Imagine the following simple example:
def doNothing():
sleep(0.5)
barVar.set(10)
sleep(0.5)
barVar.set(20)
sleep(0.5)
barVar.set(30)
mainWindow = Tk()
barVar = DoubleVar()
barVar.set(0)
bar = Progressbar(mainWindow, length=200, style='black.Horizontal.TProgressbar', variable=barVar, mode='determinate')
bar.grid(row=1, column=0)
button= Button(mainWindow, text='Click', command=doNothing)
button.grid(row=0, column=0)
mainWindow.mainloop()
What I get when I run this, the progressbar is already at 30% when clicking the button, no progress in front of me. Like attached:
What I need: I can see the progress in front of me (not hanging then suddenly 30%)
Update:
I upadted the code according to #Bernhard answer, but still I can not see the progress in front of me. Just a sudden jump of 30% after waiting 1.5 sec
Seocnd Update:
I'm only using sleep here as a simulation for a process that takes time, like connecting over ssh and grabing some info.
Do not use sleep() in tkinter. The entire reason for you problem is sleep() will freeze tkinter until it is done with its count so what you are seeing is a frozen program and when the program is finally released its already set to 30 percent on the next mainloop update.
Instead we need to use Tkinter's built in method called after() as after is specifically for this purpose.
import tkinter as tk
import tkinter.ttk as ttk
mainWindow = tk.Tk()
def update_progress_bar():
x = barVar.get()
if x < 100:
barVar.set(x+10)
mainWindow.after(500, update_progress_bar)
else:
print("Complete")
barVar = tk.DoubleVar()
barVar.set(0)
bar = ttk.Progressbar(mainWindow, length=200, style='black.Horizontal.TProgressbar', variable=barVar, mode='determinate')
bar.grid(row=1, column=0)
button= tk.Button(mainWindow, text='Click', command=update_progress_bar)
button.grid(row=0, column=0)
mainWindow.mainloop()
If you want the bar to appear to move smoothly you will need to speed up the function call and reduce the addition to the DoubbleVar.
import tkinter as tk
import tkinter.ttk as ttk
mainWindow = tk.Tk()
def update_progress_bar():
x = barVar.get()
if x < 100:
barVar.set(x+0.5)
mainWindow.after(50, update_progress_bar)
else:
print("Complete")
barVar = tk.DoubleVar()
barVar.set(0)
bar = ttk.Progressbar(mainWindow, length=200, style='black.Horizontal.TProgressbar', variable=barVar, mode='determinate')
bar.grid(row=1, column=0)
button= tk.Button(mainWindow, text='Click', command=update_progress_bar)
button.grid(row=0, column=0)
mainWindow.mainloop()
Because you are calling the function when the buttion is initialized, you need to loose the '(barVar') in the command=(barVar)). This way you bind the function to the button and don't call it when initializing it.
button= Button(mainWindow, text='Click', command=doNothing)
If you need to pass an argument you need to bypass the calling by using lambda:
button= Button(mainWindow, text='Click', command= lambda: doNothing(barVar))
I think I find the solution.
simply add mainWindow.update() after each progress. So the final code would be:
def doNothing():
sleep(0.5)
barVar.set(10)
mainWindow.update()
sleep(0.5)
barVar.set(20)
mainWindow.update()
sleep(0.5)
barVar.set(30)
mainWindow.update()
Related
def click():
button1.configure(bg="gray")
time.sleep(1)
button1.configure(bg="green")
button1 = Button(win, text="Button",bg="green",activebackground="red")
button1.pack()
I tryied to change button to gray for only second than change back to green. But it won't change to gray
You need to bind that event after the packing
from tkinter import *
import time
def click(event):
if button1["background"] == "green":
time.sleep(3)
button1["background"] = "yellow"
else:
button1["background"] = "green"
root = Tk()
myContainer1 = Frame(root)
myContainer1.pack()
button1 = Button(myContainer1, text="Button", bg="green")
button1.pack()
button1.bind("<Button-1>", click) # binding event here
root.mainloop()
btw, solid resource on the subject, a bit dated but as an educational material - written perfectly - short :D
http://thinkingtkinter.sourceforge.net/
You have to do it this way.
If you use the Time library, the software won't work
or you can use the Threading module for multithreading in Python but This method is a bit complicated
from tkinter import *
def click(event):
def loop(i):
if i==1:
button1.configure(bg="gray")
elif i==2:
button1.configure(bg="red")
return
i=i+1
button1.after (1000, lambda : loop (i))
loop (1)
root = Tk()
myContainer1 = Frame(root)
myContainer1.pack()
button1 = Button(myContainer1, text="Button", bg="red")
button1.pack()
button1.bind("<Button-1>", click) # binding event here
root.mainloop()
First click() has never been executed. Second all updates are handled by tkinter mainloop(), so those changes will be handled after the function click() exits and the last change will be seen only.
You can use .after() instead of sleep() to change the color of the button back to green after one second:
def click():
button1.configure(bg="gray")
# change the background color back to green after 1 second
button1.after(1000, lambda: button1.configure(bg="green"))
button1 = Button(win, text="Button", bg="green", activebackground="red", command=click)
button1.pack()
How can I make windows show up one at a time with tkinter? For example, if I typed in 6 as an input, and called a function with a button, I need it to show me 6 windows, but one at a time. It will only prompt me the next window after pressing a button from the previous one.
I tried using a for loop to loop through the range of the input, and create new windows with a button based on that range, but the problem is that they all show up at the same time:
from tkinter import *
from tkinter.ttk import *
root = Tk()
root.title("Multiple windows")
def multiplewindows():
for i in range(int(number.get())):
tempwindow = Toplevel()
tempwindow.title(f"Window {i+1}")
tempbutton = Button(tempwindow, text=f"Button {i+1}")
tempbutton.pack(padx=10, pady=10)
number = Entry(root, width=5)
number.pack(padx=10, pady=10)
button = Button(root, text="Show", command=multiplewindows)
button.pack(padx=10, pady=10)
root.mainloop()
Is there any way to pause the for loop and allow it to continue after pressing the button in the newly created window?
I think you don't need for loop to do this
def multiplewindows():
j=int(number.get())
tempwindow = Toplevel()
tempwindow.title(f"Window {j}")
tempbutton = Button(tempwindow, text=f"Button {j}")
tempbutton.pack(padx=10, pady=10)
And if you want to use for loop to do this
def multiplewindows():
j=int(number.get())
for i in range(int(number.get())):
if (i+1)==j:
tempwindow = Toplevel()
tempwindow.title(f"Window {j}")
tempbutton = Button(tempwindow, text=f"Button {j}")
tempbutton.pack(padx=10, pady=10)
The easiest way to do this is like acw1668 was recommanded with the builtin method of tkinter that is calld with wait_window().
from tkinter import *
from tkinter.ttk import *
root = Tk()
root.title("Multiple windows")
def multiplewindows():
for i in range(int(number.get())):
tempwindow = Toplevel()
tempwindow.title(f"Window {i+1}")
tempbutton = Button(tempwindow, text=f"Button {i+1}", command=tempwindow.destroy)
tempbutton.pack(padx=10, pady=10)
tempwindow.wait_window()
number = Entry(root, width=5)
number.pack(padx=10, pady=10)
button = Button(root, text="Show", command=multiplewindows)
button.pack(padx=10, pady=10)
root.mainloop()
Here we have created a function with a forloop that waits until the window is destroyed and added a command to the Button to destroy the window.
I try to show a status from a called function in real time. However, the messages appears in the GUI all at ones after function is done. What can I do?
Thanks for your help!
from tkinter import *
import time
def sleep():
msgbox.insert(INSERT,"go sleep...\n")
time.sleep(2)
msgbox.insert(INSERT,"... need another 2 sec \n")
time.sleep(2)
msgbox.insert(INSERT,"... that was good\n")
return
root = Tk()
root.minsize(600,400)
button= Button(text="Get sleep", command=sleep)
button.place(x=250, y=100,height=50, width=100)
msgbox =Text(root, height=10, width=60)
msgbox.place(x=20, y=200)
mainloop()
You can use the Tk.update() function to update the window without having to wait for the function to finish:
from tkinter import *
import time
def sleep():
msgbox.insert(INSERT,"go sleep...\n")
root.update()
time.sleep(2)
msgbox.insert(INSERT,"... need another 2 sec \n")
root.update()
time.sleep(2)
msgbox.insert(INSERT,"... that was good\n")
root = Tk()
root.minsize(600,400)
button= Button(text="Get sleep", command=sleep)
button.place(x=250, y=100,height=50, width=100)
msgbox =Text(root, height=10, width=60)
msgbox.place(x=20, y=200)
mainloop()
(also the return is unnecessary, you use it if you want to end a function partway through or return a value from the function).
Let me know if you have any problems :).
I am currently working on a little just for fun project, which pretends it´s generating something and then shows a specific message, but I have a question: As soon as I press the button on the screen it is showing a progressbar, that is what I want it to do, but if I press the button again it just shows the same thing again and again, is there any way to prevent the program from printing the Starting the generate text and the progressbar multiple times?
Here´s the code:
# my little import area
import tkinter as tk
from tkinter import ttk
# Initialization
win = tk.Tk()
win.title("StackOverflow")
# Window Size
win.resizable(False, False)
win.minsize(750,500)
# Button clicked command
def buttonclicked():
tk.Label(win, text="Starting to generate...").pack()
pb.pack()
pb.start(500)
#Widgets
headerlabel = tk.Label(win, text="StackOverFlow Question")
generatebutton = tk.Button(win, text="Generate", command=buttonclicked)
pb = ttk.Progressbar(win, orient="horizontal", length=250, mode="determinate")
#Positioning
headerlabel.pack()
generatebutton.pack()
win.mainloop()
You can put
global generatebutton
generatebutton.config(state='disabled')
in your buttonclicked function (which is stupid because the global keyword is usually SO BAD to use, it turns your code into nightmare), or use OOP to your advantage. You can also use win.destroy() or generatebutton.destroy().
Here is that more OOP-intensive code example:
import tkinter as tk
from tkinter import ttk
class Joke:
def __init__(self):
self.win = tk.Tk()
self.win.title("StackOverflow")
self.win.resizable(False, False)
self.win.minsize(750,500)
headerlabel = tk.Label(self.win, text="StackOverFlow Question")
self.generatebutton = tk.Button(self.win, text="Generate", command=self.buttonclicked)
self.pb = ttk.Progressbar(self.win, orient="horizontal", length=250, mode="determinate")
headerlabel.pack()
self.generatebutton.pack()
self.win.mainloop()
def buttonclicked(self):
tk.Label(self.win, text="Starting to generate...").pack()
self.pb.pack()
self.pb.start(500)
self.generatebutton.config(state='disabled')
Joke()
Hope that's helpful!
from tkinter import *
from random import *
root = Tk()
#A function to create the turn for the current player. The current player isnt in this code as it is not important
def turn():
window = Toplevel()
dice = Button(window, text="Roll the dice!", bg= "white", command=lambda:diceAction(window))
dice.pack()
window.mainloop()
#a function to simulate a dice. It kills the function turn.
def diceAction(window):
result = Toplevel()
y = randint(1, 6)
# i do something with this number
quitButton = Button(result, text="Ok!", bg="white", command=lambda: [result.destroy(), window.destroy()])
quitButton.pack()
window.destroy()
result.mainloop()
#A function to create the playing field and to start the game
def main():
label1 = Button(root, text="hi", bg="black")
label1.pack()
while 1:
turn()
print("Hi")
turn()
main()
root.mainloop()
With this code i basically create a roll the dice simulator. In my actual code i give the function turn() player1/player2(which are class objects) so i can track whose turn it is. Thats why i call turn() 2 times in the while.
The problem is that the code after the first turn() isnt executed(until i manually close the root window which is weird) anymore. At my knowledge this should work.
I open the turn function which opens the diceAction function upon button press. diceAction() gives me the number and kills both windows. Then the second turn() should be called and the process continues until someone wins(which i havent implemented in this code).
The print("Hi") isnt executed either. Am i missing something? You can copy this code and execute it yourself.
The short answer is "Infinite loops and tkinter don't play well together". The long answer is that you never escape window.mainloop(). I don't see a good enough reason that you need to have window.mainloop() and result.mainloop() running to justify the headache of multiple loops in tkinter.
A subjectively better way of doing this is to have the end of the first turn() trigger the start of the next one:
from tkinter import *
from random import *
root = Tk()
global turnCount
turnCount = 0
def turn():
window = Toplevel()
dice = Button(window, text="Roll the dice!", bg="white", command=lambda:diceAction())
dice.pack()
def diceAction():
result = Toplevel()
y = randint(1, 6)
quitButton = Button(result, text="Ok!", bg="white", command=lambda: nextTurn())
quitButton.pack()
def nextTurn():
global turnCount
turnCount = turnCount + 1
for i in root.winfo_children():
if str(type(i)) == "<class 'tkinter.Toplevel'>":
i.destroy()
turn()
def main():
label1 = Button(root, text="hi", bg="black")
label1.pack()
turn()
main()
root.mainloop()
I would recommend attempting to use OOP on a project like this instead of the global that I declared above.