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Django: Page not found but path is shown

I have recently started using Django and I am a little lost as to why my services.html page does not render as I have followed what appears to be the same steps I took for my home page to work but I keep getting the error that nothing matches the current path. Below are my snippets for views and urls.py. I also had it be included in my website urls.py by using path('', include('affiliate.urls')),
Using the URLconf defined in website.urls, Django tried these URL patterns, in this order:
admin/
[name='home']
[name='services']
The current path, services.html, didn't match any of these.
Urls.py
from django.urls import path
from . import views
urlpatterns = [
path('', views.home, name="home"),
path('', views.services, name="services"),
]
Views.py
from django.shortcuts import render
# Create your views here.
def home(request):
return render(request, 'home.html', {})
def services(request):
return render(request, 'services.html', {})

Change your urlpatterns as follows:
urlpatterns = [
path('', views.home, name="home"),
path('services/', views.services, name="services"),
]
Now when you want to access the services view, make sure to use 127.0.0.1:8000/services
because both of your paths for home and services are pointing to the same url.
Willem is trying to explain you the same thing.

Django Url Pattern Not Being Found

I followed a tutorial to allow users to register an account but the url path does not seem to be found. It allows me to access 127.0.0.1:8000/accounts/signup but not 127.0.0.1:8000/signup when I have set the name for it.
I tried changing the urlpatterns from a path to a url method but that didn't solve the problem.
my file structure is as follows:
App:
accounts:
urls.py
views.py
...
Server:
settings.py
urls.py
...
templates:
registration:
login.html
base.html
home.html
signup.html
manage.py
In my Server\urls.py I have
from django.contrib import admin
from django.urls import path, include
from django.views.generic.base import TemplateView
urlpatterns = [
path('admin/', admin.site.urls),
path('accounts/', include('accounts.urls')),
path('accounts/', include('django.contrib.auth.urls')),
path('', TemplateView.as_view(template_name='home.html'), name='home'),
]
In my accounts\urls.py I have
from django.urls import path
from . import views
urlpatterns = [
path('signup/', views.SignUp.as_view(), name='signup'),
]
The error I get is
Using the URLconf defined in Server.urls, Django tried these URL patterns, in this order:
admin/
accounts/
accounts/
[name='home']
The current path, signup, didn't match any of these.
I'm not too sure what is going on since I'm still sort of new to Django and busy learning as I go along.

path('accounts/', include('accounts.urls')),
means that all urls from accounts.urls are supposed to be prefixed with accounts/.
If that's not what you want - edit this to
path('/', include('accounts.urls')),
and accounts.urls will be treated as top-level urls.

Django Include() in urls.py with two apps

I believe this is a simple question but I am having a hard time figuring out why this is not working.
I have a django project and I've added a second app (sales). Prior to the second app, my urls.py simply routed everything to the first app (chart) with the following:
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('chart.urls')),
]
and it worked fine.
I have read the docs over and over a looked at many tutorials, so my impression is that I can simply amend the urls.py to include:
urlpatterns = [
path('admin/', admin.site.urls),
path('sales/', include('sales.urls')),
path('', include('chart.urls')),
]
and it should first look for a url with sales/ and if it finds that then it should route it to sales.urls, and if it doesn't find that then move on and route it to chart.urls. However, when I load this and type in 127.0.0.1:8000/sales, it returns the following error:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/sales/
Raised by: chart.views.index
which tells me that it is not routing my sales/ url to sales.urls but to chart.urls. When I change path('', include('chart.urls')), to path('', include('sales.urls')), it does route it to sales.urls so I know that my sales.urls file is set up correctly.
I know this is probably an easy question but I cannot figure it out with anything I've read. Any help is appreciated.
chart.urls:
from django.urls import path, re_path
from . import views
urlpatterns = [
path('dashboard/', views.chart, name='dashboard'),
path('', views.index, name='index', kwargs={'pagename': ''}),
path('<str:pagename>/', views.index, name='index'),
]
sales.urls:
from django.urls import path
from . import views
urlpatterns = [
path('sales/', views.sales, name='Sales Dashboard'),
]

I think the correct url for the sales page in your case would be http://127.0.0.1:8000/sales/sales/.
This is because sales/ is then looking in the included sales.urls and not finding any urls at the root / (the only url included there is at sales/ (within sales/) so will be sales/sales/
Reply to an OLD question but may be useful for others...

from django.urls import path, include
dont for get to import include

Do this:
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('chart.urls')),
url(r'^sales/', include('sales.urls')),
]
you are not doing it properly since you are not telling your app where go once it is loaded .this r'^' to go directly to chart.url url(r'^', include('chart.urls')),

Having issues with Django URL mapping

I am trying Django for an upcoming project and going through a tutorial and running into issue with defining URL paths. Below is the project structure showing the urls.py at the project root.
The urls.py in my timer package is pretty simple:
from django.urls import path
from . import views
urlpatterns = [
path('', views.index, name='index'),
]
However when I launch the application and navigate to localhost:8080/timer/ I am getting a 404. Any suggestions what I should be looking at?

You can try to change URLs in the settings of the whole project like this:
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^timer/$', include('timer.urls')),
]
As for the timer, the URLs will be like this:
urlpatterns = [
url(r'^$', views.index, name="index"),
]
Don't forget about r's in the url().

It turns out that I created the urls.py under a wrong folder. I misunderstood the instructions and created the urls.py in the same folder as manage.py. Once I add the new url pattern in the file projectdb/projectgb/urls.py, the issue is fixed. Thanks.

Django "homepage" app urls.py issue

I am pretty new to Django and when I laid my site out I did it in the following way:
The project is a "portal" of sorts,
App 1 "home" is the app that houses the homepage, login, registration
and other "site-wide" functionality
App 2 "inventory" is a basic asset inventory
App 3 "dashboard" is a set of status dashboards based on assets in the inventory
Right now I am trying to add the login functionality and I have a main project urls.py that looks like this:
File: /portal/urls.py
from django.conf import settings
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^$', include('home.urls'), name='home'),
url(r'^admin/', include(admin.site.urls), name='admin'),
url(r'^inventory/', include('inventory.urls'), name='inventory'),
url(r'^dashboard/', include('dashboard.urls'), name='dashboard'),
url(r'^capacity/', include('capacity.urls'), name='capacity'),
)
My plan is to use the inclusion of .../home/urls.py to manage any site-wide functionality such as logging in, registering, etc.
Right now the home index view shows just fine, but anything else in .../home/urls.py gives me a 404
File: /home/urls.py
from django.conf.urls import patterns, url
from home import views
urlpatterns = patterns('',
url(r'^test/$', views.index, name='home_test'),
url(r'^ajax_login/$', views.ajax_login, name='ajax_login'),
url(r'^$', views.index, name='home_index'),
)
At this point I suppose my question is two-fold: Am I approaching this correctly? If so, how can I get the desired functionality? If not, how should I change the way things are set up/laid out to do it the correct "best practices" way?
Thanks in advance!
EDIT
Got it working thanks to dt0xff and holdenweb, accepted holdenweb's answer since it was more accurate including the need to put the home url inclusion below the rest.
Here is my new portal/urls.py file for reference
File: /portal/urls.py
from django.conf import settings
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls), name='admin'),
url(r'^inventory/', include('inventory.urls'), name='inventory'),
url(r'^dashboard/', include('dashboard.urls'), name='dashboard'),
url(r'^capacity/', include('capacity.urls'), name='capacity'),
url(r'^', include('home.urls'), name='home'),
)

The issue is with your first pattern, which will only match the empty URL. So any empty URL will cause the home/urls.py URLs to be analyzed, but only the empty one will match even in that.
Unfortunately if there is no common prefix then that pattern "^" will match every URL (since they all start at the beginning ...).
So you should either use a common prefix for all the pages, or put the home URL specification at the end to give the other URLs a chance to match before it is tested.

Django looks in urls like this:
Get list of root urls - portal/urls
Find first, which matches to current url
If it is include, go to included urls, cutting off matched part
Your problem is here
url(r'^$', include('home.urls'), name='home'),
I mean, here
'^$'
You want url to match "start and then end of url". It works good with root(dunno.com/), but not with others, because url will contain something more...
So, just remove $ and you are fine
url(r'^', include('home.urls'), name='home'),

you never need to add regex($) at project/urls.py