I've been tinkering with the os module for a few days encountered this error. Can't seem to fix it.
Here is an example:
import os
os.chdir('C:\\Users\\User\\Desktop')
os.rename('odin', 'ddin')
print (os.listdir())
And this is the error:
PermissionError: [WinError 5] Access is denied: 'odin' -> 'ddin'
Any help?
you are running your python program from an user that does not have permissions to change the specific file name ' try running from another user or change the file permissions to allow writing to your user.
First, try running the same program in IDLE with administrator privileges.
Second, There is chance that your anti-virus software is blocking your python script so try disabling antivirus.
Related
Been trying to get this working all day, and i just can't figure out why its not working.
Trying to implement a simple trigger to run when the user submitted a file.
example in the .tmp file:
hello_trigger change-submit //testDepot/... "python F:/triggers/hello_trigger.py"
when i try to submit a file i get this:
Submit validation failed -- fix problems then use 'p4 submit -c 10199'.
'hello_trigger' validation failed: python: can't open file 'F:/triggers/hello_trigger.py': [Errno 2] No such file or directory
File exists and can be read, so its not a python issue.. same error with a .txt or .bat file.
From what i can gather the problem seems to be coming from the depot line in the trigger.
//testDepot/... fails
//depot/... doesnt fail, but the script is never fired off.
Any suggestions are greatly appreciated.
also testDepot is a stream not sure if that matters.
python: can't open file 'F:/triggers/hello_trigger.py': [Errno 2] No such file or directory
seems pretty clear that the file doesn't exist, at least from the point of view of this trigger command. Some things to double check:
This is running on the server machine, i.e. the place where the p4d service is running. If you have the script on your client machine the Python executable on the server isn't going to be able to find it!
Similarly, this is being run by whatever user is running p4d (on Windows this is usually the SYSTEM user, which may have limited permissions). Does that user have permission to read this path?
Could it be that your version of Python on Windows doesn't know how to handle paths with Unix-style forward slashes? (Many tools will normalize these for you but you shouldn't depend on it!) Try using a valid Windows path, i.e. F:\triggers\hello_trigger.py.
I am trying to run a python code that performs XGboosting and I wanted it to run parallely to take less time in building a model. But I am facing this issue while running a code.
PermissionError: [WinError 32] The process cannot access the file because it is being used by another process: 'C:\\Users\\<<username>>\\AppData\\Local\\Temp\\joblib_memmapping_folder_85680_9566857635\\85680-1746225537432-968de5958f0642829c37f0f09f0e8b00.pkl'
I have even tried running the anaconda prompt as an administrator. But it is of no use. As a workaround I have also tried what is suggested in https://github.com/joblib/joblib/issues/806 but even then I am facing the same issue.
Could you please advice?
I tried to write a windows service using python, reference from http://www.chrisumbel.com/article/windows_services_in_python.
In SvcDoRun(), when I tried to use subprocess.check_output(), I get a exception, 'WindowsError: [Error 6] The handle is invalid'.
Is there a way to overcome this issue.
I have an existing file I want to remove, and I get the following error when trying to remove it:
os.remove(input_path)
OSError: [Errno 13] Permission denied:
Is there any way to remove a file that already exists, other than doing:
subprocess.call(['rm', input_path])
Since you're getting a "permission denied" error, it is clear there's a "mismatch" between the permissions of the file (or its parent directory), and those of the user running the python process.
The best practice, instead of looking for "shortcuts" in the form of sudo, is to fix the permissions, either of the file being deleted, or the user running the python process.
Permissions are used for a reason. You're risking getting into troubles if you choose to void/bypass them by using tricks such as sudo.
In a Unix system, within a python script, I am trying to open a terminal window and start a server. It is my understanding that python has a subprocess module that is supposed to allow such a thing. So:
import subprocess
subprocess.Popen(['path to terminal'])
returns:
OSError: [Errno 13] Permission denied
How do I run this with the right permissions? Or, is there a better, secure way to do what I need?
I'm relatively new to programming, so please reorient the discussion if my question is misguided. Thank you!
Edit: you state that you would like to execute /Applications/Utilities/Terminal.app, so you are apparently running Mac OS X.
Mac OS X .app programs are directories. They can be started with the Mac OS shell command open.
To open the program /path/to/server in a fresh Max OS Terminal session:
import subprocess
termapp=['open','-a','/Applications/Utilities/Terminal.app']
sp=subprocess.Popen(termapp+['/path/to/server'])
There's also a shell-command version of the terminal, so you do not need open -a.
import subprocess
termapp=['/Applications/Utilities/Terminal.app/Contents/MacOS/Terminal']
sp=subprocess.Popen(termapp+['/path/to/server'])
The two ways have subtle differences in how the windows are grouped by the window manager. Each time you do the above you get another terminal process and another icon in the tray. While with -a a new window is opened within the same Terminal main program.