This question already has an answer here:
How to escape curly-brackets in f-strings? [duplicate]
(1 answer)
Closed 3 years ago.
i want to use f-string in my python code to write some json, but got a problem with screening {} symbols. What the correct way to screen lonely { } symbols? For example i want to write:
data = f'{[{{prod_id},{quantity},{size}}]}'
I cant get how to write it correctly, and basic python screening not working for me for some reason here.
You can escape curly braces in f-strings by doubling them, e.g.
data = f"{{[{{{prod_id},{quantity},{size}}}]}}"
Related
This question already has an answer here:
Why does printing a tuple (list, dict, etc.) in Python double the backslashes?
(1 answer)
Closed 1 year ago.
enter image description here
is there a way to print single backslash within list?
Regarding the first version of your question, I wrote this:
First, this expression x='\' isn't right in Python in python. you should rather puth it this way: x='\\', since back slash is a special character in python.
Second, try this:
l=['\\'] print(l)
This will print: ['\\']
But when you execute this: print(l[0]), it renders this '\'. So basically, this ['\\'] is the way to print a backslash within a list.
This question already has answers here:
What do backticks mean to the Python interpreter? Example: `num`
(3 answers)
Meaning of the backtick character in Python
(2 answers)
Closed 1 year ago.
Lots of old python code I look in has this ` symbol around a lot of stuff, what does it do? Now it is not considered valid syntax, obviously.
And I don't think it is just another string identifier, its sometimes wrapped around functions in the code I'm looking at.
Any help will be appreciated.
This question already has answers here:
How to split long regular expression rules to multiple lines in Python
(6 answers)
Closed 4 years ago.
Just a simple question. Lets say i have a very long regex.
regex = "(foo|foo|foo|foo|bar|bar|bar)"
Now i want to split this regex into multiple lines. I tried
regex = "(foo|foo|foo|foo|\
bar|bar|bar)"
but this doesnt seems to work. I get different outputs. Any ideas?
Just do it like this
regex = "(foo|foo|foo|foo" \
"|bar|bar|bar)"
This question already has answers here:
How do I url unencode in Python?
(3 answers)
Closed 5 years ago.
I'm trying to find a python package/sample code that can convert the following input "why+don%27t+you+want+to+talk+to+me" to "why+don't+you+want+to+talk+to+me".
Converting the Hex codes like %27 to ' respectively. I can hardcode the who hex character set and then swap them with their symbols. However, I want a simple and scalable solution.
Thanks for helping
You can use urllib's unquote function.
import urllib.parse
urllib.parse.unquote('why+don%27t+you+want+to+talk+to+me')
This question already has answers here:
Search and replace operation
(2 answers)
Closed 6 years ago.
I have written code to search and replace string in make command as per user input
make language='english' id=234 version=V1 path='/bin'
In above code i searched version=V1 and replace version with version=V2
import re
strings = "make language='english' id=234 version=V1 path='/bin'"
search_pattern= re.search('version=(.*?)\s', strings)
old_str = search_pattern.group(1)
print test.replace(old_str, "V2")
Can anyone help me write above code in pythonic way or any other way to write above code
It's very easy if you use str.replace
String = "make language='english' id=234 version=V1 path='/bin'"
String = String.replace("version=V1", "version=V2")