Printing variables in tkinter GUI - python

This is my code:
import pandas as pd
from tkinter import *
master = Tk()
label1= Label(master, text='Department')
label1.grid(row=0, column=0)
textBox = Text(master, height=1, width=10)
textBox.grid(row=0, column=1)
def retrieve_input():
Department = textBox.get("1.0","end-1c")
fileread = pd.read_csv('50.csv', encoding='latin-1')
filevalue = fileread.loc[fileread['Customer'].str.contains(Department, na=False)]
def printSomething():
label = Label(master, textvariable=filevalue)
label.grid(row=3, column=1)
button1 = Button(master,text="Show Values", command=lambda: retrieve_input())
button1.grid(row=2, column=1)
mainloop( )
I have searched around Stack Overflow of how to do this, and was able to construct my code up until this point, However when I click the Show values button, nothing happens. I could find nowhere online that helped address this issue. Is there something fundamentally wrong with my code? Using Python 3.7

You define a nested printSomething function that would display something, but you never call that function.
This would fix that problem:
def retrieve_input():
Department = textBox.get("1.0","end-1c")
fileread = pd.read_csv('50.csv', encoding='latin-1')
filevalue = fileread.loc[fileread['Customer'].str.contains("Lam Dep", na=False)]
def printSomething():
label = Label(master, textvariable=filevalue)
label.grid(row=3, column=1)
printSomething()
But I'm not sure why you need the function in the first place; you can just do this:
def retrieve_input():
Department = textBox.get("1.0","end-1c")
fileread = pd.read_csv('50.csv', encoding='latin-1')
filevalue = fileread.loc[fileread['Customer'].str.contains("Lam Dep", na=False)]
label = Label(master, textvariable=filevalue)
label.grid(row=3, column=1)
But you have a second problem: You're trying to set the textvariable=filevalue, but that doesn't make any sense.
The textvariable has to be a tkinter.StringVar instance, not a plain old Python string. You can then set the StringVar to hold your string.
filevar = StringVar()
filevar.set(filevalue)
label = Label(master, textvariable=filevar)
label.grid(row=3, column=1)
… or just pass the text in directly, without a tkinter variable:
label = Label(master, text=filevalue)
label.grid(row=3, column=1)
There's still one more problem: Every time you call retrieveInput, it's going to create a new Label and grid it in front of whatever used to be there, but you never delete the old ones. So if you press the button over and over again, there will be a whole stack of invisible widgets just wasting resources.
It probably makes more sense to move the label creation to the global scope, just like the text box and the other label, and replace its text in this function, instead of creating a new label each time.
Using a StringVar is the simplest way to do this:
# ...
textBox = Text(master, height=1, width=10)
textBox.grid(row=0, column=1)
fileVar = StringVar()
fileLabel = Label(master, textvariable=fileVar)
fileLabel.grid(row=3, column=1)
def retrieve_input():
Department = textBox.get("1.0","end-1c")
fileread = pd.read_csv('50.csv', encoding='latin-1')
filevalue = fileread.loc[fileread['Customer'].str.contains("Lam Dep", na=False)]
fileVar.set(filevalue)
# ...
You may have other bugs in your code, but I think if you fix these three, you'll at least be pretty close to everything working.

Considering you are running Python 3.7, as you said, the following code will solve your problem:
import pandas as pd
from tkinter import *
master = Tk()
label1= Label(master, text='Department')
label1.grid(row=0, column=0)
textBox = Text(master, height=1, width=10)
textBox.grid(row=0, column=1)
def retrieve_input():
global text
department = textBox.get("1.0","end-1c")
fileread = pd.read_csv('50.csv', encoding='latin-1')
filevalue = fileread.loc[fileread['Customer'].str.contains("Lam Dep", na=False)]
text.set(filevalue)
button1 = Button(master,text="Show Values", command=retrieve_input)
button1.grid(row=2, column=1)
text = StringVar()
label = Label(master, textvariable=text)
label.grid(row=0, column=1)
mainloop()
You are facing these problems:
You are defining an inner function printSomething which is never called.
Even if you were calling printSomething you are going to create a new Label every time you press button1.
In this as, you don't need to use lambda to pass the callback that will be executed, you can simply pass command=retrieve_input
The simplest solution might be to define a StringVar (text) which is going to be associated with a Label (label), and when you press the button button1 you update call the method set on that variable text.

Related

One of my variables is being printed but the other is not in tkinter Entry boxes

I'm trying to create a function in tkinter where I can print out what the user writes in a Entry box. I'm able to print out ask_an_entry_get, but when I try to print what_is_answer_entry_get
, I get nothing my empty spaces.
Please find out the problem here. Also I'm using the Entry widget, along with the get() function, to get input from the user.
def answer_quizmaker_score():
print(ask_an_entry_get)
print(what_is_answer_entry_get)
I made a lot of global variables so I could use them all around my code.
global what_is_answer_entry
what_is_answer_entry = Entry(root4)
what_is_answer_entry.pack()
I then used the get() function to retrieve what the user typed.
global what_is_answer_entry_get
what_is_answer_entry_get = what_is_answer_entry.get()
This is the exact process I did for both ask_an_entry_get and what_is_answer_entry_get. However for some reason only ask_an_entry_get is printed, while what_is_answer_entry_get is printing nothing in the console.
from tkinter import *
root = Tk()
root.geometry("500x500")
txt1 = StringVar()
txt2 = StringVar()
def txt_printer():
print(txt1.get())
print(txt2.get())
x = Entry(root, textvariable=txt1, width=20)
x.place(x=0, y=0)
y = Entry(root, textvariable=txt2, width=20)
y.place(x=0, y=50)
btn_print = Button(root, text="print", command=txt_printer)
btn_print.place(x=0, y=100)
# Or if you want to show the txt on window then:
def txt_on_window():
lb1 = Label(root, text=txt1.get())
lb1.place(x=0, y=200)
lb2 = Label(root, text=txt2.get())
lb2.place(x=0, y=235)
btn_print_on_window = Button(root, text="print on screen", command=txt_on_window)
btn_print_on_window.place(x=0, y=150)
root.mainloop()

How to correct the output from an entry box

When using the feeder button, the script for F runs through entirely through to the print before the 'master' box appears, then does not react to the inputs from the 'master' box. This results in the output being 0.0 kW because the input is a long decimals followed by an L, when what I, the user inputs is 8777
I have been roaming the internet for about a day now with no luck finding anything. I am very new to TK but have been trying to learn it.
def F():
master = tk.Tk()
tk.Label(master, text = 'Feeder Number: ').grid(row=0)
entry1 = tk.Entry(master)
entry1.grid(row=0, column=1)
button2 = tk.Button(master,
text=' Confirm',
command=entry1.get())
button2.pack()
button2.grid(row=0, column=2)
fn = entry1.pack()
print fn
feed = filtered['Feeder']==fn
feedfn = filtered[feed]
Cap = feedfn['AC Name Plate Capacity <= 10kw']
Cap = Cap.astype(float)
AcPv = Cap.sum()
print 'The total PV on this feeder is:', AcPv, 'kW'
root = tk.Tk()
frame = tk.Frame(root)
frame.pack()
button = tk.Button(frame,
text='Exit',
fg='red',
command=quit)
button.pack()
button.grid(row=1, column=1)
Fee = tk.Button(frame,
text='Feeder',
command=F)
Fee.pack()
Fee.grid(row=0, column=1)
root.mainloop()
Expected 27.702
Output 0.0
Given that I will not be posting the csv,
entry1/fn should be 8777
currently 'none'
UPDATE
I am now receiving an output of PY_VAR when printing fn, I understand that the code is running all the way through before taking an input. Any recommendations for how to take the input before the filters are run?
def F():
master = tk.Tk()
tk.Label(master, text = 'Feeder Number: ').grid(row=0)
entry1 = tk.Entry(master)
entry1.grid(row=0, column=1)
button2 = tk.Button(master,
text=' Confirm',
command=entry1.get())
button2.grid(row=0, column=2)
fn = tk.IntVar()
print fn
feed = filtered['Feeder']==fn
feedfn = filtered[feed]
Cap = feedfn['AC Name Plate Capacity <= 10kw']
Cap = Cap.astype(float)
AcPv = Cap.sum()
print 'The total PV on this feeder is:', AcPv, 'kW'
For those interested in the final code (Which worked for me):
def F():
master = tk.Tk()
tk.Label(master, text = 'Feeder Number: ').grid(row=0)
entry = tk.Entry(master)
entry.grid(row=0, column=1)
def pint():
data = entry.get()
master.destroy()
feed = filtered['Feeder']==data
feedfn = filtered[feed]
Cap = feedfn['AC Name Plate Capacity <= 10kw']
Cap = Cap.astype(float)
AcPv = Cap.sum()
fdf = tk.Tk()
tk.Label(fdf, text = AcPv).grid(row=0)
button4 = tk.Button(fdf,
text = ' Exit',
fg='red',
command=fdf.destroy)
button4.grid(row=1)
button2 = tk.Button(master,
text=' Confirm',
command = pint)
button2.grid(row=0, column=2)
button3 = tk.Button(master,
text = ' Exit',
fg='red',
command=master.destroy)
button3.grid(row=0, column=3)
master.mainloop()
There a few mistake in your code that lead to the different output you have received.
First, why is your code executing without showing the master box :
Your tkinter need a mainloop() call if you want a persistent window.
master.mainloop()
You did that right with your root, but your master lacks that mainloop. This line is what basically keeping your GUI alive and looping over it for changes until it is destroyed one way or another. You need to add this line after creating your widgets in order to be able to interact with the window. Anything written after this line (but still indented in the definition) will be executed when your window is closed, either manually or with the command :
master.destroy()
Next, although this will yield a working window, you can still interact with your root window while the master window is up, which can lead to problems if you are expecting variable from master. I suggest you read about the Toplevel widget which is made specifically for cases like yours. (http://effbot.org/tkinterbook/toplevel.htm) Alternatively, you could also use tkinter's tkSimpleDialog.askinteger or askfloat functions which seems perfect for your application.
Finally, the entry allows you to write text but how to access the text? you can use Entry1.get() to extract the content of the entry, or as you have started to to in your update, you can assign a tkinter variable to the entry. This variable will be updated as you change write strings or numbers in the entry. To bind the variable to your entry, you must state it in the entry's creation :
fn = tk.StringVar(value = '000')
entry1 = tk.Entry(master, textvariable = fn)
*Note, this will require your fn variable to be initialized before the entry. Also, you can initialize a value for that variable upon creation
the tkinter variable is an object which is why when you print it, you get PY_VAR. (the type of object) To access the value, you need to use the get() method :
print(fn.get())

Why isn't my label being displayed in tkinter?

def name_label_manager(event):
name = name_entry.get()
label_name = Label(root, text="Name: " + name)
label_name.grid(row=10, column=1, sticky=W)
label_name.delete(0, "end")
def description_label_manager(event):
description1 = description.get()
descrpt = Label(root, text="Description: " + description1)
descrpt.grid(row=9, column=1, sticky=W)
descrpt.delete(0, "end")
i am calling them like this:
button_get = Button(root, text="Submit")
button_get.bind("<Button-1>", description_label_manager,name_label_manager)
button_get.grid(row=2, column=8)
i dont know if this i right but i am calling them with button
for some reason the desctription_label_manager label will show, but the name label wont
As Bryan Oakley pointed out, labels do not have a delete method, Entry Listbox do, but not labels
More so, you can think of tkinter widgets as images drawn on your screen, for these images to display text they must have variables associated with them, here we create some StringVar() variables and assign them to the Entry which you can then use the get method to get what is currently stored in them.
You can add a command argument to a Button to call a function, that should do in this your case.
Check out the code below to understand what I just explained above
import tkinter as tk
def name_label_manager(event=None):
name = name_entry_variable.get()
label_name = tk.Label(root, text="Name: "+name)
label_name.grid(row=10, column=1)
#label_name.delete(0, "end")
description_label_manager()
def description_label_manager(event=None):
description1 = description_entry_variable.get()
descrpt = tk.Label(root, text="Description: "+description1)
descrpt.grid(row=9, column=1)
#descrpt.delete(0, "end")
root=tk.Tk()
name_entry_variable=tk.StringVar()
description_entry_variable=tk.StringVar()
name_entry=tk.Entry(root,textvariable=name_entry_variable,width=10)
name_entry.grid(row=2, column=8)
description_entry=tk.Entry(root,textvariable=description_entry_variable,width=10)
description_entry.grid(row=3, column=8)
button_get = tk.Button(root, text="Submit", command=name_label_manager)
#button_get.bind("<Button-1>", description_label_manager,name_label_manager) command argument of Button should do
button_get.grid(row=4, column=8)
root.mainloop()

Python Tkinter GUI messy printing format

import pandas as pd
import csv
from tkinter import *
master = Tk()
textBox = Text(master, height=1, width=10)
textBox.grid(row=0, column=1)
fileVar = StringVar()
fileLabel = Label(master, textvariable=fileVar)
fileLabel.grid(row=3, column=1)
fileVar2 = StringVar()
fileLabel2 = Label(master, textvariable=fileVar)
fileLabel2.grid(row=3, column=2)
def retrieve_input():
Customer = textBox.get("1.0","end-1c")
fileread = pd.read_csv('50.csv', encoding='latin-1')
filevalue = fileread.loc[fileread['Customer'].str.contains(Customer, na=False),"Jul-18\nQty"]
productheader = fileread.loc[fileread['Customer'].str.contains(Customer, na=False), 'Product']
fileVar.set(productheader)
fileVar2.set(filevalue)
button1 = Button(master,text="Show Values", command=lambda: retrieve_input())
button1.grid(row=4, column=1)
mainloop()
I have this program that prints values in Tkinter Gui, for specific values in a specific row. However the format of the values being printed is quiet messy and I am unsure how to clean it up, In addition I would like for it to not display the numbers labeled next to it, Just the product name (blurred out in blue) and the value associated with it( which are the number values with decimals).
Here is a snapshot of the GUI:
In addition, at the very bottom of the list, this is also displayed:
Ideally, I would like for it to only show the header(July-18) and not the datatype
Also if it helps to know, these are forecast files, (reason for headers with dates)
Here is a dummy image of what my csv files look like:
Ok so after some testing I think I have found a fix that should work for you.
The main issue with spacing inside of your label is the problem with your font not being one that is considered monospace.
Try using the font Consolas and see how well that fixes your layout.
import pandas as pd
from tkinter import *
master = Tk()
textBox = Text(master, height=1, width=10, font=('Consolas', 12))
textBox.grid(row=0, column=1)
fileVar = StringVar()
fileLabel = Label(master, textvariable=fileVar, font=('Consolas', 12))
fileLabel.grid(row=3, column=1)
def retrieve_input():
department = textBox.get("1.0","end-1c")
fileread = pd.read_csv('50.csv', encoding='latin-1')
filevalue = fileread.loc[fileread['Customer'].str.contains(department, na=False),("Jul-18\nQty", "Product")]
fileVar.set(filevalue)
button1 = Button(master,text="Show Values", command=lambda: retrieve_input())
button1.grid(row=4, column=1)
master.mainloop()

OS.rename() not working with tkinter

Folks I'm trying to make a tool which gets user path and file name in one entry and new file name with path in another entry, My aim is to use os.rename(oldname, newname) to rename the given file, but its throwing me some error.
My code
from tkinter import *
import os
def Rename_Function(*args):
os.rename(oldname2,newname)
oldname.set(oldname)#"Renamed Successfully !!! ")
root = Tk()
root.title("MyPython App")
root.geometry("250x250+100+50")
oldname = StringVar()
oldname2= StringVar()
newname= StringVar()
Title1 = Label(root,text="FileName (with path):")
Title1.grid(row=0, column=0)
Oldfilename = Entry(root, textvariable=oldname2)
Oldfilename.grid(row=0, column=1)
Title2 = Label(root, text="New Filename:")
Title2.grid(row=1, column=0)
Newfilename = Entry(root, textvariable=newname)
Newfilename.grid(row=1, column=1)
RenameButton = Button(root, text="RENAME MY FILE", command=Rename_Function)
RenameButton.grid(row=3,columnspan=2, sticky="NWES")
FinalOutput = Label(textvariable=oldname)
FinalOutput.grid(row=4, columnspan=2, sticky = "NWES")
root.mainloop()
I'm getting the above error when I click the button,
Can someone guide me how to make it work.
I have a doubt that os.rename() function should be accessed in some other way since its another module's function. Since I'm learner I don't have any clue how to use them effeciently. Please guide me and explain me so that I would understand this concept better.
To expand upon what #SuperSaiyan said in the comment(s).
You are using a StringVar, which has the method .get() available to it. When you pass the variable which is set to this stringvar you are just passing the reference to this object. You need to actually use the .get() method to get the string.
e.g. - oldname2.get()
Also, for selecting the path you could just use a filedialog, and use os.path.splitext to get the base path + entry in the renaming widget to use as the second parameter with os.rename
You are using StringVar, whereas rename needs Strings. Use oldname.get():
import tkinter as tk
import os
def rename(oldname, oldname2, newname):
os.rename(oldname2.get(),newname.get())
oldname.set("Renamed Successfully !!! ")
def main():
root = tk.Tk()
root.title("MyPython App")
root.geometry("250x250+100+50")
oldname = tk.StringVar()
oldname2= tk.StringVar()
newname= tk.StringVar()
tk.Label(root, text="FileName (with path):").grid(row=0, column=0)
tk.Entry(root, textvariable=oldname2).grid(row=0, column=1)
tk.Label(root, text="New Filename:").grid(row=1, column=0)
tk.Entry(root, textvariable=newname).grid(row=1, column=1)
tk.Button(root, text="RENAME MY FILE", command=lambda: rename(oldname, oldname2, newname)).grid(row=3,columnspan=2, sticky="NWES")
tk.Label(textvariable=oldname).grid(row=4, columnspan=2, sticky = "NWES")
root.mainloop()
if __name__ == '__main__':
main()

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