Develop Reference

Why is my gif appearing only after my function finishes running [duplicate]

I have got this problem. I´m trying to set text on a lineEdit object on pyqt4, then wait for a few seconds and changing the text of the same lineEdit. For this I´m using the time.sleep() function given on the python Time module. But my problem is that instead of setting the text, then waiting and finally rewrite the text on the lineEdit, it just waits the time it´s supposed to sleep and only shows the final text. My code is as follows:
from PyQt4 import QtGui
from gui import *
class Ventana(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setupUi(self)
self.button.clicked.connect(self.testSleep)
def testSleep(self):
import time
self.lineEdit.setText('Start')
time.sleep(2)
self.lineEdit.setText('Stop')
def mainLoop(self, app ):
sys.exit( app.exec_())
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = Ventana()
window.show()
sys.exit(app.exec_())

You can't use time.sleep here because that freezes the GUI thread, so the GUI will be completely frozen during this time.
You should probably use a QTimer and use it's timeout signal to schedule a signal for deferred delivery, or it's singleShot method.
For example (adapted your code to make it run without dependencies):
from PyQt4 import QtGui, QtCore
class Ventana(QtGui.QWidget):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setLayout(QtGui.QVBoxLayout())
self.lineEdit = QtGui.QLineEdit(self)
self.button = QtGui.QPushButton('clickme', self)
self.layout().addWidget(self.lineEdit)
self.layout().addWidget(self.button)
self.button.clicked.connect(self.testSleep)
def testSleep(self):
self.lineEdit.setText('Start')
QtCore.QTimer.singleShot(2000, lambda: self.lineEdit.setText('End'))
def mainLoop(self, app ):
sys.exit( app.exec_())
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = Ventana()
window.show()
sys.exit(app.exec_())

Also, take a look at the QThread sleep() function, it puts the current thread to sleep and allows other threads to run. https://doc.qt.io/qt-5/qthread.html#sleep

You can't use time.sleep here because that freezes the GUI thread, so the GUI will be completely frozen during this time.You can use QtTest module rather than time.sleep().
from PyQt4 import QtTest
QtTest.QTest.qWait(msecs)
So your code should look like:
from PyQt4 import QtGui,QtTest
from gui import *
class Ventana(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setupUi(self)
self.button.clicked.connect(self.testSleep)
def testSleep(self):
import time
self.lineEdit.setText('Start')
QtTest.QTest.qWait(2000)
self.lineEdit.setText('Stop')
def mainLoop(self, app ):
sys.exit( app.exec_())
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = Ventana()
window.show()
sys.exit(app.exec_())

Timers cannot be stopped from another thread - Remove Focus

import sys
from PyQt5.QtCore import QThread
from PyQt5.QtWidgets import QApplication, QWidget, QVBoxLayout, QLineEdit
class Worker(QThread):
def __init__(self, textBox):
super().__init__()
self.textBox = textBox
def run(self):
while True:
if self.textBox.text() == "close":
app.quit()
break
if self.textBox.text() == "removeFocus":
self.textBox.clearFocus()
class window(QWidget):
def __init__(self):
super().__init__()
vBox = QVBoxLayout()
self.setLayout(vBox)
self.resize(600, 400)
textBox = QLineEdit()
vBox.addWidget(textBox)
worker = Worker(textBox)
worker.start()
self.show()
if __name__ == "__main__":
app = QApplication(sys.argv)
window = window()
sys.exit(app.exec())
When I type "close" in the textBox it works very fine but when I type "removeFocus", it still works but I get this error:
QObject::killTimer: Timers cannot be stopped from another thread
Why am I getting such an error even though the program is running?
(Since the process I want to do is very simple, I don't think I can go into much detail. I've just started learning Python. This is the first time I use this site. I'm sorry if I made a mistake while creating a post. Thank you)

In Qt you must not access or modify the GUI information from another thread (see this for more information) since it does not guarantee that it works (the GUI elements are not thread-safe), in your case luckily you have no problems but It is dangerous to use your approach in real.
In your case it is also unnecessary to use threads since it is enough to use the textChanged signal from QLineEdit.
import sys
from PyQt5.QtCore import pyqtSlot
from PyQt5.QtWidgets import QApplication, QWidget, QVBoxLayout, QLineEdit
class Window(QWidget):
def __init__(self):
super().__init__()
vBox = QVBoxLayout(self)
self.resize(600, 400)
self.textBox = QLineEdit()
vBox.addWidget(self.textBox)
self.textBox.textChanged.connect(self.on_text_changed)
#pyqtSlot(str)
def on_text_changed(self, text):
if text == "close":
QApplication.quit()
elif text == "removeFocus":
self.textBox.clearFocus()
if __name__ == "__main__":
app = QApplication(sys.argv)
window = Window()
window.show()
sys.exit(app.exec())

PyQt5 QFileDialog stops application from closing

I am trying to write a PyQt5 application that does the following:
Creates and opens a Main Window. The MainWindow has a function that opens a QFileDialog window.
Function to open QFileDialog can be triggered in two ways (1) from a file menu option called 'Open' (2) automatically, after the Main window is shown.
My problem is that I haven't found a way to get the QfileDialog to automatically open (2) that doesn't cause the application to hang when the main window is closed. Basic example of code can be found below:
import sys
from PyQt5.QtWidgets import (QApplication, QMainWindow, QMenuBar, QWidget,
QHBoxLayout, QCalendarWidget, QScrollArea, QFileDialog, QAction, QFrame)
from PyQt5.QtGui import QIcon
from PyQt5.QtCore import Qt
class MainWindow(QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.openAction = QAction(QIcon('/usr/share/icons/breeze/places/64/folder-open.svg'), 'Open', self)
self.openAction.triggered.connect(self.openDialog)
self.menubar = QMenuBar(self)
fileMenu = self.menubar.addMenu('&File')
fileMenu.addAction(self.openAction)
self.event_widgets = EventWidgets(self)
self.setMenuBar(self.menubar)
self.setCentralWidget(self.event_widgets)
def openDialog(self):
ics_path = QFileDialog.getOpenFileName(self, 'Open file', '/home/michael/')
class EventWidgets(QWidget):
def __init__(self, parent):
super(EventWidgets, self).__init__(parent)
self.initUI()
def initUI(self):
self.calendar = QCalendarWidget(self)
self.frame = QFrame()
self.scrollArea = QScrollArea()
self.scrollArea.setWidget(self.frame)
horizontal_box = QHBoxLayout()
horizontal_box.addWidget(self.calendar)
horizontal_box.addWidget(self.scrollArea)
self.setLayout(horizontal_box)
if __name__ == '__main__':
app = QApplication(sys.argv)
app_window = MainWindow()
app_window.showMaximized()
app_window.openDialog()
sys.exit(app.exec_())
Code has been tested on KDE Neon and Arch Linux, both have same issue.
I can get round this issue by handling the close event of the Main Window manually - i.e. adding this function to MainWindow:
def closeEvent(self, event):
sys.exit()
But I am not sure a) why this is necessary b) if it is best practice.

I tried your code on macOS Sierra and it works as it's supposed to. However I would propose a different approach to solve your problem.
What you could do is to implement the showEvent() function in your MainWindow class, which is executed whenever a widget is displayed (either using .show() or .showMaximized()) and trigger your custom slot to open the QFileDialog. When doing this you could make use of a single shot timer to trigger the slot with some minimal delay: the reason behind this is that if you simply open the dialog from within the showEvent(), you will see the dialog window but not the MainWindow below it (because the QFileDialog is blocking the UI until the user perform some action). The single shot timer adds some delay to the opening of the QFileDialog, and allows the MainWindow to be rendered behind the modal dialog. Here is a possible solution (not that I made some minor changes to your code, which you should be able to easily pick up):
import sys
from PyQt5 import QtCore
from PyQt5 import QtWidgets
class MainWindow(QtWidgets.QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.openAction = QtWidgets.QAction('Open', self)
self.openAction.triggered.connect(self.openDialog)
menuBar = self.menuBar()
fileMenu = menuBar.addMenu('&File')
fileMenu.addAction(self.openAction)
self.event_widgets = EventWidgets(self)
self.setCentralWidget(self.event_widgets)
def showEvent(self, showEvent):
QtCore.QTimer.singleShot(50, self.openDialog)
#QtCore.pyqtSlot()
def openDialog(self):
ics_path = QtWidgets.QFileDialog.getOpenFileName(self, 'Open file', '/Users/daniele/')
class EventWidgets(QtWidgets.QWidget):
def __init__(self, parent):
super(EventWidgets, self).__init__(parent)
self.calendar = QtWidgets.QCalendarWidget(self)
self.frame = QtWidgets.QFrame()
self.scrollArea = QtWidgets.QScrollArea()
self.scrollArea.setWidget(self.frame)
horizontal_box = QtWidgets.QHBoxLayout()
horizontal_box.addWidget(self.calendar)
horizontal_box.addWidget(self.scrollArea)
self.setLayout(horizontal_box)
if __name__ == '__main__':
app = QtWidgets.QApplication(sys.argv)
app_window = MainWindow()
app_window.showMaximized()
sys.exit(app.exec_())

Put an Image on a QPushButton

I'm a beginner in PyQt and I have an image known as add.gif. I need to put this image in a QPushButton but I don't know how.

Example:
from PyQt4 import QtGui, QtCore
class Window(QtGui.QWidget):
def __init__(self):
QtGui.QWidget.__init__(self)
self.button = QtGui.QPushButton('', self)
self.button.clicked.connect(self.handleButton)
self.button.setIcon(QtGui.QIcon('myImage.jpg'))
self.button.setIconSize(QtCore.QSize(24,24))
layout = QtGui.QVBoxLayout(self)
layout.addWidget(self.button)
def handleButton(self):
pass
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = Window()
window.show()
sys.exit(app.exec_())

Here is the same example from #NorthCat but for PyQt5:
from PyQt5 import QtGui, QtCore
from PyQt5.QtWidgets import QWidget, QApplication, QPushButton, QVBoxLayout
class Window(QWidget):
def __init__(self):
QWidget.__init__(self)
self.button = QPushButton('', self)
self.button.clicked.connect(self.handleButton)
self.button.setIcon(QtGui.QIcon('myImage.jpg'))
self.button.setIconSize(QtCore.QSize(200,200))
layout = QVBoxLayout(self)
layout.addWidget(self.button)
def handleButton(self):
pass
if __name__ == '__main__':
import sys
app = QApplication(sys.argv)
window = Window()
window.show()
sys.exit(app.exec_())

Assuming pyqt supports gif pictures, this should work
icon = QtGui.QPixmap('add.gif')
button = QtGui.QPushButton()
button.setIcon(icon)
QPushButton
Push buttons display a textual label, and optionally a small icon.
These can be set using the constructors and changed later using
setText() and setIcon(). If the button is disabled, the appearance of
the text and icon will be manipulated with respect to the GUI style to
make the button look "disabled".

Problem in understanding connectSlotsByName() in pyqt?

I couldn't understand the connectSlotsByName() method which is predominently used by pyuic4.. As far the class is single in a PyQt file it's ok since we can use self which will be associated with a single object throughout.. But when we try to use various classes from different files the problem and the need to use connectSlotsByName() arises.. Here's what i encountered which is weird..
I created a stacked widget..
I placed my first widget on it.. It
has a button called "Next >".
On clicking next it hides the current
widget and adds another widget which has the "click me" button..
The problem here is the click event for "click me" button in second is not captured.. It's a minimal example that i can give for my original problem.. Please help me..
This is file No.1..(which has the parent stacked widget and it's first page). On clicking next it adds the second page which has "clickme" button in file2..
from PyQt4 import QtCore, QtGui
import file2
class Ui_StackedWidget(QtGui.QStackedWidget):
def __init__(self,parent=None):
QtGui.QStackedWidget.__init__(self,parent)
self.setObjectName("self")
self.resize(484, 370)
self.setWindowTitle(QtGui.QApplication.translate("self", "stacked widget", None, QtGui.QApplication.UnicodeUTF8))
self.createWidget1()
def createWidget1(self):
self.page=QtGui.QWidget()
self.page.setObjectName("widget1")
self.pushButton=QtGui.QPushButton(self.page)
self.pushButton.setGeometry(QtCore.QRect(150, 230, 91, 31))
self.pushButton.setText(QtGui.QApplication.translate("self", "Next >", None, QtGui.QApplication.UnicodeUTF8))
self.addWidget(self.page)
QtCore.QMetaObject.connectSlotsByName(self.page)
QtCore.QObject.connect(self.pushButton,QtCore.SIGNAL('clicked()'),self.showWidget2)
def showWidget2(self):
self.page.hide()
obj=file2.widget2()
obj.createWidget2(self)
if __name__ == "__main__":
import sys
app = QtGui.QApplication(sys.argv)
ui = Ui_StackedWidget()
ui.show()
sys.exit(app.exec_())
Here's file2
from PyQt4 import QtGui,QtCore
class widget2():
def createWidget2(self,parent):
self.page = QtGui.QWidget()
self.page.setObjectName("page")
self.parent=parent
self.groupBox = QtGui.QGroupBox(self.page)
self.groupBox.setGeometry(QtCore.QRect(30, 20, 421, 311))
self.groupBox.setObjectName("groupBox")
self.groupBox.setTitle(QtGui.QApplication.translate("self", "TestGroupBox", None, QtGui.QApplication.UnicodeUTF8))
self.pushButton = QtGui.QPushButton(self.groupBox)
self.pushButton.setGeometry(QtCore.QRect(150, 120, 92, 28))
self.pushButton.setObjectName("pushButton")
self.pushButton.setText(QtGui.QApplication.translate("self", "Click Me", None, QtGui.QApplication.UnicodeUTF8))
self.parent.addWidget(self.page)
self.parent.setCurrentWidget(self.page)
QtCore.QMetaObject.connectSlotsByName(self.page)
QtCore.QObject.connect(self.pushButton,QtCore.SIGNAL('clicked()'),self.printMessage)
def printMessage(self):
print("Hai")
Though in both the widgets(i mean pages)
QtCore.QMetaObject.connectSlotsByName(self.page)
the clicked signal in second dialog isn't getting processed. Thanks in advance.. Might be a beginner question..

A better question is "Why not just use new-style signals and slots?". They're much simpler and don't require any weird naming conventions:
from sys import argv, exit
from PyQt4 import QtCore, QtGui
class MyWidget(QtGui.QWidget):
def __init__(self, parent=None):
super(MyWidget, self).__init__(parent)
self._layout = QtGui.QVBoxLayout()
self.setLayout(self._layout)
self._button = QtGui.QPushButton()
self._button.setText('Click NOW!')
self._layout.addWidget(self._button)
self._button.clicked.connect(self._printMessage)
#QtCore.pyqtSlot()
def _printMessage(self):
print("Hai")
if __name__ == "__main__":
app = QtGui.QApplication(argv)
main = MyWidget()
main.show()
exit(app.exec_())

At first, here is the minimal working example:
from sys import argv, exit
from PyQt4 import QtCore, QtGui
class widget2(QtGui.QWidget):
def __init__(self, args):
self.app = MainApp(args)
QtGui.QWidget.__init__(self)
self.setObjectName('I')
self._layout = QtGui.QVBoxLayout(self)
self.setLayout(self._layout)
self.pushButtoninWidget2 = QtGui.QPushButton(self)
self.pushButtoninWidget2.setObjectName("pushButtoninWidget2")
self.pushButtoninWidget2.setText('Click NOW!')
self._layout.addWidget(self.pushButtoninWidget2)
QtCore.QMetaObject.connectSlotsByName(self)
#QtCore.pyqtSlot()
def on_pushButtoninWidget2_clicked(self):
print("Hai")
class MainApp(QtGui.QApplication):
def __init__(self, args):
QtGui.QApplication.__init__(self, args)
if __name__ == "__main__":
main = widget2(argv)
main.show()
exit(main.app.exec_())
When you trying to connect slots by name, you must give proper names to the slots and then someone (moc, uic, or you by calling connectSlotsByName) must connect them. Proper name for such a slot is: "on_PyQtObjectName_PyQtSignalName".
Note, that, if I'd omitted #QtCore.pyqtSlot() in the example, slot would be executed once for every appropriate overload (twice in this case).
You DO need to call connectSlotsByNames directly, cause there is no moc, which do it for you when you use QT in C++, and you do not use uic and .ui file. If you want to connect slots implicitly (I'm always doing so, except slots, connected directly in .ui), you'd better use more pytonish syntaxe: button.clicked.connect(self._mySlot).
And take a look at https://riverbankcomputing.com/static/Docs/PyQt5/signals_slots.html#connecting-slots-by-name

You do not need to call connectSlotsByName(), just remove those lines.
In file2, calling QtCore.QMetaObject.connectSlotsByName(self.page) tries to do this:
QtCore.QObject.connect(self.pushButton, QtCore.SIGNAL('clicked()'), self.on_pushButton_clicked())
That will not work for you since self.on_pushBotton_clicked() slot is not defined.
I find it is easiest to create your own connections in PyQt... I recommend removing the calls to connectSlotsByName from your both classes... you do not need it.
Also, your wdiget1 class should set the name of it's pushButton (preferably something other then "pushButton" to avoid confusion with the button in widget2).

Thank you so much jcoon for your reply.. But after a very long time banging my head against the wall i found the solution..
The problem was..
self.obj=test_reuse_stacked1.widget2()
self.obj.createWidget2(self)
instead of obj..

Here is #MarkVisser's QT4 code updated to QT5:
from sys import argv, exit
from PyQt5 import QtCore, QtWidgets
from PyQt5.QtWidgets import QApplication, QWidget
class MyWidget(QWidget):
def __init__(self, parent=None):
super(MyWidget, self).__init__(parent)
self._layout = QtWidgets.QVBoxLayout()
self.setLayout(self._layout)
self._button = QtWidgets.QPushButton()
self._button.setText('Click NOW!')
self._layout.addWidget(self._button)
self._button.clicked.connect(self._print_message)
#QtCore.pyqtSlot()
def _print_message(self):
print("Hai")
if __name__ == "__main__":
app = QApplication(argv)
main = MyWidget()
main.show()
exit(app.exec_())

Another minimal working example with Qt for Python aka PySide2/6.
Key ingredients:
widget to connect MUST have .setObjectName
function to connect MUST be decorated with #QtCore.Slot()
both objects (function AND widget) MUST be members of passed object (self here)
from PySide2 import QtCore, QtWidgets
# or from PySide6 import QtCore, QtWidgets
class Widget(QtWidgets.QWidget):
def __init__(self):
super(Widget, self).__init__()
layout = QtWidgets.QVBoxLayout(self)
self.button = QtWidgets.QPushButton(self)
self.button.setObjectName('button')
self.button.setText('Click Me!')
layout.addWidget(self.button)
QtCore.QMetaObject.connectSlotsByName(self)
#QtCore.Slot()
def on_button_clicked(self):
print(f'Hai from {self.sender()}')
if __name__ == '__main__':
app = QtWidgets.QApplication([])
main = Widget()
main.show()
app.exec_()
I couldn't get mit any smaller really 🤔