I am trying to write a program in Python that can take the name of a stock and its price and print it. However, when I run it, nothing is printed. it seems like the data is having a problem being fetched from the website. I double checked that the path from the web page is correct, but for some reason the text does not want to show up.
from lxml import html
import requests
page = requests.get('https://www.bloomberg.com/quote/UKX:IND?in_source=topQuotes')
tree = html.fromstring(page.content)
Prices = tree.xpath('//span[#class="priceText__1853e8a5"]/text()')
print ('Prices:' , Prices)
here is the website I am trying to get the data from
I have tried BeautifulSoup, but it has the same problem.
If you print the string page.content, you'll see that the website code it captures is actually for a captcha test, not the "real" destination page itself you see when you manually visit the website. It seems that the website was smart enough to see that your request to this URL was from a script and not manually from a human, and it effectively prevented your script from scraping any real content. So Prices is empty because there simply isn't a span tag of class "priceText__1853e8a5" on this special Captcha page. I get the same when I try scraping with urllib2.
As others have suggested, Selenium (actual web automation) might be able to launch the page and get you what you need. The ID looks dynamically generated, though I do get the same one when I manually look at the page. Another alternative is to simply find a different site that can give you the quote you need without blocking your script. I tried it with https://tradingeconomics.com/ukx:ind and that works. Though of course you'll need a different xpath to find the cell you need.
Related
I need your help because I have for the first time problems to get some information with Beautifulsoup .
I have two problems on this page
The green button GET COUPON CODE appear after a few moment see GIF capture
When we inspect the button link, we find a a simple href attribute that call to an out.php function that performs the opening of the destination link that I am trying to capture.
GET COUPON CODE
Thank you for your help
Your problem is a little unclear but if I understand correctly, your first problem is that the 'get coupon code' button looks like this when you render the HTML that you receive from the original page request.
The mark-up for a lot of this code is rendered dynamically using javascript. So that button is missing its href value until it gets loaded in later. You would need to also run the javascript on that page to render this after the initial request. You can't really get this easily using just the python requests library and BeautifulSoup. It will be a lot easier if you use Selenium too which lets you control a browser so it runs all that javascript for you and then you can just get the button info a couple of seconds after loading the page.
There is a way to do this all with plain requests, but it's a bit tedious. You would need to read through the requests the page makes and figure out which one gets the link for the button. The upside to this is it would cut the number of steps to get the info you need and the amount of time it takes to get. You could just use this new request every time to get the right PHP link then just get the info from there.
For your second point, I'm also not sure if I answered it already, but maybe you're also trying to get the redirect link from that PHP link. From inspecting the network requests, it looks like the info will be found in the response headers, there is no body to inspect.
(I know it says 'from cache' but the point is that the redirect is being caused by the header info)
I am trying to extract information from an exchange website (chiliz.net) using Python (requests module) and the following code:
data = requests.get(url,time.sleep(15)).text
I used time.sleep since the website is not directly connecting to the exchange main page, but I am not sure it is necessary.
The things is that, I cannot find anything written under <body style> in the HTML text (which is the data variable in this case). How can I reach the full HTML code and then start to extract the price information from this website?
I know Python, but not familiar with websites/HTML that much. So I would appreciate if you explain the website related info like you are talking to a beginner. Thanks!
There could be a few reasons for this.
The website runs behind a proxy server from what I can tell, so this does interfere with your request loading time. This is why it's not directly connecting to the main page.
It might also be the case that the elements are rendered using javascript AFTER the page has loaded. So, you only get the page and not the javascript rendered parts. You can try to increase your sleep() time but I don't think that will help.
You can also use a library called Selenium. It simply automates browsers and you can use the page_source property to obtain the HTML source code.
Code (taken from here)
from selenium import webdriver
browser = webdriver.Firefox()
browser.get("http://example.com")
html_source = browser.page_source
With selenium, you can also set the XPATH to obtain the data of -' extract the price information from this website'; you can see a tutorial on that here. Alternatively,
once you extract the HTML code, you can also use a parser such as bs4 to extract the required data.
I'm attempting to scrape a website, and pull each sheriff's name and county. I'm using devtools in chrome to identify the HTML tag needed to locate that information.
import pandas as pd
import numpy as np
from bs4 import BeautifulSoup
URL = 'https://oregonsheriffs.org/about-ossa/meet-your-sheriffs'
page = requests.get(URL)
soup = BeautifulSoup(page.content, 'html.parser')
sheriff_names = soup.find_all('a', class_ = 'eg-sheriff-list-skin-element-1')
sheriff_counties = soup.find_all(class_ = 'eg-sheriff-list-skin-element-2')
However, I'm finding that Requests is not pulling the entire page's html, even though the tag is at the end. If I scan page.content, I find that Sheriff Harrold is the last sheriff included, and that every sheriff from curtis landers onwards is not included (I tried pasting the full output of page.contents but it's too long).
My best guess from reading this answer is that the website has javascripts that load the remaining part of the page upon interacting with it, which would imply that I need to use something like Selenium to interact with the page to get the rest of it to first load.
However, if you look at the website, it's very simple, so as a novice part of me is thinking that there has to be a way to scrape this basic website without using a more complex tool like Selenium. That said, I recognize that the website is wordpress generated and wordpress can set up delayed javascripts on even simple web sites.
My questions are:
1) do I really need to use Selenium to scrape a simple, word-press generated website like this? Or is there a way to get the full page to load with just Requests? Is there anyway to tell when web pages will require a web driver and when Requests will not be enough?
2) I'm thinking one step ahead here - if I want to scale up this project, how would I be able to tell that Requests has not returned the full website, without manually inspecting the results of every website?
Thanks!
Unfortunately, your initial instinct is almost certainly correct. If you look at the page source it seems that they have some sort of lazy loading going on, pulling content from an external source.
A quick look at the page source indicates that they're probably using the "Essential Grid" WordPress theme to do this. I think this supports preloading. If you look at the requests that are made you might be able to ascertain how it's loading this and pull directly from that source (perhaps a REST call, AJAX, etc).
In a generalized sense, I'm afraid that there really isn't any automated way to programmatically determine if a page has 'fully' loaded, as that behavior is defined in code and can be triggered by anything.
If you want to capture information from pages that load content as you scroll, though, I believe Selenium is the tool you'll have to use.
I'm new to Python & object-oriented programming in general. I'm trying to build a simple web scraper to create data frames from NBA contract data on basketball-reference.com. I had planned to use the requests library together with BeautifulSoup. However, the get method seems to be returning the site's homepage rather than the page affiliated with the URL I give.
I give a URL to a team's contracts page (https://www.basketball-reference.com/contracts/IND.html), but when I print the html it looks like it belongs to the homepage.
I haven't been able to find any documentation on the web about anyone else having this problem...
I'm using the Spyder IDE.
# Import library
import requests
# Assign the URL for contract scraping
url = 'https://www.basketball-reference.com/contracts/IND.html'
# Pull contracts page
page = requests.get(url)
# Check that correct page is being pulled
print(page.text)
This seems like it should be very straightforward, so I'm not understanding why the console is displaying html that clearly doesn't pertain to the page I'm trying to point to. I'm not getting any errors, just html from the homepage.
After checking the code on repl.it and visiting the webpage myself, I can confirm you are pulling in the correct page's HTML. The page variable contains the tables of data, as well as their info... and also the page's advertisements, the contact info, the social media buttons and links, the adblock detection scripts, and everything else on the webpage. Your issue isn't that you're getting the wrong page, it's that you're getting the entire page, not just the data.
You'll want to pick out the exact bits you're interested in - maybe by selecting the table and its child elements? The table's HTML id is contracts - that should be a good place to start.
(Try visiting the page in your browser, right-clicking anywhere on the page, and clicking "view page source" - that's what your program is pulling in. There's a LOT more to a webpage than most people realize!)
As a word of warning, though, Sports Reference has a data use policy that precludes web crawlers / spiders on their site. I would recommend checking (and using) one of the free sites they link instead; you risk being IP banned otherwise.
Simply printing the result of the get request on the terminal won't be very helpful, as the HTML page content returned is long - your terminal will truncate the printed response. I'm assuming in your case maybe the website has parts of the homepage reused in other pages as well, so it might get confusing.
I recommend writing the response into a file and then opening the file in the browser. You will see that your code is pulling the right page.
https://www.fedsdatacenter.com/federal-pay-rates/index.php?y=2017&n=&l=&a=&o=
This website seems to be written by jquery(AJAX). I would like to scrape all pages' tables. When I inspect the 1,2,3,4 page tags, they do not have a specific href link. Besides, clicking on them does not create a clear pattern of get requests, therefore, I find it hard to use Python urllib to send a get request for each page.
You can use Selenium with Python http://selenium-python.readthedocs.io/ to navigate through the pages. I would find the Next button and .click() it then time.sleep(seconds) and scrape the page. I can't navigate to the last page on this site, unfortunately (it seems broken - which you should also be aware of), but I'm assuming the Next button disappears or something when you get to the last page. If not, you might want to save the what you've scraped everytime you go to a new page, this way you don't lose your data in the event of an error.