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The code is below
i=0
a=0
Matrix[0]=0
Matrix = [1 for i in range(1000)]
while i<1000:
i=i+1
Matrix[i]=(1/1000)*((i*(1/1000))^2
a=a+Matrix[i]
print (a)
When I try to run the program, Python highlight the first a in the 8th row and it says invalid syntax.
I can't figure out what is the problem with the code.
Much appreciated if you helped
Corrected Code:
i=0
a=0
Matrix=[1 for i in range(1000)]
while i<1000:
Matrix[i]=(1/1000)*((i*(1/1000)))**2
a=a+Matrix[i]
i=i+1
print (a)
Related
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import math
import random
possibility_1=0
possibility_2=0
while True:
list = [0, 1]
number_1=random.choice(list)
number_2=random.choice(list)
number_3=random.choice(list)
number_total=str(number_1)+","+str(number_2)+","+str(number_3)
if number_total==(1,1,0) or number_total==(0,0,1):
possibility_1 +=1
if number_total==(1,1,1) or number_total==(0,0,0):
possibility_2 +=1
print(str(number_total)+" possibility_11= "+ str(possibility_1)+" possibility_12= "+ str(possibility_2))
guys the possibility_1 and possibility_2 doesn!t changing. Please help me I want to make a heads or tails code and simulate it then check the possibilities.
Looks like number_total is a string so the output would be "1,1,0" you are comparing with a tuple. This means the if statements will not be invoked.
if number_total=="1,1,0" or number_total=="0,0,1":
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I am new to python and trying to execute my code. Below is my code.
def evod(number):
if number % 2 == 0:
print("The number is even")
return"The number is odd"
print(evod(60))
Output is:
The number is even
The number is odd
if I run this function it prints both lines. It should print a single one of those. Right? Why is this happening?
if c=="July":
print("7/1/2017")
else:
print("sorry")
Indentation matters in python!
if c == "July":
print ("7/1/2017")
else:
print ("sorry")
Correct your indentation
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Issue occurred right after I added the and x= "J1234": I don't know what's going on.
original = ""
if len(original) > 0 and x = "J123":
raw_input("Enter a word:")
original = raw_input('word')
print "original"
else:
print "empty"
x.isalpha()
So, you're getting a SyntaxError. To fix this, change:
x = "J123":
to...
x == "J123":
In Python the former is for setting values and the latter is for checking them. Therefore when you use this the wrong way round the syntax is incorrect.
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I've tried to write a peice of code in python that prints all the divisors of a number including itself. it doesn't work correctly can anyone see why?
def divisors(num):
for x in range (1, num):
if (num % x) == 0:
print(x)
print("Divisors of 6 are")
print(divisors(6))
range() excludes the upper bound and therefore should read range(1, num+1).
you can also try this
num=int(input("please eenter a number "))
a=[]
for x in range(1,num+1):
if num%x==0:
a.append(x)
print(a)
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I am trying to write a quicksort program in python, however I'm getting an invalid syntax error at else statement in the second last line below:
import random
n=int(raw_input("Enter the size of the list: ")) # size of the list
intlist = [0]*n
for num in range(n):
intlist[num]=random.randint(0,10*n)
pivot=random.choice(intlist)
list_1=[] # list of elements smaller than pivot
list_2=[] # list of elements greater than pivot
for num in range(n):
if num<=pivot:
list_1.append(num)
else
list_2.append(num)
This is not a complete program as I am still writing.
add a colon after the else so that it looks like else:. and pick up a good tutorial ;)
Looks like you need a ':' after "else".