I'm trying to change the datetime format from "2019-02-08 15:00" to "8 feb", but the hour and minute seems to stop me from doing this in an easy way.
The variable containing this info is my_task['due']['string'] and if I print it I get "2019-02-08 15:00".
Then I run this code:
variabel = time.strftime('%d %b', my_task['due']['string'])
But I am getting the error:
TypeError: argument must be sequence of length 9, not 16
In PHP, which I'm quite good at, this is easy peasy, but I'm guessing I'm missing some small detail here. Can someone please give me a push in the right direction?
Appears that you are working with datetime strings and not datetime objects, so you will first need to create a datetime object from your string in order to use datetime.strftime() to reformat it.
Also note that datetime objects and time objects are not the same despite sharing some common methods.
For example:
from datetime import datetime
formatted = datetime.strptime('2019-02-08 15:00', '%Y-%m-%d %H:%M').strftime('%d %b')
print(formatted)
# OUTPUT
# 08 Feb
Related
I need to get time in python and i am using time.ctime() and it returns this Thu Jul 8 15:37:26 2021
But i only need 15:37:26 and i cant figure out how to get only this and not the date and year.
I already tried using datetime where i could not figure it out either so im trying with time now.
here is a bit of code for the context:
cas = time.ctime()
cas = str(cas)
api.update_status('nyni je:'+ cas )
time.sleep(60)
Anyone know how to do it?
print(datetime.datetime.now().time().isoformat(timespec='seconds'))
import datetime
print(datetime.datetime.now().strftime("%H:%M:%S"))
imports
from datetime import datetime
code
now = datetime.now()
cas = now.strftime("%H:%M:%S")
print(cas)
You can use strftime to convert a datetime value to a string of a certain format. In your case you can use %H:%M:%S to only get the time. The same function can be used to get the date as well, you can read more here.
Take a look at the "strftime() and strptime() Format Codes" section also for how you can format it.
I get time data from API response like '2020-02-25T20:53:06.706401+07:00'. Now I want to convert to %Y-%m-%d %H:%M:%s format. But I do not know exactly standard format of that time data.
Help me find the time format!
In your case you can use datetime.fromisoformat:
from datetime import datetime
datetime_object = datetime.fromisoformat("2020-02-25T20:53:06.706401+07:00")
print(datetime_object.strftime("%Y-%m-%d %H:%M:%s"))
Prints
2020-02-25 20:53:1582656786
Other options:
Use the third party dateutil library
Use datetime.strptime which parses the string according to format
You can convert to a datetime object and then optionally recreate the string in a new format as follows:
from datetime import datetime
d = "2020-02-25T20:53:06.706401+07:00"
dt = datetime.strptime(d, "%Y-%m-%dT%H:%M:%S.%f%z")
# Note the capital S
new = dt.strftime("%Y-%m-%d %H:%M:%S")
However the new value here has lost the timezone offset information. I assume that's OK for you. I also used %S instead of %s since I assume that's really what you want. The lowercase %s wouldn't really make sense, and is also not truly supported by Python.
I am trying to use timestamp information to graph.
However, when I convert the number into hh:mm:ss. It does not work.
I have tried this:
timestamp = [dt.strptime(str(datetime.timedelta(seconds=round(t/1000))),'%H:%M:%S') for t in timestamp1]
Also I tried this
timestamp = [dt.strftime(dt.strptime(str(datetime.timedelta(seconds=round(t / 1000))), '%H:%M:%S'), '%H:%M:%S') for t in timestamp]
However, it is possible to see the list with the new values. However, I have problems with the graphs and these new values.
Can anybody help me?
Try using this and make sure to import the time module!
timestamp = [time.strftime('%H:%M:%S', time.gmtime(t/1000)) for t in timestamp1]
In your code you're using datetime.strptime(date_string, format) function, it's main use is to parse time strings in order to create datetime object.
In order to get a parsed string of a desired format you should use date.strftime(format) function instead.
So basically in your code you can only add it and should get the wanted result:
import datetime
from datetime import datetime as dt
timestamp = [dt.strftime(dt.strptime(str(datetime.timedelta(seconds=round(t / 1000))), '%H:%M:%S'), '%H:%M:%S') for t in timestamp1]
I'm not sure what was your input and desired output, but you could also use date.fromtimestamp(timestamp) for the parsing of timestamps
I have a field that shows time as 1900-01-01 00:05:00 but I want to show it as just 00:05:00 i.e. just five minutes.
I have been looking at the python documentation and it is driving me crazy. From the question How do I find the time difference between two datetime objects in python? it looks like is should be something do with timedelta but I am not getting any closer to a solution. The question Converting Date/Time to Just Time suggests you can just use a format tag but that is not working for me. I also looked at converting date time to string without success, I know this is something simple but I have looked at hundreds of pages looking for something simple. All help would be appreciated.
Say you have a Datetime object now:
now.time().strftime('%H:%M:%S')
Load the string with strptime() and get the time() component:
>>> from datetime import datetime
>>> s = "1900-01-01 00:05:00"
>>> dt = datetime.strptime(s, "%Y-%m-%d %H:%M:%S")
>>> dt.time().isoformat()
'00:05:00'
Here we are dumping the time with isoformat() in ISO 8601 format, but you can also dump the datetime.time back to string with strftime():
>>> dt.time().strftime("%H:%M:%S")
'00:05:00'
I am somewhat new to Python and have a seemingly simple question.
I have a python script that interacts with an API (RHN Satellite if you're curious). This API returns a date in the form of a string and it always trims leading 0's. For example, 6/1/13 or 10/9/12. I need to convert this string to a date and determine the day of the year it is.
Here is what I know:
today = datetime.datetime.now()
print today.strftime('%j')
...will return today's day of year (175). This works fine for a datetime object but I am having trouble converting the string given by the API to an actual date. If I use:
date = datetime.datetime.strptime(var, '%m/%d/$y')
I get error:
ValueError: time data '5/2/13' does not match format '%m/%d/$y'
I'm guessing because it's expecting leading 0's ? How do I get around this?
In the end, I am trying to subtract the variable date given from the current date but I can't do that until I convert the string.
Thanks for the help!
I think you just have a typo, use %y instead of $y:
date = datetime.datetime.strptime(var, '%m/%d/%y')
This code works for me, provided you change $y to %y in the format code.
Correct the $y to %y and I'd use format instead of strftime:
from datetime import datetime
print format(datetime.strptime('5/2/13', '%m/%d/%y'), '%j')