Develop Reference

NoReverseMatch at /'blog' is not a registered namespace

I am trying to link two pages. Page files are home.html and pageOne.html. I am getting "NoReverseMatch at /'blog' is not a registered namespace". I am using django. When I first created the app, I named it artclBlog, I then created a templates folder and another folder within that one, this one I named blog. I think I should have kept these two names the same, this may have caused some confusion in my code.
pic of error
my views.py
from django.shortcuts import render, get_object_or_404
from .models import Blog
def home(request):
blogs = Blog.objects.order_by('-date')
return render(request, 'blog/home.html', {'blogs': blogs})
my urls.py
from django.contrib import admin
from django.urls import path, include
from django.conf.urls.static import static
from django.conf import settings
from artclBlog import views
urlpatterns = [
path('admin/', admin.site.urls),
path('', views.home, name='home'),
path('<int:blog_id>/', views.PageOne, name='PageOne')
]
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
my models.py
from django.db import models
class Blog(models.Model):
title = models.CharField(max_length=200, default='')
summary = models.CharField(max_length=200, default='')
pageOne = models.TextField(default='')
pageTwo = models.TextField(default='')
pageThree = models.TextField(default='')
pageFour = models.TextField(default='')
date = models.DateField(default='')
def __str__(self):
return self.title
home.html
{% for blog in blogs %}
<a href="{% url 'blog:PageOne' blog.id %}">
<h2 id="txt">{{ blog.title }}</h2>
</a>
<h4 id="txt">{{ blog.date|date:'M d y' }}</h4>
<p id="txt">{{ blog.summary|truncatechars:190 }}</p>
<hr>
{% endfor %}

You did not define an app_name in your urls.py, hence that means that blog: in blog:PageOne makes no sense. You thus either define an app_name, or remove the namespace.
Option 1: Add an app_name in urls.py
You can specify the namespace by writin an app_name in the urls.py:
from django.contrib import admin
from django.urls import path, include
from django.conf.urls.static import static
from django.conf import settings
from artclBlog import views
app_name = 'blog'
urlpatterns = [
path('admin/', admin.site.urls),
path('', views.home, name='home'),
path('<int:blog_id>/', views.PageOne, name='PageOne')
]
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
This however means that thus all views now use this namespace, including home for example.
Option 2: Remove the namespace
Another option is to remove the namespace in the {% url … %} template tag [Django-doc]:
{% for blog in blogs %}
<a href="{% url 'PageOne' blog.id %}">
<h2 id="txt">{{ blog.title }}</h2>
</a>
<h4 id="txt">{{ blog.date|date:'M d y' }}</h4>
<p id="txt">{{ blog.summary|truncatechars:190 }}</p>
<hr>
{% endfor %}

This mistake comes usually when you have created different apps in your project.
First you do:
django-admin startproject mainapp
Then you do
python manage.py startapp secondapp
urls.py in your secondapp folder would automatically have app_name = 'secondapp'. However you must add in mainapp urls.py the following:
urlpatterns = [
...
path('secondapp/',include('secondapp.urls',namespace='secondapp')),
...
]
This is because your mainapp is the one that has the main access to the project and needs to know your secondapp urls.

Django Template - Cannot iterate throught this list and get menu item

i have one project andromeda where is 2 apps. 1 is blog and seccond one is blogmenu
but when I want to get information from the blog app there is no problem and i can get all information. but when I want to get a menu item from blogmenu I'm getting now error but there is empty navigation bar.
blogmenu urls.py
from django.contrib import admin
from django.urls import path,include
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('blog.urls')),
path('', include('blogmenu.urls')),
]
if settings.DEBUG:
urlpatterns += static(settings.MEDIA_URL,
document_root=settings.MEDIA_ROOT)
blogmenu views.py
from django.shortcuts import render
def Blog_Menu(request):
Menu_items = Menu.objects.all()
template_name = 'front/index.html'
return render(request, template_name, {"Menu_items":Menu_items})
blogmenu models.py
from django.db import models
class Menu(models.Model):
Menu_name = models.CharField(max_length=100,blank=True)
Menu_slug = models.SlugField(name="სლაგი",blank=True)
Menu_image = models.ImageField(upload_to="menuimages")
Menu_url = models.CharField(name="url",max_length=100,blank=True,null=True)
class Meta:
verbose_name = "მენიუ"
def __str__(self):
return self.Menu_name
sample html template code
{% for menu in Menu_items %}
<li class="main-menu-item">
just text
</li>
{% endfor %}

When iteration items in loop you should post something. You can do the below in your template.
{% for menu in Menu_items %}
<li class="main-menu-item">
{{ menu.Menu_name }}
</li>
{% endfor %}

Seems to me that you just forgot to use the object from the for loop.
This is probably what your looking for:
{% for menu in Menu_items %}
<li class="main-menu-item">
{{ menu.Menu_name }}
</li>
{% endfor %}
If this isn't working either then I would suggest putting a print(Menu_items) after you make the query in your blogmenu views.py and see if your getting your data there.
Also don't forget to import your model in your views.py.

Django : Problem with Django-allauth urls

I just started with a Django project using django-allauth, I configured the basic settings, without using any 3rd party provider. I have set up the urls.py of my project and urls.py of my app.
But on going to http://localhost:8000, I am getting to 'home.html' but how do I remove the navigation of allauth
The following is the urls.py of my project :
from django.urls import path, include
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
path('admin/', admin.site.urls),
path('accounts/', include('allauth.urls')),
path('ckeditor/',include('ckeditor_uploader.urls')),
path('',include('blog.urls')),
]
if settings.DEBUG:
urlpatterns += static(settings.STATIC_URL,
document_root=settings.STATIC_ROOT)
urlpatterns += static(settings.MEDIA_URL,
document_root=settings.MEDIA_ROOT)
And this my urls.py of app :
from django.urls import path, include
from . import views
urlpatterns = [
path("", views.PostListView.as_view(), name = 'post_list'),
path("post/add", views.CreatePostView.as_view(), name = "create_new_post"),
]
views.py
from django.shortcuts import render
from django.views.generic import ListView, View
# Create your views here.
from .forms import PostForm, CommentForm
from .models import Post, Comment
class PostListView(ListView):
queryset = Post.objects.filter(is_published=True)
template_name = 'home.html'
class CreatePostView(View):
form_class = PostForm()
template_name = 'create_post.html'
model = Post
home.html
{% extends 'base.html' %}
{% block content %}
<h1>Hello World</h1>
{% for post in post_list %}
<h1>{{post.post_title}}</h1>
<p>{{post.post_body|safe}}</p>
{% endfor %}
{% endblock %}

path("post/add/", views.CreatePostView.as_view(), name = "create_new_post"),
add trailing slash to your url

your global urls.py:
path('',include('blog.urls')),
add something in your app urls.py:
path('test/',views.PostListView.as_view()),
after adding this to your urls.py, run your app again

the extended base.html file may contain the navigation. make changes there to remove or simply remove it
{% extends 'base.html' %}

Django url page not found

So I have been trying to access a project post that I have created for my website, but every time I click on it the url can't be found. I am not sure why.
My code is below:
mywebsite/urls.py
from django.contrib import admin
from django.urls import re_path, include
from django.conf import settings
from django.conf.urls.static import static
#re_path(r'^admin/', admin.site.urls),
urlpatterns = [
re_path(r'^admin/', admin.site.urls),
re_path(r'^', include('home.urls')),
re_path(r'^projects/', include('projects.urls', namespace="create_post")),
re_path(r'^contact/', include('contact.urls')),
]
projects/urls.py
from django.urls import re_path, include
from . import views
# urls for projects page
app_name = 'create_post'
urlpatterns = [
re_path(r'^$', views.retrieve_projects, name="retrieve_projects"),
#re_path(r'^create/$', views.CreateProjectsView.as_view(), name="create_projects"),
re_path(r'^create/$', views.CreateProjectsView.as_view(), name="create_projects"),
re_path(r'^(?P<slug>[\w-]+)/$', views.details_of_project, name="details_of_project"),
re_path(r'^(?P<slug>[\w-]+)/update/$', views.update_projects, name="update_projects"),
re_path(r'^(?P<slug>[\w-]+)/delete/$', views.delete_projects, name="delete_projects"),
]
# To make images work
if settings.DEBUG:
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
projects/views.py
# Function to retrieve all different projects
def retrieve_projects(request):
# Retrieves objects based on latest publish date
projects_list = Projects.objects.all().order_by("-publish_date")
context = {
'projects_list': projects_list,
}
return render(request, 'projects/projects.html', context)
projects/projects.html
<h1>asdasdasdasdasdasdas</h1>
{% if projects_list %}
<ul>
{% for project in projects_list %}
<h2>{{project.title}}</h2>
<h2>{{project.description}}</h2>
<h2>{{ project.publish_date }}</h2>
{% endfor %}
</ul>
{% endif %}
The error returns page not found

try this

How to embed the results of my django app inside a template using something like {% include "app" %}?

So far I have been able to Create a project and setup a Homepage. So far I have had success with styling the page and getting my nav areas setup. I have also created an app that pulls a list of category names from my database and displays it in a right-justified list. When I point my browser to the app url, it works perfectly, but when I try to include the view in my project it displays the base panel with an error, and the dictionary I passed to the view does not appear to be available.
This is what I get when I load the home url localhost:8000/ in my browser:
This is what I get when I load the app url localhost:8000/categories/ in my browser:
Why am I not able to push the results of my app into my template? Both appear to work but not together?
base_right_panel.html
{% block content %}
<div style="float: right;">
<div id="base_categories" style="margin: 10px; padding-bottom: 10px;">
{% block base_categories %}
{% include "base_categories.html" %}
{% endblock %}
</div>
</div>
{% endblock %}
base_categories.html
{% block content %}
<div class="section" style="float: right;">
<h4 class="gradient">Category List</h4>
<ul>
{% if categories %}
{% for category in categories %}
<li>{{ category.title }}</li>
{% endfor %}
{% else %}
<p>no data! {{ categories|length }}</p>
{% endif %}
</ul>
</div>
{% endblock %}
CategoryList/views.py
from django.views.generic import TemplateView
from CategoryList.models import CategorylistCategorylist #<-- Changed to match inspectdb result
class IndexView(TemplateView):
template_name="base_categories.html" #<-- Changed name from index.html for clarity
def get_context_data(self, **kwargs):
context = super(IndexView, self).get_context_data(**kwargs)
context["categories"] = CategorylistCategorylist.objects.all()
return context
CategoryList/models.py
from django.db import models
class CategorylistCategorylist(models.Model): #<-- Changed to match inspectdb
id = models.IntegerField(primary_key=True)
name = models.CharField(max_length=255L, unique=True)
base_url = models.CharField(max_length=255L, unique=True)
thumb = models.ImageField(upload_to="dummy", blank=True) #<-- Ignored inspectdb's suggestion for CharField
def __unicode__(self):
return self.name
# Re-added Meta to match inspectdb
class Meta:
db_table = 'categorylist_categorylist'
CategoryList/urls.py
from django.conf.urls.defaults import patterns, url, include
from django.contrib import admin
from django.conf import settings
from CategoryList import views
admin.autodiscover()
urlpatterns = patterns('',
url(r'^$', views.IndexView.as_view(), name='base_categories'),
)
if settings.DEBUG:
urlpatterns = patterns('',
url(r'^media/(?P<path>.*)$', 'django.views.static.serve',
{'document_root': settings.MEDIA_ROOT, 'show_indexes': True}),
url(r'', include('django.contrib.staticfiles.urls')),
) + urlpatterns
MySite/urls.py
from django.conf.urls import patterns, include, url
from django.contrib import admin
from django.conf import settings
from home import views as home_view
from CategoryList import views as index_view
admin.autodiscover()
urlpatterns = patterns('',
url(r'^$', home_view.HomeView.as_view(), name="home"),
url(r'^categories/$', index_view.IndexView.as_view(), name='base_categories'),#include('CategoryList.urls')),
url(r'^admin/', include(admin.site.urls)),
#url(r'^admin/doc/', include('django.contrib.admindocs.urls')),
)
if settings.DEBUG:
urlpatterns = patterns('',
url(r'^media/(?P<path>.*)$', 'django.views.static.serve',
{'document_root': settings.MEDIA_ROOT, 'show_indexes': True}),
url(r'', include('django.contrib.staticfiles.urls')),
) + urlpatterns
I have another open question which has the relevant code examples but the question differs from what I am asking here.
Is there a simple way to display mysql data in Django template without creating an app?

You need to add the category queryset to your context in your HomeView. Remember, the view uses the templates to build the response - including a template that you also use in a different view (IndexView) does not cause any interaction with IndexView.
HomeView produces its response by rendering a template. If that template uses {% include %} tags to pull in pieces of other templates, those pieces will be rendered using the context established by HomeView. Nothing you do in IndexView has any effect on HomeView, and vice versa.
Continuing to reason by analogy to string interpolation, pretend your templates are global string variables instead of files on disk. Your situation is something like this:
base_categories = "My categories are: %(categories)s."
base_right_panel = "This is the right panel. Here are other fields before categories."
Using the {% include %} tag is something like string concatenation:
base_right_panel = base_right_panel + base_categories
Then your two views are analogous to this:
def home_view(request):
context = {}
return base_right_panel % context
def index_view(request)
context = {'categories': ['a', 'b', 'c']}
return base_categories % context
Unless you add the categories queryset to the context in HomeView, it will not be available to the template engine when rendering the response.
Your HomeView class should include the get_context_data method that you currently have in your IndexView. I am not sure you actually need IndexView at all, unless you want to have something that serves that page with just the categories list.