I have xml in similiar structure:
<terms>
<entry ID="1">
<language ID="1">en</language>
<term>user</term>
<state>text</state>
<use>text</use>
<definition ID="1">text</definition>
<subdefinition ID="1">text</subdefinition>
<definition-source>text</definition-source>
<source ID="1">text</source>
<circle>text</circle>
</entry>
In this case, parent and child elements contain attribute ID. Is there a way, how to find all elements from a tree that contains attribute ID and change value to 0 or dele it?
I was trying to do it with XPath but it's difficult when there is a deep hierarchy and any of elements can have this attribute.
another way would be to handle it as a string, but is there a way how to do it in ElementTree?
It should be fairly easy using the XPath .//*[#ID] to select the elements.
Here's an example changing all ID values to 0...
XML Input (test.xml)
<terms>
<entry ID="1">
<language ID="1">en</language>
<term>user</term>
<state>text</state>
<use>text</use>
<definition ID="1">text</definition>
<subdefinition ID="1">text</subdefinition>
<definition-source>text</definition-source>
<source ID="1">text</source>
<circle>text</circle>
</entry>
</terms>
Python
import xml.etree.ElementTree as ET
tree = ET.parse("test.xml")
for elem in tree.findall(".//*[#ID]"):
elem.attrib["ID"] = "0"
ET.dump(tree.getroot())
Output (dumped to console)
<terms>
<entry ID="0">
<language ID="0">en</language>
<term>user</term>
<state>text</state>
<use>text</use>
<definition ID="0">text</definition>
<subdefinition ID="0">text</subdefinition>
<definition-source>text</definition-source>
<source ID="0">text</source>
<circle>text</circle>
</entry>
</terms>
Related
I have this XML file :
<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<feed xml:base="https://receasy1p1942606901trial.hanatrial.ondemand.com:443/rec/Accrual_PO.xsodata/"
xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices"
xmlns:m="http://schemas.microsoft.com/ado/2007/08/dataservices/metadata"
xmlns="http://www.w3.org/2005/Atom">
<title type="text">accruals_po</title>
<id>https://receasy1p1942606901trial.hanatrial.ondemand.com:443/rec/Accrual_PO.xsodata/accruals_po</id>
<author>
<name />
</author>
<link rel="self" title="accruals_po" href="accruals_po" />
<entry>
<id>https://receasy1p1942606901trial.hanatrial.ondemand.com:443/rec/Accrual_PO.xsodata/accruals_po('96372537-120')</id>
<title type="text"></title>
<author>
<name />
</author>
<link rel="edit" title="accruals_po" href="accruals_po('96372537-120')"/>
<category term="receasy.accruals_poType" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" />
<content type="application/xml">
<m:properties>
<d:PO_NUMBER m:type="Edm.String">96372537-120</d:PO_NUMBER>
<d:SAP_AMT m:type="Edm.Single">109</d:SAP_AMT>
<d:GL_ACCOUNT m:type="Edm.Int64">65009000</d:GL_ACCOUNT>
<d:COMPANY_CODE m:type="Edm.String">US10_OH</d:COMPANY_CODE>
<d:CONFIRMED_ACCRUAL_AMT m:type="Edm.Single">109</d:CONFIRMED_ACCRUAL_AMT>
<d:FINAL_APPROVER m:type="Edm.String">europe\bamcguir</d:FINAL_APPROVER>
<d:FINAL_GL_ACCOUNT m:type="Edm.Int64">65009000</d:FINAL_GL_ACCOUNT>
<d:FINAL_COMPANY_CODE m:type="Edm.String">US10_OH</d:FINAL_COMPANY_CODE>
<d:RECONCILIATION m:type="Edm.String">Successful</d:RECONCILIATION>
</m:properties>
</content>
</entry>
</feed>
I'm trying to get the values highlighted below in bold, they are under the entry tag.
96372537-120
109
65009000
US10_OH
109
europe\bamcguir
65009000
US10_OH
Successful
This is the code I have as of now to get the values.
import urllib2
import xmltodict
import xml.etree.ElementTree as ET
import requests
tree = ET.parse('export.xml')
root = tree.getroot()
for child in root:
print child.tag, child.attrib
for child2 in child:
print child2.tag, child2.attrib
for child3 in child2:
print child3.tag, child3.attrib
for child4 in child3:
print child4.tag, child4.attrib
for child5 in child4:
print child5.tag, child5.attrib
This is part of the output that I get for PO_NUMBER.
{http://schemas.microsoft.com/ado/2007/08/dataservices}PO_NUMBER {'{http://schemas.microsoft.com/ado/2007/08/dataservices/metadata}type': 'Edm.String'}
I'm not able to get the value of PO_NUMBER which is 96372537-120. How do I get this value, and the other values as highlighted above?
In ElementTree, an element's (leading) text node is set on the text attribute. tag is the name of the XML tag (in Clark's notation) and attrib are the XML attributes only (also in Clark's notation).
So child5.text will give you the information you need.
Incidentally, you can use Clark's notation {namespace}tag with ElementTree's regular querying API to access the content or properties element directly, you don't have to iterate everything by hand:
tree.iter('{http://schemas.microsoft.com/ado/2007/08/dataservices/metadata}properties')
will give you an iterator on all the "properties" objects in the tree, and then you can just iterate on each property and get the corresponding child's text:
for child in property:
print(child.text)
Note an oddity for mixed content (when an element can have both text and element children): in the ElementTree document model, only first child is set on .text when it's a text node, otherwise it's set as .tail on the preceding element e.g.
<foo>
bar
<qux/>
baz
</foo>
will have foo.text == "bar" but "baz" will be set on qux.tail.
I have to extract friendlyName from the XML document.
Here's my current solution:
root = ElementTree.fromstring(urllib2.urlopen(XMLLocation).read())
for child in root.iter('{urn:schemas-upnp-org:device-1-0}friendlyName'):
return child.text
I there any better way to do this (maybe any other way which does not involve iteration)? Could I use XPath?
XML content:
<?xml version="1.0" encoding="UTF-8"?>
<root xmlns="urn:schemas-upnp-org:device-1-0">
<specVersion>
<major>1</major>
<minor>0</minor>
</specVersion>
<device>
<dlna:X_DLNADOC xmlns:dlna="urn:schemas-dlna-org:device-1-0">DMR-1.50</dlna:X_DLNADOC>
<deviceType>urn:schemas-upnp-org:device:MediaRenderer:1</deviceType>
<friendlyName>My Product 912496</friendlyName>
<manufacturer>embedded</manufacturer>
<manufacturerURL>http://www.embedded.com</manufacturerURL>
<modelDescription>Product</modelDescription>
<modelName>Product</modelName>
<modelNumber />
<modelURL>http://www.embedded.com</modelURL>
<UDN>uuid:93b2abac-cb6a-4857-b891-002261912496</UDN>
<serviceList>
<service>
<serviceType>urn:schemas-upnp-org:service:ConnectionManager:1</serviceType>
<serviceId>urn:upnp-org:serviceId:ConnectionManager</serviceId>
<SCPDURL>/xml/ConnectionManager.xml</SCPDURL>
<eventSubURL>/Event/org.mpris.MediaPlayer2.mansion/RygelSinkConnectionManager</eventSubURL>
<controlURL>/Control/org.mpris.MediaPlayer2.mansion/RygelSinkConnectionManager</controlURL>
</service>
<service>
<serviceType>urn:schemas-upnp-org:service:AVTransport:1</serviceType>
<serviceId>urn:upnp-org:serviceId:AVTransport</serviceId>
<SCPDURL>/xml/AVTransport2.xml</SCPDURL>
<eventSubURL>/Event/org.mpris.MediaPlayer2.mansion/RygelAVTransport</eventSubURL>
<controlURL>/Control/org.mpris.MediaPlayer2.mansion/RygelAVTransport</controlURL>
</service>
<service>
<serviceType>urn:schemas-upnp-org:service:RenderingControl:3</serviceType>
<serviceId>urn:upnp-org:serviceId:RenderingControl</serviceId>
<SCPDURL>/xml/RenderingControl2.xml</SCPDURL>
<eventSubURL>/Event/org.mpris.MediaPlayer2.mansion/RygelRenderingControl</eventSubURL>
<controlURL>/Control/org.mpris.MediaPlayer2.mansion/RygelRenderingControl</controlURL>
</service>
<service>
<serviceType>urn:schemas-embedded-com:service:RTSPGateway:1</serviceType>
<serviceId>urn:embedded-com:serviceId:RTSPGateway</serviceId>
<SCPDURL>/xml/RTSPGateway.xml</SCPDURL>
<eventSubURL>/Event/org.mpris.MediaPlayer2.mansion/RygelRTSPGateway</eventSubURL>
<controlURL>/Control/org.mpris.MediaPlayer2.mansion/RygelRTSPGateway</controlURL>
</service>
<service>
<serviceType>urn:schemas-embedded-com:service:SpeakerManagement:1</serviceType>
<serviceId>urn:embedded-com:serviceId:SpeakerManagement</serviceId>
<SCPDURL>/xml/SpeakerManagement.xml</SCPDURL>
<eventSubURL>/Event/org.mpris.MediaPlayer2.mansion/RygelSpeakerManagement</eventSubURL>
<controlURL>/Control/org.mpris.MediaPlayer2.mansion/RygelSpeakerManagement</controlURL>
</service>
<service>
<serviceType>urn:schemas-embedded-com:service:NetworkManagement:1</serviceType>
<serviceId>urn:embedded-com:serviceId:NetworkManagement</serviceId>
<SCPDURL>/xml/NetworkManagement.xml</SCPDURL>
<eventSubURL>/Event/org.mpris.MediaPlayer2.mansion/RygelNetworkManagement</eventSubURL>
<controlURL>/Control/org.mpris.MediaPlayer2.mansion/RygelNetworkManagement</controlURL>
</service>
</serviceList>
<iconList>
<icon>
<mimetype>image/png</mimetype>
<width>120</width>
<height>120</height>
<depth>32</depth>
<url>/org.mpris.MediaPlayer2.mansion-120x120x32.png</url>
</icon>
<icon>
<mimetype>image/png</mimetype>
<width>48</width>
<height>48</height>
<depth>32</depth>
<url>/org.mpris.MediaPlayer2.mansion-48x48x32.png</url>
</icon>
<icon>
<mimetype>image/jpeg</mimetype>
<width>120</width>
<height>120</height>
<depth>24</depth>
<url>/org.mpris.MediaPlayer2.mansion-120x120x24.jpg</url>
</icon>
<icon>
<mimetype>image/jpeg</mimetype>
<width>48</width>
<height>48</height>
<depth>24</depth>
<url>/org.mpris.MediaPlayer2.mansion-48x48x24.jpg</url>
</icon>
</iconList>
<X_embeddedDevice xmlns:edd="schemas-embedded-com:extended-device-description">
<firmwareVersion>v1.0 (4.155.1.15.002)</firmwareVersion>
<features>
<feature>
<name>com.sony.Product</name>
<version>1.0.0</version>
</feature>
<feature>
<name>com.sony.Product.btmrc</name>
<version>1.0.0</version>
</feature>
<feature>
<name>com.sony.Product.btmrs</name>
<version>1.0.0</version>
</feature>
</features>
</X_embeddedDevice>
</device>
</root>
Using ElementTree, you can either read directly from the file or load it into a string.
First , include the following import.
from xml.etree.ElementTree import ElementTree
from xml.parsers.expat import ExpatError
If you are using a string:
from xml.etree.ElementTree import fromstring
try:
tree = fromstring(xml_data)
except ExpatData:
print "Unable to parse XML data from string"
Otherwise, to load it directly:
try:
tree = ElementTree(file = "filename")
except ExpatData:
print "Unable to parse XML from file"
Once you have the tree initialised, you can begin parsing the information.
root = tree.getroot()
print root.find('device/friendlyName').text
Pedro, in the comments is right.
.find(match, namespaces=None)
Finds the first subelement matching match. match may be a tag name or a path. Returns an element instance or None. namespaces is an optional mapping from namespace prefix to full name.
The ElemntTree docs are really helpful in these cases.
https://docs.python.org/3/library/xml.etree.elementtree.html#xml.etree.ElementTree.Element.find
Edit:
The link I gave in the comments leads to the following code:
import xml.etree.ElementTree as ET
input = '''<stuff>
<users>
<user x="2">
<id>001</id>
<name>Chuck</name>
</user>
<user x="7">
<id>009</id>
<name>Brent</name>
</user>
</users>
</stuff>
'''
stuff = ET.fromstring(input)
lst = stuff.findall("users/user")
print len(lst)
for item in lst:
print item.attrib["x"]
item = lst[0]
ET.dump(item)
item.get("x") # get works on attributes
item.find("id").text
item.find("id").tag
for user in stuff.getiterator('user') :
print "User" , user.attrib["x"]
ET.dump(user)
The code above uses:
item.find("id").text
If you modify that, along with removing the other code which you don't need... The find should look something like this:
item.find('device/friendlyName').text
You can get the xml file, instead of using the input string with the following (from the ElementTree docs):
import xml.etree.ElementTree as ET
tree = ET.parse('your_file_name.xml')
import xml.etree.ElementTree as ElementTree
namespace = '{urn:schemas-upnp-org:device-1-0}'
root = ElementTree.fromstring(urllib2.urlopen(XMLLocation).read())
# The `//` specifies all subelements within the whole tree.
return root.find('.//{}friendlyName'.format(namespace)).text
The find() function stops when it finds the first match. To get all of the elements that match the XPath, use the findall() function.
How can I remove all the attributes of a xml tag so I can get from this:
<xml blah blah blah> to just <xml>.
With lxml I know I can remove the whole element and I didn't find any way to do it specific on a tag. (I found solutions on stackoverflow for C# but I want Python).
I am opening a gpx(xml) file and this is my code so far (based on How do I get the whole content between two xml tags in Python?):
from lxml import etree
t = etree.parse("1.gpx")
e = t.xpath('//trk')[0]
print(e.text + ''.join(map(etree.tostring, e))).strip()
Another approach I did was this:
from lxml import etree
TOPOGRAFIX_NS = './/{http://www.topografix.com/GPX/1/1}'
TRACKPOINT_NS = TOPOGRAFIX_NS + 'extensions/{http://www.garmin.com/xmlschemas/TrackPointExtension/v1}TrackPointExtension/{http://www.garmin.com/xmlschemas/TrackPointExtension/v1}'
doc1 = etree.parse("1.gpx")
for node1 in doc1.findall(TOPOGRAFIX_NS + 'trk'):
node_to_string1 = etree.tostring(node1)
print(node_to_string1)
But I get the trk tag with TOPOGRAFIX_NS attributes witch I don't want and here I am wanting to remove the tag attribute. I just want to get:
<trk> all the inside content </trk>
Thank you very much!
P.S. The content of the gpx file:
<?xml version="1.0" encoding="UTF-8"?>
<gpx version="1.1" creator="Endomondo.com" xsi:schemaLocation="http://www.topografix.com/GPX/1/1 http://www.topografix.com/GPX/1/1/gpx.xsd http://www.garmin.com/xmlschemas/GpxExtensions/v3 http://www.garmin.com/xmlschemas/GpxExtensionsv3.xsd http://www.garmin.com/xmlschemas/TrackPointExtension/v1 http://www.garmin.com/xmlschemas/TrackPointExtensionv1.xsd" xmlns="http://www.topografix.com/GPX/1/1" xmlns:gpxtpx="http://www.garmin.com/xmlschemas/TrackPointExtension/v1" xmlns:gpxx="http://www.garmin.com/xmlschemas/GpxExtensions/v3" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<metadata>
<author>
<name>Blah Blah</name>
<email id="blah" domain="blah.com"/>
</author>
<link href="http://www.endomondo.com">
<text>Endomondo</text>
</link>
<time>2014-01-20T10:50:28Z</time>
</metadata>
<trk>
<name>Galati</name>
<src>http://www.endomondo.com/</src>
<link href="http://www.endomondo.com/workouts/260782567/13005122">
<text>Galati</text>
</link>
<type>MOUNTAIN_BIKING</type>
<trkseg>
<trkpt lat="45.431074" lon="28.021038">
<time>2013-10-20T05:49:04Z</time>
</trkpt>
</trkseg>
</trk>
</gpx>
I am parsing an XML feed in python to extract certain tags. My XML contains namespaces and this results in each tag containing a namespace followed by tag name.
Here is the xml:
<?xml version="1.0" encoding="utf-8"?>
<feed xmlns="http://www.w3.org/2005/Atom" xmlns:media="http://search.yahoo.com/mrss/" xmlns:rte="http://www.rte.ie/schemas/vod">
<id>10038711/</id>
<updated>2013-01-24T22:52:43+00:00</updated>
<title type="text">Reeling in the Years</title>
<logo>http://www.rte.ie/iptv/images/logo.gif</logo>
<link rel="self" type="application/atom+xml" href="http://feeds.rasset.ie/rteavgen/player/playlist?type=iptv&showId=10038711" />
<category term="feed"/>
<author>
<name>RTE</name>
<uri>http://www.rte.ie</uri>
</author>
<entry>
<id>10038711</id>
<published>2012-07-04T12:00:00+01:00</published>
<updated>2013-01-06T12:31:25+00:00</updated>
<title type="text">Reeling in the Years</title>
<content type="text">National and international events with popular music from the year 1989.First Broadcast: 08/11/1999</content>
<category term="WEB Exclusive" rte:type="channel"/>
<category term="Classics 1980" rte:type="genre"/>
<category term="rte player" rte:type="source"/>
<category term="" rte:type="transmision_details"/>
<category term="False" rte:type="copyprotectionoptout"/>
<category term="long" rte:type="form"/>
<category term="3275" rte:type="progid"/>
<link rel="site" type="text/html" href="http://www.rte.ie/tv50/"/>
<link rel="self" type="application/atom+xml" href="http://feeds.rasset.ie/rteavgen/player/playlist/?itemId=10038711&type=iptv&format=xml" />
<link rel="alternate" type="text/html" href="http://www.rte.ie/player/#v=10038711"/>
<rte:valid start="2012-07-23T15:56:04+01:00" end="2017-08-01T15:56:04+01:00"/>
<rte:duration ms="842205" formatted="0:10"/>
<rte:statistics views="19"/>
<rte:bri id="na"/>
<rte:channel id="13"/>
<rte:item id="10038711"/>
<media:title type="plain">Reeling in the Years</media:title>
<media:description type="plain">National and international events with popular music from the year 1989. First Broadcast: 08/11/1999</media:description>
<media:thumbnail url="http://img.rasset.ie/00062efc200.jpg" height="288" width="512" time="00:00:00+00:00"/>
<media:teaserimgref1x1 url="" time="00:00:00+00:00"/>
<media:rating scheme="http://www.rte.ie/schemes/vod">NA</media:rating>
<media:copyright>RTÉ</media:copyright>
<media:group rte:format="single">
<media:content url="http://vod.hds.rasset.ie/manifest/2012/0728/20120728_reelingint_cl10038711_10039316_260_.f4m" type="video/mp4" medium="video" expression="full" duration="842205" rte:format="content"/>
</media:group>
<rte:ads>
<media:content url="http://pubads.g.doubleclick.net/gampad/ads?sz=512x288&iu=%2F3014%2FP_RTE_TV50_Pre&ciu_szs=300x250&impl=s&gdfp_req=1&env=vp&output=xml_vast2&unviewed_position_start=1&url=[referrer_url]&correlator=[timestamp]" type="text/xml" medium="video" expression="full" rte:format="advertising" rte:cue="0" />
<media:content url="http://pubads.g.doubleclick.net/gampad/ads?sz=512x288&iu=%2F3014%2FP_RTE_TV50_Pre2&ciu_szs=300x250&impl=s&gdfp_req=1&env=vp&output=xml_vast2&unviewed_position_start=1&url=[referrer_url]&correlator=[timestamp]" type="text/xml" medium="video" expression="full" rte:format="advertising" rte:cue="0" />
<media:content url="http://pubads.g.doubleclick.net/gampad/ads?sz=512x288&iu=%2F3014%2FP_RTE_TV50_Pre3&ciu_szs=300x250&impl=s&gdfp_req=1&env=vp&output=xml_vast2&unviewed_position_start=1&url=[referrer_url]&correlator=[timestamp]" type="text/xml" medium="video" expression="full" rte:format="advertising" rte:cue="0" />
</rte:ads>
</entry>
<!-- playlist.xml -->
</feed>
When the XML is parsed each element is soming out as:
{http://www.w3.org/2005/Atom}id
{http://www.w3.org/2005/Atom}published
{http://www.w3.org/2005/Atom}updated
.....
.....
{http://www.rte.ie/schemas/vod}valid
{http://www.rte.ie/schemas/vod}duration
....
....
{http://search.yahoo.com/mrss/}description
{http://search.yahoo.com/mrss/}thumbnail
....
As I have 3 different namespaces and I cannot gurantee that they will be always the same then I woul prefer not to hard specify each tag like so:
for elem in tree.iter({http://www.w3.org/2005/Atom}entry'):
stream = str(elem.find('{http://www.w3.org/2005/Atom}id').text)
date_tmp = str(elem.find('{http://www.w3.org/2005/Atom}published').text)
name_tmp = str(elem.find('{http://www.w3.org/2005/Atom}title').text)
short_tmp = str(elem.find('{http://www.w3.org/2005/Atom}content').text)
channel_tmp = elem.find('{http://www.w3.org/2005/Atom}category', "channel")
channel = str(channel_tmp.get('term'))
icon_tmp = elem.find('{http://search.yahoo.com/mrss/}thumbnail')
icon_url = str(icon_tmp.get('url'))
Is there any way that I can put a wildcard or something similar into the find so it will simply ignore the namespace?
stream = str(elem.find('*id').text)
I can hardcode them as above but it would be my luck that down the line the namespace would change and my queries stop returning data..
Thanks for the help.
You can use an XPath expression with the local-name() function:
<?xml version="1.0"?>
<root xmlns="ns">
<tag/>
</root>
Assuming "doc" is the ElementTree for the above XML:
import lxml.etree
doc = lxml.etree.parse(<some_file_like_object>)
root = doc.getroot()
root.xpath('//*[local-name()="tag"]')
[<Element {ns}tag at 0x7fcde6f7c960>]
replacing <some_file_like_object> as appropriate (alternatively, you can use lxml.etree.fromstring with an XML string to get the root element directly).
I have an xml document in the following format:
<feed xmlns="http://www.w3.org/2005/Atom" xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/" xmlns:gsa="http://schemas.google.com/gsa/2007">
...
<entry>
<id>https://ip.ad.dr.ess:8000/feeds/diagnostics/smb://ip.ad.dr.ess/path/to/file</id>
<updated>2011-11-07T21:32:39.795Z</updated>
<app:edited xmlns:app="http://purl.org/atom/app#">2011-11-07T21:32:39.795Z</app:edited>
<link rel="self" type="application/atom+xml" href="https://ip.ad.dr.ess:8000/feeds/diagnostics"/>
<link rel="edit" type="application/atom+xml" href="https://ip.ad.dr.ess:8000/feeds/diagnostics"/>
<gsa:content name="entryID">smb://ip.ad.dr.ess/path/to/directory</gsa:content>
<gsa:content name="numCrawledURLs">7</gsa:content>
<gsa:content name="numExcludedURLs">0</gsa:content>
<gsa:content name="type">DirectoryContentData</gsa:content>
<gsa:content name="numRetrievalErrors">0</gsa:content>
</entry>
<entry>
...
</entry>
...
</feed>
I need to retrieve all entry elements using xpath in lxml. My problem is that I can't figure out how to use an empty namespace. I have tried the following examples, but none work. Please advise.
import lxml.etree as et
tree=et.fromstring(xml)
The various things I have tried are:
for node in tree.xpath('//entry'):
or
namespaces = {None:"http://www.w3.org/2005/Atom" ,"openSearch":"http://a9.com/-/spec/opensearchrss/1.0/" ,"gsa":"http://schemas.google.com/gsa/2007"}
for node in tree.xpath('//entry', namespaces=ns):
or
for node in tree.xpath('//\"{http://www.w3.org/2005/Atom}entry\"'):
At this point I just don't know what to try. Any help is greatly appreciated.
Something like this should work:
import lxml.etree as et
ns = {"atom": "http://www.w3.org/2005/Atom"}
tree = et.fromstring(xml)
for node in tree.xpath('//atom:entry', namespaces=ns):
print node
See also http://lxml.de/xpathxslt.html#namespaces-and-prefixes.
Alternative:
for node in tree.xpath("//*[local-name() = 'entry']"):
print node
Use findall method.
for item in tree.findall('{http://www.w3.org/2005/Atom}entry'):
print item