This is my code so far:
import os
import openpyxl
os.chdir('C:\\Python34\\MyPy')
wb=openpyxl.load_workbook('example.xlsx')
wb.get_sheet_names()
But I get these errors:
Warning (from warnings module):
/File "main", line 1
DeprecationWarning: Call to deprecated function get_sheet_names (Use wb.sheetnames).
['Sheet1', 'Sheet2', 'Sheet3']
Warnings aren't errors - they won't hinder your program from running. In case of deprecated warnings: you use a feature that will be removed in future versions so the devs lable it deprecated.
It may work now, but next version it may no longer as this feature was removed - then you will get an error.
You can fix it like this:
wb.sheetnames # all names
sheet = wb["UseThisSheet"] # select a certain sheet by name
for sheet2 in wb: # or go over all sheets
print(sheet2.title)
sh = wb.active # normally sheet at index 0 if you create an empy one
Source: https://openpyxl.readthedocs.io/en/stable/tutorial.html
Here is a short example on how to create a workbook (my answer to some other xlsx question): https://stackoverflow.com/a/48782382/7505395
Since I bounce around in a few different worksheets in my python, I needed the whole list to work from. I added the following
wbInputFile = load_workbook(inFile)
sheetList = wbInputFile.sheetnames
worksheet = wbInputFile[ sheetList[0] ]
# now I am able to run through the rows and get the info
for row in range(2,worksheet.max_row ):
# get the values for each cell needed
It gives a warning , but the below code works fine (using Python3 ).I tried with wb.sheetnames instead of wb.get_sheet_names()
import openpyxl
path="C:\\Users\user1\PycharmProjects\Projectstatus\My Python.xlsx"
wb=openpyxl.load_workbook(path)
print(wb.sheetnames)
from openpyxl import load_workbook
#Load in the workbook
wb = load_workbook('YourFileName.xlsx')
wb.sheetnames # all names
Related
I get a huge Excel-Sheet (normal table with header and data) on a regular basis and I need to filter and delete some data and split the table up into seperate sheets based on some rules. I think I can save me some time if I use Python for that tedious task because the filtering, deleting and splitting up into several sheets is based on always the same rules that can logically be defined.
Unfortunately the sheet and the data is partially color-coded (cells and font) and I need to maintain this formating for the resulting sheets. Is there a way of doing that with python? I think I need a pointer in the right direction. I only found workarounds with pandas but that does not allow me to keep the formatting.
You can take a look at an excellent Python library for Excel called openpyxl.
Here's how you can use it.
First, install it through your command prompt using:
pip install openpyxl
Open an existing file:
import openpyxl
wb_obj = openpyxl.load_workbook(path) # Open notebook
Deleting rows:
import openpyxl
from openpyxl import load_workbook
wb = load_wordbook(path)
ws = wb.active
ws.delete_rows(7)
Inserting rows:
import openpyxl
from openpyxl import load_workbook
wb = load_wordbook(path)
ws = wb.active
ws.insert_rows(7)
Here are some tutorials that you can take a look at:
Tutorial 1
Youtube Video
Hello Guys, I have Excel and the excel has two sheets , sheet1 and sheet2.
I use sheet1 in my script, and sheet1 create drop list excel get value from sheet2.
import openpyxl
path = r"C:\Users\John\Desktop\test.xlsx"
wb = openpyxl.load_workbook(path)
sheet = wb['sheet1']
language = sheet["A2"].value
Sheet1 :
Sheet2 :
Everything work fine but I see this Error in Result :
C:\Python\lib\site-packages\openpyxl\worksheet\_reader.py:300: UserWarning: Data Validation extension is not supported and will be removed
warn(msg)
How can I fix it without remove the get value from sheet2.
though your code works fine for me , an the message you have mentioned i the warning message, may come by few reasons, 1 - you have manually deleted the data then use clear all function to clear cells 2 - if you have change the file extension manually , check if below lines can resolve your issue, also check if sheet1 is Sheet1 ..
import openpyxl
path ='test.xlsx'
wb = openpyxl.load_workbook(path, read_only=True, data_only=True)
sheet = wb['Sheet1']
language = sheet['A2'].value
print(language)
I'm using Python and openpyxl library, but, I'm not able to use the insert_cols() function in openpyxl when my spreadsheet is in write_only=True mode. So, basically, I just want to add a new column to my spreadsheet when it's in write_only=True mode.
I'm able to use insert_cols() when loading the workbook by load_workbook(), but, not when I'm using the write_only mode. I have to use the write_only mode because my spreadsheets are quite large.
Any ideas on how to add a new column are appreciated.
Thank you.
This is my code:
import openpyxl
from openpyxl import Workbook
from openpyxl import load_workbook
wb = load_workbook(filename=r'path\myExcel.xlsx', read_only=True)
ws = wb['PC Details']
wb_output = Workbook(write_only=True)
ws_output = wb_output.create_sheet(title='PC Details')
for row in ws.rows:
rowInCorrectFormat = [cell.value for cell in row]
ws_output.append(rowInCorrectFormat)
for cell in row:
print(cell.value)
### THIS IS THE PART OF THE CODE WHICH DOES NOT WORK
ws_output.insert_cols(12)
ws_output['L5'] = 'OK or NOT GOOD?'
###
wb_output.save(r'path\test_Output_optimized.xlsx')
This is the exact error that I'm getting:
ws_output.insert_cols(12)
AttributeError: 'WriteOnlyWorksheet' object has no attribute 'insert_cols'
The problem here lies in the flag write_only = True. Workbooks created by this flag set to true are different from regular Workbooks as you can look below.
Functions like insert_cols & insert_rows also do not work for such workbooks.
Possible solutions might be to not use this flag or use the ways suggested in the official documentation for adding data to the sheet.
For working with workbooks you might also find this article interesting. https://medium.com/aubergine-solutions/working-with-excel-sheets-in-python-using-openpyxl-4f9fd32de87f
You can read more in the official documentation. https://openpyxl.readthedocs.io/en/stable/optimized.html
I am starting on a code that loads and edits excel (the version I am using is office 2017) sheet using openpyxl. Right now I am still trying to wrap my head around how this module works, here's the code
import openpyxl
from openpyxl import load_workbook
from openpyxl import workbook
from openpyxl.compat import range
from openpyxl.utils import get_column_letter
import os
os.chdir("D:\Scripts\Python\Testing Scripts\My Excel Folder")
wb = load_workbook("MyExcel.xlsx")
names = wb.sheetnames()
print(names)
print(type(wb))
and the error I receive is,
TypeError: 'list' object is not callable
For the string of code
names = wb.sheetnames()
wb.get_sheet_names() returns the list of all the sheets in that excel workbook.
print (wb.get_sheet_names())
for the latest openpyxl to avoid warning:
print (wb.sheetnames)
if you want to access a particular sheet
ws = wb.get_sheet_by_name(name = 'Sheet 1')
Use: wb.sheetnames
Example -
names = wb.sheetnames
print(names)
Do not use: get_sheet_names()
If you will use this, you will get this Warning.
DeprecationWarning: Call to deprecated function get_sheet_names (Use wb.sheetnames).
I've import a xlsx sheet into Python 3.6 by using import openpyxl and now am trying to access the Cell Object by doing the following (see below), but I immediately get an error message which I don't know what it means?:
Warning (from warnings module):
File "__main__", line 1
DeprecationWarning: Call to deprecated function get_sheet_by_name (Use wb[sheetname]).
Here is my code:
import openpyxl
wb = openpyxl.load_workbook('c:\\users\\user1\\AppData\\Local\\Programs\\Python\\Python36-32\\example.xlsx')
sheet = wb.get_sheet_by_name('Sheet1')
Rather than what you're doing, it's telling you to use a different format
wb['Sheet1']
If you plan on using your script in the future, when that library is upgraded, it may break because you're using deprecated functions
the right code :
import openpyxl
wb = openpyxl.load_workbook('c:\users\user1\AppData\Local\Programs\Python\Python36-32\example.xlsx')
sheet = wb['Sheet1']
If you don't anticipate to know beforehand what the sheetname is, then your code should be:
sheet = wb[wb.sheetnames[0]]
...which will automatically choose the left most sheet in the workbook
Furthermore, it is important to note that wb[0] produces a string object...
>>> wb.sheetnames[0]
'Sheet1'
and wb[wb.sheetnames[0]] produces a 'openpyxl.worksheet.worksheet.Worksheet' object...
>>> wb[wb.sheetnames[0]]
<Worksheet "Sheet1">
>>> type(wb[wb.sheetnames[0]])
<class 'openpyxl.worksheet.worksheet.Worksheet'>
This is important on how you plan to work with this object (e.g. iterating over your worksheet).
Please try below code, hope it will help:
import openpyxl
wb = openpyxl.load_workbook('c:\\users\\user1\\AppData\\Local\\Programs\\Python\\Python36-32\\example.xlsx')
sheet = wb['Sheet1']