elif menuOption == "2":
with open("Hotel.txt", "a+") as file:
print (file.read())
Ive tried many different ways but my python file just refuses to print the txt contents. It is writing to the file but option 2 wont read it.
if menuOption == "1":
print("Please Type Your Guests Name.")
data1 = (input() + "\n")
for i in range (2,1000):
file = open("hotel.txt", "a")
file.write(data1)
print("Please Write your Guests Room")
data2 = (input("\n") + "\n")
file.write(data2)
data3 = random.randint(1, 999999)
file.write(str (data3))
print("Guest Added - Enjoy Your Stay.")
print("Guest Name is:", data1)
print("Guest Room Number Is:", data2)
print("Your Key Code Is:", data3)
I want all the above information to be added to a TXT. (That works) and then be able to read it also. which won't work.
Why and how can I fix?
You have to use r instead of a+ to read from file:
with open("Hotel.txt", "r") as file:
You are using a+ mode which is meant for appending to the file, you need to use r for reading.
Secondly I notice this
for i in range (2,1000):
file = open("hotel.txt", "a")
You are opening a new file handler for every iteration of the loop. Please open the file just once and then do whatever operations you need to like below.
with open("hotel.txt", "a") as fh:
do your processing here...
This has the added advantage automatically closing the file handler for you, otherwise you need to close the file handler yourself by using fh.close() which you are not doing in your code.
Also a slight variation to how you are using input, you don't need to print the message explicitly, you can do this with input like this.
name = input("Enter your name: ")
Related
so I'm currently trying to print a list of cards in a text based card battler I'm making for a school project, and I'm wondering if I can get some help. I'm trying to print something different if a line in a file is 0 or 1, but I can't figure it out. thanks if you can help
def mainfunc():
while i<cardlist:
#if it's zero, do this
print("the card this line represents")
#if it's one, do this
print("locked")
#else, becasue if it's else then you're at the end of the file
print("your deck:")
#print your current deck
print("which card do you want to add?")
print(filelinecount("RIPScards"))
This is what I would do (UPDATED):
# For preventing unwanted behavior if this file ever gets imported in another:
if __name__ == "__main__":
with open(**insert file path here**, 'r') as f:
for line in f:
if line.strip() == "0":
print("the card this line represents")
elif line.strip() == "1":
print("locked")
else:
print("your deck")
print("which card do you want to add?")
print(filelinecount("RIPScards"))
You can read a file line-by-line with it open like so:
with open(**file path**, 'r') as f:
for line in f:
# Do stuff with the line here
Or you can read all the lines one time and close the file, then do stuff with the lines, like so:
f = open(**file name here**, 'r')
$lines = f.readlines()
f.close() # Make sure to close it, 'with open' method automatically does that for you, but manually opening it (like in this example) will not do it for you!
# Do stuff with it:
for line in lines:
# Do something with the line
Hopefully that helps!
I used Python 3.6 version and now I want to save name & age at the file and then read the text as name + tab + age but I can't approach file read side.
My code:
while True:
print("-------------")
name=input("Name: ")
age=input ("Age: ")
contInput=input("Continue Input? (y/n) ")
fp.open("test.txt", "a")
fp.write(name+","+age+"\n")
if contInput=="n":
fp.close()
break
else:
continue
with open("test.txt", "r") as fp:
rd = fp.read().split('\n')
????
fp.close()
so I just confuse about file read. I want to print my saved data like below.
name [tab] age
but after used split method, rd type is list.
Can I divide name & age as each items?
fp.open("test.txt", "a")
At this point in your program, fp doesn't exist yet. Perhaps you meant fp = open(...) instead?
You're only closing the file if the user chose not to continue, but you're opening it every time through the loop. You should open and close it only once, or open and close it every time through the loop.
fp.write(name+","+"age"+"\n")
This writes the literal word age instead of the age variable. You probably wanted this instead: fp.write(name + "," + age + "\n")
Try this for your input loop:
with open("test.txt", "r") as fp:
for line in fp:
data = line.split(",")
name = data[0]
age = data[1]
I created this script that could be used as a login, and then created an external text file that has the data 1234 in it, this is attempting to compare the data from the file, but outputs that the two values are different, even though they are the same. Thanks In advance to any help you can give me, the code I used is below:
getUsrName = input("Enter username: ")
file = open("documents/pytho/login/cdat.txt", "r")
lines = file.readlines()
recievedUsrName = lines[1]
file.close()
print(getUsrName)
print(recievedUsrName)
if recievedUsrName == getUsrName:
print("hello")
elif getUsrName != recievedUsrName:
print("bye")
else:
Try it like:
if recievedUsrName.strip() == getUsrName:
...
It must be the trailing newline.
I am using Python 2.7 and am trying to get my program to check if a file exists and if it does, the program should then ask the user if they want to overwrite it. If the file is not there, a new one should be created. These two steps are repeated where the file is found to be existing. Here is the code:
import os.path
file_name = input("Please enter the name of the file to save your data to: Example: test.txt ")
file_open = open(file_name, "w")
if os.path.isfile(file_name):
print ("File exists")
decide = input("Do you want to overwrite the file?, Yes or No")
control = True
while control:
if decide != "Yes":
file_name = input("Please enter the name of the file to save your data to: Example: test.txt ")
if os.path.isfile(file_name):
print ("File exists")
else:
newFile = open(file_name, "w")
newFile.write(str(model))
newFile.close()
control=False
else:
print("Creating a new file..................")
file_open.write(str(model))
file_open.close()
In lines 2, 6 and 10 it should be raw_input() as you are reading string, and check indentation of code.
def function(score,name):
sumOfStudent = (name + ' scored ' + str(score))
f = open('test.txt', 'wb')
f.write(sumOfStudent)
f.close()
user_name = input("Please enter yout full name: ")
user_score = int(input("Please enter your score: "))
function(user_score,user_name)
f = open('test.txt')
print(f.read())
f.close()
I was writing a simple program in python which allowed the user to enter information and then for that text to be stored in a .txt file. This worked however it would always write to the same line, I was wondering how I would make the f.write(sumOfStudent) on a new line every time (sumOfStudent is the variable to hold user input) Thanks!
Hey what you are doing is not writing to the end of the file you are overwriting everytime 'w' what you need to be doing is appending it to the file by using 'a'
f = open('test.txt', 'a')
Also to write to a new line you must tell the program thats what you're doing by declaring a new line "\n"
f.write(sumOfStudent + "\n")