Related
When I compile the Python code below, I get
IndentationError: unindent does not match any outer indentation level
import sys
def Factorial(n): # Return factorial
result = 1
for i in range (1,n):
result = result * i
print "factorial is ",result
return result
Why?
Other posters are probably correct...there might be spaces mixed in with your tabs. Try doing a search & replace to replace all tabs with a few spaces.
Try this:
import sys
def Factorial(n): # return factorial
result = 1
for i in range (1,n):
result = result * i
print "factorial is ",result
return result
print Factorial(10)
IMPORTANT:
Spaces are the preferred method - see PEP 8 Indentation and Tabs or Spaces?. (Thanks to #Siha for this.)
For Sublime Text users:
Set Sublime Text to use tabs for indentation:
View --> Indentation --> Convert Indentation to Tabs
Uncheck the Indent Using Spaces option as well in the same sub-menu above.
This will immediately resolve this issue.
To easily check for problems with tabs/spaces you can actually do this:
python -m tabnanny yourfile.py
or you can just set up your editor correctly of course :-)
Are you sure you are not mixing tabs and spaces in your indentation white space? (That will cause that error.)
Note, it is recommended that you don't use tabs in Python code. See the style guide. You should configure Notepad++ to insert spaces for tabs.
Whenever I've encountered this error, it's because I've somehow mixed up tabs and spaces in my editor.
If you are using Vim, hit escape and then type
gg=G
This auto indents everything and will clear up any spaces you have thrown in.
If you use Python's IDLE editor you can do as it suggests in one of similar error messages:
1) select all, e.g. Ctrl + A
2) Go to Format -> Untabify Region
3) Double check your indenting is still correct, save and rerun your program.
I'm using Python 2.5.4
The line: result = result * i should be indented (it is the body of the for-loop).
Or - you have mixed space and tab characters
For Spyder users goto
Source > Fix Indentation
to fix the issue immediately
Using Visual studio code
If you are using vs code than, it will convert all mix Indentation to either space or tabs using this simple steps below.
press Ctrl + Shift + p
type indent using spaces
Press Enter
On Atom
go to
Packages > Whitespace > Convert Spaces to Tabs
Then check again your file indentation:
python -m tabnanny yourFile.py
or
>python
>>> help("yourFile.py")
If you use notepad++, do a "replace" with extended search mode to find \t and replace with four spaces.
Looks to be an indentation problem. You don't have to match curly brackets in Python but you do have to match indentation levels.
The best way to prevent space/tab problems is to display invisible characters within your text editor. This will give you a quick way to prevent and/or resolve indentation-related errors.
Also, injecting copy-pasted code is a common source for this type of problem.
If you use colab, then you can do avoid the error by this commands.
< Ctrl-A >
< Tab >
< Shift-Tab >
It's all [tab] indentation convert to [space] indentation. Then OK.
Just a addition. I had a similar problem with the both indentations in Notepad++.
Unexcepted indentation
Outer Indentation Level
Go to ----> Search tab ----> tap on replace ----> hit the radio button Extended below ---> Now replace \t with four spaces
Go to ----> Search tab ----> tap on replace ----> hit the radio button Extended below ---> Now replace \n with nothing
I was using Jupyter notebook and tried almost all of the above solutions (adapting to my scenario) to no use. I then went line by line, deleted all spaces for each line and replaced with tab. That solved the issue.
For what its worth, my docstring was indented too much and this also throws the same error
class junk:
"""docstring is indented too much"""
def fun(): return
IndentationError: unindent does not match any outer indentation level
I'm using Sublime text in Ubuntu OS. To fix this issue go to
view -> Indentation -> convert indentation to tabs
It could be because the function above it is not indented the same way.
i.e.
class a:
def blah:
print("Hello world")
def blah1:
print("Hello world")
Since I realize there's no answer specific to spyder,I'll add one:
Basically, carefully look at your if statement and make sure all if, elif and else have the same spacing that is they're in the same line at the start like so:
def your_choice(answer):
if answer>5:
print("You're overaged")
elif answer<=5 and answer>1:
print("Welcome to the toddler's club!")
else:
print("No worries mate!")
I am using Sublime Text 3 with a Flask project. I fixed the error using View > Indentation > Tab Width: 4 after unselected Indent Using Spaces
This is because there is a mix-up of both tabs and spaces.
You can either remove all the spaces and replace them with tabs.
Or,
Try writing this:
#!/usr/bin/python -tt
at the beginning of the code. This line resolves any differences between tabs and spaces.
I had the same issue yesterday, it was indentation error, was using sublime text editor. took my hours trying to fix it and at the end I ended up copying the code into VI text editor and it just worked fine. ps python is too whitespace sensitive, make sure not to mix space and tab.
for Atom Users, Packages ->whitspace -> remove trailing whitespaces
this worked for me
I had a function defined, but it did not had any content apart from its function comments...
def foo(bar):
# Some awesome temporary comment.
# But there is actually nothing in the function!
# D'Oh!
It yelled :
File "foobar.py", line 69
^
IndentationError: expected an indented block
(note that the line the ^ mark points to is empty)
--
Multiple solutions:
1: Just comment out the function
2: Add function comment
def foo(bar):
'' Some awesome comment. This comment could be just one space.''
3: Add line that does nothing
def foo(bar):
0
In any case, make sure to make it obvious why it is an empty function - for yourself, or for your peers that will use your code
Firstly, just to remind you there is a logical error you better keep result=1 or else your output will be result=0 even after the loop runs.
Secondly you can write it like this:
import sys
def Factorial(n): # Return factorial
result = 0
for i in range (1,n):
result = result * i
print "factorial is ",result
return result
Leaving a line will tell the python shell that the FOR statements have ended. If you have experience using the python shell then you can understand why we have to leave a line.
For example:
1. def convert_distance(miles):
2. km = miles * 1.6
3. return km
In this code same situation occurred for me. Just delete the previous indent spaces of
line 2 and 3, and then either use tab or space. Never use both. Give proper indentation while writing code in python.
For Spyder goto Source > Fix Indentation. Same goes to VC Code and sublime text or any other editor. Fix the indentation.
I got this error even though I didn't have any tabs in my code, and the reason was there was a superfluous closing parenthesis somewhere in my code. I should have figured this out earlier because it was messing up spaces before and after some equal signs... If you find anything off even after running Reformat code in your IDE (or manually running autopep8), make sure all your parentheses match, starting backwards from the weird spaces before/after the first equals sign.
I had the same error because of another thing, it was not about tabs vs. spaces. I had the first if slightly more indented than an else: much further down. If it is just about a space or two, you might oversee it after a long code block. Same thing with docstrings:
"""comment comment
comment
"""
They also need to be aligned, see the other answer on the same page here.
Reproducible with a few lines:
if a==1:
print('test')
else:
print('test2')
Throws:
File "<ipython-input-127-52bbac35ad7d>", line 3
else:
^
IndentationError: unindent does not match any outer indentation level
I actually get this in pylint from a bracket in the wrong place.
I'm adding this answer because I sent a lot of time looking for tabs.
In this case, it has nothing to do with tabs or spaces.
def some_instance_function(self):
json_response = self.some_other_function()
def compare_result(json_str, variable):
"""
Sub function for comparison
"""
json_value = self.json_response.get(json_str, f"{json_str} not found")
if str(json_value) != str(variable):
logging.error("Error message: %s, %s",
json_value,
variable) # <-- Putting the bracket here causes the error below
#) <-- Moving the bracket here fixes the issue
return False
return True
logging.debug("Response: %s", self.json_response)
# ^----The pylint error reports here
When I compile the Python code below, I get
IndentationError: unindent does not match any outer indentation level
import sys
def Factorial(n): # Return factorial
result = 1
for i in range (1,n):
result = result * i
print "factorial is ",result
return result
Why?
Other posters are probably correct...there might be spaces mixed in with your tabs. Try doing a search & replace to replace all tabs with a few spaces.
Try this:
import sys
def Factorial(n): # return factorial
result = 1
for i in range (1,n):
result = result * i
print "factorial is ",result
return result
print Factorial(10)
IMPORTANT:
Spaces are the preferred method - see PEP 8 Indentation and Tabs or Spaces?. (Thanks to #Siha for this.)
For Sublime Text users:
Set Sublime Text to use tabs for indentation:
View --> Indentation --> Convert Indentation to Tabs
Uncheck the Indent Using Spaces option as well in the same sub-menu above.
This will immediately resolve this issue.
To easily check for problems with tabs/spaces you can actually do this:
python -m tabnanny yourfile.py
or you can just set up your editor correctly of course :-)
Are you sure you are not mixing tabs and spaces in your indentation white space? (That will cause that error.)
Note, it is recommended that you don't use tabs in Python code. See the style guide. You should configure Notepad++ to insert spaces for tabs.
Whenever I've encountered this error, it's because I've somehow mixed up tabs and spaces in my editor.
If you are using Vim, hit escape and then type
gg=G
This auto indents everything and will clear up any spaces you have thrown in.
If you use Python's IDLE editor you can do as it suggests in one of similar error messages:
1) select all, e.g. Ctrl + A
2) Go to Format -> Untabify Region
3) Double check your indenting is still correct, save and rerun your program.
I'm using Python 2.5.4
The line: result = result * i should be indented (it is the body of the for-loop).
Or - you have mixed space and tab characters
For Spyder users goto
Source > Fix Indentation
to fix the issue immediately
Using Visual studio code
If you are using vs code than, it will convert all mix Indentation to either space or tabs using this simple steps below.
press Ctrl + Shift + p
type indent using spaces
Press Enter
On Atom
go to
Packages > Whitespace > Convert Spaces to Tabs
Then check again your file indentation:
python -m tabnanny yourFile.py
or
>python
>>> help("yourFile.py")
If you use notepad++, do a "replace" with extended search mode to find \t and replace with four spaces.
Looks to be an indentation problem. You don't have to match curly brackets in Python but you do have to match indentation levels.
The best way to prevent space/tab problems is to display invisible characters within your text editor. This will give you a quick way to prevent and/or resolve indentation-related errors.
Also, injecting copy-pasted code is a common source for this type of problem.
If you use colab, then you can do avoid the error by this commands.
< Ctrl-A >
< Tab >
< Shift-Tab >
It's all [tab] indentation convert to [space] indentation. Then OK.
Just a addition. I had a similar problem with the both indentations in Notepad++.
Unexcepted indentation
Outer Indentation Level
Go to ----> Search tab ----> tap on replace ----> hit the radio button Extended below ---> Now replace \t with four spaces
Go to ----> Search tab ----> tap on replace ----> hit the radio button Extended below ---> Now replace \n with nothing
I was using Jupyter notebook and tried almost all of the above solutions (adapting to my scenario) to no use. I then went line by line, deleted all spaces for each line and replaced with tab. That solved the issue.
For what its worth, my docstring was indented too much and this also throws the same error
class junk:
"""docstring is indented too much"""
def fun(): return
IndentationError: unindent does not match any outer indentation level
I'm using Sublime text in Ubuntu OS. To fix this issue go to
view -> Indentation -> convert indentation to tabs
It could be because the function above it is not indented the same way.
i.e.
class a:
def blah:
print("Hello world")
def blah1:
print("Hello world")
Since I realize there's no answer specific to spyder,I'll add one:
Basically, carefully look at your if statement and make sure all if, elif and else have the same spacing that is they're in the same line at the start like so:
def your_choice(answer):
if answer>5:
print("You're overaged")
elif answer<=5 and answer>1:
print("Welcome to the toddler's club!")
else:
print("No worries mate!")
I am using Sublime Text 3 with a Flask project. I fixed the error using View > Indentation > Tab Width: 4 after unselected Indent Using Spaces
This is because there is a mix-up of both tabs and spaces.
You can either remove all the spaces and replace them with tabs.
Or,
Try writing this:
#!/usr/bin/python -tt
at the beginning of the code. This line resolves any differences between tabs and spaces.
I had the same issue yesterday, it was indentation error, was using sublime text editor. took my hours trying to fix it and at the end I ended up copying the code into VI text editor and it just worked fine. ps python is too whitespace sensitive, make sure not to mix space and tab.
for Atom Users, Packages ->whitspace -> remove trailing whitespaces
this worked for me
I had a function defined, but it did not had any content apart from its function comments...
def foo(bar):
# Some awesome temporary comment.
# But there is actually nothing in the function!
# D'Oh!
It yelled :
File "foobar.py", line 69
^
IndentationError: expected an indented block
(note that the line the ^ mark points to is empty)
--
Multiple solutions:
1: Just comment out the function
2: Add function comment
def foo(bar):
'' Some awesome comment. This comment could be just one space.''
3: Add line that does nothing
def foo(bar):
0
In any case, make sure to make it obvious why it is an empty function - for yourself, or for your peers that will use your code
Firstly, just to remind you there is a logical error you better keep result=1 or else your output will be result=0 even after the loop runs.
Secondly you can write it like this:
import sys
def Factorial(n): # Return factorial
result = 0
for i in range (1,n):
result = result * i
print "factorial is ",result
return result
Leaving a line will tell the python shell that the FOR statements have ended. If you have experience using the python shell then you can understand why we have to leave a line.
For example:
1. def convert_distance(miles):
2. km = miles * 1.6
3. return km
In this code same situation occurred for me. Just delete the previous indent spaces of
line 2 and 3, and then either use tab or space. Never use both. Give proper indentation while writing code in python.
For Spyder goto Source > Fix Indentation. Same goes to VC Code and sublime text or any other editor. Fix the indentation.
I got this error even though I didn't have any tabs in my code, and the reason was there was a superfluous closing parenthesis somewhere in my code. I should have figured this out earlier because it was messing up spaces before and after some equal signs... If you find anything off even after running Reformat code in your IDE (or manually running autopep8), make sure all your parentheses match, starting backwards from the weird spaces before/after the first equals sign.
I had the same error because of another thing, it was not about tabs vs. spaces. I had the first if slightly more indented than an else: much further down. If it is just about a space or two, you might oversee it after a long code block. Same thing with docstrings:
"""comment comment
comment
"""
They also need to be aligned, see the other answer on the same page here.
Reproducible with a few lines:
if a==1:
print('test')
else:
print('test2')
Throws:
File "<ipython-input-127-52bbac35ad7d>", line 3
else:
^
IndentationError: unindent does not match any outer indentation level
I actually get this in pylint from a bracket in the wrong place.
I'm adding this answer because I sent a lot of time looking for tabs.
In this case, it has nothing to do with tabs or spaces.
def some_instance_function(self):
json_response = self.some_other_function()
def compare_result(json_str, variable):
"""
Sub function for comparison
"""
json_value = self.json_response.get(json_str, f"{json_str} not found")
if str(json_value) != str(variable):
logging.error("Error message: %s, %s",
json_value,
variable) # <-- Putting the bracket here causes the error below
#) <-- Moving the bracket here fixes the issue
return False
return True
logging.debug("Response: %s", self.json_response)
# ^----The pylint error reports here
let's take the really simple case of two nested for loops
after pressing return and tab the first time, I get an indentation level where 1 tab equals 4 spaces
after pressing return and tab the second time, I get an indentation level where 1 tab equals 9 spaces
this is rather annoying when I want to copy a piece of code from a script and run it on the interpreter, as it returns the
TabError: inconsistent use of tabs and spaces in indentation
I did some googling but you can imagine what the keywords "python", "interpreter", "indentation" returns: nothing useful
Is there a way to correct this? Thanks
EDIT
just try yourselves:
open a terminal
run python command
then type for i in range(3):
press Enter
then press Tab once, to get to the right indentation level
then type for j in range(3):
press Enter again
then press Tab twice, to get to the (expected) indentation level
if, like me, you have a Mac, chances are that the second Tab hit in the last step above, will yield 8 spaces, instead of 4
This causes problems when copying lines of code written with an IDE
(I'm using Sublime 3, with the option translate_tabs_to_spaces set to True)
I was hoping someone could identify some flag/options/setting of my interpreter which could solve this issue
Title question :
Because you are at 2nd indentation level since you have a loop inside a loop.
Tabulation/space error :
Python uses only indentation to interpret which block belongs to the code. No "BEGIN...END" , no brackets. So indentation IS information.
The rule is "indentation must be uniform", so either everything is spaces (1,2,4.. as you want) or everything is tabulations.
For more information, refer to the Python style guideline (PEP8) here :
https://www.python.org/dev/peps/pep-0008/
By using an IDE ( such as Spyder, for example) tabs will automatically be replaced by spaces. I recommend you to use one, especially if you are a new to python.
I am Python newbie and I am working on NLP using Python. I am having an error in writing an if-else block in Python. When I am writing only an if block at that time it is working fine:
if xyzzy.endswith('l'):
print xyzzy
After entering a colon (:) I am pressing Enter and it is automatically taking me to the correct indentation.
But when I am trying to add an else block to it after pressing the Enter key after the print statement, it is considering it to be statement of an IF block only, so it is giving me incorrect indentation as I want an else block after, while when I am trying to write else block my self it is giving me this error.
else:
^
IndentationError: unexpected indent
What should I do after writing print statement? Enter is clearly not working, because it is taking the cursor forward, while when I use space to come to the correct pointer it is giving me an error.
It's hard to see from your post what the problem is, but an if-else is formatted like so
if someCondition:
do_something # could be a single statement, or a series of statements
else:
do_something_else # could be a single statement, or a series of statements
I.e., the else needs to be at the same level as the corresponding if.
See this Python doc/tutorial on if, and this other tutorial too.
Sometimes when your editor does autoindent for you and you edit manually too things might get messed up, so you'll have to figure out how your editor handles indentations (e.g., is it always using tabs or spaces?, what happens if you hit return etc).
Also, be wary of mixing tabs and spaces, that will cause problems too (hard to spot since both are "invisible")
With your updated post:
if xyzzy.endswith('l'):
print xyzzy
else:
something_else
The else should be at the same level of indentation as the if with which it is coupled:
if x:
# Do something
else:
# Do something else
In your case,
if xyzzy.endswith('l'):
print xyzzy
else:
# Something else
Even if your editor is auto-indenting for you, you should still un-indent to make the code syntactically correct.
Getting the indentation correct isn't really a Python issue but rather an issue with the editor that you're using for your source code.
Most editors that understand Python will correctly add one level of indentation after a colon (as you're seeing). Because you can have as many statements as you want in that block of code, the editor has no way to know when to "outdent" the next line for the else.
You have to tell the editor to outdent that line by hitting backspace or Shift + Tab on the line before starting to type.
If you are inserting the else part after the rest of the code is written, make absolutely certain that the characters you use to indent are the same as for the if statement. If the if statement is indented with spaces, use the same number of spaces for else. If the if statement is indented with one or more tabs, use the same number of tabs for the else statement. Don't mix spaces and tabs for indentation.
Don't assume that just because the lines "look" as if they're indented the same that they are indented the same. One may use spaces and one may use tabs (or some combination).
when I use space to come to the correct pointer it is giving me a error
Of course. Using space never makes a "line break", typically this is \n in Unix systems. If you'd open your .py file in a different editor (say Notepad in Windows) you'd see that your else statement is in the same line as print.
Enter is clearly not working because it is taking the cursor forward
Press backspace the correct amount of times to reach the same level of indentation as your IF statement.
I don't agree entirely with the accepted answer. Yes, indention is very important in Python, but to state that the if-else has to always look like that with this formatting is a little bit overboard.
Python allows you a one-liners (even multiple) as long as you don't do anything fancy in there that requires indention in the body of the if, elif or else.
Here are some examples:
choice = 1
# if with one-liner
if choice == 1: print('This is choice 1')
# if-else with one-liners
if choice == 1: print('This is choice 1')
else: print('This is a choice other than 1')
# if-else if with one-liners
if choice == 1: print('This is choice 1')
elif choice == 2: print('This is choice 2')
# if-else if-else with one-liners
if choice == 1: print('This is choice 1')
elif choice == 2: print('This is choice 2')
else: print('This is a choice other than 1 and 2')
# Multiple simple statements on a single line have to be separated by a semicolumn (;) except for the last one on the line
if choice == 1: print('First statement'); print('Second statement'); print('Third statement')
Usually it is not recommended to pack too many statements on a single line because then you lose one of the big features of Python - readability of the code.
Notice also that the above examples can also easily be applied to for and while. You can go even further as to do some crazy nesting of one-liner if blocks if you use the ternary conditional operator.
Here is how the operator usually looks:
flag = True
print('Flag is set to %s' % ('AWESOME' if True else 'BORING'))
Basically, it creates a simple if-else statement. You can embed it with one of your one-liners if you need more branching (but not complex one).
I hope this clarifies the situation a bit and what is allowed and not allowed. ;)
I've been getting this error even when the indentation looked correct.
Viewing in Notepad++ there is an option to see white spaces and Tabs. The error was caused by mixing spaces and tabs to create indentation.
Replacing Tabs with spaces in every line helped to get rid of an error.
Actually, this is a Python IDLE UI issue: Once you hit Enter after the if block finishes, next the else statement is already in intent with the if statement. There isn't any need to provide any tabs or spaces to make indentation. Below is the image for reference.
When I compile the Python code below, I get
IndentationError: unindent does not match any outer indentation level
import sys
def Factorial(n): # Return factorial
result = 1
for i in range (1,n):
result = result * i
print "factorial is ",result
return result
Why?
Other posters are probably correct...there might be spaces mixed in with your tabs. Try doing a search & replace to replace all tabs with a few spaces.
Try this:
import sys
def Factorial(n): # return factorial
result = 1
for i in range (1,n):
result = result * i
print "factorial is ",result
return result
print Factorial(10)
IMPORTANT:
Spaces are the preferred method - see PEP 8 Indentation and Tabs or Spaces?. (Thanks to #Siha for this.)
For Sublime Text users:
Set Sublime Text to use tabs for indentation:
View --> Indentation --> Convert Indentation to Tabs
Uncheck the Indent Using Spaces option as well in the same sub-menu above.
This will immediately resolve this issue.
To easily check for problems with tabs/spaces you can actually do this:
python -m tabnanny yourfile.py
or you can just set up your editor correctly of course :-)
Are you sure you are not mixing tabs and spaces in your indentation white space? (That will cause that error.)
Note, it is recommended that you don't use tabs in Python code. See the style guide. You should configure Notepad++ to insert spaces for tabs.
Whenever I've encountered this error, it's because I've somehow mixed up tabs and spaces in my editor.
If you are using Vim, hit escape and then type
gg=G
This auto indents everything and will clear up any spaces you have thrown in.
If you use Python's IDLE editor you can do as it suggests in one of similar error messages:
1) select all, e.g. Ctrl + A
2) Go to Format -> Untabify Region
3) Double check your indenting is still correct, save and rerun your program.
I'm using Python 2.5.4
The line: result = result * i should be indented (it is the body of the for-loop).
Or - you have mixed space and tab characters
For Spyder users goto
Source > Fix Indentation
to fix the issue immediately
Using Visual studio code
If you are using vs code than, it will convert all mix Indentation to either space or tabs using this simple steps below.
press Ctrl + Shift + p
type indent using spaces
Press Enter
On Atom
go to
Packages > Whitespace > Convert Spaces to Tabs
Then check again your file indentation:
python -m tabnanny yourFile.py
or
>python
>>> help("yourFile.py")
If you use notepad++, do a "replace" with extended search mode to find \t and replace with four spaces.
Looks to be an indentation problem. You don't have to match curly brackets in Python but you do have to match indentation levels.
The best way to prevent space/tab problems is to display invisible characters within your text editor. This will give you a quick way to prevent and/or resolve indentation-related errors.
Also, injecting copy-pasted code is a common source for this type of problem.
If you use colab, then you can do avoid the error by this commands.
< Ctrl-A >
< Tab >
< Shift-Tab >
It's all [tab] indentation convert to [space] indentation. Then OK.
Just a addition. I had a similar problem with the both indentations in Notepad++.
Unexcepted indentation
Outer Indentation Level
Go to ----> Search tab ----> tap on replace ----> hit the radio button Extended below ---> Now replace \t with four spaces
Go to ----> Search tab ----> tap on replace ----> hit the radio button Extended below ---> Now replace \n with nothing
I was using Jupyter notebook and tried almost all of the above solutions (adapting to my scenario) to no use. I then went line by line, deleted all spaces for each line and replaced with tab. That solved the issue.
For what its worth, my docstring was indented too much and this also throws the same error
class junk:
"""docstring is indented too much"""
def fun(): return
IndentationError: unindent does not match any outer indentation level
I'm using Sublime text in Ubuntu OS. To fix this issue go to
view -> Indentation -> convert indentation to tabs
It could be because the function above it is not indented the same way.
i.e.
class a:
def blah:
print("Hello world")
def blah1:
print("Hello world")
Since I realize there's no answer specific to spyder,I'll add one:
Basically, carefully look at your if statement and make sure all if, elif and else have the same spacing that is they're in the same line at the start like so:
def your_choice(answer):
if answer>5:
print("You're overaged")
elif answer<=5 and answer>1:
print("Welcome to the toddler's club!")
else:
print("No worries mate!")
I am using Sublime Text 3 with a Flask project. I fixed the error using View > Indentation > Tab Width: 4 after unselected Indent Using Spaces
This is because there is a mix-up of both tabs and spaces.
You can either remove all the spaces and replace them with tabs.
Or,
Try writing this:
#!/usr/bin/python -tt
at the beginning of the code. This line resolves any differences between tabs and spaces.
I had the same issue yesterday, it was indentation error, was using sublime text editor. took my hours trying to fix it and at the end I ended up copying the code into VI text editor and it just worked fine. ps python is too whitespace sensitive, make sure not to mix space and tab.
for Atom Users, Packages ->whitspace -> remove trailing whitespaces
this worked for me
I had a function defined, but it did not had any content apart from its function comments...
def foo(bar):
# Some awesome temporary comment.
# But there is actually nothing in the function!
# D'Oh!
It yelled :
File "foobar.py", line 69
^
IndentationError: expected an indented block
(note that the line the ^ mark points to is empty)
--
Multiple solutions:
1: Just comment out the function
2: Add function comment
def foo(bar):
'' Some awesome comment. This comment could be just one space.''
3: Add line that does nothing
def foo(bar):
0
In any case, make sure to make it obvious why it is an empty function - for yourself, or for your peers that will use your code
Firstly, just to remind you there is a logical error you better keep result=1 or else your output will be result=0 even after the loop runs.
Secondly you can write it like this:
import sys
def Factorial(n): # Return factorial
result = 0
for i in range (1,n):
result = result * i
print "factorial is ",result
return result
Leaving a line will tell the python shell that the FOR statements have ended. If you have experience using the python shell then you can understand why we have to leave a line.
For example:
1. def convert_distance(miles):
2. km = miles * 1.6
3. return km
In this code same situation occurred for me. Just delete the previous indent spaces of
line 2 and 3, and then either use tab or space. Never use both. Give proper indentation while writing code in python.
For Spyder goto Source > Fix Indentation. Same goes to VC Code and sublime text or any other editor. Fix the indentation.
I got this error even though I didn't have any tabs in my code, and the reason was there was a superfluous closing parenthesis somewhere in my code. I should have figured this out earlier because it was messing up spaces before and after some equal signs... If you find anything off even after running Reformat code in your IDE (or manually running autopep8), make sure all your parentheses match, starting backwards from the weird spaces before/after the first equals sign.
I had the same error because of another thing, it was not about tabs vs. spaces. I had the first if slightly more indented than an else: much further down. If it is just about a space or two, you might oversee it after a long code block. Same thing with docstrings:
"""comment comment
comment
"""
They also need to be aligned, see the other answer on the same page here.
Reproducible with a few lines:
if a==1:
print('test')
else:
print('test2')
Throws:
File "<ipython-input-127-52bbac35ad7d>", line 3
else:
^
IndentationError: unindent does not match any outer indentation level
I actually get this in pylint from a bracket in the wrong place.
I'm adding this answer because I sent a lot of time looking for tabs.
In this case, it has nothing to do with tabs or spaces.
def some_instance_function(self):
json_response = self.some_other_function()
def compare_result(json_str, variable):
"""
Sub function for comparison
"""
json_value = self.json_response.get(json_str, f"{json_str} not found")
if str(json_value) != str(variable):
logging.error("Error message: %s, %s",
json_value,
variable) # <-- Putting the bracket here causes the error below
#) <-- Moving the bracket here fixes the issue
return False
return True
logging.debug("Response: %s", self.json_response)
# ^----The pylint error reports here