.start()
self.root.mainloop()
def get_status_updates()
status = self.check_pipe()
if status:
self.textbox.add_text(status)
self.root.after(500, self.get_status_updates) # loop every 500ms
def check_pipe():
if self.parent_conn.poll():
status = self.parent_conn.recv()
return status
return None

PyQT and threads

I am developing an application that uses multiple threads to gather data from a variety of network devices. I'm using PyQT to display the collected data on a GUI. I am using regular python threads (from thread, threading) in my app (instead of QThread). In order to update the GUI on the different threads, I use a lock (thread.allocate_lock()). So, anytime a GUI update will happen, I call with lock, update GUI. Any concerns about this?
I'm pretty sure that updating the GUI from different threads is dangerous in Qt, even if you try to lock things in your own code. For one thing, Qt might be doing its own event processing on the main thread, and it will not acquire your lock to protect objects that it might modify. On this page in the Qt docs, the fact that QWidget is not reentrant or thread-safe is explicitly mentioned.
I recommend that you post the collected data, or a processed version of it, back to the main thread. Use a queued signal/slot connection, or a custom QEvent and QApplication::postEvent to do this. In the previous question that jkerian mentions, it says that you'll have to use QThread instead of python's threads if you want event posting to work correctly.
This is a late reply but I wanted to share what I found. This is code from WickedDevice Blog that I found useful to understand threads and PyQt:
#authors: Dirk Swart, Doudewijn Rempt, Jacob Hallen
import sys, time, threading, random, Queue
from PyQt4 import QtGui, QtCore as qt
import serial
SERIALPORT = 'COM6'
class GuiPart(QtGui.QMainWindow):
def __init__(self, queue, endcommand, *args):
QtGui.QMainWindow.__init__(self, *args)
self.setWindowTitle('Arduino Serial Demo')
self.queue = queue
# We show the result of the thread in the gui, instead of the console
self.editor = QtGui.QTextEdit(self)
self.setCentralWidget(self.editor)
self.endcommand = endcommand
def closeEvent(self, ev):
self.endcommand()
def processIncoming(self):
"""
Handle all the messages currently in the queue (if any).
"""
while self.queue.qsize():
try:
msg = self.queue.get(0)
# Check contents of message and do what it says
# As a test, we simply print it
self.editor.insertPlainText(str(msg))
except Queue.Empty:
pass
class ThreadedClient:
"""
Launch the main part of the GUI and the worker thread. periodicCall and
endApplication could reside in the GUI part, but putting them here
means that you have all the thread controls in a single place.
"""
def __init__(self):
# Create the queue
self.queue = Queue.Queue()
# Set up the GUI part
self.gui=GuiPart(self.queue, self.endApplication)
self.gui.show()
# A timer to periodically call periodicCall :-)
self.timer = qt.QTimer()
qt.QObject.connect(self.timer,
qt.SIGNAL("timeout()"),
self.periodicCall)
# Start the timer -- this replaces the initial call to periodicCall
self.timer.start(100)
# Set up the thread to do asynchronous I/O
# More can be made if necessary
self.running = 1
self.thread1 = threading.Thread(target=self.workerThread1)
self.thread1.start()
def periodicCall(self):
"""
Check every 100 ms if there is something new in the queue.
"""
self.gui.processIncoming()
if not self.running:
root.quit()
def endApplication(self):
self.running = 0
def workerThread1(self):
"""
This is where we handle the asynchronous I/O.
Put your stuff here.
"""
while self.running:
#This is where we poll the Serial port.
#time.sleep(rand.random() * 0.3)
#msg = rand.random()
#self.queue.put(msg)
ser = serial.Serial(SERIALPORT, 115200)
msg = ser.readline();
if (msg):
self.queue.put(msg)
else: pass
ser.close()
if __name__ == "__main__":
#rand = random.Random()
root = QtGui.QApplication(sys.argv)
client = ThreadedClient()
sys.exit(app.exec_())
I use pyqtSignal and Python's threading. You can create threads and when the thread is completed have it send a signal to update your GUI.

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