UPDATE(4/10/2018):
So I found that my problem was that the information wasn't available in the source code which means I have to use Selenium.
UPDATE:
I played around with this problem a bit more. What I did was instead or running soup, I just took pageH, decoded it into a string and made a text file out of it, and I found that the '{{ optionTitle }}' or '{{priceFormat (showPrice, session.currency)}}' were from the template section separately stated in the HTML file. Which I THINK means that I was just looking at the wrong place. I am still unsure but that's what I think.
So now I have a new question. After having looked at the text file, I am now realizing that the information necessary is not even in pageH. At the place where it should give me the information I am looking for, it says instead:
<bread-crumbs :location="location" :product-name="product.productName"></bread-crumbs>
<product-info ref="productInfo" :basic="product" :location="location" :prod-info="prodInfo"></product-info>
What does this mean?/Is there a way to get through this to get to the information?
ORIGINAL QUESTION:
I am trying to collect the names/prices for products off of a website. I am unsure if the data is being lost because of the html parser or because of BeautifulSoup but what is happening is that once I do get to the position I want to be in, what is returned instead of the specific name/price is '{{ optionTitle }}' or '{{priceFormat (showPrice, session.currency)}}'. After I get the url using pageH = urllib.request.urlopen(), the code that gives this result is:
pageS = soup(pageH, "html.parser")
pageB = pageS.body
names = pageB.findAll("h4")
optionTitle = names[3].get_text()
optionPrice = names[5].get_text()
Because this didn't work, I tried going about it a different way and looked for more specific tags, but the section of the code that mattered just does not show. It completely disappears. Is there something I can do to get the specific names/prices or is this a security measure that I cannot work through?
The {{}} syntax looks like Angular. Try Requests-HTML to do the rendering (by using render())and get the content afterward. Example shows below:
from requests_html import HTMLSession
session = HTMLSession()
r = session.get('http://python-requests.org/')
r.html.render()
r.html.search('Python 2 will retire in only {months} months!')['months']
'<time>25</time>'
Related
I am using Beautiful Soup to search an XML file provided by the SEC (this is public data). Beautiful Soup works very well for referencing tags but I can not seem to pass a variable to its find function. Static content is fine. I think there is a gap in my python understanding that I can't seem to figure out. (I code a few days a year, not my main role)
File:
https://reports.adviserinfo.sec.gov/reports/CompilationReports/IA_FIRM_SEC_Feed_02_08_2023.xml.gz
I download, unzip and then create the soup from the file using lxml.
with open(Firm_Download_name,'r') as f:
soup = BeautifulSoup(f, 'lxml')
Next is where I am running into trouble, I have a list of Firm CRD numbers (these are public numbers identifying the firm) that I am looking for in the XML file and then pulling out various data points from the child tags.
If I write it statically such as:
soup.find(firmcrdnb="5639055").parent
This works perfectly, but I want to loop through a list of CRD numbers and pull out a different block each time. I can not figure out how to pass a variable to the soup.find function.
I feel like this should be simple. I appreciate any help you can provide.
Here is my current attempt:
searchstring = 'firmcrdnb="'+Firm_CRD+'"'
select_firm = soup.find(searchstring).parent
I have tried other similar setups and reviewed other stack exchanges such as Is it possible to pass a variable to (Beautifulsoup) soup.find()? but just not quite getting it.
Here is an example of the XML.
<?xml version="1.0" encoding="iso-8859-1"?>
<IAPDFirmSECReport GenOn="2017-09-30">
<Firms>
<Firm>
<Info SECRgnCD="MIRO" FirmCrdNb="9999" SECNb="999-99999" BusNm="XXXX INC." LegalNm="XXX INC" UmbrRgstn="N"/>
<MainAddr Strt1="9999 XXXX" Strt2="XXXX" City="XXX" State="FL" Cntry="XXX" PostlCd="999999" PhNb="999-999-9999" FaxNb="999-999-9999"/>
<MailingAddr Strt1="9999 XXXX" Strt2="XXXX" City="XXX" State="FL" Cntry="XXX" PostlCd="999999" />
<Rgstn FirmType="Registered" St="APPROVED" Dt="9999-01-01"/>
<NoticeFiled>
Thanks
ps: if anyone has ideas on how to improve the speed of the search on this large file I'd appreciate that to. I get messages such as "pydevd warning: Computing repr of soup (BeautifulSoup) was slow (took 43.83s)" I did install and import chardet per the beautifulsoup documentation but that hasn't seemed to help.
I'm not sure where I got turned around but my static answer did in fact not work.
The tag is "info" and the attribute is "firmcrdnb".
The answer that works was:
select_firm = soup.find("info", {"firmcrdnb" : Firm_CRD}).parent
Welcome to StackOverFlow
Try use,
select_firm = soup.find(attrs={'firmcrdnb': str(Firm_CRD)}).parent
Maybe I'm missing something. If it works statically, have you tried something such as:
list_of_crds = ["11111","22222","33333"]
for crd in list_of_crds:
result = soup.find(firmcrdnb=crd).parent
...
I'm very new to Python and am attempting my first web scraping project. I'm attempting to extract the data following a tag within a XML data source. I've attached an image of the data I'm working with. My issue is that, it seems like no matter what tag I try to extract I constantly return no results. I am able to return the entire data source so I know the connection is not the issue.
My ultimate goal is to loop through all of the data and return the data following a particular tag. I think if I can understand why I'm unable to print a singular particular tag I should be able to figure out how to loop through all of the data. I've looked through similar posts but I think the tree in my set of data is particularly troublesome (that and my inexperience).
My Code:
from bs4 import BeautifulSoup
import requests
#Assign URL to scrape
URL = "http://api.powertochoose.org/api/PowerToChoose/plans?zip_code=78364"
#Fetch the raw HTML Data
Data = requests.get(URL)
Soup = BeautifulSoup(Data.text, "html.parser")
tags = Soup.find_all('fact_sheet')
print (tags)
Try to check the response of your example first, it is JSON not XML so no BeautifulSoup needed here, simply iterate the data list to pick your fact_sheets:
for plan in Data.json()['data']:
print(plan['fact_sheet'])
Out:
https://rates.cleanskyenergy.com:8443/rates/DownloadDoc?path=a70e9298-5537-481a-985c-c7a005b2e4f3.html&id_plan=223344
https://texpo-prod-api.eroms.works/api/v1/document/ViewProductDocument?type=efl&rateCode=SRCPLF24PTC&lang=en
https://www.txu.com/Handlers/PDFGenerator.ashx?comProdId=TCXSIMVL1212AR&lang=en&formType=EnergyFactsLabel&custClass=3&tdsp=AEPTCC
https://signup.myvaluepower.com/Home/EFL?productId=32653&Promo=16410
https://docs.cloud.flagshippower.com/EFL?term=36&duns=007924772&product=galleon&lang=en&code=FPSPTC2
...
As you've already realized by now, you're getting the data as json, so doing something like:
fact_sheet_links = [d['fact_sheet'] for d in Data.json()['data']]
would get you the data you want.
But also, if you'd prefer to work with the xml, you can add headers to the request:
Data = requests.get(URL, headers={ 'Accept': 'application/xml' })
and get an xml response. When I did this, Soup.find_all('fact_sheet') still did not work (although I've seen this method used in some tutorials, so it might be a version problem - and it might still work for you), but it did work when I used find_all with lambda:
tags = Soup.find_all(lambda t: 'fact_sheet' in t.name)
and the results after altering your code looked like this. That just gives you the tags though, so if you want a list of the contents instead, one way would be to use list comprehension:
fact_sheet_links = [t.text for t in tags]
so that you get them like this.
Classic case of code used to work, changed nothing, now it doesn't work no more here. I'm trying to extract a list of unique appid values from this page that I'm saving locally as roguelike.html
The code I have looks like this and it used to work as of a couple months ago when I last ran it, but now the end result is a list of 1 with just a NoneType in it. Any ideas as to what's going wrong here?
from bs4 import BeautifulSoup
text_file = open("roguelike.html", "rb")
steamdb_text = text_file.read()
text_file.close()
soup = BeautifulSoup(steamdb_text, "html.parser")
trs = [tr for tr in soup.find_all('tr')]
apps = []
for app in soup.find_all('tr'):
apps.append(app.get('data-appid'))
appset = list(set(apps))
Is there a simpler way to get the unique appids from the page source? The individual elements I'm trying to cycle over and grab look like:
<tr class="app" data-appid="98821" data-cache="1533726913">
where I want all the unique data-appid values. I'm scratching my head trying to figure out if formatting in the page changed (doesn't seem like it), or some kind of version upgrade in Spyder, Python, or Beautifulsoup broke something that used to be working.
Any ideas?
I tried this code and it worked well for me. You should make sure that the html file you have is the right file. Perhaps you've hit a capcha test in the html test.
venturing into the world of python. I've done the codeacademy course and traweled through stack and youtube but hitting an issue I cant solve.
I'm attempting to do a simple print of a table located in wikipedia, failing misreably at writing my own code I decided to use a tutorial example and build off. However this isn't working and I haven't the foggest idea why.
This is the code here with the appropiate link included. My end result is an empty list "[ ]". I'm using PyCharm 2017.2, beautifulsoup 4.6.0, requests 2.18.4 & python 3.6.2. Any advice appreciated. For reference, the tutorial website is here
import requests
from bs4 import BeautifulSoup
WIKI_URL = "https://en.wikipedia.org/wiki/List_of_volcanoes_by_elevation"
req = requests.get(WIKI_URL)
soup = BeautifulSoup(req.content, 'lxml')
table_classes = {"class": ["sortable", "plainrowheaders"]}
wikitables = soup.findAll("table", table_classes)
print(wikitables)
You can accomplish that using regular expressions.
You get site content by requests.get(WIKI_URL).content
See source code of the site to see how Wikipedia presents tables in HTML.
Find a regular expression that can fit whole table (might be something like <table>(?P<table>*+?)</table>). What this does is get anything between <table> and </table> tokens. Good documentation for regex with python. Take a look at re.findall().
Now you are left with table data. You can use regular expressions again to get data for each row, then regex on each row to get columns. re.findall() is the key again.
I am starting to program in Python, and have been reading a couple of posts where they say that I should use an HTML parser to get an URL from a text rather than re.
I have the source code which I got from page.read() with the urllib and urlopen.
Now, my problem is that the parser is removing the url part from the text.
Also, if I had read correctly, var = page.read(), var is stored as a string?
How can I tell it to give me the text between 2 "tags"? The URL is always in between flv= and ; so and as such it doesn't start with href which is what the parsers look for, and it doesn't contain http:// either.
I have read many posts, but it seems they all look for ``href in the code.
Do I have it all completely wrong?
Thank you!
You could consider implementing your own search / grab. In psuedocode, it would look a little like this:
find location of 'flv=' in HTML = location_start
find location of ';' in HTML = location_end
grab everything in between: HTML[location_start : location_end]
You should be able to implement this in python.
Good luck!