I cannot create the .click() action on the button - python

I cannot create the .click()-action on the button.
HTML:
<button class="btn__type btn__type_close">Закрыть</button>
I try to make an element clickable for execute_script:
driver.execute_script("return document.getElementsByClassName('.btn__type_close')").click()
My code using Selenium:
driver.find_element_by_css_selector('button.btn__type_close').click()
None of the methods is working.
Question: How will it be correct?

Did you try clicking using XPath?
WebElement btnClose=driver.findElement(By.xpath("//button[#class='btn__type btn__type_close']"));
if(btnClose.isEnabled()){
btnClose.click();
}

Related

Can't Click Radio Button in Selenium Using Python

Here is the HTML Code:
<div class="ui-helper-hidden-accessible">
<input type="radio" name="group2" value="yes">
</div>
Full script
Here are the code which i've tried to click the radio button:
driver.find_element(By.CSS_SELECTOR, 'input[name= "group2"][value="yes"]').click()
AND
rdbutton = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, 'input[name= "group2"][value="yes"]'))).click()
AND
rdbutton = driver.find_elements(By.XPATH, "//input[#name='group2']")
for rdbuttons in rdbutton:
if rdbuttons.is_selected():
pass
else:
rdbuttons.click()
It seems that you are using wrong locator. From the HTML you have given i think you are trying to click on radio button that have label Ya if this is the case then try with below xpath:
"//label[contains(text(),'Ya')]"
OR
"//*[normalize-space()='Ya']"
If this does not solve your problem, so please explain and add HTML of proper element either by screenshot or in textual format

Selenium click on button

On web-page there is button, which describe by code below:
<button onclick="getListRating(1); return false;" class="button is-gray pagination__more">Open</button>
Need to click by use selenium lib - first i tried to find as "css_celector" but it didn't work:
allm=driver.find_element(By.CSS_SELECTOR, 'button is-gray pagination__more') # Find button
allm.click() # Click!
What find class i need to use to click this button?
I'd find the button by the onclick attr. Here is a solution with xpath.
button = driver.find_element_by_xpath('//button[#onclick="getListRating(1); return false;"]')
button.click()

Element not being clicked even though it is found using Selenium

I'm trying to click on an element (radio button) using Selenium (in Python), I can't disclose the URL because it's a private corporate intranet, but will share the relevants part of code.
So basically this element is within an iframe, thus, I've used the following code to get the element:
# Select the item on main DOM that will udpate the iframe contents
wait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//*[#id='sm20']"))).click()
# Don't sleep, but only WedDriverWait...
wait(driver, 20).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH,"//iframe[#name='ifrInterior']")))
# Select the element inside the iframe and click
wait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#name='gestionesPropias_Equipo']"))).click()
The HTML code for the element is this:
<span class="W1">
<input type="radio" name="gestionesPropias_Equipo" value="1" onclick="javascript:indicadorPropiasEquipo(); ocultarPaginacion('1'); limpiarDatosCapaResultado();">
</span>
I'm interested in clicking this because when we click on it a drop-down is enabled:
If clicked then the dropdown is enabled:
The intersting HTML code for this is
<span id="filtroAsignado" class="W30">
<select name="nuumaAsignado" class="W84">
<option value="">[Todo mi equipo]</option></select>
</span>
Debugging a bit Selenium I can see that the elemtn is found:
And this is actually the base64 image of the element, which is the expected radio button
So I'm wondering why the element actually does not get clicked??
UPDATE: Based on request from #DebanjanB, I'm adding the HTML code from the iframe, which is enclosed inside a div in the main page:
<div id="contenido">
<iframe frameborder="0" id="ifrInterior" name="ifrInterior" src="Seguimiento.do?metodo=inicio" scrolling="auto" frameborder="0"></iframe>
</div>
Actually if I look for the word "iframe", there's only one...
Now checking the iframe source itself, has several iframes hidden but the element I need to interact with is in the iframe mentioned above, the only thing that I forgot to mention is that it's inside a form, but I guess that's not relevant? You can see the whole structure in the following image:
Great question. If you know that selenium found the element, you can use Javascript to click the element directly.
The syntax is:
driver.execute_script("arguments[0].click();", element)
You can also do this, which works the same way:
automate.execute_script("arguments[0].click();", wait.until(EC.element_to_be_clickable((By.XPATH, 'Your xpath here'))))
Essentially you are having Selenium run a javascript click on the element you have found which bypasses Selenium. Let me know if this helps!
I don't see any such issue with your code block either. Perhaps you can try out either of the following options:
Using ActionChains:
ActionChains(driver).move_to_element(WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#name='gestionesPropias_Equipo' and #type='radio']")))).click().perform()
Using executeScript() method:
driver.execute_script("arguments[0].click();", WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#name='gestionesPropias_Equipo' and #type='radio']"))))

Click a button using Selenium and Python

I have the following code:
<a class="sectionname" href="#" onclick="expandAll();return false;">Expand all</a>
When I click on expand all, the whole page loads. How can I do it using WebDriver for Python?
As per the HTML you can use the find_element_by_link_text and invoke click() method as follows :
driver.find_element_by_link_text("Expand all").click()
You can get more granualar with find_element_by_xpath as follows :
driver.find_element_by_xpath("//a[#class='sectionname' and contains(.,'Expand all')]").click()
Update
As you still don't see the expansion you can try the Javascript way as follows :
myElement = driver.find_element_by_xpath("//a[#class='sectionname' and contains(.,'Expand all')]")
driver.execute_script("arguments[0].click();", myElement)

Python+Selenium, can't click the 'button' wrapped by span

I am new to selenium here. I am trying to use selenium to click a 'more' button to expand the review section everytime after refreshing the page.
The website is TripAdvisor. The logic of more button is, as long as you click on the first more button, it will automatically expand all the review sections for you. In other words, you just need to click on the first 'more' button.
All buttons have a similar class name. An example is like taLnk.hvrIE6.tr415411081.moreLink.ulBlueLinks. Only the numbers part changes everytime.
The full element look like this:
<span class="taLnk hvrIE6 tr413756996 moreLink ulBlueLinks" onclick=" var options = {
flow: 'CORE_COMBINED',
pid: 39415,
onSuccess: function() { ta.util.cookie.setPIDCookie(2247); ta.call('ta.servlet.Reviews.expandReviews', {type: 'dummy'}, ta.id('review_413756996'), 'review_413756996', '1', 2247);; window.location.hash = 'review_413756996'; }
};
ta.call('ta.registration.RegOverlay.show', {type: 'dummy'}, ta.id('review_413756996'), options);
return false;
">
More </span>
I have tried several ways to get the button click. But since it is an onclick event wrapped by span, I can't successfully get it clicked.
My last version looks like this:
driver = webdriver.Firefox()
driver.get(newurl)
page_source = driver.page_source
soup = BeautifulSoup(page_source)
moreID = soup.find("span", class_=re.compile(r'.*\bmoreLink\b.*'))['class']
moreID = '.'.join(moreID[0:(len(moreID)+1)])
moreButton = 'span.' + moreID
button = driver.find_element_by_css_selector(moreButton)
button.click()
time.sleep(10)
However, I keep getting the error message like this:
WebDriverException: Message: Element is not clickable at point (318.5,
7.100006103515625). Other element would receive the click....
Can you advise me on how to fix the problem? Any help will be appreciated!
WebDriverException: Message: Element is not clickable at point (318.5, 7.100006103515625). Other element would receive the click....
This error to be occur when element is not in the view port and selenium couldn't click due to some other overlay element on it. In this case you should try one of these following solution :-
You can try using ActionChains to reach that element before click as below :-
from selenium.webdriver.common.action_chains import ActionChains
button = driver.find_element_by_css_selector(moreButton)
ActionChains(button).move_to_element(element).click().perform()
You can try using execute_script() to reach that element before click as :-
driver.execute_script("arguments[0].scrollIntoView(true)", button)
button.click()
You can try using JavaScript::click() with execute_script() but this JavaScript::click() defeats the purpose of the test. First because it doesn't generate all the events like a real click (focus, blur, mousedown, mouseup...) and second because it doesn't guarantee that a real user can interact with the element. But to get rid from this issues you can consider it as an alternate solution.
driver.execute_script("arguments[0].click()", button)
Note:- Before using these options make sure you're trying to interact with correct element using with correct locator, otherwise WebElement.click() would work well after wait until element visible and clickable using WebDriverWait.
Try using an ActionChains:
from selenium.webdriver.common.action_chains import ActionChains
# Your existing code here
# Minus the `button.click()` line
ActionChains(driver).move_to_element(button).cli‌​ck().perform()
I have used this technique when I need to click on a <div> or a <span> element, rather than an actual button or link.

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