python running python2 instead of python3 on windows - python

Well I have this code:
#!/usr/bin/env python3
for i in range(15):
print(i, end=' ')
when I run it like this in command prompt:
prog1.py
I get:
C:\Users\Ja\Desktop>prog1.py
File "C:\Users\Ja\Desktop\prog1.py", line 4
print(i, end=' ')
^
SyntaxError: invalid syntax
but when I run it like this:
py prog1.py
it works fine. It's running python2.7.15 instead of python3.6.5 (I tested it using sys.version).
( It's the same for icon clicks )

You may be under the impression that Windows understands the "shebang line":
#!/usr/bin/env python3
It does not. All Windows knows is that .py files can be run by Python. So you need to update your file association, or run the correct version of Python explicitly, passing the path to your script as an argument.

Related

Newbie issue with python, script works fine on other os

I am using a bot with python to create accounts on a website. When I use it on my windows machine with python installed, it works fine. I bought a linux VPS yesterday (Ubuntu 16.04) and my script apparently isn't working anymore. This is the error I get on my linux machine:
Traceback (most recent call last):
File "roblox.py", line 2, in <module>
from utils import *
File "/home/py/newbot/utils.py", line 18
key, *values = line.split(" ")
^
SyntaxError: invalid syntax
The line in the script its referring to is this
def string_to_dict(headers):
headers_dict = {}
for line in headers.split("\n"):
if not line: continue
line = line.strip()
key, *values = line.split(" ")
key = key[:-1]
if not (key and values): continue
headers_dict[key] = " ".join(values)
return headers_dict
Any ideas what could have gone wrong?
This syntax is invalid in python 2. Run your script with python3.
As mentioned in other answers, you need to run this in Python3. The shortest answer is:
Install python3, which may not already be on your machine: $ sudo apt-get update; sudo apt-get install python3
Get in the habit of using a shebang in your script files. Add #!/usr/bin/env python3 to the first line of your script to direct the shell to invoke python3 instead of python2 -- most systems come with /usr/bin/python aliased to python2 installations.
You can find out more about sourcing files in the Bash shell (default shell for Ubuntu 16.04) here.
The longer answer -- if you're wondering why the code doesn't work in Python2 but does work in Python3 -- is that Python3 introduced extended iterable unpacking in PEP 3132, but this feature was not implemented in Python2.

How can I execute commands through python in terminal MAC?

When I manually run this command in Terminal, it executes, but through Python it gives the error that the directory is not available in Python packages.
I am using the following command
source ~/trytry/shell.sh
This is my test shell file:
#!/bin/sh
echo hello
when I executed " source ~/test.sh ", it will print hello at console.
This is my python code:
>>> import commands
>>> commands.getstatusoutput("source ~/test.sh")
(0, 'hello')
It works without any problem. So, would you please show your code?
What it looks like to me is that you have a shell script, and not a python file which would have the .py extension instead of .sh. The error may have to do with the fact that it isn't a python file you're trying to run.

Standard input inconsistency between command line and subprocess.call

I would like to create a file that will be used as standard input for a python script, and invoke said script with subprocess.call.
When I do it directly in the command line it works fine:
The input file:
# test_input
1/2/3
The python script
# script.py
thisDate = input('Please enter date: ').rstrip()
The following command works just fine:
python script.py < test_input
But when I try to do the following from within another python script, it doesn't work. (from this)
outfile1 = open('test_input', 'w')
outfile1.write('1/2/3')
outfile1.close()
input1 = open('test_input')
subprocess.call(['python', 'script.py'], stdin=input1)
But then I get the following error:
>>>thisDate = input('Please enter date: ').rstrip()
>>>AttributeError: 'int' object has no attribute 'rstrip'
When I did some debugging, it seems that it is getting the integer 0 as the input.
What is causing the inconsistency here? Are the two methods not equivalent (evidently they are not, but why)? My ultimate goal is to perform the exact same task as the above command line version that worked.
Thank you
You are using input when it should be raw_input, input in python2 will eval the string. If you run the script with python3 it will work as is, for python2 change to raw_input.
Using check_call is usually a better approach and using with to open your files.
import subprocess
with open('test_input') as input1:
subprocess.check_call(['python3', 'script.py'], stdin=input1)
So chepner was correct. When I amended the following line:
subprocess.call(['python', 'script.py'], stdin=input1)
to:
subprocess.call(['python3', 'script.py'], stdin=input1)
it worked just fine.
(I am trying to do this in python3)
In the first instance, the file has two lines, and input() reads and parses the first line, which is a comment.
In the second case, the comment line is missing, so Python reads and parses a number.
You probably meant to use raw_input(), or run the script with Python 3.
(You probably also meant for the input file to end with a newline, and it doesn't really make sense to use subprocess.call() to run Python when you are already running Python.)
python script.py < test_input command should fail. You might mean: python3 script.py < test_input instead due to the difference between input() vs raw_input() on Python 2 as mentioned in other answers. python as a rule refers to Python 2 version.
if the parent script is run only using python3 then you could use sys.executable to run the child script using the same python version (the same executable):
#!/usr/bin/env python3
import subprocess
import sys
with open('test_input', 'rb', 0) as input_file:
subprocess.check_call([sys.executable or 'python3', 'script.py'],
stdin=input_file)
If the parent and the child may use different python versions then set the correct shebang in script.py e.g., #!/usr/bin/env python3 and run the script directly:
#!/usr/bin/env python
import subprocess
with open('test_input', 'rb', 0) as input_file:
subprocess.check_call(['./script.py'], stdin=input_file)
Here, the child script may choose its own python version. Make sure the script has executable permissions: chmod +x script.py. Note: Python Launcher for Windows understands the shebang syntax too.
Unrelated: use .communicate() instead of outfile1.write('1/2/3'):
#!/usr/bin/env python3
from subprocess import Popen, PIPE
with Popen(['./script.py'], stdin=PIPE, universal_newlines=True) as p:
p.communicate('1/2/3')

install error or error running python file

I am running a basic Python file on Windows XP from IDLE.
The file name is assignment1.py.
The file content is:
import sys
var = 5
but when I run it, it gives the error:
Command: python assignment1.py
SyntaxError: invalid syntax
Then I tried another thing which also gave an error:
Command: which python
SyntaxError: invalid syntax
Not sure if the installation is wrong or something.
I am able to run the print command successfully:
>>> print "I am working fine"
I am working fine
Not sure of the issue. Request help.
It looks like what you are entering as the "command" is being interpreted as Python code. I mean, python assignment1.py is interpreted as Python code. The result is as expected:
$ python -c 'python assignment1.py'
File "<string>", line 1
python assignment1.py
^
SyntaxError: invalid syntax
You need to run the file in the correct way, probably via the IDLE menu or by pressing F5. You can check these questions for details:
How do I run a Python program?
Running Python script from IDLE on Windows 7 64 bit

Python+ubuntu error

Am trying to run the following python program
import re
regex=re.compile("http...imgs.xkcd.com.comics.[\\S]*.[jpg|png]")
f=open('out.txt')
for a in f:
print regex.findall(a)
print '\n'
when I type the code into the interpreter manually, it works as expected
but when i save it as a file and try to run it , it gives errors.
The command i used to run it is
chmod +x
sudo ./pymod.py
ERROR:
./pymod.py: 2: Syntax error: "(" unexpected
if i dont use sudo, the error i get is
./pymod.py: line 2: syntax error near unexpected token `('
./pymod.py: line 2: `regex=re.compile("http...imgs.xkcd.com.comics.[\\S]*.[jpg|png]")'
am using ubuntu 10.04 with everything on default
it takes about 10-15 seconds for the error to appear
Your file should start with shebang. You should include the path to the python interpreter
#!/usr/bin/env python
import re
regex=re.compile("http...imgs.xkcd.com.comics.[\\S]*.[jpg|png]")
Check out : http://en.wikipedia.org/wiki/Shebang_(Unix)
This is probably executing as a bash script instead of in Python. Put
#!/usr/bin/env python
at the beginning of your script.
When you set something as executable, you have to specify what you want it to run it with, or Linux will consider it to be a bash script.
Add this as the first line of the file:
#!/usr/bin/python
Or run it like:
python pymod.py
Cheers!
Either use the "shebang". I.e. put
#! /usr/bin/python
as the first line of your script.
Or teach your ubuntu how to treat python scripts without it
as described here: http://www.daniweb.com/code/snippet241988.html

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