I'm trying to connect another computer in local network via python (subprocesses module) with this commands from CMD.exe
net use \\\\ip\C$ password /user:username
copy D:\file.txt \\ip\C$
Then in python it look like below.
But when i try second command, I get:
"FileNotFoundError: [WinError 2]"
Have you met same problem?
Is there any way to fix it?
import subprocess as sp
code = sp.call(r'net use \\<ip>\C$ <pass> /user:<username>')
print(code)
sp.call(r'copy D:\file.txt \\<ip>\C$')
The issue is that copy is a built-in, not a real command in Windows.
Those Windows messages are awful, but "FileNotFoundError: [WinError 2]" doesn't mean one of source & destination files can't be accessed (if copy failed, you'd get a normal Windows message with explicit file names).
Here, it means that the command could not be accessed.
So you'd need to add shell=True to your subprocess call to gain access to built-ins.
But don't do that (security issues, non-portability), use shutil.copy instead.
Aside, use check_call instead of call for your first command, as if net use fails, the rest will fail too. Better have an early failure.
To sum it up, here's what I would do:
import shutil
import subprocess as sp
sp.check_call(['net','use',r'\\<ip>\C$','password','/user:<username>'])
shutil.copy(r'D:\file.txt,r'\\<ip>\C$')
you need make sure you have right to add a file.
i have testted successfully after i corrected the shared dirctory's right.
Related
I'm trying to remove a file in Python 3 on Linux (RHEL) the following way:
os.remove(or.getcwd() + '/file.txt')
(sorry not allowed to publish the real paths).
and it gives me the usual error
No such file or directory: '/path/to/file/file.txt'
(I've respected slash or antislash in the path)
What is strange is that when I just ls the file (by copy pasting, so the very same path) the file does exist.
I've read this post but i'm not on Windows and slash direction seems correct.
Any idea ?
EDIT: as suggested by #DominicPrice os.system('ls') is showing the file while os.listdir() does not show it (but shows other files in the same directory)
EDIT 2: So my issue was due a a bad usage of os.popen. I used this method to copy file but did not wait for the subprocess to be terminated. So my understanding is that the file was not copied yet when I tried to delete it.
The problem is that, as you have explained in the comments, you are creating the file using os.popen("cp ..."). This works asynchronously, so it may not have had time to complete by the time you call os.remove(). You can force python to wait for it to finish by calling the close method:
proc = os.popen("cp myfile myotherfile")
proc.close() # wait for process to finish
os.remove("myotherfile") # we're all good
I would highly recommend staying away from using os.popen in favour of the subprocess library, which has a run function which is way safer to use.
For the specific functions of copying a file, an even better (and cross platform) solution is to use the shutil library:
import shutil
shutil.copyfile("myfile", "myotherfile")
you should use os.path.dirname(__file__).
this is an inbuilt function of os module in python.
you can read more here.
https://www.geeksforgeeks.org/find-path-to-the-given-file-using-python/
I have a script that has 4 lines of code:
import subprocess
folderAdd = r"D:\Program Files (x86)\someapp\"
result = subprocess.run(['"' + folderAdd +'someProgram.exe"','"' + folderAdd +'somefile.ext"'], stdout=subprocess.PIPE)
print(result.stdout)
I've edited the code slightly to remove the specifics of the files/folders (since I assume that's not the issue?). The someProgram.exe is a go lang program I've made, the somefile.ext is a file that I pass to the go land program using the command line (eg the syntax in command line is: "someProgram.ext somefile.ext". The issue I'm having is when I run this script (which is stored on my E drive - so that's the working directory) I get the following error:
PermissionError: [WinError 5] Access is denied
I've tried running this python script from within spyder (my ide of choice) and from command line. Both of which I've tried running as administrator (based on this question/answer). I still get the same permission error. Is there any other way around this?
you're adding double quotes that should not be here.
Also you should join path using python's facility : os.path.join
(https://docs.python.org/3.8/library/os.path.html#os.path.join)
If you only what stdout, you can use subprocess.check_outout
(https://docs.python.org/3.8/library/subprocess.html#subprocess.check_output)
import subprocess
folderAdd = r"D:\Program Files (x86)\someapp"
print(subprocess.check_output([os.path.join(folderAdd, 'someProgram.exe'), os.path.join(folderAdd, 'somefile.ext'])
I am making a body tracking application where I want to run Open Pose if the user chooses to track their body movements. The OpenPose binary file can be run like so:
bin\OpenPoseDemo.exe --write_json 'path\to\dump\output'
So, in my Python script, I want to have a line of code that would run Open Pose, instead of having to ask the user to manually run OpenPose by opening a separate command line window. For that, I have tried:
import os
os.popen(r"C:\path\to\bin\OpenPoseDemo.exe --write_json 'C:\path\to\dump\output'")
But this gives the following error:
Error:
Could not create directory: 'C:\Users\Admin\Documents\Openpose\. Status error = -1. Does the parent folder exist and/or do you have writing access to that path?
Which I guess means that OpenPose can be opened only by going inside the openpose directory where the bin subdirectory resides. So, I wrote a shell script containing this line:
bin\OpenPoseDemo.exe --write_json 'C:\path\to\dump\output'
and saved it as run_openpose_binary.sh in the openpose directory (i.e., the same directory where bin is located).
I then tried to run this shell script from within my Python script like so:
import subprocess
subprocess.call(['sh', r'C:\path\to\openpose\run_openpose_binary.sh'])
and this gives the following error:
FileNotFoundError: [WinError 2] The system cannot find the file specified
I also tried the following:
os.popen(r"C:\path\to\openpose\run_openpose_binary.sh")
and
os.system(r"C:\path\to\openpose\run_openpose_binary.sh")
These do not produce any error, but instead just pop up a blank window and closes.
So, my question is, how do I run the OpenPoseDemo.exe from within my Python script?
For your last method, you're missing the return value from os.popen, which is a pipe. So, what you need is something like:
# untested as I don't have access to a Windows system
import os
with os.popen(r"/full/path/to/sh C:/path/to/openpose/run_openpose_binary.sh") as p:
# pipes work like files
output_of_command = p.read().strip() # this is a string
or, if you want to future-proof yourself, the alternative is:
# untested as I don't have access to a Windows system
popen = subprocess.Popen([r'/full/path/to/sh.exe', r'/full/path/to/run_openpose_binary.sh')], stdin=subprocess.PIPE, stdout=subprocess.PIPE,encoding='utf-8')
stdout, stderr = popen.communicate(input='')
Leave a comment if you have further difficulty.
I've had to fight this battle several times and I've found a solution. It's likely not the most elegant solution but it does work, and I'll explain it using an example of how to run OpenPose on a video.
You've got your path to the openpose download and your path to the video, and from there it's a 3-line solution. First, change the current working directory to that openpose folder, and then create your command, then call subprocess.run (I tried using subprocess.call and that did not work. I did not try shell=False but I have heard it's a safer way to do so. I'll leave that up to you.)
import os
import subprocess
openpose_path = "C:\\Users\\me\\Desktop\\openpose-1.7.0-binaries-win64-gpu-python3.7-flir-3d_recommended\\openpose\\"
video_path = "C:\\Users\\me\\Desktop\\myvideo.mp4"
os.chdir(openpose_path)
command = "".join(["bin\\OpenPoseDemo.exe", " -video ", video_path])
subprocess.run(command, shell=True)
I want to call a program multiple times from a python code, and save the output of that program in a text file. My first problem right now is just calling the other code. I have to redirect to a different directory and call ./rank on output.txt. This is how Im trying to do it:
TheCommand = "~/src/rank-8-9-2011/rank output.txt"
os.system(TheCommand)
but im getting a parsing error.
[Parsing error on line ]Unknown error: 0
Im running python2.7 on Mac OS 10.5.8. Im not sure what the problem is. I also tried using subprocess:
subprocess.call(["~/src/rank-8-9-2011/rank", "output.txt"])
This does not find the directory (I have a feeling Im using the subprocess incorrectly), but I dont know what is wrong with the os.system.
the name of the program in the first argument to subprocess.Popen must not contain ~ as it doesn't pass the string to the shell for processing (which like always using parameterized queries in sql, protects one from string injection attacks, e.g. if instead of output.text one had ;rm -rf /, the system version would run rank and then run rm -rf . but the subprocess.Popen would only have rank open a file named ;rm -rf .), so one should expand it by calling os.path.expanduser:
subprocess.Popen([os.path.expanduser('~/src/rank-8-9-2011/rank'), "output.txt"])
although it is possible to turn shell processing on by passing shell=True, it is not recommended for the aforementioned reason.
you should try http://docs.python.org/library/os.path.html#os.path.expanduser
import os.path
subprocess.call([os.path.expanduser("~/src/rank-8-9-2011/rank"), "output.txt"])
I'm fairly certain your parsing error is coming from rank, not from your os.system command, as nothing there looks weird. What happens if you run rank manually?
subprocess seems to have a problem with '~', although I'm not immediately sure why. Put the full path and it should work (although you'll likely get that parsing error if it is indeed a problem with rank).
I'm trying to use python to run a program.
from subprocess import Popen
sa_proc = Popen(['C:\\sa\\sa.exe','--?'])
Running this small snippit gives the error:
WindowsError: [Error 2] The system cannot find the file specified
The program exists and I have copy and pasted directly from explorer the absolute path to the exe. I have tried other things and have found that if I put the EXE in the source folder with the python script and use './sa.exe' then it works. The only thing I can think of is that I'm running the python script (and python) from a separate partition (F:).
Any ideas?
Thanks
As the docs say, "On Windows: the Popen class uses CreateProcess() to execute the child program, which operates on strings. If args is a sequence, it will be converted to a string using the list2cmdline() method.". Maybe that method is messing things up, so why not try the simpler approach of:
sa_proc = Popen('C:\\sa\\sa.exe --?')
If this still fails, then: what's os.environ['COMSPEC'] just before you try this? What happens if you add , shell=True to Popen's arguments?
Edit: turns out apparently to be a case of simple mis-spellling, as 'sa' was actually the program spelled SpamAssassin -- double s twice -- and what the OP was writing was spamassasin -- one double s but a single one the second time.
You may not have permission to execute C:\sa\sa.exe. Have you tried running the program manually?