Develop Reference

Python tKinter - Is there a way to get rid of existing label before making a new count-up?

I've found a countdown code and modified it so it counts up to a given number. It all works, but every time I push the button to run the functions, the existing label stays there and the new one gets put on top. (If I pack them, they get put underneath each other). It's because they get created inside the function, but I can't seem to find a way around it.
It might be a newbie question, but I'm just trying to learn :)
Code:
import time
from tkinter import *
import threading
betongtrykk = Tk()
betongtrykk.geometry("400x300")
canvas = Canvas(
betongtrykk,
bg = "#FFFFFF",
height = 300,
width = 400,
bd = 0,
highlightthickness = 0,
relief = "ridge"
)
canvas.place(x = 0, y = 0)
utnyttelseres = 65
def cd(timer_label_obj,ts):
while ts < utnyttelseres:
timer_label_obj.config(text=ts)
ts+=1
timer_label_obj.place(x=100, y=150)
time.sleep(0.01)
if ts == utnyttelseres:
timer_label_obj.config(text=utnyttelseres)
def countup(t):
timer = Label(betongtrykk)
th = threading.Thread(target=cd,args=[timer,t])
th.start()
submitCountdown = Button(betongtrykk, padx=5, pady=5, text="Submit", font=("Arial", 20), command= lambda:countup(0))
submitCountdown.place(x= 100, y=100)
betongtrykk.mainloop()

You can use the <widget>.destroy() method on the Label widget once the countdown is complete. This method will delete the widget and remove it from the screen.
Corrected Code:
import time
from tkinter import *
import threading
betongtrykk = Tk()
betongtrykk.geometry("400x300")
canvas = Canvas(
betongtrykk,
bg = "#FFFFFF",
height = 300,
width = 400,
bd = 0,
highlightthickness = 0,
relief = "ridge"
)
canvas.place(x = 0, y = 0)
utnyttelseres = 65
def cd(timer_label_obj,ts):
while ts < utnyttelseres:
timer_label_obj.config(text=ts)
ts+=1
timer_label_obj.place(x=100, y=150)
time.sleep(0.01)
if ts == utnyttelseres:
timer_label_obj.config(text=utnyttelseres)
timer_label_obj.destroy()
def countup(t):
timer = Label(betongtrykk)
th = threading.Thread(target=cd,args=[timer,t])
th.start()
submitCountdown = Button(betongtrykk, padx=5, pady=5, text="Submit", font=("Arial", 20), command = lambda:countup(0))
submitCountdown.place(x= 100, y=100)
betongtrykk.mainloop()
Alternate Solution:
If you want the countdown label to be removed JUST before the next countdown starts, you can make timer a global variable and use the .destroy() method on it before creating the new countdown label in countup.
def cd(timer_label_obj,ts):
while ts < utnyttelseres:
timer_label_obj.config(text=ts)
ts+=1
timer_label_obj.place(x=100, y=150)
time.sleep(0.01)
if ts == utnyttelseres:
timer_label_obj.config(text=utnyttelseres)
def countup(t):
global timer
try:
timer.destroy()
except NameError:
pass
timer = Label(betongtrykk)
th = threading.Thread(target=cd,args=[timer,t])
th.start()

To perform the timer task using python

I want reset the timer to 0 when it reaches to 8 and should sleep for 5 secs showing timer value as 0 and again restart from zero and repeat.
when linemode == 'dashed': But with my current code when it reaches 8 it displays 8, where i want to display 0 for 5 secs. I have posted full code snippet as well as piece of code where code has to perform expectation. Thanks in Advnc
code Snippet:-
if ton > ontym:
if linemode == 'dashed':
counter=0
lbl['text']='00'
sleep(offtym)
ton=-1
lbl.after(1000, count)
else:
lbl.after(1000, count)
else:
lbl.after(1000, count)
Full code Snippet:-
#!/usr/bin/env python
from Tkinter import Tk,Label,Button
import rospy
from time import sleep
from PIL import Image, ImageTk
ws = Tk()
#ws.geometry('400x450+1000+300')
ws.title('Stopwatch')
ws.attributes('-fullscreen', True)
ws.config(bg='#efb570')
#ws.resizable(0,0)
ontym=8
offtym=5
ton=-1
linemode = 'dashed'
counter = 0
running = False
def counter_label(lbl):
def count():
if running:
global counter,offtym,ontym,ton,linemode
if counter == 0:
display="00"
else:
display='0' +str(counter)
if counter > 9:
display = str(counter)
lbl['text']=display
counter += 1
ton += 1
if ton > ontym:
if linemode == 'dashed':
counter=0
lbl['text']='00'
sleep(offtym)
ton=-1
lbl.after(1000, count)
else:
lbl.after(1000, count)
else:
lbl.after(1000, count)
count()
def StartTimer(lbl):
global running
running=True
counter_label(lbl)
start_btn['state']='disabled'
stop_btn['state']='normal'
def StopTimer():
global running
start_btn['state']='normal'
stop_btn['state']='disabled'
running = False
pic=Image.open("/home/nooduupachuu/catkin_ws/src/gui_sample/scripts/abc.png")
tkImg=ImageTk.PhotoImage(pic)
lbl1=Label(ws, image=tkImg, bg='#efb570')
lbl1.image=tkImg
lbl1.place(x=405, y=50)
lbl = Label(ws, text="00", fg="black", bg='#efb570', font="Verdana 80 bold")
label_msg = Label(ws, text="seconds", fg="black", bg='#efb570', font="Verdana 30 bold")
lbl.place(x=585, y=315)
label_msg.place(x=570, y=445)
start_btn=Button(ws, text='START', width=9, bd=2, font=("Arial Bold", 12), command=lambda:StartTimer(lbl))
stop_btn = Button(ws, text='STOP', width=9, bd=2, font=("Arial Bold", 12), state='disabled', command=StopTimer)
start_btn.place(x=535, y=700)
stop_btn.place(x=675, y=700)
ws.mainloop()

“name is not defined” inside function

I want to create a countdown clock and I almost did but if I run this code down below and press the 'go' button, I get the error: NameError: name 'be' is not defined. Even if I try to put global be in there it doesn't seem to work
import tkinter as tk
def set1():
global be
if be1 is not '':
be = int(en.get())
def countdown():
global be
if be >= 0:
mins, secs = divmod(be, 60)
timer = '{:02d}:{:02d}'.format(mins, secs)
label['text'] = timer
root.after(1000, countdown)
be -= 1
root = tk.Tk()
label = tk.Label(root, text = '00:00', font = 'Helvetica 25')
label.pack()
en = tk.Entry(root)
en.pack()
be1 = en.get()
tk.Button(root, text = 'set', height = 3, width = 20, command = lambda: set1()).pack()
tk.Button(root, text = 'go', height = 3, width = 20, command = lambda: countdown()).pack()
root.mainloop()

Please give be a value on top of your code, for example
be = 0

Increasing integers at specific time with elapsed time

I'm trying to make a program that will work as an "infomercial" in a separate window.
What i have are two integers (x and y) that both increase at the same time, in this case every 5 seconds. With the increasing values i need a timer displayed at the same time, that can show the elapsed time of how long the program has been running. I want to be albe to start and pause the program
So far i have an infinite while loop running where the values are increased every 5 seconds with time.sleep(5). I have tried implementing a timer in the form of a time.time(), and get it to work with the increments. I have also added buttons but don't work. I'm using tkinter as gui obtion.
How am i supposed to make it work? with threading?
import time
from tkinter import *
import math
usage = 0
yearly = 0
cubik = 0
price = 0
root = Tk()
root.title("Usage of fluid")
root.geometry("300x400")
var = IntVar()
var1 = IntVar()
var2 = StringVar()
var3 = StringVar()
var4 = StringVar()
def update_timeText():
current= time.strftime("%H:%M:%S")
timeText.configure(text=current)
root.after(1000, update_timeText)
def start():
global state
state = True
def pause():
global state
state = False
def exist():
root.destroy()
frame = LabelFrame(root, text="Liter", font=30)
frame.pack(fill = "both", expand="yes")
l = Label(frame, textvariable=var, font=20)
l.pack(pady = 3)
frame2 = LabelFrame(root, text="price from use", font=30)
frame2.pack(fill = "both", expand= "yes")
l2 = Label(frame2, textvariable=var1, font=16)
l2.pack(side = LEFT)
l3 = Label(frame2, text="dollars", font=16)
l3.pack(side=LEFT)
frame3 = LabelFrame(root, text="yearly", font=30)
frame3.pack(fill = "both", expand="yes")
m3 = Label(frame3, textvariable=var2, font=16, wraplength=0)
m3.pack(side=TOP)
l4 = Label(frame3, text="Liter", font=16)
l4.pack(side=TOP)
l5 = Label(frame3, text="m3", font=16)
l5.pack(side=BOTTOM, fill="both")
m4 = Label(frame3, textvariable=var3, font=16, wraplength=0)
m4.pack(side=BOTTOM)
frame4 = LabelFrame(root, text='runtime', font=30)
frame4.pack(fill = "both", expand="yes")
timeText= Label(frame4, text="", font=16)
timeText.pack()
startButton = Button(frame4, text='Start', command=start)
startButton.pack()
pauseButton = Button(frame4, text='Pause', command=pause)
pauseButton.pack()
quitButton = Button(frame4, text='Quit', command=quit)
quitButton.pack()
while True:
var.set(usage)
usage += 300
var1.set(round(price,1))
price+= 10
var2.set(yearly)
var3.set(round(cubik,1))
yearly += 300
cubik += 0.1
time.sleep(5)
update_timeText()
root.update_idletasks()
##update_timeText()
##root.mainloop()

Combine two windows with tkinter

I have just started playing with tkinter today and I have two bit of code I have been playing with as examples however I am struggling to combine these can anyone advise. I would like to clock to display in the main window.
import tkinter
from tkinter import *
import sys
import time
root = Tk()
root.title('Logging')
Label(text='Time logging').pack(side=TOP,padx=100,pady=100)
entry = Entry(root, width=25)
entry.pack(side=TOP,padx=25,pady=25)
def onok():
x, y = entry.get().split('x')
for row in range(int(y)):
for col in range(int(x)):
print((col, row))
Button(root, text='Log Time', command=onok).pack(side=LEFT)
Button(root, text='CLOSE').pack(side= RIGHT)
def tick():
global time1
# get the current local time from the PC
time2 = time.strftime('%H:%M:%S')
# if time string has changed, update it
if time2 != time1:
time1 = time2
clock.config(text=time2)
# calls itself every 200 milliseconds
# to update the time display as needed
# could use >200 ms, but display gets jerky
clock.after(200, tick)
root = Tk()
time1 = ''
status = Label(root, text="v1.0", bd=1, relief=SUNKEN, anchor=W)
status.grid(row=10, column=10)
clock = Label(root, font=('times', 20, 'bold'), bg='green')
clock.grid(row=0, column=1)
tick()
root.mainloop()

You can use Frame to group clock widgets and use grid inside this frame. And frame you can put in main window. (And you don't need second Tk())
I put it at the top but you can choose other place.
import tkinter as tk
import time
# --- functions ---
def on_ok():
x, y = entry.get().split('x')
for row in range(int(y)):
for col in range(int(x)):
print((col, row))
def tick():
global time1
# get the current local time from the PC
time2 = time.strftime('%H:%M:%S')
# if time string has changed, update it
if time2 != time1:
time1 = time2
clock.config(text=time2)
# calls itself every 200 milliseconds
# to update the time display as needed
# could use >200 ms, but display gets jerky
clock.after(200, tick)
# --- main window ---
time1 = ''
root = tk.Tk()
root.title('Logging')
# add frame in main window (root)
other = tk.Frame(root)
other.pack()
# put widgets in frame (other)
status = tk.Label(other, text="v1.0", bd=1, relief=tk.SUNKEN, anchor=tk.W)
status.grid(row=10, column=10)
clock = tk.Label(other, font=('times', 20, 'bold'), bg='green')
clock.grid(row=0, column=1)
# put other widget directly in main widnow (root)
tk.Label(root, text='Time logging').pack(side=tk.TOP, padx=100, pady=100)
entry = tk.Entry(root, width=25)
entry.pack(side=tk.TOP, padx=25, pady=25)
tk.Button(root, text='Log Time', command=on_ok).pack(side=tk.LEFT)
tk.Button(root, text='CLOSE', command=root.destroy).pack(side= tk.RIGHT)
tick()
# --- start ---
root.mainloop()

You have two different root windows. Use one root = Tk() line at the top and you should have them on the same page.