Selenium not working except launching browser and open the page - python

I see that my selenium cannot execute codes except to launch Chrome.
I don't know why my selenium is not working. It just open the browser (Chrome) with the URL and then doing nothing even to maximize the window, not even inserting the form.
Is there anything wrong with my code:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import re, time, csv
driver = webdriver.Chrome("C:\\Users\\Ashraf%20Misran\\Installer\\chromedriver.exe")
driver.get("file:///C:/Users/Ashraf%20Misran/Devs/project-html/learning-html/selenium sandbox.html")
driver.maximize_window()
username = driver.find_element_by_xpath(".//input")
username.click()
username.send_keys("000200020002")
The page I opened is coded as below:
<!DOCTYPE html>
<html>
<head>
<title>Sandbox</title>
</head>
<body>
<form>
<input type="text" name="username">
</form>
</body>
</html>

I think the problem is with web-page, you are trying to open. Would suggest to try first with simple test, like Open Google page, enter something in search field. With this you will be able to verify, if you correctly implemented driver initialization.
Update: try to use this css selector: input[name='username'], if page is loaded correctly, then you have a problem with your web element selector.

I think, there is a problem with using relative xpath locator. Please try that one:
username = driver.findElement(By.xpath("//input"))

Related

Scraping dynamic data with Python

I have this simple page on html:
<html>
<body>
<p>Javascript (dynamic data) test:</p>
<p class='jstest' id='yesnojs'>Hello</p>
<button onclick="myFunction()">Try it</button>
<script>
function myFunction() {
document.getElementById('yesnojs').innerHTML = 'GoodBye';
}
</script>
</body>
</html>
I would like now scrap this page using Python to get when the id "yesnojs" is "GoodBye", I mean, when the user has clicked the button. I have been trying some tutorials but I always get "Hello", it doesn´t care if I have click and I am viewing on the page "GoodBye".
I hope your help, thank you.
PD:
this is my code on Python for try scrape the page:
from selenium import webdriver
chrome_path=
"C:\\Users\\Antonio\\Downloads\\chromedriver_win32\\chromedriver.exe"
driver = webdriver.Chrome(chrome_path)
driver.get("http://localhost/templates/scraping.html")
review = driver.find_elements_by_class_name("jstest")
for post in review:
print(post.text)
Selenium does not attach to your existing open web pages. It opens a new web page. You would have to simulate clicking with Selenium if you're designing a unit test.
Alternatively, are you looking at making a browser extension that does the scraping when this event happens, Selenium is not the tool for this.

I m not able to click on a button in a web page using selenium in python

What is wrong in the below code
import os
import time
from selenium import webdriver
driver = webdriver.Firefox()
driver.get("http://x.x.x.x/html/load.jsp")
elm1 = driver.find_element_by_link_text("load")
time.sleep(10)
elm1.click()
time.sleep(30)
driver.close()
The page source is
<body>
<div class="formcenterdiv">
<form class="form" action="../load" method="post">
<header class="formheader">Loader</header>
<div align="center"><button class="formbutton">load</button></div>
</form>
</div>
</body></html>
I want to click on button load. when I ran the above code getting this error
selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: load
As the documentation says, find_elements_by_link_text only works on a tags:
Use this when you know link text used within an anchor tag. With this
strategy, the first element with the link text value matching the
location will be returned. If no element has a matching link text
attribute, a NoSuchElementException will be raised.
The solution is to use a different selector like find_element_by_class_name:
elm1 = driver.find_element_by_class_name('formbutton')
Did you try using Xpath?
As the OP said, find_elements_by_link_text works on a tags only:
Below code might help you out
driver.get_element_by_xpath("/html/body/div/form/div/button")

Python Selenium ChromeDriver: chromedriver dummy frame

I had this simple login script to facebook that used to work perfectly until about a month ago. But yesterday when I tried running it again I got this dummy page:
<html xmlns="http://www.w3.org/1999/xhtml">
<head></head>
<body><pre style="word-wrap: break-word; white-space: pre-wrap;">
</pre>
<iframe name="chromedriver dummy frame" src="about:blank"></iframe>
</body>
</html>
I guess they've added some new detections. Is there a way to avoid those?
This is my simplified code:
browser = webdriver.Chrome(executable_path=path, service_args=['--ignore-ssl-errors=true', '--ssl-protocol=TLSv1'])
browser.get("https://www.facebook.com/")
for line in browser.page_source.split('\n'):
print line
I have a similar problem which is not Facebook but our developing pages.
I might be ssl problem. (which might be solved --ignore-ssl-... option.)
Mostly, This is waiting problem.
The Selenium bot captures whole HTML PAGE before the server print out their contexts.
Thus, it might be solved, using same wait options (See this)
If there is some unique ID html elements, please insert following codes:
wait = WebDriverWait(driver, 5)
element = wait.until(EC.visibility_of_element_located((By.ID, 'unique')))

Python Selenium On Local HTML String

I am trying to run Selenium on a local HTML string but can't seem to find any documentation on how to do so. I retrieve HTML source from an e-mail API, so Selenium won't be able to parse it directly. Is there anyway to alter the following so that it would read the HTML string below:
Python Code for remote access:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Firefox()
driver.get("http://www.python.org")
assert "Python" in driver.title
elem = driver.find_element_by_class_name("q")
Local HTML Code:
s = "<body>
<p>This is a test</p>
<p class="q">This is a second test</p>
</body>"
If you don't want to create a file or load a URL before being able to replace the content of the page, you can always leverage the Data URLs feature, which supports HTML, CSS and JavaScript:
from selenium import webdriver
driver = webdriver.Chrome()
html_content = """
<html>
<head></head>
<body>
<div>
Hello World =)
</div>
</body>
</html>
"""
driver.get("data:text/html;charset=utf-8,{html_content}".format(html_content=html_content))
If I understand the question correctly, I can imagine 2 ways to do this:
Save HTML code as file, and load it as url file:///file/location. The problem with that is that location of file and how file is loaded by a browser may differ for various OSs / browsers. But implementation is very simple on the other hand.
Another option is to inject your code onto some page, and then work with it as a regular dynamic HTML. I think this is more reliable, but also more work. This question has a good example.
Here was my solution for doing basic generated tests without having to make lots of temporary local files.
import json
from selenium import webdriver
driver = webdriver.PhantomJS() # or your browser of choice
html = '''<div>Some HTML</div>'''
driver.execute_script("document.write('{}')".format(json.dumps(html)))
# your tests
If I am reading correctly you are simply trying to get text from an element. If that is the case then the following bit should fit your needs:
elem = driver.find_element_by_class_name("q").text
print elem
Assuming "q" is the element you need.

Selenium send_keys doesn't work if input type="number"

I'm writing tests using selenium. In those tests I need to enter a number into a field in a form.
Here is the html:
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<form>
<input type="number" id="field_id">
</form>
</body>
</html>
And the code:
browser = webdriver.Firefox()
browser.get('file:///home/my_username/test.html')
field = browser.find_element_by_id('field_id')
field.send_keys('12') # NOTHING HAPPEN!
BTW, if I change the type of the field to "text" for example there is no problem at all. In addition, field.send_keys(Keys.UP) work great (but doesn't work when I'm using bootstrap) and field.clear() work all the time, as well as field.click().
Selenium version: 2.41.0
Firefox version: 29.0
Because you are using Firefox 29. Please downgrade to Firefox 28, which is the one Selenium 2.41.0 supports to, see CHANGES file. Otherwise you need to wait for new Selenium updates.
Here is what I have tested working with Firefox 28:
from selenium import webdriver
DEMO_PAGE = '''
data:text/html,
<form><input type="number" id="field_id"></form>
'''
browser = webdriver.Firefox()
browser.get(DEMO_PAGE)
input_number = browser.find_element_by_id('field_id')
input_number.send_keys('12')
input_number_value = input_number.get_attribute('value')
print "input_number_value = " + input_number_value
See also: Selenium can't find fields with type number
I'm on Fedora (which doesn't provide old versions of packages like Firefox) so "downgrade Firefox" is a bit of a non-answer.
Luckily, an answer to a very similar question hints at a better solution -- setting the "dom.forms.number" Firefox preference to disable special treatment of input type="number". In Python:
profile = webdriver.FirefoxProfile()
profile.set_preference("dom.forms.number", False)
browsers = webdriver.Firefox(profile)
Working with Firefox 29 and Selenium 2.41.0
I ran into this problem this morning. After upgrading Selenium, it now works properly.
So if you are reading this, run
pip install -U selenium
and try again. I went from Selenium version 2.41.0 to 2.42.1 and it now works properly with Firefox 30.0.
You can probably use Javascript to tackle this issue. The following code is in Java, but it can probably be done similarly in Python:
((IJavaScriptExecutor)webdriver)
.ExecuteScript("document.getElementById('field_id').value='12';");
I had the same issue and using Javascript solved it.
In my case selenium Send_keys work fine in this way.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
browser = webdriver.Firefox()
browser.get('http://www.yahoo.com')
assert 'Yahoo' in browser.title
elem = browser.find_element_by_name('p') # Find the search box
elem.send_keys('seleniumhq' + Keys.RETURN)
browser.quit()enter code here`
it is the web https://pypi.python.org/pypi/selenium
I resolved this issue in this way:
locator = <element xpath>
field = browser.find_element_by_xpath(to_unicode(**locator**,"utf-8"))
if(field != None):
field.send_keys(Keys.CONTROL + 'a')
field.send_keys(value)

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