How to control axis limits in mplot3d in pythons matplotlib - python

in mplot3d how do I change my axis limits such gets cut off the at the limites. When using ax.set_xlim3d() the graph continuous out the plot.
Consider the graph generated by:
import numpy as np; import matplotlib.pyplot as plt;
from mpl_toolkits import mplot3d
def func(x, y):
return x ** 2 + 0.5*y ** 3
x = np.linspace(-6, 6, 30)
y = np.linspace(-6, 6, 30)
X, Y =np. meshgrid(x, y)
Z = func(X, Y)
plt.clf()
fig = plt.figure(1)
ax = fig.add_subplot(111, projection='3d')
ax.plot_surface(X, Y, Z, rstride=2, cstride=1,
cmap='viridis', edgecolor='none')
Say I want to cut my z = 50, so the last part disappears. ax.set_zlim3d(-100,50) doesn't do the trick. I have a lot of code written in this form so I prefer not to use the method described here mplot3D fill_between extends over axis limits where the core code of the plots are totally different than mine. TI figure there must be a way to fix my problem my adding a line of code to my existing code.

Related

python 3d plot with two y axis

I am trying to create a plot similar like the one below taken from this paper, essentially a 3d plot with two distinct y-axis. Following guidance in this blog, I created a minimal example.
Modules
from mpl_toolkits import mplot3d
import numpy as np
%matplotlib inline
import numpy as np
import matplotlib.pyplot as plt
Create some data
def f(x, y):
return np.sin(np.sqrt(x ** 2 + y ** 2))
x = np.linspace(-6, 6, 30)
y = np.linspace(-6, 6, 30)
X, Y = np.meshgrid(x, y)
Z = f(X, Y)
Z2 = Z*100+100
Plotting
This creates a nice 3d plot, but obviously with only one y-axis. I could not find any advice online on how to get there for python, albeit some for matlab.
fig = plt.figure()
ax = plt.axes(projection='3d')
ax.plot_surface(X, Y, Z2, rstride=1, cstride=1,
cmap='viridis', edgecolor='none')
ax.set_title('surface');
ax.set_xlabel('x')
ax.set_ylabel('y')
ax.set_zlabel('z');
Code gives:
Reference graph:

How to plot horizontal stack of heatmaps or a stack of grid?

I want to plot a stack of heatmaps, contour, or grid computed over time. The plot should like this,
I have tried this:
from mpl_toolkits.mplot3d import Axes3D
import numpy as np
import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.gca(projection='3d')
x = np.linspace(0, 1, 100)
X, Z = np.meshgrid(x, x)
Y = np.sin(X)*np.sin(Z)
levels = np.linspace(-1, 1, 40)
ax.contourf(X, Y, Z, zdir='y')
ax.contourf(X, Y+3, Z, zdir='y')
ax.contourf(X, Y+7, Z, zdir='y')
ax.legend()
ax.view_init(15,155)
plt.show()
For one my plot looks ugly. It also does not look like what I want. I cannot make a grid there, and the 2d surfaces are tilted.
Any help is really appreciated! I am struggling with this.
Related stackoverflow:
[1] Python plot - stacked image slices
[2] Stack of 2D plot
How about making a series of 3d surface plots, with the data your wish to present in contour plotted as facecolor?
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
from matplotlib import cm
from matplotlib.ticker import LinearLocator
import numpy as np
fig = plt.figure()
ax = fig.gca(projection='3d')
X = np.arange(-5, 5, 0.25)
Z = np.arange(-5, 5, 0.25)
X, Z = np.meshgrid(X, Z)
C = np.random.random(size=40*40*3).reshape((40, 40, 3))
ax.plot_surface(X, np.ones(shape=X.shape)-1, Z, facecolors=C, linewidth=0)
ax.plot_surface(X, np.ones(shape=X.shape), Z, facecolors=C, linewidth=0)
ax.plot_surface(X, np.ones(shape=X.shape)+1, Z, facecolors=C, linewidth=0)

Changing position of axes in Axes3D

I am using mplot3d from the mpl_toolkits library. When displaying the 3D surface on the figure I'm realized the axis were not positioned as I wished they would.
Let me show, I have added to the following screenshot the position of each axis:
Is there a way to change the position of the axes in order to get this result:
Here's the working code:
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
ax = Axes3D(plt.figure())
def f(x,y) :
return -x**2 - y**2
X = np.arange(-1, 1, 0.02)
Y = np.arange(-1, 1, 0.02)
X, Y = np.meshgrid(X, Y)
Z = f(X, Y)
ax.plot_surface(X, Y, Z, alpha=0.5)
# Hide axes ticks
ax.set_xticks([-1,1])
ax.set_yticks([-1,1])
ax.set_zticks([-2,0])
ax.set_yticklabels([-1,1],rotation=-15, va='center', ha='right')
plt.show()
I have tried using xaxis.set_ticks_position('left') statement, but it doesn't work.
No documented methods, but with some hacking ideas from https://stackoverflow.com/a/15048653/1149007 you can.
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = ax = fig.add_subplot(111, projection='3d')
ax.view_init(30, 30)
def f(x,y) :
return -x**2 - y**2
X = np.arange(-1, 1, 0.02)
Y = np.arange(-1, 1, 0.02)
X, Y = np.meshgrid(X, Y)
Z = f(X, Y)
ax.plot_surface(X, Y, Z, alpha=0.5)
# Hide axes ticks
ax.set_xticks([-1,1])
ax.set_yticks([-1,1])
ax.set_zticks([-2,0])
ax.xaxis._axinfo['juggled'] = (0,0,0)
ax.yaxis._axinfo['juggled'] = (1,1,1)
ax.zaxis._axinfo['juggled'] = (2,2,2)
plt.show()
I can no idea of the meaning of the third number in triples. If set zeros nothing changes in the figure. So should look in the code for further tuning.
You can also look at related question Changing position of vertical (z) axis of 3D plot (Matplotlib)? with low level hacking of _PLANES property.
Something changed, code blow doesn't work, all axis hide...
ax.xaxis._axinfo['juggled'] = (0,0,0)
ax.yaxis._axinfo['juggled'] = (1,1,1)
ax.zaxis._axinfo['juggled'] = (2,2,2)
I suggest using the plot function to create a graph

How to plot contourf and my graph in the same figure

I have a figure showing the contourf plot and another showing a plot i've made earlier and I want to plot both on the same figure what should I do?
Here is the code of my contourf plot:
import pylab as pl
from pylab import *
import xlrd
import math
import itertools
from matplotlib import collections as mc
import matplotlib.pyplot as plt
import copy as dc
import pyexcel
from pyexcel.ext import xlsx
import decimal
x_list = linspace(0, 99, 100)
y_list = linspace(0, 99, 100)
X, Y = meshgrid(x_list, y_list, indexing='xy')
Z = [[0 for x in range(len(x_list))] for x in range(len(y_list))]
for each_axes in range(len(Z)):
for each_point in range(len(Z[each_axes])):
Z[len(Z)-1-each_axes][each_point] = power_at_each_point(each_point, each_axes)
figure()
CP2 = contourf(X, Y, Z, cmap=plt.get_cmap('Reds'))
colorbar(CP2)
title('Coverage Plot')
xlabel('x (m)')
ylabel('y (m)')
show()
This is the code of my previously plotted plot:
lc = mc.LineCollection(lines, linewidths=3)
fig, ax = pl.subplots()
ax.add_collection(lc)
ax.autoscale()
ax.margins(0.05)
#The code blow is just for drawing the final plot of the building.
Nodes = xlrd.open_workbook(Node_file_location)
sheet = Nodes.sheet_by_index(0)
Node_Order_Counter = range(1, sheet.nrows + 1)
In_Node_Order_Counter = 0
for counter in range(len(Node_Positions_Ascending)):
plt.plot(Node_Positions_Ascending[counter][0], Node_Positions_Ascending[counter][1], marker='o', color='r',
markersize=6)
pl.text(Node_Positions_Ascending[counter][0], Node_Positions_Ascending[counter][1],
str(Node_Order_Counter[In_Node_Order_Counter]),
color="black", fontsize=15)
In_Node_Order_Counter += 1
#Plotting the different node positions on our plot & numbering them
pl.show()
Without your data we can't see what the plot is supposed to look like, but I have some general recommendations.
Don't use pylab. And if you absolutely must use it, use it within its namespace, and don't do from pylab import *. It makes for very sloppy code - for example, linspace and meshgrid are actually from numpy, but it's hard to tell that when you use pylab.
For complicated plotting, don't even use pyplot. Instead, use the direct object plotting interface. For example, to make a normal plot on top of a contour plot, (such as you want to do) you could do the following:
import numpy as np
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
x = np.linspace(1, 5, 20)
y = np.linspace(2, 5, 20)
z = x[:,np.newaxis] * (y[np.newaxis,:])**2
xx, yy = np.meshgrid(x, y)
ax.contourf(xx, yy, z, cmap='Reds')
ax.plot(x, 0.2*y**2)
plt.show()
Notice that I only used pyplot to create the figure and axes, and show them. The actual plotting is done using the AxesSubplot object.

Normalizing colors in matplotlib

I am trying to plot a surface using matplotlib using the code below:
from matplotlib import cm
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import axes3d, Axes3D
import pylab as p
vima=0.5
fig = plt.figure()
ax = fig.gca(projection='3d')
X = np.arange(0, 16.67, vima)
Y = np.arange(0, 12.5, vima)
X, Y = np.meshgrid(X, Y)
Z = np.sqrt(((1.2*Y+0.6*X)**2+(0.2*Y+1.6*X)**2)/(0.64*Y**2+0.36*X**2))
surf = ax.plot_surface(X, Y, Z,rstride=1, cstride=1, alpha=1,cmap=cm.jet, linewidth=0)
fig.colorbar(surf, shrink=0.5, aspect=5)
plt.show()
If you run it you will see a blue surface, but I want to use the whole color range of jet... I know there is a class "matplotlib.colors.Normalize", but I don't know how to use it. Could you please add the necessary code in order to do it?
I realise that the poster's issue has already been resolved, but the question of normalizing the colors was never dealt with. Since I've figured out how I thought I'd just drop this here for anyone else who might need it.
First you create a norm and pass that to the plotting function, I've tried to add this to the OP's code.
from matplotlib import cm
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import axes3d, Axes3D
import pylab as p
import matplotlib
vima=0.5
fig = plt.figure()
ax = fig.gca(projection='3d')
X = np.arange(0, 16.67, vima)
Y = np.arange(0, 12.5, vima)
X, Y = np.meshgrid(X, Y)
Z = np.sqrt(((1.2*Y+0.6*X)**2+(0.2*Y+1.6*X)**2)/(0.64*Y**2+0.36*X**2))
Z = np.nan_to_num(Z)
# Make the norm
norm = matplotlib.colors.Normalize(vmin = np.min(Z), vmax = np.max(Z), clip = False)
# Plot with the norm
surf = ax.plot_surface(X, Y, Z,rstride=1, cstride=1, norm=norm, alpha=1,cmap=cm.jet, linewidth=0)
fig.colorbar(surf, shrink=0.5, aspect=5)
plt.show()
The norm works the same way for the "imshow" command.
As JoshAdel noted in a comment (credit belongs to him), it appears that the surface plot is improperly ranging the colormap when a NaN is in the Z array. A simple work-around is to simply convert the NaN's to zero or very large or very small numbers so that the colormap can be normalized to the z-axis range.
from matplotlib import cm
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import axes3d, Axes3D
import pylab as p
vima=0.5
fig = plt.figure()
ax = fig.gca(projection='3d')
X = np.arange(0, 16.67, vima)
Y = np.arange(0, 12.5, vima)
X, Y = np.meshgrid(X, Y)
Z = np.sqrt(((1.2*Y+0.6*X)**2+(0.2*Y+1.6*X)**2)/(0.64*Y**2+0.36*X**2))
Z = np.nan_to_num(Z) # added this line
surf = ax.plot_surface(X, Y, Z,rstride=1, cstride=1, alpha=1,cmap=cm.jet, linewidth=0)
fig.colorbar(surf, shrink=0.5, aspect=5)
plt.show()
Replying to an old question, I know, but the answers posted were at least in my case somewhat unsatisfactory. For those still stumbling here, I give a solution that worked for me.
Firstly, I did not want use zeros to replace NaNs, as for me they represent points with missing or undefined data. I'd rather not have anything plotted at these points. Secondly, the whole z range of my data was way above zero, so dotting the plot with zeros would result in an ugly and badly scaled plot.
Solution given by leifdenby was quite close, so +1 for that (though as pointed out, the explicit normalisation does not add to the earlier solution). I just dropped the NaN-to-zero replacement, and used the functions nanmin and nanmax instead of min and max in the color scale normalisation. These functions give the min and max of an array but simply ignore all NaNs. The code now reads:
# Added colors to the matplotlib import list
from matplotlib import cm, colors
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import axes3d, Axes3D
import pylab as p
vima=0.5
fig = plt.figure()
ax = fig.gca(projection='3d')
X = np.arange(0, 16.67, vima)
Y = np.arange(0, 12.5, vima)
X, Y = np.meshgrid(X, Y)
Z = np.sqrt(((1.2*Y+0.6*X)**2+(0.2*Y+1.6*X)**2)/(0.64*Y**2+0.36*X**2))
# MAIN IDEA: Added normalisation using nanmin and nanmax functions
norm = colors.Normalize(vmin = np.nanmin(Z),
vmax = np.nanmax(Z))
# Added the norm=norm parameter
surf = ax.plot_surface(X, Y, Z,rstride=1, cstride=1, alpha=1, norm=norm, cmap=cm.jet, linewidth=0)
fig.colorbar(surf, shrink=0.5, aspect=5)
plt.show()
Running this, I get a correctly scaled plot, with the (0, 0) datapoint missing. This is also the behaviour that I find most preferable, as the limit (x, y) to (0, 0) does not seem to exist for the function in question.
This has been my first contribution to StackOverflow, I hope it was a good one (wink).

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