What i'm trying to do is print or execute a certain string after
certain amount of time, in case of this function it is 20 seconds,
the problem is on the second loop, sure it waits 20 seconds on first loop,
but the second loop it no longer wait, it just keeps printing..
why does this happen? and how can i solve it?
from threading import Timer
import time
startlog = time.time()
def tess():
tm = 0
while True:
tm += 1
print(tm)
tess()
time.sleep(1)
You need to reset startlog between calls to tess that "succeed" (have passed 20 s), this code works the way you want (but is ugly because of the global variables).
import time
startlog = time.time()
def tess():
global startlog
if time.time() - 20 > startlog:
print('its been 20 secs')
startlog = time.time()
tm = 0
while True:
tm += 1
print(tm)
tess()
time.sleep(1)
You need to update your startlog variable inside loop in tess() function. You need to replace
start = time.time()
with:
startlog = time.time()
You have to change start = time.time() to startlog = time.time() and define such variable as global or nonlocal:
def tess():
nonlocal startlog
...
startlog = time.time()
Or just wait 20 secs: time.sleep(20)
It sounds like you are trying to run something for 20 seconds in the background, and then execute your function.
If this is the case, you threading / multiprocessing makes more sense.
Using this decorator, your code could be rewritten as
#time_limit(20)
def will_stop_after_20_secs():
print ("doing stuff")
time.sleep(20)
will_stop_after_20_secs()
print ("20 seconds had passed")
Related
I want to build a function that will stop another function after a set time.
For example:
def start():
global bol_start
bol_start = True
timer()
if bol_start is True:
"do something until time is over"
def stop():
global bol_start
bol_start = False
sys.exit(0)
def timer():
"code for actual timer" ?
I would like to let the user define the time x how long the tool should run start().
After the time is over it should call stop().
If you have a loop in the function, that runs continuously, the simplest mechanic would be to measure time every iteration:
import time
def run():
start = time.time()
stop_seconds = 10
while time.time() - start < stop_seconds:
# do something
If you don't have a loop or the function consists of time consuming operations, you would need to kill the function in the middle of execution like suggested here: Timeout on a function call
I am trying to figure out how to do the following:
If "some logic" occurs for more than 15 seconds:
"execute some code"
Im not quite sure how to ask python to do this. I am working with stock prices and my index column is dtype='datetime64[ns].
I tried searching other threads for hints on how to do this but i wasn't even quite sure what to search for.
Sorry in advance if its a very elementary question.
try takinng the current time and comparing it every tick
One way to accomplish this is to use threads (multiprocessing) as they would be 2 tasks "some logic" and the "scheduler".
This can be addressed easily with the following logic:
import threading
import time
lock = threading.Lock()
cond = threading.Condition(threading.Lock())
def waitLock(timeout):
with cond:
current_time = start_time = time.time()
while current_time < start_time + timeout:
if lock.acquire(False):
return True
else:
cond.wait(timeout - current_time + start_time)
current_time = time.time()
return False
Source: How to implement a Lock with a timeout in Python 2.7
import time
def check():
if not some_logic(): return False
start_time = time.time()
while time.time() - start_time <= 15:
if not some_logic(): return False
return True
if check():
... # do stuff
This runs some_logic as many times as possible to ensure that it returns True throughout the whole 15-second period.
I'm making a simple client/server program in Python 3 and in the client I would like a clock or printout of the running time. I'm trying to make it in a loop that starts at the beginning of the program, but in a thread so the rest of the code keeps going.
class time_thread():
def run(self):
loop = 0
while (zetime > -1):
print(zetime);
zetime = zetime + 1;
time_thread.start()
zetime = 0
This is what I have so far, but it doesn't work. It says:
time_thread has no attribute start()
I'm new to this and haven't used threads before, so I'm not sure how to go about this. Is there a better way?
I think this is what you're looking for:
import time, sys
zetime = 0
while (zetime > -1):
sys.stdout.write("\r" + str(zetime))
sys.stdout.flush()
time.sleep(1)
zetime = zetime + 1;
First of all , to use Thread module, you have to inherit the class Thread on your class, so you can use their methods like start.
To calculate time, you can use datetime.
from datetime import datetime
from time import sleep
start_time = datetime.now()
sleep(5) # code that you want to calculate.
end_time = datetime.now()
print(end_time - start_time)
Just place this
So let's say you define a function elapsed_time such as:
import time, sys
def elapsed_time(time_start):
''' time_start: a time.time()
Goal: print the elapsed time since time_start '''
# Allow to stop the counting once bool_time = False in the main program
global bool_elapsed_time
# loop while the condition
while bool_elapsed_time == True:
# Note: erase and write below does not work in spyder but in a shell yes
print ("Elapsed time: {} seconds".format(int(time.time() - time_start))),
sys.stdout.flush()
print ("\r"),
time.sleep(1)
# erase the line with elapsed time to clean the shell at the end
sys.stdout.flush()
print ("\r"),
Then in your program:
import threading
bool_elapsed_time = True
t = threading.Thread(name='child procs', target=elapsed_time, args=(time.time(),))
t.start()
## Here add the job you want to do as an example:
time.sleep(10)
bool_elapsed_time = False #to stop the elapsed time printing
Should do the job you want to do.
Note: I used python 2.7 so it might be slightly different with 3.x
I am running pool.map on big data array and i want to print report in console every minute.
Is it possible? As i understand, python is synchronous language, it can't do this like nodejs.
Perhaps it can be done by threading.. or how?
finished = 0
def make_job():
sleep(1)
global finished
finished += 1
# I want to call this function every minute
def display_status():
print 'finished: ' + finished
def main():
data = [...]
pool = ThreadPool(45)
results = pool.map(make_job, data)
pool.close()
pool.join()
You can use a permanent threaded timer, like those from this question: Python threading.timer - repeat function every 'n' seconds
from threading import Timer,Event
class perpetualTimer(object):
# give it a cycle time (t) and a callback (hFunction)
def __init__(self,t,hFunction):
self.t=t
self.stop = Event()
self.hFunction = hFunction
self.thread = Timer(self.t,self.handle_function)
def handle_function(self):
self.hFunction()
self.thread = Timer(self.t,self.handle_function)
if not self.stop.is_set():
self.thread.start()
def start(self):
self.stop.clear()
self.thread.start()
def cancel(self):
self.stop.set()
self.thread.cancel()
Basically this is just a wrapper for a Timer object that creates a new Timer object every time your desired function is called. Don't expect millisecond accuracy (or even close) from this, but for your purposes it should be ideal.
Using this your example would become:
finished = 0
def make_job():
sleep(1)
global finished
finished += 1
def display_status():
print 'finished: ' + finished
def main():
data = [...]
pool = ThreadPool(45)
# set up the monitor to make run the function every minute
monitor = PerpetualTimer(60,display_status)
monitor.start()
results = pool.map(make_job, data)
pool.close()
pool.join()
monitor.cancel()
EDIT:
A cleaner solution may be (thanks to comments below):
from threading import Event,Thread
class RepeatTimer(Thread):
def __init__(self, t, callback, event):
Thread.__init__(self)
self.stop = event
self.wait_time = t
self.callback = callback
self.daemon = True
def run(self):
while not self.stop.wait(self.wait_time):
self.callback()
Then in your code:
def main():
data = [...]
pool = ThreadPool(45)
stop_flag = Event()
RepeatTimer(60,display_status,stop_flag).start()
results = pool.map(make_job, data)
pool.close()
pool.join()
stop_flag.set()
One way to do this, is to use main thread as the monitoring one. Something like below should work:
def main():
data = [...]
results = []
step = 0
pool = ThreadPool(16)
pool.map_async(make_job, data, callback=results.extend)
pool.close()
while True:
if results:
break
step += 1
sleep(1)
if step % 60 == 0:
print "status update" + ...
I've used .map() instead of .map_async() as the former is synchronous one. Also you probably will need to replace results.extend with something more efficient. And finally, due to GIL, speed improvement may be much smaller than expected.
BTW, it is little bit funny that you wrote that Python is synchronous in a question that asks about ThreadPool ;).
Consider using the time module. The time.time() function returns the current UNIX time.
For example, calling time.time() right now returns 1410384038.967499. One second later, it will return 1410384039.967499.
The way I would do this would be to use a while loop in the place of results = pool(...), and on every iteration to run a check like this:
last_time = time.time()
while (...):
new_time = time.time()
if new_time > last_time+60:
print "status update" + ...
last_time = new_time
(your computation here)
So that will check if (at least) a minute has elapsed since your last status update. It should print a status update approximately every sixty seconds.
Sorry that this is an incomplete answer, but I hope this helps or gives you some useful ideas.
I have a code:
function_1()
function_2()
Normally, function_1() takes 10 hours to end.
But I want function_1() to run for 2 hours, and after 2 hours, function_1 must return and program must continue with function_2(). It shouldn't wait for function_1() to be completed. Is there a way to do this in python?
What makes functions in Python able to interrupt their execution and resuming is the use of the "yield" statement -- your function then will work as a generator object. You call the "next" method on this object to have it start or continue after the last yield
import time
def function_1():
start_time = time.time()
while True:
# do long stuff
running_time = time.time() -start_time
if running_time > 2 * 60 * 60: # 2 hours
yield #<partial results can be yield here, if you want>
start_time = time.time()
runner = function_1()
while True:
try:
runner.next()
except StopIteration:
# function_1 had got to the end
break
# do other stuff
If you don't mind leaving function_1 running:
from threading import Thread
import time
Thread(target=function_1).start()
time.sleep(60*60*2)
Thread(target=function_2).start()
You can try to use module Gevent: start function in thread and kill that thread after some time.
Here is example:
import gevent
# function which you can't modify
def func1(some_arg)
# do something
pass
def func2()
# do something
pass
if __name__ == '__main__':
g = gevent.Greenlet(func1, 'Some Argument in func1')
g.start()
gevent.sleep(60*60*2)
g.kill()
# call the rest of functions
func2()
from multiprocessing import Process
p1 = Process(target=function_1)
p1.start()
p1.join(60*60*2)
if p1.is_alive():p1.terminate()
function_2()
I hope this helps
I just tested this using the following code
import time
from multiprocessing import Process
def f1():
print 0
time.sleep(10000)
print 1
def f2():
print 2
p1 = Process(target=f1)
p1.start()
p1.join(6)
if p1.is_alive():p1.terminate()
f2()
Output is as expected:
0
2
You can time the execution using the datetime module. Probably your optimizer function has a loop somewhere. Inside the loop you can test how much time has passed since you started the function.
def function_1():
t_end = datetime.time.now() + datetime.timedelta(hours=2)
while not converged:
# do your thing
if datetime.time.now() > t_end:
return