Develop Reference

import error when importing module from the same directory [duplicate]

I have a directory that stores all the .py files.
bin/
main.py
user.py # where class User resides
dir.py # where class Dir resides
I want to use classes from user.py and dir.py in main.py.
How can I import these Python classes into main.py?
Furthermore, how can I import class User if user.py is in a sub directory?
bin/
dir.py
main.py
usr/
user.py

Python 2
Make an empty file called __init__.py in the same directory as the files. That will signify to Python that it's "ok to import from this directory".
Then just do...
from user import User
from dir import Dir
The same holds true if the files are in a subdirectory - put an __init__.py in the subdirectory as well, and then use regular import statements, with dot notation. For each level of directory, you need to add to the import path.
bin/
main.py
classes/
user.py
dir.py
So if the directory was named "classes", then you'd do this:
from classes.user import User
from classes.dir import Dir
Python 3
Same as previous, but prefix the module name with a . if not using a subdirectory:
from .user import User
from .dir import Dir

I just learned (thanks to martineau's comment) that, in order to import classes from files within the same directory, you would now write in Python 3:
from .user import User
from .dir import Dir

From python3.3 upwards, __init__.py is no longer necessary. If the current directory of the console is the directory where the python script is located, everything works fine with
import user
However, this won't work if called from a different directory, which does not contain user.py.
In that case, use
from . import user
This works even if you want to import the whole file instead of just a class from there.

In your main.py:
from user import Class
where Class is the name of the class you want to import.
If you want to call a method of Class, you can call it using:
Class.method
Note that there should be an empty __init__.py file in the same directory.

If user.py and dir.py are not including classes then
from .user import User
from .dir import Dir
is not working. You should then import as
from . import user
from . import dir

You can import the module and have access through its name if you don't want to mix functions and classes with yours
import util # imports util.py
util.clean()
util.setup(4)
or you can import the functions and classes to your code
from util import clean, setup
clean()
setup(4)
you can use wildchar * to import everything in that module to your code
from util import *
clean()
setup(4)

To make it more simple to understand:
Step 1: lets go to one directory, where all will be included
$ cd /var/tmp
Step 2: now lets make a class1.py file which has a class name Class1 with some code
$ cat > class1.py <<\EOF
class Class1:
OKBLUE = '\033[94m'
ENDC = '\033[0m'
OK = OKBLUE + "[Class1 OK]: " + ENDC
EOF
Step 3: now lets make a class2.py file which has a class name Class2 with some code
$ cat > class2.py <<\EOF
class Class2:
OKBLUE = '\033[94m'
ENDC = '\033[0m'
OK = OKBLUE + "[Class2 OK]: " + ENDC
EOF
Step 4: now lets make one main.py which will be execute once to use Class1 and Class2 from 2 different files
$ cat > main.py <<\EOF
"""this is how we are actually calling class1.py and from that file loading Class1"""
from class1 import Class1
"""this is how we are actually calling class2.py and from that file loading Class2"""
from class2 import Class2
print Class1.OK
print Class2.OK
EOF
Step 5: Run the program
$ python main.py
The output would be
[Class1 OK]:
[Class2 OK]:

Python 3
Same directory.
import file:log.py
import class: SampleApp().
import log
if __name__ == "__main__":
app = log.SampleApp()
app.mainloop()
or
directory is basic.
import in file: log.py.
import class: SampleApp().
from basic import log
if __name__ == "__main__":
app = log.SampleApp()
app.mainloop()

from user import User
from dir import Dir

For Python 3+, suppose you have this structure:
A/
__init__.py
bar.py
foo.py
In your __init__.py file, you can put from . import foo
then you can import foo in bar file
# A/bar.py
from foo import YourClass
The purpose of the __init__.py files is to include optional initialization code that runs as different levels of a package are encountered. everything you put in the __init__.py will be initialized during the package load.

I'm not sure why this work but using Pycharm build from file_in_same_dir import class_name
The IDE complained about it but it seems it still worked. I'm using Python 3.7

For python3
import from sibling: from .user import User
import from nephew: from .usr.user import User

If you have filename.py in the same folder, you can easily import it like this:
import filename
I am using python3.7

Python3
use
from .user import User inside dir.py file
and
use from class.dir import Dir inside main.py
or from class.usr import User inside main.py
like so

# My Python version: 3.7
# IDE: Pycharm 2021.1.2 Community
# Have "myLib" in folder "labs":
class Points:
def __init__(self, x = 0, y = 0):
self.__x = x
self.__y = y
def __str__(self):
return f"x = {self.__x}, y = {self.__y}"
# Have "myFile" in (same) folder "labs":
from myFile import Point
p1 = Point(1, 4)
p2 = Point(1, 4)
print(f"p1: {p1}, p2: {p2}")
# Result:
# p1: x = 1, y = 4, p2: x = 1, y = 4
# Good Luck!

Indeed Python does not provide an elegant solution for this everyday use-case. It is especially problematic when you are testing your code that eventually will be delivered as part of a Python package. Here is an approach that has worked for me:
dir
|
file1.py
file2.py
And let's say you want to import file2 from file1.
# In file1.py:
try:
# This works when packaged as Python package
from . import file2
except:
# This works when simply invoking file1 as a module (i.e. python file1)
import file2
# rest of the code ...

I cannot submit an edit for the top answer, so based on some pointers given in comments above, another thing to try out is:
from subfolder.MyClassFile import MyClass
And that's it. Just remember to have an __init__.py empty file in our subfolder.
Just for reference, the solution works if your structure is something like this:
your_project/
__ini__.py
main.py
subfolder/
__init__.py
MyClassFile.py <-- You want this
MyClassFile.py contains the class MyClass.

Just too brief,
Create a file __init__.py is classes directory and then import it to your script like following (Import all case)
from classes.myscript import *
Import selected classes only
from classes.myscript import User
from classes.myscript import Dir

to import from the same directory
from . import the_file_you_want_to_import
to import from sub directory the directory should contain
init.py
file other than you files then
from directory import your_file

ModuleNotFoundError: I can't import custom modules properly

below the folder structure of my software:
below the code of all the .py files:
run.py:
import modules.module_01.aa as a
a.test()
# test:
if __name__=="__main__":
pass
aa.py (module 1):
import libraries.qq as q
import libraries.zz as z
def test():
q.qq_fun()
z.zz_fun()
print("ciao")
qq.py (library used by aa.py):
def qq_fun():
pass
zz.py (library used by aa.py):
def zz_fun():
pass
my question is really simple, why when I run "run.py" Python say to me:
why "aa.py" can't import the module "qq.py" and "zz.py"? how can I fix this issue?

run.py
In run.py, the Python interpreter thinks you're trying to import module_01.aa from a module named module. To import aa.py, you'll need to add this code to the top of your file, which adds the directory aa.py is in to the system path, and change your import statement to import aa as a.
import sys
sys.path.insert(0, "./modules/module_01/")
aa.py
The same problem occurs in aa.py. To fix the problem in this file, you'll need to add this code to the top of aa.py, which adds the directory qq.py and zz.py are in, and remove the libraries. from both of your import statements.
import sys
sys.path.insert(0, "./modules/module_01/libraries")

How can I import all files under subdir in python

I have dir structure like this:
Proj/
run.py
Util/
__init__.py
x.py
y.py
In x.py, I define a function:
def p():
return 1
In y.py, I define:
def q():
return 2
Currently in run.py, I'll use
from Util import *
But I have to call them using
x.p()
y.q()
But I want to call them using
p()
q()
Is there a way that I can do that? Like (as I imagine)
from Util.* import *

Bring the names up into the package namespace, by using star imports in the __init__.py:
# in util/__init__.py
from util.x import *
from util.y import *
In each submodule, define the names which you want to export by using the __all__ name:
# in x.py
__all__ = ['p']
And:
# in y.py
__all__ = ['q']
This is a pretty standard usage of the __init__.py module within a package, documented here.

Importlib.import_module will not import the module even though the param is the abs path

I have my .py module which is in C:\Python_Projects\MyModules\ with the name button_generator.py.
My code goes something like this:
module_path='C:\\Python_Projects\\MyModules'
module_name='button_generator.py'
sys.path.append(module_path)
try:
limp=importlib.import_module(module_name.split('.')[0])
except:
print 'module import error'
I have tried other versions aswell:
importlib.import_module(module_name) without the split
importlib.import_module('C:\Python_Projects\MyModules\button_generator.py')
importlib.import_module('C:\Python_Projects\MyModules\button_generator')
The folder C:\Python_Projects\MyModules is in my sys.path as I checked during debug.
Why wouldn't the module import?

I suggest you to reorder your project directories and avoid calling other modules which are not in your current directory project. You'll avoid those kind of errors.
For example, let's organize our project directories and folders to look something like this:
MyProjectFolder/
├── main.py
└── modules
├── __init__.py
└── MyLib.py
NB: Don't forget to add an empty file called __init__.py
MyLib.py :
#!/usr/bin/python3
class MyLib:
def __init__(self):
self.say_hello = "Hello i'm in modules/MyLib"
def print_say_hello(self):
print(self.say_hello)
main.py:
#!/usr/bin/python3
# from folder.file import class
from modules.MyLib import MyLib
class MainClass:
def __init__(self):
my_lib = MyLib() # load MyLib class
my_lib.print_say_hello() # access to MyLib methods
### Test
if __name__ == '__main__':
app = MainClass()
In terminal when i run:
$ python3 main.py
output:
Hello i'm in modules/MyLib
So here we have successfully imported the class in modules/MyLib.py into our main.py file.

I found the error:
After treating the ImportError exception by printing it's args, I noticed that button_generator.py had an Import that was not resolving. Basically, button_generator.py could not be imported because it had a wrong import.

How to import the class within the same directory or sub directory?

I have a directory that stores all the .py files.
bin/
main.py
user.py # where class User resides
dir.py # where class Dir resides
I want to use classes from user.py and dir.py in main.py.
How can I import these Python classes into main.py?
Furthermore, how can I import class User if user.py is in a sub directory?
bin/
dir.py
main.py
usr/
user.py

Python 2
Make an empty file called __init__.py in the same directory as the files. That will signify to Python that it's "ok to import from this directory".
Then just do...
from user import User
from dir import Dir
The same holds true if the files are in a subdirectory - put an __init__.py in the subdirectory as well, and then use regular import statements, with dot notation. For each level of directory, you need to add to the import path.
bin/
main.py
classes/
user.py
dir.py
So if the directory was named "classes", then you'd do this:
from classes.user import User
from classes.dir import Dir
Python 3
Same as previous, but prefix the module name with a . if not using a subdirectory:
from .user import User
from .dir import Dir

I just learned (thanks to martineau's comment) that, in order to import classes from files within the same directory, you would now write in Python 3:
from .user import User
from .dir import Dir

From python3.3 upwards, __init__.py is no longer necessary. If the current directory of the console is the directory where the python script is located, everything works fine with
import user
However, this won't work if called from a different directory, which does not contain user.py.
In that case, use
from . import user
This works even if you want to import the whole file instead of just a class from there.

In your main.py:
from user import Class
where Class is the name of the class you want to import.
If you want to call a method of Class, you can call it using:
Class.method
Note that there should be an empty __init__.py file in the same directory.

If user.py and dir.py are not including classes then
from .user import User
from .dir import Dir
is not working. You should then import as
from . import user
from . import dir

You can import the module and have access through its name if you don't want to mix functions and classes with yours
import util # imports util.py
util.clean()
util.setup(4)
or you can import the functions and classes to your code
from util import clean, setup
clean()
setup(4)
you can use wildchar * to import everything in that module to your code
from util import *
clean()
setup(4)

To make it more simple to understand:
Step 1: lets go to one directory, where all will be included
$ cd /var/tmp
Step 2: now lets make a class1.py file which has a class name Class1 with some code
$ cat > class1.py <<\EOF
class Class1:
OKBLUE = '\033[94m'
ENDC = '\033[0m'
OK = OKBLUE + "[Class1 OK]: " + ENDC
EOF
Step 3: now lets make a class2.py file which has a class name Class2 with some code
$ cat > class2.py <<\EOF
class Class2:
OKBLUE = '\033[94m'
ENDC = '\033[0m'
OK = OKBLUE + "[Class2 OK]: " + ENDC
EOF
Step 4: now lets make one main.py which will be execute once to use Class1 and Class2 from 2 different files
$ cat > main.py <<\EOF
"""this is how we are actually calling class1.py and from that file loading Class1"""
from class1 import Class1
"""this is how we are actually calling class2.py and from that file loading Class2"""
from class2 import Class2
print Class1.OK
print Class2.OK
EOF
Step 5: Run the program
$ python main.py
The output would be
[Class1 OK]:
[Class2 OK]:

Python 3
Same directory.
import file:log.py
import class: SampleApp().
import log
if __name__ == "__main__":
app = log.SampleApp()
app.mainloop()
or
directory is basic.
import in file: log.py.
import class: SampleApp().
from basic import log
if __name__ == "__main__":
app = log.SampleApp()
app.mainloop()

from user import User
from dir import Dir

For Python 3+, suppose you have this structure:
A/
__init__.py
bar.py
foo.py
In your __init__.py file, you can put from . import foo
then you can import foo in bar file
# A/bar.py
from foo import YourClass
The purpose of the __init__.py files is to include optional initialization code that runs as different levels of a package are encountered. everything you put in the __init__.py will be initialized during the package load.

I'm not sure why this work but using Pycharm build from file_in_same_dir import class_name
The IDE complained about it but it seems it still worked. I'm using Python 3.7

For python3
import from sibling: from .user import User
import from nephew: from .usr.user import User

If you have filename.py in the same folder, you can easily import it like this:
import filename
I am using python3.7

Python3
use
from .user import User inside dir.py file
and
use from class.dir import Dir inside main.py
or from class.usr import User inside main.py
like so

# My Python version: 3.7
# IDE: Pycharm 2021.1.2 Community
# Have "myLib" in folder "labs":
class Points:
def __init__(self, x = 0, y = 0):
self.__x = x
self.__y = y
def __str__(self):
return f"x = {self.__x}, y = {self.__y}"
# Have "myFile" in (same) folder "labs":
from myFile import Point
p1 = Point(1, 4)
p2 = Point(1, 4)
print(f"p1: {p1}, p2: {p2}")
# Result:
# p1: x = 1, y = 4, p2: x = 1, y = 4
# Good Luck!

Indeed Python does not provide an elegant solution for this everyday use-case. It is especially problematic when you are testing your code that eventually will be delivered as part of a Python package. Here is an approach that has worked for me:
dir
|
file1.py
file2.py
And let's say you want to import file2 from file1.
# In file1.py:
try:
# This works when packaged as Python package
from . import file2
except:
# This works when simply invoking file1 as a module (i.e. python file1)
import file2
# rest of the code ...

I cannot submit an edit for the top answer, so based on some pointers given in comments above, another thing to try out is:
from subfolder.MyClassFile import MyClass
And that's it. Just remember to have an __init__.py empty file in our subfolder.
Just for reference, the solution works if your structure is something like this:
your_project/
__ini__.py
main.py
subfolder/
__init__.py
MyClassFile.py <-- You want this
MyClassFile.py contains the class MyClass.

Just too brief,
Create a file __init__.py is classes directory and then import it to your script like following (Import all case)
from classes.myscript import *
Import selected classes only
from classes.myscript import User
from classes.myscript import Dir

to import from the same directory
from . import the_file_you_want_to_import
to import from sub directory the directory should contain
init.py
file other than you files then
from directory import your_file