In HTML
<form method='post'>
{% csrf_token %}
{{form.name}}
{{form.email}}
<textarea name='message'>{{form.message}}</textarea>
<button type='submit'>Send</button>
</form>
How I can get the message data from my textarea in my view? Or the right way is put {{form.as_p}} in form? Please help
Above answer is perfectly alright if you want this on view. Another safe method is request.POST.get('message') it will return None instead of error message, if it's available.
But, you want it on template then you can use
{{ form.data.message }}
request.POST is basically a dictionary returned. It contains csrfmiddlewaretoken and all form data with name specified as key in the request.POST dict.
So, as per your form, you can get the message data from textarea by simply writing
message_data = request.POST['message']
in view.py .
If you want to display form in your style then do it manually. Otherwise, django provides few techniques to render form, and they are as follows:
{{ form.as_table }} will render form as table cells wrapped in <tr> tags,
{{ form.as_p }} will render form wrapped in <p> tags,
{{ form.as_ul }} will render form wrapped in <li> tags.
Now, it depends upon you, how you want your form to look on page.
Related
I'm making an application where I need to render identical forms multiple times on one page (number of forms might be from 1 to 20). In the video below I'm using simple for loop over a range from 0 to 5, just for a test. When I input data into the first form and submit it, all data duplicates to other forms but I need the user to submit data of each form independently from others. In other words, the user can fill in data in some forms (in 1, in 2 or in all forms) and submit those data separately.
Youtube video showing my problem
I have tried to change submit buttons manually with unique ids and names for each form but this didn't help.
I also tried to use Field Enclosures from WTForms but this also didn't help.
Here is my FlaskForm I haven't included all fields to save space
class EnvelopeForm(FlaskForm):
vme_name = StringField('VME')
outside_diameter = DecimalField('OD', validators=[DataRequired()])
submit = SubmitField('build envelope')
Here is my view handler
#app.route('/bokeh', methods=['GET', 'POST'])
def nonuniform_ellipse():
form = EnvelopeForm()
if form.validate_on_submit():
envelope = Envelopes(vme_name=form.vme_name.data,
outside_diameter=form.outside_diameter.data)
db.session.add(envelope)
db.session.commit()
return render_template('vme.html', form=form)
Here is HTML I haven't included all fields to save space.
{% for i in range(0, 5) %}
<form method="POST" action="" name="{{ i }}">
{{ form.hidden_tag() }}
<div>
{{ form.vne_name.label }}
{{ form.vme_name }}
</div>
<div>
{{ form.outside_diameter.label }}
{{ form.outside_diameter }}
</div>
<div>
{{ form.submit) }}
</div>
</form>
{% endfor %}
Here is a solution as per #ser-zhm comment. Now I can render whatever forms I have in DB separately on each other as it is shown on this image.
But when I submit data from one of the forms it is always updates the last record in DB and not the particular row. Lets say I have three empty forms rendered on the page and three records (rows) in my DB with NULL data in each column name referring to each form fields like it is shown here. When I fill in form #2, all the data is saved in row #3 instead of the row #2. So whatever form I fill in it is always the last record is updated.
How can I updated the particular row which is referring to the form ID?
View handler
#app.route('/envelope_forms_test', methods=['GET', 'POST'])
def nonuniform_ellipse():
form_ids = list(map(str, [id[0] for id in
Envelopes.query.with_entities(Envelopes.id).all()]))
forms = []
for form_id in form_ids:
form = EnvelopeForm(prefix=form_id)
forms.append(form)
for form in forms:
if form.submit.data and form.validate_on_submit():
Envelopes.query.filter_by(id=form_id).\
update({'vme_name': form.vme_name.data,
'outside_diameter': form.outside_diameter.data})
db.session.commit()
Here is HTML
{% for form in forms %}
<form method="POST" action="">
{{ form.csrf_token() }}
<div>
{{ form.vne_name.label }}
{{ form.vme_name }}
</div>
<div>
{{ form.outside_diameter.label }}
{{ form.outside_diameter }}
</div>
<div>
{{ form.submit) }}
</div>
</form>
{% endfor %}
How do i do specify the many database field when in a wtf form, so i can insert a row in the database correctly. I need something like this in my template
{{ wtf.form_field(gform.GHF(value="{{ project.name }}")) }}
because I'm iterating over one (Projects) to many (Goals)
Project-(has many goals)
-goal-
and my goal form shows up multiple times.
{% for project in P %}
{% for pgoal in project.goals.all() %}
<li>
Goal: {{ pgoal.goal }}<br>
{% if loop.last %}
<form class="form form-horizontal" method="post" role="gform">
{{ gform.hidden_tag() }}
{{ wtf.form_errors(gform) }}
{{ wtf.form_field(gform.goal) }}
Help here? do i need a hiddenfield to know which project?
{{ wtf.form_field(gform.submit) }}<br>
and so on...
Once I have the correct project, I will use it in my view here
u=models.Projects.query.get(correct project?)
p=models.Goals(goal=gform.goal.data,proj=u)
I wouldn't do it with a hidden field. I'd make each form submit a little differently.
You should have something like
<form class="form form-horizontal" method="post" role="gform"
action="{{ url_for('add_goal_to_project', project_id=project.id) }}">
And the route would be
#app.route('.../<int:project_id>', methods=['POST'])
def add_goal_to_project(project_id):
gform = GForm(....)
if gform.validate_on_submit():
project = models.Projects.query.get(project_id)
goal = models.Goals(gform.goal.data, proj=project)
# Do anything else you need to do, such as adding and committing
# the new object
return redirect(...)
return render_template(...)
I'm skipping the details in the form creation, redirect and render_template calls, but this should get the idea across. Each goal form's action points to a route built from the project id.
You could extend this to allow for the editing of goals, and you'd be able to make it a lot better with some nice ajax posts as well.
I have managed to create the forms I need using modelformset_factory.
avaluos = Avaluo.objects.filter(Estatus__contains='CONCLUIDO',Factura__isnull=True)
FacturaFormset = modelformset_factory(Avaluo,form=FacturaForm,extra=0)
Currently this is generating the following HTML for each of the rows found:
<form id="id-FacturaForm" class="blueForms" method="post">[..]</form>
<form id="id-FacturaForm" class="blueForms" method="post">[..]</form>
<form id="id-FacturaForm" class="blueForms" method="post">[..]</form>
I want to submit all the forms using a single submit button.
Any ideas?
UPDATE
I ended up using django-crispy-forms which allowed me to gerate inputs for each row, and then I just manually added the form and submit.
self.helper.form_tag = False
{{example_formset.management_form }}
{% for a,b in olist %}
{{ b.id }}
<tr>
<td style="width:10px;"> {% crispy b %} </td>
<td> {{a.id}} </td>
</tr>
{% endfor %}
Read more into model formsets. You don't need to have separate form tags, it's the whole point of using a formset.
<form method="post" action="">
{{ factura_formset.management_form }}
<table>
{% for form in factura_formset %}
{{ form }}
{% endfor %}
</table>
</form>
Also, every time you use the id attribute more than once on a page… a developer cries themselves to sleep somewhere in the world.
I suspect you will need to do it using Ajax - otherwise as soon as one form is submitted you will not be able to go the other way.
There are a few jQuery form libraries that should make it relatively straightforward. For example, http://malsup.com/jquery/form/.
It would look something like:
$('#button-id').click(function() {
$('.blueForms').ajaxSubmit();
});
Of course, you'll then need to deal with error handling and waiting for all the forms to have submitted.
If you're trying to create many instances of the "same" form (this is, they all look equal), as if it were one of many childs belonging to a single, master element, you don't actually need to create a form tag for each of the formsets.
If I'm not mistaken, you're trying to edit many facturas for a single avaluo object. Am I right? The representation would be a single "avaluo" form with many inline formsets, one for each "factura".
Check out the inline formsets factory instead of the modelformset factory.
I wish to edit ini files over web server, decided to use django, been using it for few days now. I can't figure out how to accomplish this. I have ini file structure looking like this:
{'GROUP', {PROPERTY : VALUE}}
Example when I read this kind of ini file:
[LOG]
FilePath = C:/Log
[CMD]
Level = 5
I will get my data structure filled like this:
{'LOG', {'FilePath' : 'C:/Log',},
{'CMD', {'Level', '5'}}}
Loop looks like this:
for group in settingsDict:
print group # group
for property in settingsDict[group]:
print property , # property
print settingsDict[group][property] # value
I am using ini file parser.
I am having trouble understanding how to correctly develop in django: views.py is some kind of controller for django and templates are views and model would be my ini file (probably linked with db using django model), or am I getting something wrong?
I have no problem passing this dictionary to template, making a for loop in it and creating html tags like: <input type="text" name={{ property }} value={{ value }} maxlength="100" />. But how do I then post all the edited values back to control to save them in file (or db)? I Would need all 3 values, that is GROUP, PROPERTY and VALUE.
Then I discovered django also has html widgets, which you create in views.py and then pass it to template. But this is where I stop understanding things, since I am creating widget in my controller class, but even if I am.
Shall I create a list of all django widgets and pass it to template? Same question occurs, how do I get all the widget values back to controller (views.py)?
Update (11.6.2012):
My code looks like this:
views.py
class DynForm(forms.Form):
def setFields(self, kwds):
keys = kwds.keys()
keys.sort()
for k in keys:
self.fields[k] = kwds[k]
def settings(request):
global Settings #my ini dict
kwargs = {}
for group in Settings:
for property in Settings[group]:
kwargs[property] = forms.CharField(label = property, initial = Settings[group][property])
f = DynForm()
f.setFields(kwargs)
return render_to_response('/settings.html',
{
'textWidget' : f,
})
#csrf_exempt
def save(request):
if request.method == 'POST': # If the form has been submitted...
form = DynForm(request.POST) # A form bound to the POST data
if form.is_valid(): # All validation rules pass
# process form data
# and return response
settings.html
<form action="/save/" method="post">
{% csrf_token %}
{% for field in textWidget %}
<div class="fieldWrapper">
{{ field.errors }}
{{ field.label }}: {{ field }}
</div>
{% endfor %}
<p><input type="submit" value="Save" /></p>
</form>
The problem is, DynForm(request.POST) returns null so I can't get field values. My request.POST is correct, containing all fields and values. As much as I know, I am not suppose to parse request.POST data "by hands"?
OK, finally figured it out, taking me a lot of time (I am lacking a lot of python and django knowledge). I can't paste final solution because of copy right permissions, here is the concept:
Form
class DynamicForm(forms.Form):
def __init__(self,*k,**kw):
forms.Form.__init__(self,*k,**kw)
# loop over data from **kw
# create field
# set field default value
Notes about this code:
If form doesn't use super(SuperForm, self).__init__(*args, **kwargs), you must use forms.Form.__init__(self,*k,**kw) so you can append fields to form using self.fields attribute.
If you need to use default field value, use self.data[field] = defVal not initial = defVal. Form becomes unbound and you won't be able to parse data in your request.POST method. Unbound form (and with errors) will always return is_valid() False.
With this class, you have no problems parsing request.POST data. Looping over dynamic form fields looks like this:
View
for name,field in form.fields.items():
# name - field name
# form.data[name] - field value
Notes:
For the sake of simplisity use #csrf_exempt tag before POST method. See http://jordanmessina.com/2010/05/24/django-1-2-csrf-verification-failed/
Template code loops over fields in form displaying field label and value separated with :
Template
<form action="/Tris/save/" method="post">
{% csrf_token %}
{% for field in textWidget %}
<div class="fieldWrapper">
{{ field.errors }}
{{ field.non_field_errors }}
{{ field.label }}: {{ field }}
</div>
{% endfor %}
<p><input type="submit" value="Save" /></p>
</form>
Most of the solution is from here: http://jacobian.org/writing/dynamic-form-generation/ and django documentation.
I plan on creating a sidebar with changing elements (depending on the current url and authentication-status).
For example: The default sidebar shows a login and a tag cloud.
If a user is already logged in, I want to display a user menu.
If the current url is /tagcloud, I want to hide it from the sidebar.
Actually, I need a way which enables me to do something like this in a view:
def some_view(request):
if request.user.is_authenticated():
sidebar.remove('login')
sidebar.add('user_menu')
def tag_cloud(request):
sidebar.remove('tag_cloud')
Afterwards, I want to pass the sidebar (implicitly, without passing it to render_to_response) to the template where I have in mind to do something like this:
<div id="sidebar">
{{ sidebar }}
</div>
Is this possible?
You'd better do this in a context_processors.py file
That also mean you have to use a RequestContext when returning your views
def include_tagcloud(request):
if request.path == '/tagcould/':
tagcloud = Tags.objects.filter(active=True) #whatever
return {'tagcloud': tagcloud}
def include_login(request):
if request.user.is_authenticated():
loginform = MyLoginForm(request.POST)
#passing a Django form + POST data in the case of re-submit
return {'loginform' : loginform}
And then in your template :
{% if loginform %}
<form action="accounts/login/">
{{form.as_p}}
<input type="submit" name="Login">
</form>
{% endif %}
{% if tagcloud %}
{%for tag in tagcloud %}.....{%for}
{% endif %}
In this example the login form points to a fixed view,
if you want to catch the login form post on everyview, I don't know how to do
EDIT : if you don't use the CSRF features of Django, you could simply insert the login form in the base template without using any django form and pointing to a login view :
{% if user.is_authenticated %}
<form action="accounts/login/">
<input type="text" name="username"><input type="password" name="password">
<input type="submit" name="Login">
</form>
{% endif %}
Yeah, but you can use inheritance of templates as well as composition. Then include your sidebar in a parent template that is used/inherited from in all of your templates. Then it is easy to find the template for the sidebar: it's in a separate file.
Answer of #Dominique is correct but When you write something in context_processors that's load at any page of the website. That maybe makes a performance issue.
I think the right way to handle dynamic sidebar is simpletag and use where you need.
def get_sidebar():
tags = Tags.objects.filter(active=True)
latest_posts = Post.objects.all().order_by('-create_at')[:10]
html = render_to_string("sidebar.html", {
"tags": tags,
"latest_posts": latest_posts
})
return html
And now just use in template files:
<div class="col-md-4 sidebar">
{% get_sidebar %}
</div>
Also, you can pass request to simpletag to use user.is_authenticated for authenticated user access.