Develop Reference

Python Json.decoder.JSONDecodeError: Expecting ',' delimiter:

I'm trying to load a dictionary into json but I'm getting error.
strsdc = '''
{"ext":{"amznregion":["useast"],"someURL":"https://som_url.com/x/px/Iyntynt/{"c":"client","als2s":TIME}","id":"7788y"}}
'''
json.loads(strsdc)
gives me the following error:
Traceback (most recent call last):
File "main.py", line 187, in
lol = json.loads(str(strsdc))
File "/nix/store/p21fdyxqb3yqflpim7g8s1mymgpnqiv7-python3-3.8.12/lib/python3.8/json/init.py", line 357, in loads
return _default_decoder.decode(s)
File "/nix/store/p21fdyxqb3yqflpim7g8s1mymgpnqiv7-python3-3.8.12/lib/python3.8/json/decoder.py", line 337, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "/nix/store/p21fdyxqb3yqflpim7g8s1mymgpnqiv7-python3-3.8.12/lib/python3.8/json/decoder.py", line 353, in raw_decode
obj, end = self.scan_once(s, idx)
json.decoder.JSONDecodeError: Expecting ',' delimiter: line 2 column 79 (char 79)

Your json string is invalid.
I don't know if this is the way you want it but you can try using this string
{"ext":{"amznregion":["useast"],"someURL":"https://som_url.com/x/px/Iyntynt/{\"c\":\"client\",\"als2s\":TIME}","id":"7788y"}}

json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0) while opening json file

i am trying to create blog page using flask and i want to take input file as a config.json which i have created. Please help me i am getting json decoder error
i also tried to convert str to utf8 but its showing the error
with open('config.json', 'r', encoding ='utf-8') as c:
params = json.load(c)["params"]
json content:
{
"params":
{
"local_server":"True",
"local_uri":"mysql://root:#localhost/codingthunder",
"prod_uri":"mysql://root:#localhost/codingthunder",
"fb_url":"https://facebook.com/codingthunder",
"tw_url":"https://twitter.com/codingthunder",
"gh_url":"https://github.com/codingthunder",
"blog_name":"Coding Thunder",
"tag_line":"A Blog liked by Programmers"
}
}
output log:
PS C:\Users\ASHISH\Desktop\Coding\Flask> python -u "c:\Users\ASHISH\Desktop\Coding\Flask\Blog Page\main.py"
Traceback (most recent call last):
File "c:\Users\ASHISH\Desktop\Coding\Flask\Blog Page\main.py", line 7, in <module>
params = json.load(c)["params"]
File "C:\Users\ASHISH\AppData\Local\Programs\Python\Python37\lib\json\__init__.py", line 296, in load
parse_constant=parse_constant, object_pairs_hook=object_pairs_hook, **kw)
File "C:\Users\ASHISH\AppData\Local\Programs\Python\Python37\lib\json\__init__.py", line 348, in loads
return _default_decoder.decode(s)
File "C:\Users\ASHISH\AppData\Local\Programs\Python\Python37\lib\json\decoder.py", line 337, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "C:\Users\ASHISH\AppData\Local\Programs\Python\Python37\lib\json\decoder.py", line 355, in raw_decode
raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

Expecting value: line 1 column 1 (char 0) hints that there is no value at the beginning of the file, so no content in the parsed file.
This could mean, that
the file is empty
you opened the wrong or a non existing file
you are using a relative path and your working direktory is wrong (e.g. the direktory you execute your program in)

Python json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0) with Spaces in path name

I am uploading a file to a REST API with a Python 3 script via the windows command line. The filename is an argument passed in to the script. Everything works fine unless there is a space in the path name. i.e. c:\temp\myFolder\1.jpg works, but c:\temp\my Folder\1.jpg throws an error:
raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)
The code up until the error is as follows:
def upload_photo(filename):
f = open(filename, "rb")
data = f.read()
data_md5 = hashlib.md5(data).hexdigest()
f.close()
r = requests.put('https://upload.mysite.com/{}'.format(filename), data=data)
response = json.loads(r.text)
I'm not sure how to fix it. Thanks for the help.
--Edit--
Full traceback
c:\>python test.py "c:/temp/my folder/1.jpg"
Traceback (most recent call last):
File "test.py", line 144, in <module>
print(test(sys.argv[1]))
File "test.py", line 132, in upload_photo
response = json.loads(r.text)
File "C:\Users\Default\AppData\Local\Programs\Python\Python37-32\lib\json\__init__.py", line 348, in loads
return _default_decoder.decode(s)
File "C:\Users\Default\AppData\Local\Programs\Python\Python37-32\lib\json\decoder.py", line 337, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "C:\Users\Default\Default\Local\Programs\Python\Python37-32\lib\json\decoder.py", line 355, in raw_decode
raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

You need to encode the link properly; escaping the invalid character(s). You can do that with urllib.
>>> import urllib
>>> filename = urllib.parse.quote('c:\temp\my Folder\1.jpg')
>>> 'https://upload.mysite.com/' + filename
'https://upload.mysite.com/c%3A%09emp%5Cmy%20Folder%01.jpg'

reading a json file in python

hi I want to read a JSON file in python and any kind of syntax that i use i receive an error and i don't know what to do the code :
import urllib
import pprint
import json
import re
import requests
import pprint
with open('synsets.json' , encoding = 'utf-8') as json_data:
d = json.loads(json_data.read())
json_data.close()
pprint(d)
the error :
Traceback (most recent call last):
File "D:\markaz\wikiomega\code1.py", line 13, in <module>
d = json.loads(json_data.read())
File "C:\Users\BehnaM1\AppData\Local\Programs\Python\Python35-32\lib\json\__init__.py", line 319, in loads
return _default_decoder.decode(s)
File "C:\Users\BehnaM1\AppData\Local\Programs\Python\Python35-32\lib\json\decoder.py", line 339, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "C:\Users\BehnaM1\AppData\Local\Programs\Python\Python35-32\lib\json\decoder.py", line 357, in raw_decode
raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)
[Finished in 0.7s with exit code 1]

How to convert this json string to dict?

After executing the following code:
import json
a = '{"excludeTypes":"*.exe;~\\$*.*"}'
json.loads(a)
I get:
Traceback (most recent call last):
File "", line 1, in
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/init.py", line 338, in loads
return _default_decoder.decode(s)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 365, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 381, in raw_decode
obj, end = self.scan_once(s, idx)
ValueError: Expecting property name: line 1 column 2 (char 1)
So how can I convert 'a' to dict.
Please note that the string is already in 'a' and I cannot add 'r' in front of it. Ideally, the string should have been {"excludeTypes":"*.exe;~\\\\$*.*"}
Also, the following code doesn't work:
import json
a = '{"excludeTypes":"*.exe;~\\$*.*"}'
b = repr(a)
json.loads(b)

import ast
d = ast.literal_eval(a)

By escaping Escape Character "\":
import json
a = '{"excludeTypes":"*.exe;~\\$*.*"}'
a = a.replace("\\","\\\\")
json.loads(a)