Django Selected Radio button choice and dropdown - python

I have created radio button and dropdown menu populated from the static tuple from the Form. I would like to fetch the item what user selected on the same page below the submitting.
FORM.py
## VIEW: Populate dropdown to select Data center
def get_role_dc_data(request, *args, **kwargs):
if request.method == 'POST':
form = SelectionForm(request.POST or None)
if form.is_valid():
form.save()
return render(request, 'selectsite.html', {'form': form })
else:
form = SelectionForm()
return render(request, 'selectsite.html', {'form': form })
## POPULATE: Data
def gather_data(request, *args, **kwargs):
selectedsite = ''
roletype = ''
if request.method == 'POST':
form = SelectionForm(request.POST or None)
if form.is_valid():
selectedsite = form.cleaned_data.get('location')
roletype = form.cleaned_data.get('roletype')
print (selectedsite)
print (region)
context_dict = { "selectedsite": selectedsite, "roletype": roletype }
else:
context_dict = {}
return render(request, 'configure.html', context_dict)
HTML:
<form method="post" action=/configure/> {% csrf_token %}
<table class="table"><tr><th>
<label name="roletype" for="region" class="form-check-label">
Type: {% for choice in form.roletype %}
<name="roletype"> {{ choice }} {% endfor %}
</label></th><th>
<select name="location">
<datalist id="location">Select an the site</option>
{% for dc in form.location %}
<option selected="selected" value="{{ dc }}"></option>
{% endfor %}</datalist></select></th><th>
<button align="right" class="button execute" name="submit" value="submit">GO TO</button>
</th></tr></table></form>

If i understand you correctly you want to display the selected choices without submitting the form, right?
In that case you´d have to render and return this specific part of your page seperately (using javascript - ajax might come in handy as well).
I did something similar before but i need to look it up as well.

Related

Django "if request.method == 'POST':" returns False

I'm making Django app and I have an issue, I've never had problem with before. As always in form view, I'm checking if request.method == 'POST' but somehow it returns False,
My code looks like that:
def recipe_create_view(request):
context = {}
form = RecipeForm(request.POST or None)
IngredientFormset = formset_factory(IngredientForm)
formset = IngredientFormset(request.POST or None)
context['form'] = form
context['formset'] = formset
if request.method == 'POST':
if form.is_valid():
if formset.is_valid():
form.save()
print("made a recipe")
for form in formset:
child = form.save(commit=False)
child.recipe = parent
child.save()
print("made a Ingredient")
else:
print("formset is not valid")
else:
print("form is not valid")
else:
print("request method is not correct")
return render(request, 'recipes/create_recipe.html', context)
create_recipe.html file:
<form method="POST">
{% csrf_token %}
<label>recipe</label>
<p>{{form}}</p>
<label>ingredients</label>
{% for form in formset %}
<ul>
<label>name</label>
<li>{{ form.name }}</li>
<label>quantity</label>
<li>{{ form.quantity }}</li>
</ul>
{% endfor %}
<div>
<input type="submit" value="submit" class="button-33" role="button">
</div>
</form>
Where is the problem?
It is necessary to return HttpResponseRedirect after dealing with POST data, the tip is not specific to Django, it's a good web practice in general.
Also, try to maintain both GET and POST request separately, so try below view:
def recipe_create_view(request):
context = {}
form="" # for the error of variable refrenced before assignment.
IngredientFormset=""
formset=""
if request.method == 'POST':
form = RecipeForm(request.POST)
IngredientFormset = formset_factory(IngredientForm)
formset = IngredientFormset(request.POST)
if form.is_valid():
if formset.is_valid():
form.save()
print("made a recipe")
for form in formset:
child = form.save(commit=False)
child.recipe = parent
child.save()
print("made a Ingredient")
return redirect('some_success_path_name')
else:
print("formset is not valid")
else:
print("form is not valid")
else: # GET method
print("request method is GET")
form = RecipeForm()
IngredientFormset = formset_factory(IngredientForm)
formset = IngredientFormset()
context['form'] = form
context['formset'] = formset
return render(request, 'recipes/create_recipe.html', context)
add action in your HTML form and POST in small case.
<form action="/your_backend_url_to_view/" method="post">
{% csrf_token %}
<label>recipe</label>
<p>{{form}}</p>
<label>ingredients</label>
{% for form in formset %}
<ul>
<label>name</label>
<li>{{ form.name }}</li>
<label>quantity</label>
<li>{{ form.quantity }}</li>
</ul>
{% endfor %}
<div>
<input type="submit" value="submit" class="button-33" role="button">
</div>
</form>

Update a single object from a database - Django/Python

So I am trying to allow users to edit menu item prices that are in the database currently. The fields will auto-populate data into the page and users will be able to edit that data to change the price. Here is what I have. I have tried and asked many questions, but I am still lost. I have googled a lot and it helped me understand forms a bit, but I'm not able to fix it. Please let me know if you need more info.
Views.py:
def edit_menu(request):
queryset = Product.objects.all()
context = { "object_list": queryset }
if request.method == 'POST':
post=ProductModelForm(request.POST)
if request.POST.get('price') and request.POST.get('name'):
if 'name' == Product.name:
post.name= request.POST.get('name')
post.price= request.POST.get('price')
post.save()
return redirect('Edit Menu Item')
else:
return redirect('Edit Menu Item')
else:
return render(request, 'mis446/edit-menu-item.html', context)
else:
return render(request, 'mis446/edit-menu-item.html', context)
forms.py:
class ProductModelForm(forms.ModelForm):
class Meta:
model = Product
fields = ['name','price'] # specify which field you need to be in the form
HTML:
<title>ACRMS - Edit Menu Price</title>
<div class = "container">
<form action = "" method = 'POST'>
{% csrf_token %}
{% for instance in object_list %}
<input name = "name" value = "{{ instance.name }}"></input>
<input type="number" name="price" value = "{{ instance.price }}"/><br>
{% endfor %}
</select>
<button type ="submit">Submit Changes</button>
</form>
</div>
Urls.py:
url('edit-menu/edit/',views.edit_menu, name='Edit Menu Item'),
models.py:
class Product(models.Model):
name = models.CharField(max_length=100)
price = models.IntegerField()
slug = models.SlugField()
def __str__(self):
return self.name
For your current implementation, you do not need a form. Instead, update the view like this:
# view
def edit_single_menu(request, pk):
if request.method == 'POST':
post=Product.objects.get(pk=pk)
if request.POST.get('price') and request.POST.get('name'):
post.name= request.POST.get('name')
post.price= request.POST.get('price')
post.save()
return redirect('Edit Menu Item')
else:
return redirect('Edit Menu Item')
return render(request, 'mis446/edit-menu-item.html', context)
# url
url('edit-menu/edit/<pk:id>/',views.edit_single_menu, name='edit_single_menu'),
# template (mis446/edit-menu-item.html)
<title>ACRMS - Edit Menu Price</title>
<div class = "container">
{% for instance in object_list %}
<form action = "{% url 'edit_single_menu' instance.pk %}" method = 'POST'>
{% csrf_token %}
<input name = "name" value = "{{ instance.name }}"></input>
<input type="number" name="price" value = "{{ instance.price }}"/><br>
<button type ="submit">Submit Changes</button>
</form>
{% endfor %}
</div>
Here I am sending individual edit to a new separated view named edit_single_menu and store the changes there.
Update
New url is not meant to replace the old one. It is only to assist you to update individual product. So, you need to keep both of the urls. Also, here is an answer based on #brunodesthuilliers's suggestion:
# view
def edit_single_menu(request, pk):
if request.method == 'POST':
post=Product.objects.get(pk=pk)
form = ProductForm(request.POST, instance=post)
if form.is_valid():
form.save()
return redirect('Edit Menu Item')
Also, do some changes on edit_menu view:
def edit_menu(request):
queryset = Product.objects.all()
context = { "object_list": queryset }
return render(request, 'mis446/edit-menu-item.html', context)
And urls should look like this:
from django.urls import include, path
# rest of the code
path('edit-menu/edit/<int:pk>/',views.edit_single_menu, name='edit_single_menu'),
path('edit-menu/edit/',views.edit_menu, name='Edit Menu Item'),

How to get value from form and redirect to /value in Django 1.10

I need to get value from tag and redirect to '/value/' by submit.
Now I'm getting:
'ApartmentForm' object has no attribute 'cleaned_data'
I'm totally missing something.
forms.py
class ApartmentForm(ModelForm):
class Meta:
model = Apartment
fields = ['title']
views.py
def index(request):
context = {}
context['apartments'] = get_list_or_404(Apartment)
if request.method == 'POST':
form = ApartmentForm(request.POST or None)
context = {'form': form,}
id = form.cleaned_data.get('id', None)
return redirect(id)
else:
context['apartment_form'] = ApartmentForm
return render(request, 'main/main.html', context)
template
<form action="/{{ apartment.id }}" method="post">
{% csrf_token %}
<p><select size="10">
<option disabled>Chose apartment</option>
{% for apartment in apartments %}
<option value="{{ apartment.id }}">{{ apartment.title }}</option>
{% endfor %}
</select></p>
<input type="submit" value="Chose">
</form>
Update
Thanks Daniel!
It was such a fail not to call form in the template. I fixed that, but it still passing None to url (http://127.0.0.1:8000/None). Can't figure out why.
view.py
def index(request):
context = {}
context['apartments'] = get_list_or_404(Apartment)
if request.method == 'POST':
form = ApartmentForm(request.POST or None)
if form.is_valid():
id = form.cleaned_data.get('id', None)
return redirect(id)
else:
context['apartment_form'] = ApartmentForm
return render(request, 'main/main.html', context)
forms.py
APARTMENTS = ()
for apartment in Apartment.objects.all():
APARTMENTS += ((apartment.id, apartment.title),)
class ApartmentForm(Form):
apartment = ChoiceField(label='', widget=Select, choices=APARTMENTS)
template
<form action="." method="post">
{% csrf_token %}
{{ apartment_form }}
<input type="submit" value="Chose">
form.cleaned_data comes from form.is_valid(), so you sould change your views.py like this:
def index(request):
[...]
if request.method == 'POST':
form = ApartmentForm(request.POST or None)
if form.is_valid():
[...]
id = form.cleaned_data.get('id', None)
return redirect(id)

Handling two forms in the same view

I have the following stripped function.
def jobs(request):
pms = PM.objects.all()
a = Job.objects.all().filter(enddate__gte=datetime.date.today()).order_by('enddate')
ljform = LaunchJobForm(request.POST or None)
form = LimitedJobForm(request.POST or None, prefix='add')
if request.method=='POST' and 'addjobbtn' in request.POST:
if form.is_valid():
...do stuff...
elif request.method=='POST' and 'launchjobbtn' in request.POST:
print('test')
... do other stuff...
My ljform is
<form method='POST' action = '' class='launchjob'>{% csrf_token %}
{{ ljform }}
<td><button class = 'btn btn-primary' name='launchjobbtn' type='submit'>Launch Job</button></td>
<td><input id='emailcheck' type="checkbox">Modify Email</input></td>
</form>
My addjob form is:
<div class='jobfrm{% if form.errors %} has_errors{% endif %}'>
<span class='closex' >✖</span>
<form method='POST' action = '' class='addjob'>{% csrf_token %}
{{form|crispy}}
<input class = 'btn btn-default' name='addjobbtn' type = 'submit' value = 'Submit'/>
</form>
</div>
My problem is that when I click the launch job button form validation errors are triggered on the jobfrm. It doesn't actually take that if path. It does take the elif path and prints 'test'. But I cannot figure out why it's triggering the other form.
You only want to pass request.POST as an argument to your form if that is the form that has been submitted. This means you have to do something like this:
def jobs(request):
pms = PM.objects.all()
a = Job.objects.all().filter(enddate__gte=datetime.date.today()).order_by('enddate')
ljform = LaunchJobForm()
form = LimitedJobForm()
if request.method=='POST' and 'addjobbtn' in request.POST:
form = LimitedJobForm(request.POST)
if form.is_valid():
...do stuff...
elif request.method=='POST' and 'launchjobbtn' in request.POST:
ljform = LaunchJobForm(request.POST)
print('test')
... do other stuff...

Take In Input from User and Display the same input on the same page

Hi i am trying to create a post form in django where the user creates a post and the post is displayed back to them on the same page so far i have been unsuccessful. My articles display on the page but the form to post articles doesnt only the submit button shows.
views.py
def articles(request):
args = {}
args.update(csrf(request))
args ['posts'] = post.objects.filter(user = request.user)
args ['full_name'] = User.objects.get(username = request.user.username)
return render_to_response('articles.html', args)
def article(request, post_id=1):
return render(request, 'article.html',
{'post': post.objects.get(id=post_id) })
def create(request):
if request.POST:
form = PostForm(request.POST, request.FILES)
if form.is_valid():
a = form.save(commit=False)
a.user = User.objects.get(username = request.user.username)
a.save()
messages.add_message(request, messages.SUCCESS, "You Article was added")
return HttpResponseRedirect('/posts/all')
else:
form = PostForm()
args = {}
args.update(csrf(request))
args['form'] = form
return render_to_response('articles.html', args)
articles.html
<form action="/posts/create/" method="post" enctype="multipart/form-data">{% csrf_token %}
<ul>
{{form.as_ul}}
</ul>
<input type="submit" name="submit" value="Create Article">
</form>
{% if posts.count > 0 %}
{% for post in posts %}
<div>
<h2>{{full_name}}</h2>
<p>{{ post.body|lower|truncatewords:50 }}</p>
<p>{{post.likes}} people liked this article</a></p>
</div>
{% endfor %}
{% else %}
<p>None to show!</p>
{% endif %}
{% endblock %}
urls.py
from django.conf.urls import patterns, include, url
urlpatterns = patterns('',
url(r'^create/$', 'posts.views.articles'),
url(r'^get/(?P<post_id>\d+)/$', 'posts.views.article'),
url(r'^create/$', 'posts.views.create'),
url(r'^like/(?P<post_id>\d+)/$', 'posts.views.like_article'),
url(r'^article/(?P<post_id>\d+)/$', 'posts.views.add_comment'),
)
First off you aren't passing the form to the template in articles(). You need to have something along the lines of:
args['form'] = YourForm()
In your first view function. Also, in your create view you do this:
a.user = User.objects.get(username = request.user.username)
Which does an unnecessary database lookup of the user again, you can just do this to be clearer and faster:
a.user = request.user

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