I'm trying to make a basic python interface for demo purposes and I really want to keep it simple. I have to use two scrollbars side by side. In scrollbarNR1 there are some user numbers and the other one has to be refreshed whenever someone clicks between the users. I tried to solve it with a recursive function by refreshing every 20 milliseconds my scrollbarNR2 but that just doesn't work because it clears my selection. My question is, how can I tell if my scrollbar was clicked and refresh the data just then?
My code is:
import tkinter
F1 = tkinter.Frame()
userScroll = tkinter.Scrollbar(F1)
userList = tkinter.Listbox(F1)
userScroll.pack(side=tkinter.RIGHT, fill=tkinter.Y)
userList.pack(side=tkinter.LEFT, fill=tkinter.Y)
userScroll['command'] = userList.yview
userList['yscrollcommand'] = userScroll.set
//here comes the insertion loop with the datas - irrelevant atm
def userSelect():
selectedUser = userList.get('active')
print(selectedUser)
userScroll.after(20, userSelect)
Related
I am looking for a simple way to display changing real time data in a GUI in python. I am connected to 2 devices and want to display data constantly (like 20 different values), and when I press a button I want to control the one device.
Unfortunately I fail already with the display of the data. For this I have looked at some tkinter tutorials and explanations.
My idea was to implement it with a config function and to overwrite the label continuously. As example how I wanted to display one value:
import tkinter as tk
from pydualsense import pydualsense
# connect to the device
dualsense = pydualsense()
dualsense.init()
# create a window
window = tk.Tk()
# function for updating data
def show_data():
global dualsense
data_label_output.config(text=dualsense.state.LX)
# showing the data as a lable
data_label_output = tk.Label(window)
data_label_output.grid(row=1, column=1)
show_data()
#### or different solution
# showing the data as a lable
data_label_output = tk.Label(window, comand=show_data)
data_label_output.grid(row=1, column=1)
window.mainloop()
Unfortunately, the value is displayed only once at the beginning and nothing changes after that.
Another problem:
When I press the button, I want to be able to control the one device. For this I have a while True loop that permanently checks if a button is pressed and then executes actions. As a separate program no problem, but how do I integrate this into the tkinter GUI? When I start this PyCharm always crashes.
I use PyCharm and Python 3.8
About simple and functional ideas I would be happy, also to other tools/modules etc., as long as you can easily and quickly implement the idea. It's only for a research project and the programming is only a means to an end.
You can use the after method in tkinter to run something after a short delay. The following code will run show_data once the GUI is ready and then again every 1000 milliseconds.
import tkinter as tk
from pydualsense import pydualsense
# connect to the device
dualsense = pydualsense()
dualsense.init()
# create a window
window = tk.Tk()
# function for updating data
def show_data():
global dualsense
data_label_output.config(text=dualsense.state.LX)
window.after(1000,show_data)
# showing the data as a lable
data_label_output = tk.Label(window)
data_label_output.grid(row=1, column=1)
window.after_idle(show_data)
window.mainloop()
This resolves the updating issue, I'm not sure what behaviour you want when you press the button but if you elaborate and explain, I might be able to help and update this answer.
I have a general problem, which I sketch here as the details will be too involved to post here. I know the problem statement, is a bit fuzzy and I may need to go back and forth with an expert in this site. (unfortunately, it is difficult to put everything up here based on the type of the problem. I will really appreciate any help).
I am trying to create a GUI application using Tkinter. The way I am doing is as follows. I have a background script (say back.py) which has the data loaded, calculations done and graph plotted.
Now the way I want to do is that I have a GUI script which uses Tkinter and calls the back.py ( using import). Now I have the window created, with a button. This is where I am stuck. I want to click the button to trigger the background script and generate the plots ( which the background script generates).
After this I want to close the plot and want my GUI to pop up some buttons to input me some parameters. These parameters will be input to the next part of the back.py code ( I chose the parameters based on the plot). When I again click the button ( with the parameters selected), I want to start running the background code again which will output me a file.
How can I do this?. A general rough idea will be helpful.
Let me put an example as much as I can:( at least the skeleton of the code)
I have a background file say (a.py) and gui file ( say g.py)
a.py
import ...
def progA():
# reading a file
# doing something and generating a plot from the file
# Once the GUI's first part is done generating the plot, I need to close that
# plot (or button) and then click the button 2 to run the next function
def progB(y1, y2,y3):
#run a code... and generate an output file
g.py
from tkinter import *
from tkinter.ttk import *
class GUI ():
def create widgets(self):
#....
def create panel(self):
#create buttons
panel1 = ...
btn1 = Button(panel1, text="yyyyy", command=progA)
btn1.pack()
def create_panel1(self):
#create buttons
panel1 = ...
btn1 = Button(panel1, text="yyyyy", command=progA)
btn1.pack()
def create_panel2(self):
#create buttons
panel2 = ...
btn2 = Button(panel1, text="yyyyy", command=progB)
btn2.pack()
All_Entries = []
window = Tk()
D=GUI(window)
window.mainloop()
import a
runprogram1 = a.progA()
runprogram2 = a.probB(x, y, z)
My question is now, does the above makes sense? So I have a couple of questions:
How will I ensure that when I close the plots (from the output of progA), that the second button will show up?
Where can I input the there values of the parameters in the second button?
New to GUI. Not quite getting there. I used page and get can get buttons to do something (click on a button and get a response). With Combobox, I can't pass a value. Searched here, tried many things, watched a few hours of youtube tutorials.
What am I doing wrong below? This is the code page generates (basically) then I added what I think I need to do to use the Combobox.
I am just trying to have 1,2,3 in a combo box and print out the value that is chosen. Once I figure that out I think I can actually make a simple GUI that passes variables I can then program what I want to do with these variables being selected.
class New_Toplevel_1:
def __init__(self, top):
self.box_value = StringVar()
self.TCombobox1 = ttk.Combobox(textvariable=self.box_value)
self.TCombobox1.place(relx=0.52, rely=0.38, relheight=0.05, relwidth=0.24)
self.TCombobox1['values']=['1','2','3']
self.TCombobox1.configure(background="#ffff80")
self.TCombobox1.configure(takefocus="")
self.TCombobox1.bind('<<ComboboxSelected>>',func=select_combobox)
def select_combobox(self,top=None):
print 'test combo ' # this prints so the bind works
self.value_of_combo = self.ttk.Combobox.get() # this plus many other attempts does not work
It's hard to know what you're actually asking about, since there is more than one thing wrong with your code. Since you say the print statement is working, I'm assuming the only problem you have with your actual code is with the last line.
To get the value of the combobox, get the value of the associated variable:
self.value_of_combo = self.box_value.get()
Here's a working version where I fixed the other things that were wrong with the program:
from tkinter import *
from tkinter import ttk
class New_Toplevel_1:
def __init__(self, top):
self.box_value = StringVar()
self.TCombobox1 = ttk.Combobox(textvariable=self.box_value)
self.TCombobox1.place(relx=0.52, rely=0.38, relheight=0.05, relwidth=0.24)
self.TCombobox1['values']=['1','2','3']
self.TCombobox1.configure(background="#ffff80")
self.TCombobox1.configure(takefocus="")
self.TCombobox1.bind('<<ComboboxSelected>>',func=self.select_combobox)
def select_combobox(self,top=None):
print('test combo ') # this prints so the bind works
self.value_of_combo = self.box_value.get()
print(self.value_of_combo)
root = Tk()
top = New_Toplevel_1(root)
root.mainloop()
Note: I strongly advise you not to start with place. You should try to learn pack and place first. I know place seems easier, but to get the most responsive and flexible GUI you should leverage the power of pack and grid.
I'm currently trying to update a TKinter window every second. So the idea is that is should open a window, let python updates the field, show updated window. The situation right now is that the second window is only showing when i close the first one. I'm guessing this has something to do with mainloop(). I looked into .update() and .update_idletasks() but I can't figure out how to implement it. TKinter is used to show a field with houses in it. So in general is should do this:
Generate house location (already implemented)
Show field with houses in it (already implemented)
Generate new location of houses (already implemented)
Show updated field
This is my current code. I'm not sure if the update function is necessary.
class Plot(tk.Frame):
def __init__(self, master=None):
tk.Frame.__init__(self, master)
self.grid()
def createWidgets(self, list_houses):
houses = list_houses
self.w = tk.Canvas(self, width = field.width*SIZE, height = field.height*SIZE, bg = '#E4E4E4')
...
self.w.grid()
def update(self):
?
#GENERATES FIELD AND HOUSES
...
#PRINT FIRST WINDOW
plot = Plot()
plot.createWidgets(houses) <- PUT HOUSES IN TK INTER
plot.master.title('map of houses')
plot.mainloop()
# UPDATE FIELD <- THIS PART IS ONLY EXECUTED WHEN I CLOSE THE FIRST WINDOW, WHY?
i = 0
while i < 2:
update = field.update_houses(houses) <- GENERATES NEW LOCATION OF HOUSES
#PRINT UPDATED WINDOW, IT SHOULD BE PRINTED IN THE SAME WINDOW!
plot = Plot()
plot.createWidgets(houses) <- PUT HOUSES IN TKINTER
plot.master.title('map of houses')
i += 1
Thanks in advance!
Your update field is only executed when you close the window because tkinter's mainloop keeps running until the window is closed. Because of this mainloop, using a (long) while loop in tkinter is a bad idea, because the while loop locks up the tkinter mainloop.
To do something multiple times without blocking the mainloop, use the after method. This calls a function after a certain amount of time. You can call it once before entering your mainloop and then call it again in your update function, so that the update function calls itself. Take a look at this small example which uses after to execute an update function every second:
import Tkinter as tk
import random
def update():
l.config(text=str(random.random()))
root.after(1000, update)
root = tk.Tk()
l = tk.Label(text='0')
l.pack()
root.after(1000, update)
root.mainloop()
you could use the .update to the window. That would make it update the window and allow everything to be on it.
I'm trying to remove a Tkinter progress bar widget from an active window (after the GUI window using Tkinter has been initialized). I'm using a Tkinter Frame for my window. I've initialized the progress bar as pb, as below.
pb = ttk.Progressbar(root,orient ="horizontal",length = 540, mode ="determinate")
And then I've tried two different methods to get rid of the progress bar. The line below causes the window to freeze and stop responding when I try to use it after the GUI is initialized.
pb.pack_forget()
The line below causes only a middle section of the progress bar to disappear, but you can still see the two sides of it.
pb.destroy()
Is there any way I could get this widget to disappear after the Frame has been initialized?
The specific answer to your question is that pack_forget, grid_forget or grid_remove are what you want if you want to make a widget temporarily invisible. Which one you choose depends on if you're using grid or pack, and whether or not you want grid to remember where it was so you can later put it back in the same spot.
destroy is what you want to call if you want to literally destroy the widget.
When used properly, none of those methods will cause your program to freeze. Without seeing your code, it's impossible to know what the root cause of the problem is.
Sorry for my bad English.
This code worked for me. I simply follow Oakley's instruction.
def progressBar(*args, **kwargs):
def progress(currentValue):
progressbar["value"] = currentValue
maxValue = 100
progressbar = ttk.Progressbar((kwargs), orient="horizontal", length=150, mode="determinate", takefocus=True)
progressbar.pack(side=tk.BOTTOM)
currentValue = 0
progressbar["value"] = currentValue
progressbar["maximum"] = maxValue
divisions = 10
for i in range(divisions):
currentValue = currentValue + 10
progressbar.after(500, progress(currentValue))
progressbar.update() # Force an update of the GUI
progressbar.destroy()
Hence I simply tried progressbar.destroy() outside of the loader loop. So after
complete the loading, it will disappear from the main App window.
Thank you, Bryan Oakley sir.