Develop Reference

Why does the github API python POST request not work?

I want to create a pull request on github using the API. The following curl command does work
curl \
-X POST \
-H "Accept: application/vnd.github.v3+json" -H "Authorization: token ghp_abc...123" \
https://api.github.com/repos/alex4200/hello-world/pulls \
-d '{"head":"copyright_updater","base":"master","title":"Test PR curl"}'
but this python snippet does not work:
import requests
headers = {
"Accept": "application/vnd.github.v3+json",
"Authorization": "token ghp_abc...123"
}
data = {
"head": "copyright_updater",
"base": "master",
"title": "Test PR python"
}
response = requests.post(
"https://api.github.com/repos/alex4200/hello-world/pulls",
headers=headers,
data=data
)
print(response.text)
This command, with the exact same data as the curl, returns a 400 error with the message
{"message":"Problems parsing JSON","documentation_url":"https://docs.github.com/rest/reference/pulls#create-a-pull-request"}
What is the problem here?

How to turn python dict into Curl

For some reasons my requests to an API is failing. This is the code:
def create_alert(alert_dict)
url = host + '/api/alerts'
headers = {
'Content-Type': 'application/json',
'Authorization': 'Bearer tokengen'
}
response = requests.request('POST', url, headers = headers, data=json.dumps(alert_dict))
return response
alert_dict = {
"priority": "1",
"to": to,
"from": from_
}
response = create_alert(alert_dict)
print(response)
The way I'm doing it is saving everything to a dictionary, then making the POST request with it. But for some reason im getting a 500 error.
This is the curl that is working
curl --location --request POST "http://newhost.com/api/alerts" \
--header "Content-Type: application/json" \
--header "Authorization: Bearer tokengen" \
--data "{
\"to\": \"sample#email.com\",
\"from\": \"from#email.com\",
\"priority\": \"1\",
}"
How should I convert my dict in a way that it would work just like the curl --data when requested

Python - curl request - 'data-urlencode'

I would like to make a python query with this data but I can not convert the 'data-urlencode' interpretable for the python query.
It's my curl request :
curl \
--compressed \
-H 'Accept-Encoding:gzip' \
-H 'Accept-Language:fr-FR,fr;q=0.9,en-US;q=0.8,en;q=0.7' \
--get '**myurl**' \
--data-urlencode 'app_code=xxxxxx' \
--data-urlencode 'app_id=xxxxxx'
And this this my actual python request:
import requests
headers = {
'Accept-Encoding': 'gzip',
'Accept-Language': 'fr-FR,fr;q=0.9,en-US;q=0.8,en;q=0.7',
}
data = {
'app_code': 'xxxxx',
'app_id': 'xxxxx'
}
response = requests.post('https://places.cit.api.here.com/places/v1/autosuggest', headers=headers, data=data)
I have trouble encoding the data to get the json.
Thanks

Isn't that curl command a GET request?
I'm not able to try your example but could you please try using the code below.
import requests
url = "https://places.cit.api.here.com/places/v1/autosuggest"
h = {
"Accept-Encoding":"gzip",
"Accept-Language":"fr-FR,fr;q=0.9,en-US;q=0.8,en;q=0.7"
}
params = {
"app_code":"xxxxx",
"app_id":"xxxxx"
}
r = request.get(url, headers=h, params=params).json()

How can I convert this cURL command to a python script?

curl -X POST -H "Content-Type: application/x-www-form-urlencoded" -d 'client_id=535fb089-9ff3-47b6-9bfb-4f1264799865&scope=https%3A%2F%2Fgraph.microsoft.com%2F.default&client_secret=qWgdYAmab0YSkuL1qKv5bPX&grant_type=client_credentials' 'https://login.microsoftonline.com/common/oauth2/v2.0/token'
Here is the command.

How about this sample script?
Sample script :
import json
import requests
url = "https://login.microsoftonline.com/common/oauth2/v2.0/token"
payload = {
"client_id": "535fb089-9ff3-47b6-9bfb-4f1264799865",
"client_secret": "qWgdYAmab0YSkuL1qKv5bPX",
"grant_type": "client_credentials",
"scope": "https://graph.microsoft.com/.default"
}
headers = {
"Content-Type": "application/x-www-form-urlencoded"
}
res = requests.post(url, headers=headers, data=json.dumps(payload))
print(res.text)
If I misunderstand your question, I'm sorry.

You could use os (though it's outdated)
import os
os.system("curl -X POST -H "Content-Type: application/x-www-form-urlencoded" -d 'client_id=535fb089-9ff3-47b6-9bfb-4f1264799865&scope=https%3A%2F%2Fgraph.microsoft.com%2F.default&client_secret=qWgdYAmab0YSkuL1qKv5bPX&grant_type=client_credentials' 'https://login.microsoftonline.com/common/oauth2/v2.0/token'")

CURL in Python or Django

What's the alternative of doing this, in Python?
curl -X POST \
-H 'accept: application/json' \
-H 'content-type: application/x-www-form-urlencoded' \
'https://api.mercadolibre.com/oauth/token' \
-d 'grant_type=client_credentials' \
-d 'client_id=CLIENT_ID' \
-d 'client_secret=CLIENT_SECRET'
And the JSON response is something like this:
Status code: 200 OK
{
"access_token": "TU_ACCESS_TOKEN",
"token_type": "bearer",
"expires_in": 10800,
"scope": "...",
"refresh_token": "REFRESH_TOKEN"
}
Anyone knows how can I get the access_token? Not the entire JSON, I only need the access_token.
Thanks

There appears to be a Python library for MercadoLibre which wraps all that up for you.

Something like this should work for you:
import httplib
import urllib
conn = httplib.HTTPSConnection("api.mercadolibre.com")
conn.request("POST", "/oauth/token", urllib.urlencode({
"grant_type": "client_credentials",
"client_id": "CLIENT_ID",
"client_secret": "CLIENT_SECRET",
}), {"accept": "application/json", "content-type": "application/x-www-form-urlencoded"})
conn.getresponse()

Look here http://docs.python-requests.org/en/latest/ requests library is good enough.