i am trying to do my own property but i can't understand how to implement method set.
this command x.value = 20 doesnt work. how can i do setter for decorator #myownproperties?
class myownproperties:
def __init__(self, dget, dset=None):
self.dget = dget
self.dset = dset
def __get__(self, obj, klass = None):
return self.dget.__get__(obj, klass)()
def __set__(self, obj, value):
type_ = type(obj)
return self.dset.__get__(obj, type_)(value)
def setter(self, func):
self.dset = classmethod(func)
return self
class Foo:
def __init__(self, foo):
self.foo = foo
#myownproperties
def value(self):
return self.foo
#value.setter
def value_setter(self, new_val):
self.foo = new_val
x = Foo(10)
print(x.value)
x.value = 20
print(x.value)
Here's a simple version:
class myownproperties:
def __init__(self, dget, dset=None):
self.dget = dget
self.dset = dset
def __get__(self, obj, _cls):
return self.dget(obj)
def __set__(self, obj, value):
self.dset(obj, value)
def setter(self, func):
self.dset = func
return func
class Foo:
def __init__(self, foo):
self.foo = foo
#myownproperties
def value(self):
return self.foo
#value.setter
def value_setter(self, new_val):
self.foo = new_val
x = Foo(10)
print(x.value) # 10
x.value = 20
print(x.value) # 20
I couldn't figure out the purpose behind wrapping dset in classmethod or in calling __get__ on the resulting object, so I just removed all that and it seems to work fine.
At the time the decorator is applied, and within that scope, def value_setter(self, new_val): is just an ordinary function. (We aren't looking it up on an instance of the class, so there is no opportunity for method binding to occur.) So in the decorator's setter method, we should just have self.dset = func, just like how we have just self.dget = dget in the __init__.
When the __set__ of the descriptor is called, we should directly invoke this function, because it's the function that contains the logic for what should happen upon the attribute access. That is, just self.dset(obj, value) - here, self is the descriptor; its dset attribute (a function which is stored in the object, not a bound method) is looked up and called with obj as the Foo instance and value as the value to set. The function takes in self, obj where self is bound to the Foo instance - not by method-call binding, but by normal argument passing. The setter does self.foo = new_val, thus assigning the foo attribute of the Foo instance.
Similarly for __get__ - just use self.dget directly, and return the result.
Putting these pieces together gives Samwise's version of the code.
(Incidentally, in case you weren't aware: method binding, itself, uses this mechanism! Functions are descriptors; their class implements __get__ to do the binding and create an object that represents the bound method, which can then be called.)
I have a class and I want to reassign a certain method to an hidden one of the same class.
In my case I have a generic filter that I want to assign to a specific implementation.
I'd like to have the func_map as a class attribute instead of an instance attribute because it seems more logic. How should I do that?
class MyClass:
func_map = {"eq" : __eq_filter}
def set_filter(self, func):
self.filter = MyClass.func_map[func]
def filter(self, value):
raise NotImplementedError
def __eq_filter(self, value):
return self.attribute == value
Maybe use the built-in #staticmethod decorator, which, according to the docs, allows to bound a method to the class instead of to the instance (Transform a method into a static method):
class MyClass:
func_map = {"eq" : __eq_filter}
def set_filter(self, func):
self.filter = func_map[func]
def filter(self, value):
raise NotImplementedError
#staticmethod
def __eq_filter(self, value):
return self.attribute == value
Check the docs for more info: https://docs.python.org/3/library/functions.html#staticmethod
I'd like to create a delegator D for an existing class A instance s.t. method calls and #property attribute access to A can be mocked in D:
class D(object):
def __init__(self, instance_of_A):
self.instance_of_A = instance_of_A
def __getattr__(self, attr):
...
def attr_wrapper(*args, **kwargs):
print('accessing attribute', attr)
res = getattr(self.instance_of_A, attr)(*args, **kwargs)
...
return res
return attr_wrapper
While that works for delegating to A's method calls that doesn't work
for #property attributes of A. What's the best way to make it work?
EDIT
To clarify, this doesn't work if A has a #property attribute:
class A(object):
#property
def foo():
return 1
EDIT2
Returning attr_wrapper is important since I want to intercept the return
value that call.
This question already has answers here:
Using property() on classmethods
(19 answers)
Closed 3 years ago.
In python I can add a method to a class with the #classmethod decorator. Is there a similar decorator to add a property to a class? I can better show what I'm talking about.
class Example(object):
the_I = 10
def __init__( self ):
self.an_i = 20
#property
def i( self ):
return self.an_i
def inc_i( self ):
self.an_i += 1
# is this even possible?
#classproperty
def I( cls ):
return cls.the_I
#classmethod
def inc_I( cls ):
cls.the_I += 1
e = Example()
assert e.i == 20
e.inc_i()
assert e.i == 21
assert Example.I == 10
Example.inc_I()
assert Example.I == 11
Is the syntax I've used above possible or would it require something more?
The reason I want class properties is so I can lazy load class attributes, which seems reasonable enough.
Here's how I would do this:
class ClassPropertyDescriptor(object):
def __init__(self, fget, fset=None):
self.fget = fget
self.fset = fset
def __get__(self, obj, klass=None):
if klass is None:
klass = type(obj)
return self.fget.__get__(obj, klass)()
def __set__(self, obj, value):
if not self.fset:
raise AttributeError("can't set attribute")
type_ = type(obj)
return self.fset.__get__(obj, type_)(value)
def setter(self, func):
if not isinstance(func, (classmethod, staticmethod)):
func = classmethod(func)
self.fset = func
return self
def classproperty(func):
if not isinstance(func, (classmethod, staticmethod)):
func = classmethod(func)
return ClassPropertyDescriptor(func)
class Bar(object):
_bar = 1
#classproperty
def bar(cls):
return cls._bar
#bar.setter
def bar(cls, value):
cls._bar = value
# test instance instantiation
foo = Bar()
assert foo.bar == 1
baz = Bar()
assert baz.bar == 1
# test static variable
baz.bar = 5
assert foo.bar == 5
# test setting variable on the class
Bar.bar = 50
assert baz.bar == 50
assert foo.bar == 50
The setter didn't work at the time we call Bar.bar, because we are calling
TypeOfBar.bar.__set__, which is not Bar.bar.__set__.
Adding a metaclass definition solves this:
class ClassPropertyMetaClass(type):
def __setattr__(self, key, value):
if key in self.__dict__:
obj = self.__dict__.get(key)
if obj and type(obj) is ClassPropertyDescriptor:
return obj.__set__(self, value)
return super(ClassPropertyMetaClass, self).__setattr__(key, value)
# and update class define:
# class Bar(object):
# __metaclass__ = ClassPropertyMetaClass
# _bar = 1
# and update ClassPropertyDescriptor.__set__
# def __set__(self, obj, value):
# if not self.fset:
# raise AttributeError("can't set attribute")
# if inspect.isclass(obj):
# type_ = obj
# obj = None
# else:
# type_ = type(obj)
# return self.fset.__get__(obj, type_)(value)
Now all will be fine.
If you define classproperty as follows, then your example works exactly as you requested.
class classproperty(object):
def __init__(self, f):
self.f = f
def __get__(self, obj, owner):
return self.f(owner)
The caveat is that you can't use this for writable properties. While e.I = 20 will raise an AttributeError, Example.I = 20 will overwrite the property object itself.
[answer written based on python 3.4; the metaclass syntax differs in 2 but I think the technique will still work]
You can do this with a metaclass...mostly. Dappawit's almost works, but I think it has a flaw:
class MetaFoo(type):
#property
def thingy(cls):
return cls._thingy
class Foo(object, metaclass=MetaFoo):
_thingy = 23
This gets you a classproperty on Foo, but there's a problem...
print("Foo.thingy is {}".format(Foo.thingy))
# Foo.thingy is 23
# Yay, the classmethod-property is working as intended!
foo = Foo()
if hasattr(foo, "thingy"):
print("Foo().thingy is {}".format(foo.thingy))
else:
print("Foo instance has no attribute 'thingy'")
# Foo instance has no attribute 'thingy'
# Wha....?
What the hell is going on here? Why can't I reach the class property from an instance?
I was beating my head on this for quite a while before finding what I believe is the answer. Python #properties are a subset of descriptors, and, from the descriptor documentation (emphasis mine):
The default behavior for attribute access is to get, set, or delete the
attribute from an object’s dictionary. For instance, a.x has a lookup chain
starting with a.__dict__['x'], then type(a).__dict__['x'], and continuing
through the base classes of type(a) excluding metaclasses.
So the method resolution order doesn't include our class properties (or anything else defined in the metaclass). It is possible to make a subclass of the built-in property decorator that behaves differently, but (citation needed) I've gotten the impression googling that the developers had a good reason (which I do not understand) for doing it that way.
That doesn't mean we're out of luck; we can access the properties on the class itself just fine...and we can get the class from type(self) within the instance, which we can use to make #property dispatchers:
class Foo(object, metaclass=MetaFoo):
_thingy = 23
#property
def thingy(self):
return type(self).thingy
Now Foo().thingy works as intended for both the class and the instances! It will also continue to do the right thing if a derived class replaces its underlying _thingy (which is the use case that got me on this hunt originally).
This isn't 100% satisfying to me -- having to do setup in both the metaclass and object class feels like it violates the DRY principle. But the latter is just a one-line dispatcher; I'm mostly okay with it existing, and you could probably compact it down to a lambda or something if you really wanted.
If you use Django, it has a built in #classproperty decorator.
from django.utils.decorators import classproperty
For Django 4, use:
from django.utils.functional import classproperty
I think you may be able to do this with the metaclass. Since the metaclass can be like a class for the class (if that makes sense). I know you can assign a __call__() method to the metaclass to override calling the class, MyClass(). I wonder if using the property decorator on the metaclass operates similarly.
Wow, it works:
class MetaClass(type):
def getfoo(self):
return self._foo
foo = property(getfoo)
#property
def bar(self):
return self._bar
class MyClass(object):
__metaclass__ = MetaClass
_foo = 'abc'
_bar = 'def'
print MyClass.foo
print MyClass.bar
Note: This is in Python 2.7. Python 3+ uses a different technique to declare a metaclass. Use: class MyClass(metaclass=MetaClass):, remove __metaclass__, and the rest is the same.
As far as I can tell, there is no way to write a setter for a class property without creating a new metaclass.
I have found that the following method works. Define a metaclass with all of the class properties and setters you want. IE, I wanted a class with a title property with a setter. Here's what I wrote:
class TitleMeta(type):
#property
def title(self):
return getattr(self, '_title', 'Default Title')
#title.setter
def title(self, title):
self._title = title
# Do whatever else you want when the title is set...
Now make the actual class you want as normal, except have it use the metaclass you created above.
# Python 2 style:
class ClassWithTitle(object):
__metaclass__ = TitleMeta
# The rest of your class definition...
# Python 3 style:
class ClassWithTitle(object, metaclass = TitleMeta):
# Your class definition...
It's a bit weird to define this metaclass as we did above if we'll only ever use it on the single class. In that case, if you're using the Python 2 style, you can actually define the metaclass inside the class body. That way it's not defined in the module scope.
def _create_type(meta, name, attrs):
type_name = f'{name}Type'
type_attrs = {}
for k, v in attrs.items():
if type(v) is _ClassPropertyDescriptor:
type_attrs[k] = v
return type(type_name, (meta,), type_attrs)
class ClassPropertyType(type):
def __new__(meta, name, bases, attrs):
Type = _create_type(meta, name, attrs)
cls = super().__new__(meta, name, bases, attrs)
cls.__class__ = Type
return cls
class _ClassPropertyDescriptor(object):
def __init__(self, fget, fset=None):
self.fget = fget
self.fset = fset
def __get__(self, obj, owner):
if self in obj.__dict__.values():
return self.fget(obj)
return self.fget(owner)
def __set__(self, obj, value):
if not self.fset:
raise AttributeError("can't set attribute")
return self.fset(obj, value)
def setter(self, func):
self.fset = func
return self
def classproperty(func):
return _ClassPropertyDescriptor(func)
class Bar(metaclass=ClassPropertyType):
__bar = 1
#classproperty
def bar(cls):
return cls.__bar
#bar.setter
def bar(cls, value):
cls.__bar = value
bar = Bar()
assert Bar.bar==1
Bar.bar=2
assert bar.bar==2
nbar = Bar()
assert nbar.bar==2
I happened to come up with a solution very similar to #Andrew, only DRY
class MetaFoo(type):
def __new__(mc1, name, bases, nmspc):
nmspc.update({'thingy': MetaFoo.thingy})
return super(MetaFoo, mc1).__new__(mc1, name, bases, nmspc)
#property
def thingy(cls):
if not inspect.isclass(cls):
cls = type(cls)
return cls._thingy
#thingy.setter
def thingy(cls, value):
if not inspect.isclass(cls):
cls = type(cls)
cls._thingy = value
class Foo(metaclass=MetaFoo):
_thingy = 23
class Bar(Foo)
_thingy = 12
This has the best of all answers:
The "metaproperty" is added to the class, so that it will still be a property of the instance
Don't need to redefine thingy in any of the classes
The property works as a "class property" in for both instance and class
You have the flexibility to customize how _thingy is inherited
In my case, I actually customized _thingy to be different for every child, without defining it in each class (and without a default value) by:
def __new__(mc1, name, bases, nmspc):
nmspc.update({'thingy': MetaFoo.services, '_thingy': None})
return super(MetaFoo, mc1).__new__(mc1, name, bases, nmspc)
If you only need lazy loading, then you could just have a class initialisation method.
EXAMPLE_SET = False
class Example(object):
#classmethod
def initclass(cls):
global EXAMPLE_SET
if EXAMPLE_SET: return
cls.the_I = 'ok'
EXAMPLE_SET = True
def __init__( self ):
Example.initclass()
self.an_i = 20
try:
print Example.the_I
except AttributeError:
print 'ok class not "loaded"'
foo = Example()
print foo.the_I
print Example.the_I
But the metaclass approach seems cleaner, and with more predictable behavior.
Perhaps what you're looking for is the Singleton design pattern. There's a nice SO QA about implementing shared state in Python.
In a class, I want to define N persistent properties. I can implement them as follow:
#property
def prop1(self):
return self.__prop1
#prop1.setter
def prop1(self, value):
self.__prop1 = value
persistenceManagement()
#property
def prop2(self):
return self.__prop2
#prop2.setter
def prop2(self, value):
self.__prop2 = value
persistenceManagement()
[...]
#property
def propN(self):
return self.__propN
#propN.setter
def propN(self, value):
self.__propN = value
persistenceManagement()
Of course, the only different thing between these blocks is the property name (prop1, prop2, ..., propN). persistenceManagement() is a function that has to be called when the value of one of these property changes.
Since these blocks of code are identical except for a single information (i.e., the property name), I suppose there must be some way to replace each of these blocks by single lines declaring the existence of a persistent property with a given name. Something like
def someMagicalPatternFunction(...):
[...]
someMagicalPatternFunction("prop1")
someMagicalPatternFunction("prop2")
[...]
someMagicalPatternFunction("propN")
...or maybe some decorating trick that I cannot see at the moment. Is someone has an idea how this could be done?
Properties are just descriptor classes and you can create your own and use them:
class MyDescriptor(object):
def __init__(self, name, func):
self.func = func
self.attr_name = '__' + name
def __get__(self, instance, owner):
return getattr(self, self.attr_name)
def __set__(self, instance, value):
setattr(self, self.attr_name, value)
self.func(self.attr_name)
def postprocess(attr_name):
print 'postprocess called after setting', attr_name
class Example(object):
prop1 = MyDescriptor('prop1', postprocess)
prop2 = MyDescriptor('prop2', postprocess)
obj = Example()
obj.prop1 = 'answer' # prints 'postprocess called after setting __prop1'
obj.prop2 = 42 # prints 'postprocess called after setting __prop2'
Optionally you can make it a little easier to use with something like this:
def my_property(name, postprocess=postprocess):
return MyDescriptor(name, postprocess)
class Example(object):
prop1 = my_property('prop1')
prop2 = my_property('prop2')
If you like the decorator # syntax, you could do it this way (which also alleviates having to type the name of the property twice) -- however the dummy functions it requires seem a little weird...
def my_property(method):
name = method.__name__
return MyDescriptor(name, postprocess)
class Example(object):
#my_property
def prop1(self): pass
#my_property
def prop2(self): pass
The property class (yes it's a class) is just one possible implementation of the descriptor protocol (which is fully documented here: http://docs.python.org/2/howto/descriptor.html). Just write your own custom descriptor and you'll be done.