This question already has answers here:
Maximum and Minimum values for ints
(10 answers)
What is the maximum float in Python?
(4 answers)
Closed 4 years ago.
I use python3.x,I want to know the scope of numerical type.
For example, the float, the maximum and the minimum.
I know the scope of java's float and int, but in python I can't find it now.
For example,java float from 10^-38 to 10^38,so python's float?
int and float are the names of built-in types and are always in scope in Python. I don't know what you mean by "the maximum and the minimum" but max and min are built-in functions, thus always in scope.
Related
This question already has answers here:
Safely evaluate simple string equation
(4 answers)
Evaluating a mathematical expression in a string
(14 answers)
Closed 5 months ago.
Sorry if this is a stupid question I am still very new to python but I was wondering,
If I have string, s = '1+6.3+3-7.6'
how could I take the sum of that?
I have tried using isdigit() but that just gets all the digits
I have also tried turning it to a float but I got could not convert string to float
I also tried turning it into an integer but I got invalid literal for int() with base 10.
This question already has answers here:
Why does integer division yield a float instead of another integer?
(4 answers)
Why does floating-point arithmetic not give exact results when adding decimal fractions?
(31 answers)
Closed 1 year ago.
I've learnt that python supports very large numbers with int itself.
But in this case :
print(int(12630717197566440579/10))
My answer is
1263071719756644096
and not
1263071719756644057
As it's supposed to be.
Can someone tell me why?
This question already has answers here:
How to convert large float values to int?
(2 answers)
Closed 1 year ago.
Why does variable 'a = 123465789123456789' have a different value than variable 'b = int(123456789123456789.0)'?
Because python’s float (like in any other language) have a limit in precision, and you’ve reached it. On contrary, python’s integer type is of arbitrary precision, meaning that you’ll never reach its limit.
This question already has answers here:
Splitting a number into the integer and decimal parts
(9 answers)
How to get numbers after decimal point?
(37 answers)
Closed 2 years ago.
If I have a float like 32.879, and I want to end up with just 0.879, I can think of a few ways to do it, like:
Convert to string, strip off everything before the ., convert back to float; OR
32.879 - int(32.879)
Both of those feel like hacks. Is there no pure math operation that can do this?
Sort of like using abs() instead of if x < 0: x = x*-1
I'm dealing with Python, but if anyone can tell me the math name for this operation, I can probably google the Python way to do it.
This question already has answers here:
"is" operator behaves unexpectedly with integers
(11 answers)
Closed 2 years ago.
i tried the below code but I am not getting the reason why it is happening?
x=2
y=2
print(id(x),id(y))
in above I have got like below
140732101468592 140732101468592
but if I tried with the float type data like below
x=2.0
y=2.0
print(id(x),id(y))
I have got the output like below
2226214428496 2226204728400
why am I getting same id for integer variable with same value but not for float variable with same values?
The id() function returns identity of the object. As you mentioned, floats and integers are different objects in Python.