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how to cretae zip file using zipfile in python?

import os
from zipfile import ZipFile
from os.path import basename
src = "C:\git\mytest"
full_path=[]
for root, dirs, files in os.walk(src, topdown=False):
for name in files:
full_path.append(os.path.join(root, name))
with ZipFile('output.zip', 'w') as zipObj:
for item in full_path:
zipObj.write(item, basename(item))
Trying to create a zip file with containing some file of a specific folder.
In specific folder has some files. then it will add to zip file
In the mentioned code, one zipfile is created but there is no file. I am not getting the exact reason

Zip all the files of a folder in the same folder

I am trying to zip all the files from a folder and places it in the same folder. Below is my code:
import os as __os
import zipfile
def zipdir(path, ziph):
for root, dirs, files in __os.walk(path):
for file in files:
print(file)
ziph.write(__os.path.join(root, file))
if __name__ == '__main__':
zip_name = 'test.zip'
working_directory = "C:\\Users\\Admin\\Downloads\\gaz"
archive_name = __os.path.join(working_directory, zip_name)
with zipfile.ZipFile(archive_name, 'w', zipfile.ZIP_DEFLATED) as zipf:
zipdir(working_directory + '', zipf)
I am trying to create zip of all the files inside a folder. I am expecting the code to create a zip in the same folder. Its going into infinite.

I don't really see an endless loop but you're including the newly created test.zip (empty) to the archive of the same name.
It would be better to check file before adding it to the archive:
def zipdir(path, ziph):
for root, dirs, files in __os.walk(path):
for file in files:
if file != zip_name:
print(file)
ziph.write(__os.path.join(root, file))

The zipdir() funciton is calling itself recursively, resulting in the infinite loop. Try zipf.write(). That function adds a file to a zip archive.
with zipfile.ZipFile(archive_name, 'w', zipfile.ZIP_DEFLATED) as zipf:
for root, dirs, files in __os.walk(working_directory):
for file in files:
if os.path.samefile(archive_path, os.path.join(root, file)):
continue
zipf.write(__os.path.join(root, file))
Edit: Check if archive_name file is located in working_directory

Save outputs to new directory in Python

I am trying to identify all .kml in a specific directory and save them into a new directory. Is this possible? I'm able to print the file path but I would like to use Python to copy those files to a new directory.
Here is my code so far:
import os
# traverse whole directory
for root, dirs, files in os.walk(r'C:\Users\file_path_here'):
# select file name
for file in files:
# check the extension of files
if file.endswith('.kml'):
# print whole path of files
print(os.path.join(root, file))

Try this:
import os
# traverse whole directory
for root, dirs, files in os.walk(r'C:\Users\file_path_here'):
# select file name
for each_file in files:
# check the extension of files
if each_file.endswith('.kml'):
# print whole path of files
print(os.path.join(root, file))
kml_file = open(each_file, "r")
content = kml_file.read()
file.close()
with open('newfile.kml', 'w') as f:
f.write(content)

Getting the correct directory structure using Zipfile with Python

I have a directory structure that is like /level1/level2/level3/level4/level5 and in level5 I have .json files I want to replace with zipped up versions so from
/level1/level2/level3/level4/level5/{file1.json, file2.json, file3.json} to
/level1/level2/level3/level4/level5/{file1.zip, file2.zip, file3.zip}
However my code generates the zip files in the folder where the script is, which is level 3, resulting in /level1/level2/[level3]{file1.zip, file2.zip, file3.zip}/level4/level5/{file1.json, file2.json, file3.json}
In addition if I unzip the file I get the entire directory structure instead of just the file. For example if I unzip file1.zip I get /level1/level2/[level3]{(/level1/level2/level3/level4/level5/file1.json), file2.zip, file3.zip}/level4/level5/{file1.json, file2.json, file3.json}
I've tried different arguments but I'm not sure how to get the result I want. How can I accomplish this?
This is my code currently
path = os.path.join(
os.path.dirname(os.path.abspath(__file__)),
level4, level5)
for root, dirs, files in os.walk(path, topdown=True):
print('This is root: ', root)
for file in files:
zf = zipfile.ZipFile(
'{}.zip'.format(file[:-5]), 'w',
zipfile.ZIP_DEFLATED)
zf.write(os.path.join(root, file))
zf.close()

You should create the zip file with the root path joined so that the zip file will be created where the JSON file is, and when writing the JSON file into the zip file, use the writestr method instead of write so that you can name the file with the path name you want, which in this case is just the file name with no path name at all:
for root, dirs, files in os.walk(path, topdown=True):
print('This is root: ', root)
for file in files:
zf = zipfile.ZipFile(os.path.join(root, '{}.zip'.format(file[:-5])), 'w', zipfile.ZIP_DEFLATED)
zf.writestr(file, open(os.path.join(root, file)).read())
zf.close()

Create a zip file from a directory, but not his fullpath

Im trying to create a zipfile with the content of a folder ( some dirs and files ) using the code belllow:
import zip,os
path = "c:\\tester\\folderToZip"
zip = zipfile.ZipFile("zippedFolder.zip", "w")
for root, dirs, files in os.walk(path):
for file in files:
zip.write(os.path.join(root, file))
zip.close()
But after the code runs, when i check the zip file, the zip file, instead having the content of the folder "folderToZip" ( ex: f1,f2,f2, a.txt,b.txt,c.txt ) it have the full path of the variable path.
So, the question is, how can i create a zipfile based on a folder content, but not his fullpath ?

write takes a second optional parameter arcname, which when specified will provide the name for the file stored. Use that to specify the name you want.
If you only want the filename:
import zip,os
path = "c:\\tester\\folderToZip"
zip = zipfile.ZipFile("zippedFolder.zip", "w")
for root, dirs, files in os.walk(path):
for file in files:
filename = os.path.join(root, file)
zip.write(filename, filename)
zip.close()