Develop Reference

Search text in file and print all text

okay. you didnt understand anything from the title. let me explain.
now ı have a file. There is some text in this file. for example "jack.123 jackie.321"
I want to check if the word jack exists in the file and ı wanna print "jack.123".
its my problem. ı didnt print all text.
def append(name,password):
f = open("myfile.txt", "w")
f.write("{},{}".format(name,password))
append("jack",".123")
append("jackie" , ".321")
f = open("myfile.txt" ,"r")
if "jack" in f.read():
print("query found")

Open the file and read all its contents then split on whitespace. That effectively gives you all the words in the file.
Iterate over the list of words checking to see if a word starts with the name you're searching for followed by '.'.
Note that there may be more than one occurrence so build a list.
def find_name(filename, name):
if not name[-1] == '.':
name += '.'
found = []
with open(filename) as myfile:
for word in myfile.read().split():
if word.startswith(name):
found.append(word)
return found
print(*find_name('myfile.txt', 'jack'))

def new_pass(name, passwd):
"creates file and write name and passwd to it"
with open("myfile1.txt", "a") as f:
f.write(name + "." + passwd + "\n")
new_pass("jack", "123")
new_pass("jack", "183")
new_pass("jack", "129")
new_pass("jack", "223")
def check_word(file, word):
"""checks if a word exists and returns its first occurence """
with open(file) as f:
l = f.read().split("\n")
for i in l:
if i.startswith(word):
print("query found")
return i
print(check_word("myfile1.txt", "jack"))

In python you can do it like that :
with open('file.txt', 'r') as file:
data = file.read()
if "jack" in data:
print("jack")
If I understood uncorrectly let me know

How often does xy occur in a line of a txt file? In Python

I am provided with a txt file including lots of different letters.
e.g:
ab sbfdjd iojdig
ds fjk sdfji oer
lkjäp foküeeferf
How can I check how often for example the letter "j" was used in line 1, line 2 and line 3 and store this information in an array/list?
So for this certain example
print(NumberOfJInLine[0])
would output:
2

Try this
def NumberOfStringInLine(index, string_to_find):
print(string_to_find, lines_of_file[index])
return lines_of_file[index].count(string_to_find)
def NumberOfJInLine(index):
return NumberOfStringInLine(index, "j")
lines_of_file = open("text.txt", "r").readlines()
print(NumberOfStringInLine(0, "jd"))
print(NumberOfJInLine(0))
You don't need the other function I added but it adds flexibility.
Alternatively:
def AccumulateAppearances():
with open("text.txt", "r") as file:
for line in file:
yield line.count("j")
for n in AccumulateAppearances():
print(n)

seekLetter = "j"
occur = {}
with open("{your filename}", "r") as file:
for nbLine,line in enumerate(file):
occur[nbLine] = line.count(seekLetter)
for line in occur.keys():
print("line {0} : ".format(line) + str(occur[line]) + seekLetter)
you can do it more easily with a dictionary

Deleting a specific word form a text file in python

I used this code to delete a word from a text file.
f = open('./test.txt','r')
a = ['word1','word2','word3']
lst = []
for line in f:
for word in a:
if word in line:
line = line.replace(word,'')
lst.append(line)
f.close()
f = open('./test.txt','w')
for line in lst:
f.write(line)
f.close()
But for some reason if the words have the same characters, all those characters get deleted. So for e.g
in my code:
def cancel():
global refID
f1=open("refID.txt","r")
line=f1.readline()
flag = 0
while flag==0:
refID=input("Enter the reference ID or type 'q' to quit: ")
for i in line.split(','):
if refID == i:
flag=1
if flag ==1:
print("reference ID found")
cancelsub()
elif (len(refID))<1:
print("Reference ID not found, please re-enter your reference ID\n")
cancel()
elif refID=="q":
flag=1
else:
print("reference ID not found\n")
menu()
def cancelsub():
global refIDarr, index
refIDarr=[]
index=0
f = open('flightbooking.csv')
csv_f = csv.reader(f)
for row in csv_f:
refIDarr.append(row[1])
for i in range (len(refIDarr)):
if refID==refIDarr[i]:
index=i
print(index)
while True:
proceed=input("You are about to cancel your flight booking, are you sure you would like to proceed? y/n?: ")
while proceed>"y" or proceed<"n" or (proceed>"n" and proceed<"y") :
proceed=input("Invalid entry. \nPlease enter y or n: ")
if proceed=="y":
Continue()
break
elif proceed=="n":
main_menu
break
exit
break
def Continue():
lines = list()
with open('flightbooking.csv', 'r') as readFile:
reader = csv.reader(readFile)
for row in reader:
lines.append(row)
for field in row:
if field ==refID:
lines.remove(row)
break
with open('flightbooking.csv', 'w') as writeFile:
writer = csv.writer(writeFile)
writer.writerows(lines)
f = open('refID.txt','r')
a=refIDarr[index]
print(a)
lst = []
for line in f:
for word in a:
if word in line:
line = line.replace(word,'')
lst.append(line)
print(lst)
f.close()
f = open('refID.txt','w')
for line in lst:
f.write(line)
f.close()
print("Booking successfully cancelled")
menu()
When the code is run, the refID variable has one word stored in it, and it should replace just that word with a blank space, but it takes that word for e.g 'AB123', finds all other words which might have an 'A' or a 'B' or the numbers, and replace all of them. How do I make it so it only deletes the word?
Text file before running code:
AD123,AB123
Expected Output in the text file:
AD123,
Output in text file:
D,
Edit: I have added the entire code, and maybe you can help now after seeing that the array is being appended to and then being used to delete from a text file.

here's my opinion.
refIDarr = ["AB123"]
a = refIDarr[0] => a = "AB123"
strings in python are iterable, so when you do for word in a, you're getting 5 loops where each word is actually a letter.
Something like the following is being executed.
if "A" in line:
line = line.replace("A","")
if "B" in line:
line = line.replace("B","")
if "1" in line:
line = line.replace("1","")
if "2" in line:
line = line.replace("2","")
if "3" in line:
line = line.replace("3","")
they correct way to do this is loop over refIDarr
for word in refIDarr:
line = line.replace(word,'')
NOTE: You don't need the if statement, since if the word is not in the line it will return the same line as it was.
"abc".replace("bananan", "") => "abc"
Here's a working example:
refIDarr = ["hello", "world", "lol"]
with open('mytext.txt', "r") as f:
data = f.readlines()
for word in refIDarr:
data = [line.replace(word, "") for line in data]
with open("mytext.txt", "w") as newf:
newf.writelines(data)

The problem is here:
a=refIDarr[index]
If refIDarr is a list of words, accessing specific index makes a be a word. Later, when you iterate over a (for word in a:), word becomes a letter and not a word as you expect, which causes eventually replacing characters of word instead the word itself in your file.
To avoid that, remove a=refIDarr[index] and change your loop to be:
for line in f:
for word in refIDarr:
if word in line:
line = line.replace(word,'')

Read lines from a text file into variables

I have two different functions in my program, one writes an output to a txt file (function A) and the other one reads it and should use it as an input (function B).
Function A works just fine (although i'm always open to suggestions on how i could improve).
It looks like this:
def createFile():
fileName = raw_input("Filename: ")
fileNameExt = fileName + ".txt" #to make sure a .txt extension is used
line1 = "1.1.1"
line2 = int(input("Enter line 2: ")
line3 = int(input("Enter line 3: ")
file = (fileNameExt, "w+")
file.write("%s\n%s\n%s" % (line1, line2, line3))
file.close()
return
This appears to work fine and will create a file like
1.1.1
123
456
Now, function B should use that file as an input. This is how far i've gotten so far:
def loadFile():
loadFileName = raw_input("Filename: ")
loadFile = open(loadFileName, "r")
line1 = loadFile.read(5)
That's where i'm stuck, i know how to use this first 5 characters but i need line 2 and 3 as variables too.

f = open('file.txt')
lines = f.readlines()
f.close()
lines is what you want
Other option:
f = open( "file.txt", "r" )
lines = []
for line in f:
lines.append(line)
f.close()
More read:
https://docs.python.org/2/tutorial/inputoutput.html#reading-and-writing-files

from string import ascii_uppercase
my_data = dict(zip(ascii_uppercase,open("some_file_to_read.txt"))
print my_data["A"]
this will store them in a dictionary with lettters as keys ... if you really want to cram it into variables(note that in general this is a TERRIBLE idea) you can do
globals().update(my_data)
print A

Read special characters from .txt file in python

The goal of this code is to find the frequency of words used in a book.
I am tying to read in the text of a book but the following line keeps throwing my code off:
precious protégés. No, gentlemen; he'll always show 'em a clean pair
specifically the é character
I have looked at the following documentation, but I don't quite understand it: https://docs.python.org/3.4/howto/unicode.html
Heres my code:
import string
# Create word dictionary from the comprehensive word list
word_dict = {}
def create_word_dict ():
# open words.txt and populate dictionary
word_file = open ("./words.txt", "r")
for line in word_file:
line = line.strip()
word_dict[line] = 1
# Removes punctuation marks from a string
def parseString (st):
st = st.encode("ascii", "replace")
new_line = ""
st = st.strip()
for ch in st:
ch = str(ch)
if (n for n in (1,2,3,4,5,6,7,8,9,0)) in ch or ' ' in ch or ch.isspace() or ch == u'\xe9':
print (ch)
new_line += ch
else:
new_line += ""
# now remove all instances of 's or ' at end of line
new_line = new_line.strip()
print (new_line)
if (new_line[-1] == "'"):
new_line = new_line[:-1]
new_line.replace("'s", "")
# Conversion from ASCII codes back to useable text
message = new_line
decodedMessage = ""
for item in message.split():
decodedMessage += chr(int(item))
print (decodedMessage)
return new_line
# Returns a dictionary of words and their frequencies
def getWordFreq (file):
# Open file for reading the book.txt
book = open (file, "r")
# create an empty set for all Capitalized words
cap_words = set()
# create a dictionary for words
book_dict = {}
total_words = 0
# remove all punctuation marks other than '[not s]
for line in book:
line = line.strip()
if (len(line) > 0):
line = parseString (line)
word_list = line.split()
# add words to the book dictionary
for word in word_list:
total_words += 1
if (word in book_dict):
book_dict[word] = book_dict[word] + 1
else:
book_dict[word] = 1
print (book_dict)
# close the file
book.close()
def main():
wordFreq1 = getWordFreq ("./Tale.txt")
print (wordFreq1)
main()
The error that I received is as follows:
Traceback (most recent call last):
File "Books.py", line 80, in <module>
main()
File "Books.py", line 77, in main
wordFreq1 = getWordFreq ("./Tale.txt")
File "Books.py", line 60, in getWordFreq
line = parseString (line)
File "Books.py", line 36, in parseString
decodedMessage += chr(int(item))
OverflowError: Python int too large to convert to C long

When you open a text file in python, the encoding is ANSI by default, so it doesn't contain your é chartecter. Try
word_file = open ("./words.txt", "r", encoding='utf-8')

The best way I could think of is to read each character as an ASCII value, into an array, and then take the char value. For example, 97 is ASCII for "a" and if you do char(97) it will output "a". Check out some online ASCII tables that provide values for special characters also.

Try:
def parseString(st):
st = st.encode("ascii", "replace")
# rest of code here
The new error you are getting is because you are calling isalpha on an int (i.e. a number)
Try this:
for ch in st:
ch = str(ch)
if (n for n in (1,2,3,4,5,6,7,8,9,0) if n in ch) or ' ' in ch or ch.isspace() or ch == u'\xe9':
print (ch)