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I have measurements taken from 1st January 1993. They were recorded in second elapsed from that date. I would like to have them in date time.
I know in MatLab the function would be
time = datenum(1993,01,01,00,00, time)
However, I struggle to find an equivalent function in Python.
I have tried:
datetime.fromordinal(time) doesn't work because 'module object has no attribute fromordinal'?
datetime.datetime(time) doesn't work (I have a matrix because there are many scans done)
https://docs.python.org/3/library/datetime.html
You will first have to create a datetime object for Jan 1st 1993 and then add the number of seconds to that date. The code below should help you get started.
from datetime import datetime, timedelta
original_date = datetime.strptime('01-01-1993', '%d-%m-%Y')
original_date + timedelta(seconds= 10000)
output: datetime.datetime(1993, 1, 1, 2, 46, 40)
Let us say you have list of timevalues in seconds starting from 1993-01-01 00:00.
Easiest would be:
datevec=[datetime.datetime(1993,1,1,0)+datetime.timedelta(seconds=val) for val in timevector]
It is like UNIX time, but with a different start.
You can compute the offset once:
>>> import datetime as dt
>>> dt.datetime(1993,1,1).timestamp()
725842800.0
and use it in your program:
OFFSET = 725842800.0
mydate = dt.datetime.fromtimestamp(OFFSET + seconds_from_1993)
I am getting a random datetime between two datetimes with following code
start_date = datetime.datetime(2013, 1, 1, tzinfo=pytz.UTC).toordinal()
end_date = datetime.datetime.now(tz=pytz.utc).toordinal()
return datetime.date.fromordinal(random.randint(start_date, end_date))
The problem is that it is not timezone aware.
I have already tried making it timezone aware by using tzinfo=pytz.UTC as seen in the code above but it doesn't work. I guess datetime.date.fromordinal() makes it a naive datetime format.
If you use datetime.datetime instead of datetime.date in your code then .replace(tzinfo=pytz.utc) works on the result.
To support arbitrary steps (not only 1 day):
#!/usr/bin/env python3
import random
from datetime import datetime, timedelta, timezone
step = timedelta(days=1)
start = datetime(2013, 1, 1, tzinfo=timezone.utc)
end = datetime.now(timezone.utc)
random_date = start + random.randrange((end - start) // step + 1) * step
Note: if start uses a timezone with a non-fixed utc offset then call tz.normalize() at the end.
I am dealing with dates in Python and I need to convert them to UTC timestamps to be used
inside Javascript. The following code does not work:
>>> d = datetime.date(2011,01,01)
>>> datetime.datetime.utcfromtimestamp(time.mktime(d.timetuple()))
datetime.datetime(2010, 12, 31, 23, 0)
Converting the date object first to datetime also does not help. I tried the example at this link from, but:
from pytz import utc, timezone
from datetime import datetime
from time import mktime
input_date = datetime(year=2011, month=1, day=15)
and now either:
mktime(utc.localize(input_date).utctimetuple())
or
mktime(timezone('US/Eastern').localize(input_date).utctimetuple())
does work.
So general question: how can I get a date converted to seconds since epoch according to UTC?
If d = date(2011, 1, 1) is in UTC:
>>> from datetime import datetime, date
>>> import calendar
>>> timestamp1 = calendar.timegm(d.timetuple())
>>> datetime.utcfromtimestamp(timestamp1)
datetime.datetime(2011, 1, 1, 0, 0)
If d is in local timezone:
>>> import time
>>> timestamp2 = time.mktime(d.timetuple()) # DO NOT USE IT WITH UTC DATE
>>> datetime.fromtimestamp(timestamp2)
datetime.datetime(2011, 1, 1, 0, 0)
timestamp1 and timestamp2 may differ if midnight in the local timezone is not the same time instance as midnight in UTC.
mktime() may return a wrong result if d corresponds to an ambiguous local time (e.g., during DST transition) or if d is a past(future) date when the utc offset might have been different and the C mktime() has no access to the tz database on the given platform. You could use pytz module (e.g., via tzlocal.get_localzone()) to get access to the tz database on all platforms. Also, utcfromtimestamp() may fail and mktime() may return non-POSIX timestamp if "right" timezone is used.
To convert datetime.date object that represents date in UTC without calendar.timegm():
DAY = 24*60*60 # POSIX day in seconds (exact value)
timestamp = (utc_date.toordinal() - date(1970, 1, 1).toordinal()) * DAY
timestamp = (utc_date - date(1970, 1, 1)).days * DAY
How can I get a date converted to seconds since epoch according to UTC?
To convert datetime.datetime (not datetime.date) object that already represents time in UTC to the corresponding POSIX timestamp (a float).
Python 3.3+
datetime.timestamp():
from datetime import timezone
timestamp = dt.replace(tzinfo=timezone.utc).timestamp()
Note: It is necessary to supply timezone.utc explicitly otherwise .timestamp() assume that your naive datetime object is in local timezone.
Python 3 (< 3.3)
From the docs for datetime.utcfromtimestamp():
There is no method to obtain the timestamp from a datetime instance,
but POSIX timestamp corresponding to a datetime instance dt can be
easily calculated as follows. For a naive dt:
timestamp = (dt - datetime(1970, 1, 1)) / timedelta(seconds=1)
And for an aware dt:
timestamp = (dt - datetime(1970,1,1, tzinfo=timezone.utc)) / timedelta(seconds=1)
Interesting read: Epoch time vs. time of day on the difference between What time is it? and How many seconds have elapsed?
See also: datetime needs an "epoch" method
Python 2
To adapt the above code for Python 2:
timestamp = (dt - datetime(1970, 1, 1)).total_seconds()
where timedelta.total_seconds() is equivalent to (td.microseconds + (td.seconds + td.days * 24 * 3600) * 10**6) / 10**6 computed with true division enabled.
Example
from __future__ import division
from datetime import datetime, timedelta
def totimestamp(dt, epoch=datetime(1970,1,1)):
td = dt - epoch
# return td.total_seconds()
return (td.microseconds + (td.seconds + td.days * 86400) * 10**6) / 10**6
now = datetime.utcnow()
print now
print totimestamp(now)
Beware of floating-point issues.
Output
2012-01-08 15:34:10.022403
1326036850.02
How to convert an aware datetime object to POSIX timestamp
assert dt.tzinfo is not None and dt.utcoffset() is not None
timestamp = dt.timestamp() # Python 3.3+
On Python 3:
from datetime import datetime, timedelta, timezone
epoch = datetime(1970, 1, 1, tzinfo=timezone.utc)
timestamp = (dt - epoch) / timedelta(seconds=1)
integer_timestamp = (dt - epoch) // timedelta(seconds=1)
On Python 2:
# utc time = local time - utc offset
utc_naive = dt.replace(tzinfo=None) - dt.utcoffset()
timestamp = (utc_naive - datetime(1970, 1, 1)).total_seconds()
For unix systems only:
>>> import datetime
>>> d = datetime.date(2011, 1, 1)
>>> d.strftime("%s") # <-- THIS IS THE CODE YOU WANT
'1293832800'
Note 1: dizzyf observed that this applies localized timezones. Don't use in production.
Note 2: Jakub Narębski noted that this ignores timezone information even for offset-aware datetime (tested for Python 2.7).
Assumption 1: You're attempting to convert a date to a timestamp, however since a date covers a 24 hour period, there isn't a single timestamp that represents that date. I'll assume that you want to represent the timestamp of that date at midnight (00:00:00.000).
Assumption 2: The date you present is not associated with a particular time zone, however you want to determine the offset from a particular time zone (UTC). Without knowing the time zone the date is in, it isn't possible to calculate a timestamp for a specific time zone. I'll assume that you want to treat the date as if it is in the local system time zone.
First, you can convert the date instance into a tuple representing the various time components using the timetuple() member:
dtt = d.timetuple() # time.struct_time(tm_year=2011, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=5, tm_yday=1, tm_isdst=-1)
You can then convert that into a timestamp using time.mktime:
ts = time.mktime(dtt) # 1293868800.0
You can verify this method by testing it with the epoch time itself (1970-01-01), in which case the function should return the timezone offset for the local time zone on that date:
d = datetime.date(1970,1,1)
dtt = d.timetuple() # time.struct_time(tm_year=1970, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=3, tm_yday=1, tm_isdst=-1)
ts = time.mktime(dtt) # 28800.0
28800.0 is 8 hours, which would be correct for the Pacific time zone (where I'm at).
I defined my own two functions
utc_time2datetime(utc_time, tz=None)
datetime2utc_time(datetime)
here:
import time
import datetime
from pytz import timezone
import calendar
import pytz
def utc_time2datetime(utc_time, tz=None):
# convert utc time to utc datetime
utc_datetime = datetime.datetime.fromtimestamp(utc_time)
# add time zone to utc datetime
if tz is None:
tz_datetime = utc_datetime.astimezone(timezone('utc'))
else:
tz_datetime = utc_datetime.astimezone(tz)
return tz_datetime
def datetime2utc_time(datetime):
# add utc time zone if no time zone is set
if datetime.tzinfo is None:
datetime = datetime.replace(tzinfo=timezone('utc'))
# convert to utc time zone from whatever time zone the datetime is set to
utc_datetime = datetime.astimezone(timezone('utc')).replace(tzinfo=None)
# create a time tuple from datetime
utc_timetuple = utc_datetime.timetuple()
# create a time element from the tuple an add microseconds
utc_time = calendar.timegm(utc_timetuple) + datetime.microsecond / 1E6
return utc_time
follow the python2.7 document, you have to use calendar.timegm() instead of time.mktime()
>>> d = datetime.date(2011,01,01)
>>> datetime.datetime.utcfromtimestamp(calendar.timegm(d.timetuple()))
datetime.datetime(2011, 1, 1, 0, 0)
A complete time-string contains:
date
time
utcoffset [+HHMM or -HHMM]
For example:
1970-01-01 06:00:00 +0500 == 1970-01-01 01:00:00 +0000 == UNIX timestamp:3600
$ python3
>>> from datetime import datetime
>>> from calendar import timegm
>>> tm = '1970-01-01 06:00:00 +0500'
>>> fmt = '%Y-%m-%d %H:%M:%S %z'
>>> timegm(datetime.strptime(tm, fmt).utctimetuple())
3600
Note:
UNIX timestamp is a floating point number expressed in seconds since the epoch, in UTC.
Edit:
$ python3
>>> from datetime import datetime, timezone, timedelta
>>> from calendar import timegm
>>> dt = datetime(1970, 1, 1, 6, 0)
>>> tz = timezone(timedelta(hours=5))
>>> timegm(dt.replace(tzinfo=tz).utctimetuple())
3600
Using the arrow package:
>>> import arrow
>>> arrow.get(2010, 12, 31).timestamp
1293753600
>>> time.gmtime(1293753600)
time.struct_time(tm_year=2010, tm_mon=12, tm_mday=31,
tm_hour=0, tm_min=0, tm_sec=0,
tm_wday=4, tm_yday=365, tm_isdst=0)
the question is a little confused. timestamps are not UTC - they're a Unix thing. the date might be UTC? assuming it is, and if you're using Python 3.2+, simple-date makes this trivial:
>>> SimpleDate(date(2011,1,1), tz='utc').timestamp
1293840000.0
if you actually have the year, month and day you don't need to create the date:
>>> SimpleDate(2011,1,1, tz='utc').timestamp
1293840000.0
and if the date is in some other timezone (this matters because we're assuming midnight without an associated time):
>>> SimpleDate(date(2011,1,1), tz='America/New_York').timestamp
1293858000.0
[the idea behind simple-date is to collect all python's date and time stuff in one consistent class, so you can do any conversion. so, for example, it will also go the other way:
>>> SimpleDate(1293858000, tz='utc').date
datetime.date(2011, 1, 1)
]
Considering you have a datetime object called d,
use the following to get the timestamp in UTC:
d.strftime("%Y-%m-%dT%H:%M:%S.%fZ")
And for the opposite direction, use following :
d = datetime.strptime("2008-09-03T20:56:35.450686Z", "%Y-%m-%dT%H:%M:%S.%fZ")
This works for me, pass through a function.
from datetime import timezone, datetime, timedelta
import datetime
def utc_converter(dt):
dt = datetime.datetime.now(timezone.utc)
utc_time = dt.replace(tzinfo=timezone.utc)
utc_timestamp = utc_time.timestamp()
return utc_timestamp
# create start and end timestamps
_now = datetime.datetime.now()
str_start = str(utc_converter(_now))
_end = _now + timedelta(seconds=10)
str_end = str(utc_converter(_end))
i'm impressed of the deep discussion.
my 2 cents:
from datetime import datetime
import time
the timestamp in utc is:
timestamp = \
(datetime.utcnow() - datetime(1970,1,1)).total_seconds()
or,
timestamp = time.time()
if now results from datetime.now(), in the same DST
utcoffset = (datetime.now() - datetime.utcnow()).total_seconds()
timestamp = \
(now - datetime(1970,1,1)).total_seconds() - utcoffset
I am dealing with dates in Python and I need to convert them to UTC timestamps to be used
inside Javascript. The following code does not work:
>>> d = datetime.date(2011,01,01)
>>> datetime.datetime.utcfromtimestamp(time.mktime(d.timetuple()))
datetime.datetime(2010, 12, 31, 23, 0)
Converting the date object first to datetime also does not help. I tried the example at this link from, but:
from pytz import utc, timezone
from datetime import datetime
from time import mktime
input_date = datetime(year=2011, month=1, day=15)
and now either:
mktime(utc.localize(input_date).utctimetuple())
or
mktime(timezone('US/Eastern').localize(input_date).utctimetuple())
does work.
So general question: how can I get a date converted to seconds since epoch according to UTC?
If d = date(2011, 1, 1) is in UTC:
>>> from datetime import datetime, date
>>> import calendar
>>> timestamp1 = calendar.timegm(d.timetuple())
>>> datetime.utcfromtimestamp(timestamp1)
datetime.datetime(2011, 1, 1, 0, 0)
If d is in local timezone:
>>> import time
>>> timestamp2 = time.mktime(d.timetuple()) # DO NOT USE IT WITH UTC DATE
>>> datetime.fromtimestamp(timestamp2)
datetime.datetime(2011, 1, 1, 0, 0)
timestamp1 and timestamp2 may differ if midnight in the local timezone is not the same time instance as midnight in UTC.
mktime() may return a wrong result if d corresponds to an ambiguous local time (e.g., during DST transition) or if d is a past(future) date when the utc offset might have been different and the C mktime() has no access to the tz database on the given platform. You could use pytz module (e.g., via tzlocal.get_localzone()) to get access to the tz database on all platforms. Also, utcfromtimestamp() may fail and mktime() may return non-POSIX timestamp if "right" timezone is used.
To convert datetime.date object that represents date in UTC without calendar.timegm():
DAY = 24*60*60 # POSIX day in seconds (exact value)
timestamp = (utc_date.toordinal() - date(1970, 1, 1).toordinal()) * DAY
timestamp = (utc_date - date(1970, 1, 1)).days * DAY
How can I get a date converted to seconds since epoch according to UTC?
To convert datetime.datetime (not datetime.date) object that already represents time in UTC to the corresponding POSIX timestamp (a float).
Python 3.3+
datetime.timestamp():
from datetime import timezone
timestamp = dt.replace(tzinfo=timezone.utc).timestamp()
Note: It is necessary to supply timezone.utc explicitly otherwise .timestamp() assume that your naive datetime object is in local timezone.
Python 3 (< 3.3)
From the docs for datetime.utcfromtimestamp():
There is no method to obtain the timestamp from a datetime instance,
but POSIX timestamp corresponding to a datetime instance dt can be
easily calculated as follows. For a naive dt:
timestamp = (dt - datetime(1970, 1, 1)) / timedelta(seconds=1)
And for an aware dt:
timestamp = (dt - datetime(1970,1,1, tzinfo=timezone.utc)) / timedelta(seconds=1)
Interesting read: Epoch time vs. time of day on the difference between What time is it? and How many seconds have elapsed?
See also: datetime needs an "epoch" method
Python 2
To adapt the above code for Python 2:
timestamp = (dt - datetime(1970, 1, 1)).total_seconds()
where timedelta.total_seconds() is equivalent to (td.microseconds + (td.seconds + td.days * 24 * 3600) * 10**6) / 10**6 computed with true division enabled.
Example
from __future__ import division
from datetime import datetime, timedelta
def totimestamp(dt, epoch=datetime(1970,1,1)):
td = dt - epoch
# return td.total_seconds()
return (td.microseconds + (td.seconds + td.days * 86400) * 10**6) / 10**6
now = datetime.utcnow()
print now
print totimestamp(now)
Beware of floating-point issues.
Output
2012-01-08 15:34:10.022403
1326036850.02
How to convert an aware datetime object to POSIX timestamp
assert dt.tzinfo is not None and dt.utcoffset() is not None
timestamp = dt.timestamp() # Python 3.3+
On Python 3:
from datetime import datetime, timedelta, timezone
epoch = datetime(1970, 1, 1, tzinfo=timezone.utc)
timestamp = (dt - epoch) / timedelta(seconds=1)
integer_timestamp = (dt - epoch) // timedelta(seconds=1)
On Python 2:
# utc time = local time - utc offset
utc_naive = dt.replace(tzinfo=None) - dt.utcoffset()
timestamp = (utc_naive - datetime(1970, 1, 1)).total_seconds()
For unix systems only:
>>> import datetime
>>> d = datetime.date(2011, 1, 1)
>>> d.strftime("%s") # <-- THIS IS THE CODE YOU WANT
'1293832800'
Note 1: dizzyf observed that this applies localized timezones. Don't use in production.
Note 2: Jakub Narębski noted that this ignores timezone information even for offset-aware datetime (tested for Python 2.7).
Assumption 1: You're attempting to convert a date to a timestamp, however since a date covers a 24 hour period, there isn't a single timestamp that represents that date. I'll assume that you want to represent the timestamp of that date at midnight (00:00:00.000).
Assumption 2: The date you present is not associated with a particular time zone, however you want to determine the offset from a particular time zone (UTC). Without knowing the time zone the date is in, it isn't possible to calculate a timestamp for a specific time zone. I'll assume that you want to treat the date as if it is in the local system time zone.
First, you can convert the date instance into a tuple representing the various time components using the timetuple() member:
dtt = d.timetuple() # time.struct_time(tm_year=2011, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=5, tm_yday=1, tm_isdst=-1)
You can then convert that into a timestamp using time.mktime:
ts = time.mktime(dtt) # 1293868800.0
You can verify this method by testing it with the epoch time itself (1970-01-01), in which case the function should return the timezone offset for the local time zone on that date:
d = datetime.date(1970,1,1)
dtt = d.timetuple() # time.struct_time(tm_year=1970, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=3, tm_yday=1, tm_isdst=-1)
ts = time.mktime(dtt) # 28800.0
28800.0 is 8 hours, which would be correct for the Pacific time zone (where I'm at).
I defined my own two functions
utc_time2datetime(utc_time, tz=None)
datetime2utc_time(datetime)
here:
import time
import datetime
from pytz import timezone
import calendar
import pytz
def utc_time2datetime(utc_time, tz=None):
# convert utc time to utc datetime
utc_datetime = datetime.datetime.fromtimestamp(utc_time)
# add time zone to utc datetime
if tz is None:
tz_datetime = utc_datetime.astimezone(timezone('utc'))
else:
tz_datetime = utc_datetime.astimezone(tz)
return tz_datetime
def datetime2utc_time(datetime):
# add utc time zone if no time zone is set
if datetime.tzinfo is None:
datetime = datetime.replace(tzinfo=timezone('utc'))
# convert to utc time zone from whatever time zone the datetime is set to
utc_datetime = datetime.astimezone(timezone('utc')).replace(tzinfo=None)
# create a time tuple from datetime
utc_timetuple = utc_datetime.timetuple()
# create a time element from the tuple an add microseconds
utc_time = calendar.timegm(utc_timetuple) + datetime.microsecond / 1E6
return utc_time
follow the python2.7 document, you have to use calendar.timegm() instead of time.mktime()
>>> d = datetime.date(2011,01,01)
>>> datetime.datetime.utcfromtimestamp(calendar.timegm(d.timetuple()))
datetime.datetime(2011, 1, 1, 0, 0)
A complete time-string contains:
date
time
utcoffset [+HHMM or -HHMM]
For example:
1970-01-01 06:00:00 +0500 == 1970-01-01 01:00:00 +0000 == UNIX timestamp:3600
$ python3
>>> from datetime import datetime
>>> from calendar import timegm
>>> tm = '1970-01-01 06:00:00 +0500'
>>> fmt = '%Y-%m-%d %H:%M:%S %z'
>>> timegm(datetime.strptime(tm, fmt).utctimetuple())
3600
Note:
UNIX timestamp is a floating point number expressed in seconds since the epoch, in UTC.
Edit:
$ python3
>>> from datetime import datetime, timezone, timedelta
>>> from calendar import timegm
>>> dt = datetime(1970, 1, 1, 6, 0)
>>> tz = timezone(timedelta(hours=5))
>>> timegm(dt.replace(tzinfo=tz).utctimetuple())
3600
Using the arrow package:
>>> import arrow
>>> arrow.get(2010, 12, 31).timestamp
1293753600
>>> time.gmtime(1293753600)
time.struct_time(tm_year=2010, tm_mon=12, tm_mday=31,
tm_hour=0, tm_min=0, tm_sec=0,
tm_wday=4, tm_yday=365, tm_isdst=0)
the question is a little confused. timestamps are not UTC - they're a Unix thing. the date might be UTC? assuming it is, and if you're using Python 3.2+, simple-date makes this trivial:
>>> SimpleDate(date(2011,1,1), tz='utc').timestamp
1293840000.0
if you actually have the year, month and day you don't need to create the date:
>>> SimpleDate(2011,1,1, tz='utc').timestamp
1293840000.0
and if the date is in some other timezone (this matters because we're assuming midnight without an associated time):
>>> SimpleDate(date(2011,1,1), tz='America/New_York').timestamp
1293858000.0
[the idea behind simple-date is to collect all python's date and time stuff in one consistent class, so you can do any conversion. so, for example, it will also go the other way:
>>> SimpleDate(1293858000, tz='utc').date
datetime.date(2011, 1, 1)
]
Considering you have a datetime object called d,
use the following to get the timestamp in UTC:
d.strftime("%Y-%m-%dT%H:%M:%S.%fZ")
And for the opposite direction, use following :
d = datetime.strptime("2008-09-03T20:56:35.450686Z", "%Y-%m-%dT%H:%M:%S.%fZ")
This works for me, pass through a function.
from datetime import timezone, datetime, timedelta
import datetime
def utc_converter(dt):
dt = datetime.datetime.now(timezone.utc)
utc_time = dt.replace(tzinfo=timezone.utc)
utc_timestamp = utc_time.timestamp()
return utc_timestamp
# create start and end timestamps
_now = datetime.datetime.now()
str_start = str(utc_converter(_now))
_end = _now + timedelta(seconds=10)
str_end = str(utc_converter(_end))
i'm impressed of the deep discussion.
my 2 cents:
from datetime import datetime
import time
the timestamp in utc is:
timestamp = \
(datetime.utcnow() - datetime(1970,1,1)).total_seconds()
or,
timestamp = time.time()
if now results from datetime.now(), in the same DST
utcoffset = (datetime.now() - datetime.utcnow()).total_seconds()
timestamp = \
(now - datetime(1970,1,1)).total_seconds() - utcoffset
Quick question:
Is there a pythonic (whether in the standard libraries or not) way to convert unix 32-bit epoch time to windows 64-bit epoch time and back again?
You can convert a POSIX timestamp to a datetime with
>>> tstamp = 1325178061 # right about now
>>> from datetime import datetime
>>> datetime.fromtimestamp(tstamp)
datetime.datetime(2011, 12, 29, 18, 1, 1)
The fromtimestamp named constructor accepts POSIX timestamps on all platforms (!).
Conversion to a Windows timestamp would be a matter of subtracting the Windows epoch, which Wikipedia says is January 1, 1601, and converting the resulting timedelta to a number of seconds:
>>> W_EPOCH = datetime(1601, 1, 1)
>>> (datetime.fromtimestamp(tstamp) - W_EPOCH).total_seconds()
12969655261.0
Now you've got a float that you convert to int and store as a 64-bit quantity in whichever way you like.
To convert from a Windows EPOCH timestamp to a datetime object (but not the other way around); here's a solution I came up with:
from datetime import datetime, timezone
def convert_from(windows_timestamp: int) -> datetime:
unix_epoch = datetime(1970, 1, 1, tzinfo=timezone.utc)
windows_epoch = datetime(1601, 1, 1, tzinfo=timezone.utc)
epoch_delta = unix_epoch - windows_epoch
windows_timestamp_in_seconds = windows_timestamp / 10_000_000
unix_timestamp = windows_timestamp_in_seconds - epoch_delta.total_seconds()
return datetime.utcfromtimestamp(unix_timestamp)
This allows you to pass in the Windows timestamp as is and it will spit out a valid Python datetime object.
NOTE: This is Python 3 specific.