How to replace the input with url - python

Hello there I want to code a python program, that opens a website. When you just type a shortcut e.g. "google" it will open "https://www.google.de/". The problem is that it won´t open the right url.
import webbrowser
# URL list
google = "https://www.google.de"
ebay = "https://www.ebay.de/"
# shortcuts
Websites = ("google", "ebay")
def inputString():
inputstr = input()
if inputString(google) = ("https://www.google.de")
else:
print("Please look for the right shortcut.")
return
url = inputString()
webbrowser.open(url)

Using your example you can do:
google = "https://www.google.de"
ebay = "https://www.ebay.de/"
def inputString():
return input()
if inputString() == "google":
url = google
webbrowser.open(url)
Or you can do it the simple way as #torxed said:
inputstr = input()
sites = {'google' : 'https://google.de', 'ebay':'https://www.ebay.de/'}
if inputstr in sites:
webbrowser.open(sites[inputstr])

How about:
import webbrowser
import sys
websites = {
"google":"https://www.google.com",
"ebay": "https://www.ebay.com"
}
if __name__ == "__main__":
try:
webbrowser.open(websites[sys.argv[1]])
except:
print("Please look for the right shortcut:")
for website in websites:
print(website)
run like so python browse.py google

Related

How can i use my python script as proxy for urls

i have a script that check the input link, if it's equivalent to one i specified in the code, then it will use my code, else it open the link in chrome.
i want to make that script kind of as a default browser, as to gain speed compared to opening the browser, getting the link with an help of an extension and then send it to my script using POST.
i used procmon to check where the process in question query the registry key and it seem like it tried to check HKCU\Software\Classes\ChromeHTML\shell\open\command so i added a some key there and in command, i edited the content of the key with my script path and arguments (-- %1)(-- only here for testing purposes)
unfortunately, once the program query this to send a link, windows prompt to choose a browser instead of my script, which isn't what i want.
Any idea?
in HKEY_CURRENT_USER\Software\Classes\ChromeHTML\Shell\open\command Replace the value in default with "C:\Users\samdra.r\AppData\Local\Programs\Python\Python39\pythonw.exe" "[Script_path_here]" %1
when launching a link, you'll be asked to set a default browser only once (it ask for a default browser for each change you make to the key):
i select chrome in my case
as for the python script, here it is:
import sys
import browser_cookie3
import requests
from bs4 import BeautifulSoup as BS
import re
import os
import asyncio
import shutil
def Prep_download(args):
settings = os.path.abspath(__file__.split("NewAltDownload.py")[0]+'/settings.txt')
if args[1] == "-d" or args[1] == "-disable":
with open(settings, 'r+') as f:
f.write(f.read()+"\n"+"False")
print("Background program disabled, exiting...")
exit()
if args[1] == "-e" or args[1] == "-enable":
with open(settings, 'r+') as f:
f.write(f.read()+"\n"+"True")
link = args[-1]
with open(settings, 'r+') as f:
try:
data = f.read()
osupath = data.split("\n")[0]
state = data.split("\n")[1]
except:
f.write(f.read()+"\n"+"True")
print("Possible first run, wrote True, exiting...")
exit()
if state == "True":
asyncio.run(Download_map(osupath, link))
async def Download_map(osupath, link):
if link.split("/")[2] == "osu.ppy.sh" and link.split("/")[3] == "b" or link.split("/")[3] == "beatmapsets":
with requests.get(link) as r:
link = r.url.split("#")[0]
BMID = []
id = re.sub("[^0-9]", "", link)
for ids in os.listdir(os.path.abspath(osupath+("/Songs/"))):
if re.match(r"(^\d*)",ids).group(0).isdigit():
BMID.append(re.match(r"(^\d*)",ids).group(0))
if id in BMID:
print(link+": Map already exist")
os.system('"'+os.path.abspath("C:/Program Files (x86)/Google/Chrome/Application/chrome.exe")+'" '+link)
return
if not id.isdigit():
print("Invalid id")
return
cj = browser_cookie3.load()
print("Downloading", link, "in", os.path.abspath(osupath+"/Songs/"))
headers = {"referer": link}
with requests.get(link) as r:
t = BS(r.text, 'html.parser').title.text.split("·")[0]
with requests.get(link+"/download", stream=True, cookies=cj, headers=headers) as r:
if r.status_code == 200:
try:
id = re.sub("[^0-9]", "", link)
with open(os.path.abspath(__file__.split("NewAltDownload.pyw")[0]+id+" "+t+".osz"), "wb") as otp:
otp.write(r.content)
shutil.copy(os.path.abspath(__file__.split("NewAltDownload.pyw")[0]+id+" "+t+".osz"),os.path.abspath(osupath+"/Songs/"+id+" "+t+".osz"))
except:
print("You either aren't connected on osu!'s website or you're limited by the API, in which case you now have to wait 1h and then try again.")
else:
os.system('"'+os.path.abspath("C:/Program Files (x86)/Google/Chrome/Application/chrome.exe")+'" '+link)
args = sys.argv
if len(args) == 1:
print("No arguments provided, exiting...")
exit()
Prep_download(args)
you obtain the argument %1 (the link) with sys.argv()[-1] (since sys.argv is a list) and from there, you just check if the link is similar to the link you're looking for (in my case it need to look like https://osu.ppy.sh/b/ or https://osu.ppy.sh/beatmapsets/)
if that's the case, do some code, else, just launch chrome with chrome executable and the link as argument. and if the id of the beatmap is found in the Songs folder, then i also open the link in chrome.
to make it work in the background i had to fight with subprocesses and even more tricks, and at the end, it started working suddenly with pythonw and .pyw extension.

How to split selenium python code into multiply functions

I'm writing a python program which will test some functions on website. It will log in to this site, check it version and do some tests on it regarding the site version. I want to write few tests for this site but few things will repeat, for example login to the site.
I try to split my code into functions, like hue_login() and use it on every test I need to login to the site. To login to site I use selenium webdriver. So If I split the code into small functions and try to use it in other function where I also use selenium webdriver I end up with two browser windows. One from my hue_login() function where function log me in. And second browser window where it try to put url where I want to go after I log in to the site interface. Of course, because I am not login into the second browser window, site wont show and other tests will fail (tests from this second function).
Example:
def hue_version():
url = global_var.domain + global_var.about
response = urllib.request.urlopen(url)
htmlparser = etree.HTMLParser()
xpath = etree.parse(response, htmlparser).xpath('/html/body/div[4]/div/div/h2/text()')
string = "".join(xpath)
pattern = re.compile(r'(\d{1,2}).(\d{1,2}).(\d{1,2})')
return pattern.search(string).group()
hue_ver = hue_version()
print(hue_ver)
if hue_ver == '3.9.0':
do something
elif hue_version == '3.7.0':
do something else
else:
print("Hue version not recognized!")
def hue_login():
driver = webdriver.Chrome(global_var.chromeDriverPath)
driver.get(global_var.domain + global_var.loginPath)
input_username = driver.find_element_by_name('username')
input_password = driver.find_element_by_name('password')
input_username.send_keys(username)
input_password.send_keys(password)
input_password.submit()
sleep(1)
driver.find_element_by_id('jHueTourModalClose').click()
def file_browser():
hue_login()
click_file_browser_link = global_var.domain + global_var.fileBrowserLink
driver = webdriver.Chrome(global_var.chromeDriverPath)
driver.get(click_file_browser_link)
How can I call hue_login() from file_browser() function that rest of the code from file_browser() will be executed in the same window opened by hue_login()?
Here you go:
driver = webdriver.Chrome(global_var.chromeDriverPath)
def hue_login():
driver.get(global_var.domain + global_var.loginPath)
input_username = driver.find_element_by_name('username')
input_password = driver.find_element_by_name('password')
input_username.send_keys(username)
input_password.send_keys(password)
input_password.submit()
sleep(1)
driver.find_element_by_id('jHueTourModalClose').click()
def file_browser():
hue_login()
click_file_browser_link = global_var.domain + global_var.fileBrowserLink
driver.get(click_file_browser_link)

extracting hyperlinks in python.

Im trying to make a simple web browser in python. (i'm a novice programmer and this is the first time I'm using python.)
I'm aware that i have to save my links in a list and create a function to to go to my url overtime sees that list but i have no idea how to do that. I would very much appreciate it if someone could please help me with that.
Heading
Here's my code: #!/usr/bin/env python
import urllib
url = "http://google.com"
data = urllib.urlopen(url)
tokens = data.read().split()
List=[]
for token in tokens:
if token == '<body>':
print ''
elif token == '</body>':
print ''
#elif token[6:-2] == '<a href':
else:
enter code here
print token,
selectedLink = raw_input('Select a link:')

Taking an argument from user (URL)

Does anyone know how I would be able to take the the URL as an argument in Python as page?
Just to readline in the script, user inputs into the shell and pass it through as an argument just to make the script more portable?
import sys, re
import webpage_get
def print_links(page):
''' find all hyperlinks on a webpage passed in as input and
print '''
print '\n[*] print_links()'
links = re.findall(r'(\http://\w+\.\w+[-_]*\.*\w+\.*?\w+\.*?\w+\.*[//]*\.*?\w+ [//]*?\w+[//]*?\w+)', page)
# sort and print the links
links.sort()
print '[+]', str(len(links)), 'HyperLinks Found:'
for link in links:
print link
def main():
# temp testing url argument
sys.argv.append('http://www.4chan.org')
# Check args
if len(sys.argv) != 2:
print '[-] Usage: webpage_getlinks URL'
return
# Get the web page
page = webpage_get.wget(sys.argv[1])
# Get the links
print_links(page)
if __name__ == '__main__':
main()
It looks like you kind of got started with command line arguments but just to give you an example for this specific situation you could do something like this:
def main(url):
page = webpage_get.wget(url)
print_links(page)
if __name__ == '__main__':
url = ""
if len(sys.argv >= 1):
url = sys.argv[0]
main(url)
Then run it from shell like this
python test.py http://www.4chan.org
Here is a tutorial on command line arguments which may help your understanding more than this snippet http://www.tutorialspoint.com/python/python_command_line_arguments.htm
Can you let me know if I miss understood your question? I didn't feel to confident in the meaning after I read it.

Looking for multiple things in a string

I am trying to make a script that opens a url when the OPEN command is entered. This is for an IRC bot I am creating. I am trying to make it like this
OPEN http://url.com and it opens the url. This is what I have so far.
import webbrowser
test = s.recv(1024)
if test.find("http://") != 1:
webbrowser.open(test)
else:
print "it didnt work"
I honestly have no idea how this is done.
I figured it out
import webbrowser
#command is OPEN http://url.com
a = raw_input("Command: ")
if "OPEN" in a:
url = a.strip("OPEN ")
webbrowser.open(url)

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