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The answer always comes out to be 16 but what happens to the x in function sq(func,x) because func turned into 16 but x remains 2. So it should show something like 16, 2 when I try to print it.
def sq(func,x):
y = x**2
return func(y)
def f(x):
return x**2
Calc = sq(f,2)
print(Calc)
Your print statement prints cal, which is the number returned by the function f(x), which is what is returned by the function sq(f,y).
If you want to print the structure that you need, try to do the following:
def sq(func,x):
y = x**2
return (func(y), x)
def f(x):
return x**2
Calc = sq(f,2)
print(Calc)
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I have a list e.g. ["1","2","n","5","n","x","0","v","-","a","l","4","1","v","m","z","o","5","%","d",";","a","m","6"]
I want to print out the elements that are a letter or special symbol.
how do I do this?
Python comes with an isnumeric() method that returns true when a string is a number. In the case you listed you could try:
string_list = ["1","2","n","5","n","x","0","v","-","a","l","4","1","v","m","z","o","5","%","d",";","a","m","6"]
for value in string_list:
if not value.isnumeric():
print(value)
...which would output
n
n
x
v
-
a
l
v
m
z
o
%
d
;
a
m
You can use isdigit(). Like so:
some_str = "12a"
for i in some_str:
print(i.isdigit())
# outputs
True
True
False
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I don't understand whether 15 is sent to x or n
def func_compute(n):
return lambda x : x * n
result = func_compute(2)
print("Double the number of 15 =", result(15))
Assume a function f(x, n) = xn. Now you want to have this function for a fixed n, i.e., f_n(x) = xn. This is what func_compute(n) does, it returns f_n(x), a function, for the given n.
result(15) is then f_2(15) = f(15, 2) = 30.
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I need an example of a recursive function that will append all integer elements of a number into a list using python and doing this with the most basic algorithm.
For example if n = 1234, list will be [1,2,3,4].
Try this?
def numberToList(number):
# base case
if number == 0:
return []
# recurse
return numberToList(number / 10) + [ number % 10 ]
Run it like this:
>>> numberToList(1234)
[4, 3, 2, 1]
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I was trying to do something like this for example
def functionx(x):
while x > 0:
x = 2 + 2
x -= 1
for x in functionx(x):
print(x)
Well, in for I wanted to print x = 2 + 2 but it just give me the direction where the function is.
Also just wanted to use x = 2 + 2, use it in another function but then use the stored number again and so on but I don't know how to do that.
Use the yield keyword.
Example
def functionx(x):
while x > 0:
x += 1
yield x
for i in functionx(1):
print i
This creates the functionx as an iterator.