Using a python string output in curl - python

I have this python script
users=['mark','john','steve']
text=''
for user in users:
text+=str(user + " ")
print(text)
I want to output that string "text" into a curl terminal command.
I tried:
curl -d "#python-scirpt.py" --insecure -i -X POST https://10.10.10.6/hooks/84kk9emcdigz8xta1bykiymn5e
and
curl --insecure -i -X POST -H 'Content-Type: application/json' -d '{"text": 'python /home/scripts/python-script.py'}' https://10.10.10.6/hooks/84kk9emcdigz8xta1bykiymn5e
or without the quotations in the text option
Everything returns this error
{"id":"Unable to parse incoming data","message":"Unable to parse incoming data","detailed_error":"","request_id":"fpnmfds8zifziyc85oe5eyf3pa","status_code":400}
How to approach this ? Any help is appreciated thank you.
another approach would be to curl inside python but would need help in that too.
Thank you

Use command substitution (i.e. $(...)) to make the shell run the python code first.
So
curl -d "$(python-scirpt.py)" --insecure -i -X POST https://10.10.10.6/hooks/84kk9emcdigz8xta1bykiymn5e

Related

Attempts to use curl in conjunction with api give 404 error

I am attempting to query Confluence knowledge base pages using the API and failing.
I have researched the api and have the following:
Browsing Content
curl -u admin:admin http://localhost:8080/confluence/rest/api/content/ | python -mjson.tool
Read Content and Expand the Body:
curl -u admin:admin http://localhost:8080/confluence/rest/api/content/3965072?expand=body.storage | python -mjson.tool
What I actually want to do is dump out the contents of a page / pages in a "Space" as Confluence calls it to a file, or on screen.
This is an actual page:
"https://bob.atlassian.net/wiki/spaces/BKB/pages/1234567/BOB+KNOWLEDGE+BANK"
And this is an example I found of using the REST API to do what I want:
curl -u admin:admin -G "http://myinstance.address:8090/rest/api/content/search" --data-urlencode "cql=(type=page and space=low and title ~ "LOWERTOWN")" \ | python -m json.tool
How I am translating what I have researched:
curl -u "bob#bob.com:12345678" -G "https://bob.atlassian.net/rest/api/content/search" --data-urlencode "cql=(type=page and space=BKB and title ~ "BOB+KNOWLEDGE+BANK")" \ | python -m json.tool
Which results in this error:
curl: (3) URL using bad/illegal format or missing URL
No JSON object could be decoded
I have grabbed my logic here from this site:
https://community.atlassian.com/t5/Confluence-questions/How-to-get-Conflunece-knowledge-base-data-through-API/qaq-p/1030159
And I am assuming I have misunderstood this:
/rest/api/content/search
And where it belongs in my curl statement and linking it to the knowledge base. I am also unsure if applying the -mjson.tool is applicable in my case or if I actually have it installed / need to verify that.
Can you help me interpret this correctly?
You are almost there! You just need to pass cql as query parameter to the service as mentioned here in Atlassian documentation:
curl --request GET
--url 'https://your-domain.atlassian.net/wiki/rest/api/search?cql={cql}'
--header 'Authorization: Bearer <access_token>'
--header 'Accept: application/json'

Python: curl -d json will not work without apostrophe

I have to send the curl exact in that form to get a response in cli
curl -d '{"id":0,"params":["aa:aa:00:00:00:00",["mixer","volume","80"]],"method":"slim.request"}' http://localhost:9000/jsonrpc.js
curl -d '{"id":0,"params":["aa:aa:00:00:00:00",["playlist","play","/home/pi/mp3/File.mp3"]],"method":"slim.request"}' http://localhost:9000/jsonrpc.js
Running the command above in my script, I get a syntax error for the apostrophe
File "./updateTimers.py", line 126
strVolume = curl -d '{"id":0,"params":["aa:aa:00:00:00:00",["mixer","volume","80"]],"method":"slim.request"}' http://localhost:9000/jsonrpc.js
^
SyntaxError: invalid syntax
If I change apostrophes and quotation than my python script does not like the syntax also. Would be happy any advice. At least I need to run both commands one by one.
strVolume = curl -d '{"id":0,"params":["aa:aa:00:00:00:00",["mixer","volume","80"]],"method":"slim.request"}' http://localhost:9000/jsonrpc.js
strPlayMP3Command = curl -d '{"id":0,"params":["aa:aa:00:00:00:00",["playlist","play","/home/pi/adhan/mp3/Adhan-Makkah.mp3"]],"method":"slim.request"}' http://localhost:9000/jsonrpc.js
If I understand your question correctly, you want the curl -d ... to be a string in Python. To do this, you will also have to wrap curl in quotes: strVolume = "curl -d '{\"id\": 0, ...}' ...". Make sure you escape the quotes inside.

Send curl POST Request in Python without installing a lib

I wanna send a curl post request in python. But I can't install any lib like 'request'. I could send POST request like following example :
curl -H "Content-Type: application/json" -X POST -d {\"username\":\"myusername\",\"password\":\"mypassword\"} https://example.com/login
I need equal code as the above in python2. Then, i must read what it returns. I'm working on Windows 10.
Write a curl command in a way that it can work in the shell and then execute the command in the shell.
This way you don't need the requests package.
import os
command = "curl -u {username}:{password} [URL]"
os.system(command)

Pass the variable to curl command to inovoke rest api url n python

I am trying to pass the report title name using a variable triggername. When I execute the code, I am value of the triggername is not captured in the api url.
Can someone help me to fix this?
**#!/usr/bin/python2.7
import requests
import os
import commands
triggername="GSD_Trigger_Active"
print("**********",triggername, type(triggername))
cmd="""curl -v -u $(ops_unv_cred_user_35ab1e1285be4e659f9ab15fca0a35fc):$(ops_unv_cred_pwd_35ab1e1285be4e659f9ab15fca0a35fc) -H "Accept: application/json" -X GET 'https://xxxxx.cloud/resources/report/run?reporttitle=triggername'
"""
os.system(cmd)
I am getting the below error message:
Could not find report with name "triggername"
Think you need to interpolate the variable. The most simplest way is this.
triggername = "GSD_Trigger_Active"
cmd= f'curl -v -u $(ops_unv_cred_user_35ab1e1285be4e659f9ab15fca0a35fc):$(ops_unv_cred_pwd_35ab1e1285be4e659f9ab15fca0a35fc) -H "Accept: application/json" -X GET "https://xxxxx.cloud/resources/report/run?reporttitle={triggername}"'
This should give you the cmd as
'curl -v -u $(ops_unv_cred_user_35ab1e1285be4e659f9ab15fca0a35fc):$(ops_unv_cred_pwd_35ab1e1285be4e659f9ab15fca0a35fc) -H "Accept: application/json" -X GET "https://xxxxx.cloud/resources/report/run?reporttitle=GSD_Trigger_Active"'
Adding Screenshot:
Prior to python3.6 use this:
cmd = 'curl -v -u $(ops_unv_cred_user_35ab1e1285be4e659f9ab15fca0a35fc):$(ops_unv_cred_pwd_35ab1e1285be4e659f9ab15fca0a35fc) -H "Accept: application/json" -X GET "https://xxxxx.cloud/resources/report/run?reporttitle={}"'.format(triggername)

Telegram Bot how to set parsing mode in curl?

Im editing some script for telegram bot, and I only want to add parsing mode html, so it allows me to use bold,italic etc..
I cant seem to find way to adopt parse_mode: "HTML" to curl line
if [ -n "${TOKEN}" ];
then
echo "Sending telegram...";
#Telegram notification
curl -s -X POST https://api.telegram.org/bot${TOKEN}/sendMessage -d chat_id=${CHAT_ID} -d text="${1}" >> /dev/null
fi
parse_mode is just another parameter like text or chat_id. You can use -d!
curl -s -X POST https://api.telegram.org/bot${TOKEN}/sendMessage -d chat_id=${CHAT_ID} -d text="${1}" -d "parse_mode='HTML'" >> /dev/null
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