Made a quick script on my windows pc to query an api and write to a spreadsheet. The issue is that the person running this will be on mac, so Im trying to port it to mac os but I believe I've run into a file path error? Everything looks right though so I'm confused. Thank you in advance for any help. I'm very unfamiliar with mac.
The excel module I'm using isnt able to open the workbook I have. It's openpyxl.
root = Tkinter.Tk()
root.withdraw()
file_path = tkFileDialog.askopenfilename()
save =tkFileDialog.asksaveasfilename(defaultextension=".xlsx",initialfile=file_path)
main(file_path,save)
def main(load,save):
try:
wb = load_workbook(load)
except:
print load,save
return
I expect the workbook to be opened but instead it's printing the file path and ending main().
Here are the file paths it's printing out:
/Users/edwin/Downloads/190117 CA Device Roster.xlsx
/Users/edwin/Downloads/:Users:edwin:Downloads:test.xlsx
except:
. Why are you expclicitly catching all exceptions and then not exposing them to the user? Ignoring exceptions doesn't make the problem go away - it just stops you from seeing it. Which means your code doesn't work and you don't know why.
If you need additional debugging in your except, it's fine, just raise the original exception afterwards:
except Exception as e:
print(load,save)
raise e
Anything other than exposing the exception you got is going to hide your errors, leaving you with no option but to guess what's going wrong. Good engineers don't guess - they increase logging.
Related
I've been working on the script for a couple days now, and for some reason I am struggling with my my code to work properly. When I run the python code the program is suppose to add a value to a key in the windows registry; however, that doesn't happen in there. I ended up looping the values to see if its on python side and the program spits out my values I've placed so I'm not sure.
Output:
('notepad', 'notepad.exe', 1)
('PythonTestFile', 'explorer', 1)
('testpurpose', '1', 1)
('notepad.exe', 'notepad.exe', 1)
Windows Registry
CODE
import winreg
#connecting to key in registry
access_registry = winreg.ConnectRegistry(None,winreg.HKEY_CURRENT_USER)
access_key = winreg.OpenKey(access_registry, "SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Policies\\Explorer\\DisallowRun", 0, winreg.KEY_ALL_ACCESS | winreg.KEY_WOW64_64KEY)
#accessing the key to open the registry directories under
for n in range(20):
try:
x = winreg.EnumKey(access_key,n)
print(x)
except:
break
try:
winreg.SetValueEx(access_key, "testpurpose", 0, winreg.REG_SZ, "1")
winreg.CloseKey(access_key)
except Exception as e:
print(e)
I've tried multiple videos and looked through the documentation, but I'm not sure where I'm going wrong. I even switched between the 64x and 32x with the permissions and tried restarting my computer multiple times, and nothing seems to work. The only thing I can think of is it has the wrong path. If you could help that would be awesome!
I ran into the same thing. Looks to be affected by the fact that I'm using the python build provided from the Microsoft Store, and its problems are documented here: https://docs.python.org/3/using/windows.html#redirection-of-local-data-registry-and-temporary-paths
I monitored the process with Process Explorer and it showed that opens of the registry were being redirected to a silo-ed location. o_O
I'm writing a code in Python, in which I check if a certain folder exists; if it does, I remove it and create a new one (with the same name). The code is as follows:
if os.path.exists(output_folder):
shutil.rmtree(output_folder)
os.makedirs(output_folder)
This code works fine, accept for when I have that specific output_folder open with the windows explorer. When it's open, I get the following error in my code:
WindowsError: [Error 5] Access is denied: [foldername]
Simultaneously, windows explorer switches itself to foldername's parent directory, and throws an error.
Is there a way to make python ignore the error and continue running, or am I asking for something that is impossible due to the system?
I tried using shutil.rmtree(output_folder, ignore_errors=True) but it didn't change anything.
You can use Python's exception handling to catch the error. You would also probably benefit from a short delay before creating the folder again to give Windows Explorer a chance to close:
import shutil
import time
try:
shutil.rmtree(output_folder)
except WindowsError as e:
print("Failed to delete") # Or just pass
time.sleep(0.5)
os.makedirs(output_folder)
My problem is that logging stops for a python program when the log is rotated.
I have tracked it down to the stream itself. I don't see any way to tell if the stream is broken from python. After the file is deleted it still accepts writes without any issue.
import os
FILE = 'testing.txt'
fs = open(FILE, 'a')
fs.write('word')
os.remove(FILE)
fs.write('Nothing....') # Nothing breaks
print(fs.errors) # No errors
So, how can I find out if the file stream is still valid?
And checking to see if the file exists will not help since the file will always exist regardless of whether or not the stream is still valid.
Upon much more inspection, I found the solution. It is an OS specific problem. When the file is deleted in Linux (or Macintosh) it just unlinks it. (I was not aware of this)
So if you run lsof on the machine, it still shows the file as open.
[user#machine]$ lsof | grep --color -i "testing.txt"
python26 26495 user 8w REG 8,33 23474 671920 /home/user/temp/testing.txt (deleted)
The solution is to stat the stream in python.
stat = os.fstat(fs.fileno())
Which will give you the number of links it has.
if stat.st_nlink < 1:
#has been deleted
And there you go. Now you know if you should reload it or not. Hopefully this helps someone else.
Try Exception handling:
import os
FILE = 'testing.txt'
try:
fs = open(FILE, 'a')
fs.write('word')
os.remove(FILE)
fs.write('Nothing....') # Nothing breaks
except Exception, e:
print "Error:", e
print(fs.errors) # No errors
There are python bindings for ionotify if you need more intelligence than just an try: except: clause. But I think its only pertinent to Linux (im not sure of your platform)
Another solution I found is to add the "copytruncate" flag into the logrotate config.
See "man logrotate" for more info.
edit:OK, I could swear that the way I'd tested it showed that the getcwd was also causing the exception, but now it appears it's just the file creation. When I move the try-except blocks to their it actually does catch it like you'd think it would. So chalk that up to user error.
Original Question:
I have a script I'm working on that I want to be able to drop a file on it to have it run with that file as an argument. I checked in this question, and I already have the mentioned registry keys (apparently the Python 2.6 installer takes care of it.) However, it's throwing an exception that I can't catch. Running it from the console works correctly, but when I drop a file on it, it throws an exception then closes the console window. I tried to have it redirect standard error to a file, but it threw the exception before the redirection occurred in the script. With a little testing, and some quick eyesight I saw that it was throwing an IOError when I tried to create the file to write the error to.
import sys
import os
#os.chdir("C:/Python26/Projects/arguments")
try:
print sys.argv
raw_input()
os.getcwd()
except Exception,e:
print sys.argv + '\n'
print e
f = open("./myfile.txt", "w")
If I run this from the console with any or no arguments, it behaves as one would expect. If I run it by dropping a file on it, for instance test.txt, it runs, prints the arguments correctly, then when os.getcwd() is called, it throws the exception, and does not perform any of the stuff from the except: block, making it difficult for me to find any way to actually get the exception text to stay on screen. If I uncomment the os.chdir(), the script doesn't fail. If I move that line to within the except block, it's never executed.
I'm guessing running by dropping the file on it, which according to the other linked question, uses the WSH, is somehow messing up its permissions or the cwd, but I don't know how to work around it.
Seeing as this is probably not Python related, but a Windows problem (I for one could not reproduce the error given your code), I'd suggest attaching a debugger to the Python interpreter when it is started. Since you start the interpreter implicitly by a drag&drop action, you need to configure Windows to auto-attach a debugger each time Python starts. If I remember correctly, this article has the needed information to do that (you can substitute another debugger if you are not using Visual Studio).
Apart from that, I would take a snapshot with ProcMon while dragging a file onto your script, to get an idea of what is going on.
As pointed out in my edit above, the errors were caused by the working directory changing to C:\windows\system32, where the script isn't allowed to create files. I don't know how to get it to not change the working directory when started that way, but was able to work around it like this.
if len(sys.argv) == 1:
files = [filename for filename in os.listdir(os.getcwd())
if filename.endswith(".txt")]
else:
files = [filename for filename in sys.argv[1:]]
Fixing the working directory can be managed this way I guess.
exepath = sys.argv[0]
os.chdir(exepath[:exepath.rfind('\\')])
I am on windows with Python 2.5. I have an open file for writing. I write some data. Call file close. When I try to delete the file from the folder using Windows Explorer, it errors, saying that a process still holds a handle to the file.
If I shutdown python, and try again, it succeeds.
It does close them.
Are you sure f.close() is getting called?
I just tested the same scenario and windows deletes the file for me.
Are you handling any exceptions around the file object? If so, make sure the error handling looks something like this:
f = open("hello.txt")
try:
for line in f:
print line
finally:
f.close()
In considering why you should do this, consider the following lines of code:
f = open('hello.txt')
try:
perform_an_operation_that_causes_f_to_raise_an_exception()
f.close()
except IOError:
pass
As you can see, f.close will never be called in the above code. The problem is that the above code will also cause f to not get garbage collected. The reason is that f will still be referenced in sys.traceback, in which case the only solution is to manually call close on f in a finally block or set sys.traceback to None (and I strongly recommend the former).
Explained in the tutorial:
with open('/tmp/workfile', 'r') as f:
read_data = f.read()
It works when you writing or pickling/unpickling, too
It's not really necessary that try finally block: Java way of doing things, not Python
I was looking for this, because the same thing happened to me. The question didn't help me, but I think I figured out what happened.
In the original version of the script I wrote, I neglected to add in a 'finally' clause to the file in case of an exception.
I was testing the script from the interactive prompt and got an exception while the file was open. What I didn't realize was that the file object wasn't immediately garbage-collected. After that, when I ran the script (still from the same interactive session), even though the new file objects were being closed, the first one still hadn't been, and so the file handle was still in use, from the perspective of the operating system.
Once I closed the interactive prompt, the problem went away, at which I remembered that exception occurring while the file was open and realized what had been going on. (Moral: Don't try to program on insufficient sleep. : ) )
Naturally, I have no idea if this is what happened in the case of the original poster, and even if the original poster is still around, they may not remember the specific circumstances, but the symptoms are similar, so I thought I'd add this as something to check for, for anyone caught in the same situation and looking for an answer.
I did it using intermediate file:
import os
f = open("report.tmp","w")
f.write("{}".format("Hello"))
f.close()
os.system("move report.tmp report.html") #this line is for Windows users