Develop Reference

For loop in tkinter Label return only last line

I am trying to update a variabletext with new meaning with FOR LOOP but I only get the last line.
team_list = StringVar()
team_list.set('76ers: \nBucks: \nBulls: \nCavaliers: \nCeltics: \nClippers: \nGolden State Warriors: \nGrizzlies: \nHawks: \nHeat: \nHornets: \nJazz: \nKings: \nKnicks: \nLakers: \nMagic: \nMavericks: \nNets: \nNuggets: \nPacers: \nPelicans: \nPistons: \nRaptors: \nRockets: \nSpurs: \nSuns: \nThunder: \nTimberwolves: \nTrail Blazers: \nWizards: ')
def analize():
if len(t_text.get(1.0, END)) == 1:
tkinter.messagebox.showinfo(title='Error', message='No text was added')
else:
full_list = ['76ers', 'Bucks', 'Bulls', 'Cavaliers', 'Celtics', 'Clippers', 'Golden State Warriors', 'Grizzlies', 'Hawks', 'Heat', 'Hornets', 'Jazz', 'Kings', 'Knicks', 'Lakers', 'Magic', 'Mavericks', 'Nets', 'Nuggets', 'Pacers', 'Pelicans', 'Pistons', 'Raptors', 'Rockets', 'Spurs', 'Suns', 'Thunder', 'Timberwolves', 'Trail Blazers', 'Wizards']
for team in full_list:
result = (t_text.get(1.0, END)).count(team)
team_list.set(str(team) + ': ' + str(result))
When trying to print FOR LOOP in terminal, it prints everything as expected, but on tkinter Label variabletext it doesn't work. Just returns last FOR LOOP line.

"team_list" in your last line does not append data, it is written to reset with the latest value. Consider creating an empty list to track counts and then append data for each iteration of the loop.
team_counts = {}
for team in full_list:
result = (t_text.get(1.0, END)).count(team)
team_counts[team] = result
team_list.set('\n'.join(f"{team}: {count}" for team, count in team_counts.items()))

can't return a list with desired order from a python function

wanna write a code that would add to burgerlist the items of my_order with the following order: first and last element of burgerlist should be bread, second and pre-last element should be mayonnaise(if it exist among the arguments while calling function), then beef / chicken, then vegitables.
pls help to understand what to change here
def my_odrer(*g):
ingredients = [['long_bread', 'circle_bread'], ['mayonnaise', 'ketchup'], ['beef', 'chicken'],
['cucumber', 'tomato', 'onion']]
burgerlist = []
for i in g:
if i in ingredients[0]:
burgerlist.insert(0, i)
elif i in ingredients[1]:
burgerlist.insert(1, i)
elif i in ingredients[2]:
burgerlist.append(i)
elif i in ingredients[3]:
burgerlist.append(i)
if burgerlist[1] == 'mayonnaise':
burgerlist.append(burgerlist[1])
burgerlist.append(burgerlist[0])
return burgerlist
print(my_odrer('circle_bread', 'beef', 'tomato', 'mayonnaise', 'ketchup'))
the output is: ['circle_bread', 'ketchup', 'mayonnaise', 'beef', 'tomato', 'circle_bread']
but I want to get: ['circle_bread', 'mayonnaise', 'ketchup', 'beef', 'tomato','mayonnaise', 'circle_bread']

Create 3 lists containing the ingredients that should be at the beginning, middle, and end. Then concatenate them to produce the final result.
def my_odrer(*g):
breads = {'long_bread', 'circle_bread'}
condiments = {'ketchup'} # mayonnaise not included, since it's handled specially
meats = {'beef', 'chicken'}
vegetables = {'cucumber', 'tomato', 'onion'}
beginning = []
middle = []
end = []
for item in g:
if item in breads:
beginning.append(item)
end.append(item)
if "mayonnaise" in g:
beginning.append("mayonnaise")
end.insert(-1, "mayonnaise")
for item in g:
if item in condiments:
middle.append(item)
for item in g:
if item in meats:
middle.append(item)
for item in g:
if item in vegetables:
middle.append(item)
return beginning + middle + end

It works after I added an additional condition in your final if statement.
def my_odrer(*g):
ingredients = [['long_bread', 'circle_bread'], ['mayonnaise', 'ketchup'], ['beef', 'chicken'],
['cucumber', 'tomato', 'onion']]
burgerlist = []
for i in g:
if i in ingredients[0]:
burgerlist.insert(0, i)
elif i in ingredients[1]:
burgerlist.insert(1, i)
elif i in ingredients[2]:
burgerlist.append(i)
elif i in ingredients[3]:
burgerlist.append(i)
if burgerlist[1] == 'mayonnaise':
burgerlist.append(burgerlist[1])
elif burgerlist[2] == 'mayonnaise':
burgerlist[1], burgerlist[2] = burgerlist[2], burgerlist[1]
burgerlist.append(burgerlist[1])
burgerlist.append(burgerlist[0])
return burgerlist

How to resolve AttributeError: 'list' object has no attribute 'next' in Python

I am trying to read a file where the odd lines are department numbers, and even ones are sales totals. I need to be able to read a line and append it to a variable to be used later.
def main():
with open('P2data.txt') as x:
data = x.readlines()
dept = (data)[::2]
sales = (data)[1::2]
if dept == '1':
total = sales.next()
total.append(total1)
elif dept == '2':
total = sales.next()
total.append(total2)
else:
total = sales.next()
total.append(total3)
print('Dept 1:', total1)
print('Dept 2:', total2)
print('Dept 3:', total3)
main()

Your code is going in the wrong direction. You also are doing things like checking an entire data structure against what should be compared to one of that structure's elements, and mixing up the syntax for appending to a list. Simply loop over the data structures you create and add to a dictionary:
def main():
with open('P2data.txt') as x:
data = [line.strip() for line in x]
dept = data[::2]
sales = data[1::2]
totals = {'1':0, '2':0, '3':0}
for dep,sale in zip(dept, sales):
totals[dep] += float(sale)
for dep in sorted(totals):
print('Dept {}: {}'.format(dep, totals[dep]))
main()

for loop to insert things into a tkinter window

I have Tkinter program that has to add a significant amount of data to the window so I tried to write a for loop to take care of it but since I have to use a string variable for the name of the object that Tkinter is running .insert() on the object. I didn't explain it very well here is the method
def fillWindow(self):
global fileDirectory
location = os.path.join(fileDirectory, family + '.txt')
file = open(location, 'r')
ordersDict = {}
for line in file:
(key, value) = line.split(':', 1)
ordersDict[key] = value
for key in ordersDict:
ordersDict[key] = ordersDict[key][:-2]
for item in ordersDict:
if item[0] == '#':
if item[1] == 'o':
name = 'ordered%s' %item[2:]
right here is the problem line because I have the variable that matches the name of the entry object already created but 'name' is actually a string variable so it gives me the error "AttributeError: 'str' object has no attribute 'insert'"
name.insert(0,ordersDict[item])
here is the entire class. It makes a Tkinter window and fills it with a sort of shipping screen so all the entries are for how many orders of a certain thing are needed. I'm also very new so I know that I do things the long way a lot.
class EditShippingWindow(Tkinter.Toplevel):
def __init__(self, student):
Tkinter.Toplevel.__init__(self)
self.title('Orders')
family = student
## Window Filling
ageGroupLabel = Tkinter.Label(self,text='Age Group')
ageGroupLabel.grid(row=0,column=0)
itemColumnLabel = Tkinter.Label(self,text='Item')
itemColumnLabel.grid(row=0, column=1)
costColumnLabel = Tkinter.Label(self,text='Cost')
costColumnLabel.grid(row=0, column=2)
orderedColumnLabel = Tkinter.Label(self,text='Ordered')
orderedColumnLabel.grid(row=0, column=3)
paidColumnLabel = Tkinter.Label(self,text='Paid')
paidColumnLabel.grid(row=0, column=4)
receivedColumnLabel = Tkinter.Label(self,text='Received')
receivedColumnLabel.grid(row=0, column=5)
#Item Filling
column1list = ['T-Shirt (2T):$9.00', 'T-Shirt (3T):$9.00', 'T-Shirt (4T):$9.00',
'Praise Music CD:$10.00', ':', 'Vest L(Size 6):$10.00', 'Vest XL(Size 8):$10.00',
'Hand Book (KJ/NIV):$8.75', 'Handbook Bag:$6.00', 'Memory CD (KJ/NIV):$10.00',
':', 'Vest L(size 10):$10.00', 'Vest XL(Size 12):$10.00', 'Hand Glider (KJ/NIV/NKJ):$10.00',
'Wing Runner (KJ/NIV/NKJ):$10.00', 'Sky Stormer (KJ/NIV/NKJ):$10.00', 'Handbook Bag:$5.00',
'Memory CD (S/H/C):$10.00', 'Hand Glider Freq. Flyer:$8.00', 'Wing Runner Freq. Flyer:$8.00',
'Sky Stormer Handbook:$8.00' , ':', 'Uniform T-Shirt Size (10/12/14):$13.00',
'Uniform T-Shirt Size(10/12/14):$13.00', 'Uniform T-Shirt(Adult S / M / L / XL):$13.00',
'3rd & 4th Gr. Book 1 (KJ / NIV / NKJ):$8.75', '3rd & 4th Gr. Book 2 (KJ / NIV / NKJ):$8.75',
'4th & 5th Gr. Book 1 (KJ / NIV / NKJ):$8.75', '4th & 5th Gr. Book 2 (KJ / NIV / NKJ):$8.75',
'Memory CD 3rd & 4th Gr. Book (1/2):$10.00', 'Drawstring Backpack:$5.50']
column1num = 1
for item in column1list:
num = str(column1num)
(title, price) = item.split(':')
objectName1 = 'column1row' + num
objectName1 = Tkinter.Label(self,text=title)
objectName1.grid(row=column1num, column=1)
objectName2 = 'column1row' + num
objectName2 = Tkinter.Label(self,text=price)
objectName2.grid(row=column1num, column=2)
column1num += 1
#Ordered Paid Recieved Filler
for i in range(32):
if i == 11 or i == 22 or i == 0 or i == 5:
pass
else:
width = 10
# First Column
title1 = 'ordered' + str(i)
self.title1 = Tkinter.Entry(self,width=width)
self.title1.grid(row=i,column=3)
#self.title1.insert(0, title1)
#Second
title2 = 'paid' + str(i)
self.title2 = Tkinter.Entry(self,width=width)
self.title2.grid(row=i,column=4)
#self.title2.insert(0, title2)
#Third
title3 = 'received' + str(i)
self.title3 = Tkinter.Entry(self,width=width)
self.title3.grid(row=i,column=5)
#self.title3.insert(0, title3)
## Methods
def fillWindow(self):
global fileDirectory
location = os.path.join(fileDirectory, family + '.txt')
file = open(location, 'r')
ordersDict = {}
for line in file:
(key, value) = line.split(':', 1)
ordersDict[key] = value
for key in ordersDict:
ordersDict[key] = ordersDict[key][:-2]
for item in ordersDict:
if item[0] == '#':
if item[1] == 'o':
self.name = 'ordered%s' %item[2:]
self.name.insert(0,ordersDict[item])
fillWindow(self)

It looks like you have a conceptual error there: inside this method, the variable "name" does not exist up to the last line on the first listing. Then it is created, and points to an ordinary Python string -- if you are using a "name" variable elsewhere on your class that variable does not exist inside this method.
For an easy fix of your existing code, try calling the variable as "self.name" instead of just name where it is created, and on your last line in this method use:
self.name.insert(0,ordersDict[item]) instead.
The self. prefix will turn your variable into an instance variable, which is shared across methods on the same instance of the class.
On a side note, you don' t need even the dictionary much less three consecutive for loops on this method, just insert the relevant values you extract from "line" in your text variable.

ANSI graphic codes and Python

I was browsing the Django source code and I saw this function:
def colorize(text='', opts=(), **kwargs):
"""
Returns your text, enclosed in ANSI graphics codes.
Depends on the keyword arguments 'fg' and 'bg', and the contents of
the opts tuple/list.
Returns the RESET code if no parameters are given.
Valid colors:
'black', 'red', 'green', 'yellow', 'blue', 'magenta', 'cyan', 'white'
Valid options:
'bold'
'underscore'
'blink'
'reverse'
'conceal'
'noreset' - string will not be auto-terminated with the RESET code
Examples:
colorize('hello', fg='red', bg='blue', opts=('blink',))
colorize()
colorize('goodbye', opts=('underscore',))
print colorize('first line', fg='red', opts=('noreset',))
print 'this should be red too'
print colorize('and so should this')
print 'this should not be red'
"""
code_list = []
if text == '' and len(opts) == 1 and opts[0] == 'reset':
return '\x1b[%sm' % RESET
for k, v in kwargs.iteritems():
if k == 'fg':
code_list.append(foreground[v])
elif k == 'bg':
code_list.append(background[v])
for o in opts:
if o in opt_dict:
code_list.append(opt_dict[o])
if 'noreset' not in opts:
text = text + '\x1b[%sm' % RESET
return ('\x1b[%sm' % ';'.join(code_list)) + text
I removed it out of the context and placed in another file just to try it, the thing is that it doesn't seem to colour the text I pass it. It might be that I don't understand it correctly but isn't it supposed to just return the text surrounded with ANSI graphics codes which than the terminal will convert to actual colours.
I tried all the given examples of calling it, but it just returned the argument I specified as a text.
I'm using Ubuntu so I think the terminal should support colours.

It's that you have many terms undefined, because it relies on several variables defined outside of the function.
Instead just
import django.utils.termcolors as termcolors
red_hello = termcolors.colorize("Hello", fg='red') # '\x1b[31mHello\x1b[0m'
print red_hello
Or just also copy the first few lines of django/utils/termcolors.py specifically:
color_names = ('black', 'red', 'green', 'yellow', 'blue', 'magenta', 'cyan', 'white')
foreground = dict([(color_names[x], '3%s' % x) for x in range(8)])
background = dict([(color_names[x], '4%s' % x) for x in range(8)])
RESET = '0'
def colorize( ... ):
...
print colorize("Hello", fg='red') # '\x1b[31mHello\x1b[0m'
Also note:
>>> from django.utils.termcolors import colorize
>>> red_hello = colorize("Hello", fg="red")
>>> red_hello # by not printing; it will not appear red; special characters are escaped
'\x1b[31mHello\x1b[0m'
>>> print red_hello # by print it will appear red; special characters are not escaped
Hello