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I am having issues with my code working properly and im stuck

I am having a problem with my code and getting it to work. Im not sure if im sorting this correctly. I am trying to sort with out lambda pandas or itemgetter.
Here is my code that I am having issues with.
with open('ManufacturerList.csv', 'r') as man_list:
ml = csv.reader(man_list, delimiter=',')
for row in ml:
manufacturerList.append(row)
print(row)
with open('PriceList.csv', 'r') as price_list:
pl = csv.reader(price_list, delimiter=',')
for row in pl:
priceList.append(row)
print(row)
with open('ManufacturerList.csv', 'r') as service_list:
sl = csv.reader(service_list, delimiter=',')
for row in sl:
serviceList.append(row)
print(row)
new_mfl = (sorted(manufacturerList, key='None'))
new_prl = (sorted(priceList, key='None'))
new_sdl = (sorted(serviceList, key='None'))
for x in range(0, len(new_mfl)):
new_mfl[x].append(priceList[x][1])
for x in range(0, len(new_mfl)):
new_mfl[x].append(serviceList[x][1])
new_list = new_mfl
inventoryList = (sorted(list, key=1))
i have tried to use the def function to try to get it to work but i dont know if im doing it right. This is what i tried.
def new_mfl(x):
return x[0]
x.sort(key=new_mfl)

You can do it like this:
def manufacturer_key(x):
return x[0]
sorted_mfl = sorted(manufacturerList, key=manufacturer_key)
The key argument is the function that extracts the field of the CSV that you want to sort by.

sorted_mfl = sorted(manufacturerList, key=lambda x: x[0])
There are different Dialects and Formatting Parameters that allow to handle input and output of data from comma separated value files; Maybe it could be used in a way with fewer statements using the correct delimiter which depends on the type of data you handle, this would be added to using built in methods like split for string data or another method to sort and manipulate lists, for example for single column data, delimiter=',' separate data by comma and it would iterate trough each value and not as a list of lists when you call csv.reader
['9.310788653967691', '4.065746465800029', '6.6363356879192965', '7.279020237137884', '4.010297786910394']
['9.896092029283933', '7.553018448286675', '0.3268282119829197', '2.348011394854333', '3.964531054345021']
['5.078622663277619', '4.542467725728741', '3.743648062104161', '12.761916277286993', '9.164698479088221']
# out:
column1 column2 column3 column4 column5
0 4.737897984379577 6.078414943611958 2.7021438955897095 5.8736388919905895 7.878958949784588
1 4.436982168483749 3.9453563399358544 12.66647791861843 5.323017508568736 4.156777982870004
2 4.798241413768279 12.690268531982028 9.638858110105895 7.881360524434767 4.2948334000783195
This is achieved because I am using lists that contain singular values, since for columns or lists that are of the form sorted_mfl = {'First Name' : ['name', 'name', 'name'], 'Second Name ' : [...], 'ID':[...]}, new_prl = ['example', 'example', 'example'] new_sdl = [...] the data would be added by something like sorted_mfl + new_prl + new_sdl and since different modules are also used to set and manage comma separated files, you should add more information to your question like the data type you use or create a minimal reproducible example with pandas.

pandas how to replace only empty list data?

my dataframe look like this:
variations_list1 variations_list2
["yellow","ornage"] []
["xl","xxl"] []
["Burger","pizza"] ["$25","$30"]
expected dataframe:
variations_list1 variations_list2
["yellow","ornage"] ["yellow","ornage"] #filling emty list with current row data
["xl","xxl"] ["xl","xxl"]
["Burger","pizza"] ["$25","$30"]

You can just do
df.loc[~df['variations_list2'].astype(bool),'variations_list2'] = df['variations_list1']
You have the same issue like before, list is not list
df.loc[df['variations_list2']=='[]','variations_list2'] = df['variations_list1']

populate column in dataframe with a list using for loop

I would like to populate a dataframe using a for loop.
one of the column is a list.
this list is empty at the begining at each itteration an element is added or removed from it.
when I print my list at each iteration I am getting the right results, but when I print my dataframe, I am getting the same list on each row:
I you have a look to my code the list I am updatin is list_employe. The magic should happen in the 3 last rows but it did not.
Does anyone have an idea why the list is updated in one way and the dataframe record only the last update on all rows
list_employe = []
total_employe = 0
rows=[]
shiftday = example['SHIFT_DATE'].dt.strftime('%Y-%m-%d').unique().tolist()
for i in shiftday:
shift_day = example[example['SHIFT_DATE'] == i]
list_employe_shift = example[example['SHIFT_DATE']==i]['EMPLOYEE_CODE_POS_UPPER'].unique().tolist()
new_employe = 0
end_employe = 0
for k in list_employe_shift:
shift_days_emp = shift_day[shift_day['EMPLOYEE_CODE_POS_UPPER'] == k]
days = shift_days_emp.iloc[0]['last_day']
#print(days)
if k in list_employe:
if days>1:
end_employe= end_employe+1
total_employe = total_employe-1
list_employe.remove(k)
else:
new_employe = new_employe+1
total_employe = total_employe + 1
list_employe.extend([k])
day = i
total_emp = total_employe
new_emp = new_employe
end_emp = end_employe
rows.append([day, total_emp, new_emp, end_emp, list_employe])
print(list_employe)
df = pd.DataFrame(rows, columns=["day", "total_employe", "new_employe", "end_employe", "list_employe"])

the list list_employe is always the same object that you append to the list rows. What you need to do to solve the problem is at the 3rd line from the bottom : rows.append([day, total_emp, new_emp, end_emp, list(list_employe)]) Which create a new list at each itteration

Drop rows in dataframe if length of the name columns <=1

Please point out where i am doing wrong or a duplicate of this question
I have 11 columns in my table, i am loading data from Ceph(AWS) bucket to Postgres and while doing that i have to filter the data with the below conditions before inserting data into Postgres
Drop the entire row if there is any empty/ Null values in any column
First name and last name should have more than a single letter. Ex : first name = A or last name = P, any record either first name or last name or both , entire record/row should be dropped
Zip code should be 5 digit or greater . Max 7 digit
First name and last name records should not have [Jr, Sr, I, II, etc] in it. or drop the entire record
i have managed to execute the first step (new to pandas) but i was blocked at the next step and i believe that it might also help me solve step3 if i find a solution for step2. While doing a quick research in google, I found that i might be complicating the process by using chunks and might have to use 'concat' to apply it for all chunks or may be i am wrong but i am dealing with huge amount of data and using chunks would help me load the data faster into Postgres.
I am going to paste my code here and mention what i tried, what was the output and what would be the expected output
what i tried:
columns = [
'cust_last_nm',
'cust_frst_nm',
'cust_brth_dt',
'cust_gendr_cd',
'cust_postl_cd',
'indiv_entpr_id',
'TOKEN_1',
'TOKEN_2',
'TOKEN_3',
'TOKEN_4',
'TOKEN_KEY'
]
def push_to_pg_weekly(key):
vants = []
print(key)
key = _download_s3(key)
how_many_files_pushed.append(True)
s=sp.Popen(["wc", "-l", key], stdout=sp.PIPE)
a, b = s.communicate()
total_rows = int(a.split()[0])
rows = 0
data = pd.read_csv(key, sep="|", header=None, chunksize=100000)
for chunk in data:
rows += len(chunk)
print("Processed rows: ", (float(rows)/total_rows)*100)
chunk = chunk.dropna(axis=0) #step-1 Drop the rows where at least one element is missing.
index_names = chunk[(len(chunk[0]) <= 1) | (len(chunk[1]) <= 1)].index #step2
chunk.drop(index_names, axis=0)
chunk.to_csv("/tmp/sample.csv", sep="|", header=None, index=False)
connection = psycopg2.connect(user = os.environ.get("DATABASE_USER", “USERNAME”),
password = os.environ.get("DATABASE_PASS", “PASSWORD“),
host = os.environ.get("DATABASE_HOST", "cvlpsql.pgsql.com"),
port = 5432,
dbname = os.environ.get("DATABASE_NAME", "cvlpsql_db"),
options = "-c search_path=DATAVANT_O")
with connection.cursor() as cursor:
cursor.copy_from(open('/tmp/sample.csv'), "COVID1", sep='|')
connection.commit()
def push_to_pg():
paginator = CLIENT.get_paginator('list_objects')
pages = paginator.paginate(Bucket=bucket)
for page in pages:
if "Contents" in page:
for obj in page["Contents"]:
if obj['Key'].startswith('test/covid-2020-11-10-175213') and (obj['Key'].endswith('.txt') or obj['Key'].endswith('.csv')):
push_to_pg_weekly(obj['Key'])
os.remove(obj['Key'])
return
Data:
john|doe|1974-01-01|F|606.0|113955973|cC80fi6kHVjKRNgUnATuE8Nn5x/YyoTUdSDY3sUDis4=|2qalDHguJRO9gR66LZcRLSe2SSQSQAIcT9btvaqLnZk=|eLQ9vYAj0aUfMM9smdpXqIh7QRxLBh6wYl6iYkItz6g=|3ktelRCCKf1CHOVBUdaVbjqltxa70FF+9Lf9MNJ+HDU=|cigna_TOKEN_ENCRYPTION_KEY
j|ab|1978-01-01|M|328.0|125135976|yjYaupdG9gdlje+2HdQB+FdEEj6Lh4+WekqEuB1DSvM=|j8VuTUKll7mywqsKrqBnomppGutsoJAR+2IoH/Tq0b8=|6qNP9ch57MlX912gXS7RMg7UfjtaP6by/cR68PbzNmQ=|R5DemSNrFvcevijrktwf3aixOShNU6j7wfahyKeUyzk=|cigna_TOKEN_ENCRYPTION_KEY
j|j|1985-01-01|F|105.0|115144390|fn0r8nVzmDJUihnaQh1SXm1sLOIjzGsPDBskdX4/b+0=|Fh6facONoOiL9hCCA8Q1rtUp9n5h9VBhg2IaX9gjaKI=|NWtnZegpcpgcit2u063zQv3pcEhk4bpKHKFa9hW7LtU=|P3cVOUd6PyYN5tKezdMkVDI62aW8dv+bjIwKtAgX3OM=|cigna_TOKEN_ENCRYPTION_KEY
jh|on|1989-01-01|M|381.0|133794239|PvCWdh+ucgi1WyP5Vr0E6ysTrTZ1gLTQIteXDxZbEJg=|7K3RsfC8ItQtrEQ+MdBGpx6neggYvBvR8nNDMOBTRtU=|nHsF/rJFM/O+HPevTj9cVYwrXS1ou+2/4FelEXTV0Ww=|Jw/nzI/Gu9s6QsgtxTZhTFFBXGLUv06vEewxQbhDyWk=|cigna_TOKEN_ENCRYPTION_KEY
||1969-01-01|M|926.0|135112782|E2sboFz4Mk2aGIKhD4vm6J9Jt3ZSoSdLm+0PCdWsJto=|YSILMFS5sPPZZF/KFroEHV77z1bMeiL/f4FqF2kj4Xc=|tNjgnby5zDbfT2SLsCCwhNBxobSDcCp7ws0zYVme5w4=|kk25p0lrp2T54Z3B1HM3ZQN0RM63rjqvewrwW5VhYcI=|cigna_TOKEN_ENCRYPTION_KEY
||1978-01-01|M|70.0|170737333|Q8NDJz563UrquOUUz0vD6Es05vIaAD/AfVOef4Mhj24=|k5Q02GVd0nJ6xMs1vHVM24MxV6tZ46HJNKoePcDsyoM=|C9cvHz5n+sDycUecioiWZW8USE6D2dli5gRzo4nOyvY=|z4eNSVNDAjiPU2Sw3VY+Ni1djO5fptl5FGQvfnBodr4=|cigna_TOKEN_ENCRYPTION_KEY
||1996-01-01|M|840.0|91951973|Y4kmxp0qdZVCW5pJgQmvWCfc4URg9oFnv2DWGglfQKM=|RJfyDYJjwuZ1ZDjP+5PA5S2fLS6llFD51Lg+uJ84Tus=|+PXzrKt7O79FehSnL3Q8EjGmnyZVDUfdM4zzHk1ghOY=|gjyVKjunky2Aui3dxzmeLt0U6+vT39/uILMbEiT0co8=|cigna_TOKEN_ENCRYPTION_KEY
||1960-01-01|M|180.0|64496569|80e1CgNJeO8oYQHlSn8zWYL4vVrHSPe9AnK2T2PrdII=|bJl7veT+4MlU4j2mhFpFyins0xeCFWeaA30JUzWsfqo=|0GuhUfbS4xCnCj2ms43wqmGFG5lCnfiIQdyti9moneM=|lq84jO9yhz8f9/DUM0ACVc/Rp+sKDvHznVjNnLOaRo4=|cigna_TOKEN_ENCRYPTION_KEY
||1963-01-01|M|310.0|122732991|zEvHkd5AVT7hZFR3/13dR9KzN5WSulewY0pjTFEov2Y=|eGqNbLoeCN1GJyvgaa01w+z26OtmplcrAY2vxwOZ4Y4=|6q9DPLPK5PPAItZA/x253DvdAWA/r6zIi0dtIqPIu2g=|lOl11DhznPphGQOFz6YFJ8i28HID1T6Sg7B/Y7W1M3o=|cigna_TOKEN_ENCRYPTION_KEY
||2001-01-01|F|650.0|43653178|vv/+KLdhHqUm13bWhpzBexwxgosXSIzgrxZIUwB7PDo=|78cJu1biJAlMddJT1yIzQAH1KCkyDoXiL1+Lo1I2jkw=|9/BM/hvqHYXgfmWehPP2JGGuB6lKmfu7uUsmCtpPyz8=|o/yP8bMzFl6KJ1cX+uFll1SrleCC+8BXmqBzyuGdtwM=|cigna_TOKEN_ENCRYPTION_KEY
output - data inserted into postgresDB:
john|doe|1974-01-01|F|606.0|113955973|cC80fi6kHVjKRNgUnATuE8Nn5x/YyoTUdSDY3sUDis4=|2qalDHguJRO9gR66LZcRLSe2SSQSQAIcT9btvaqLnZk=|eLQ9vYAj0aUfMM9smdpXqIh7QRxLBh6wYl6iYkItz6g=|3ktelRCCKf1CHOVBUdaVbjqltxa70FF+9Lf9MNJ+HDU=|cigna_TOKEN_ENCRYPTION_KEY
j|ab|1978-01-01|M|328.0|125135976|yjYaupdG9gdlje+2HdQB+FdEEj6Lh4+WekqEuB1DSvM=|j8VuTUKll7mywqsKrqBnomppGutsoJAR+2IoH/Tq0b8=|6qNP9ch57MlX912gXS7RMg7UfjtaP6by/cR68PbzNmQ=|R5DemSNrFvcevijrktwf3aixOShNU6j7wfahyKeUyzk=|cigna_TOKEN_ENCRYPTION_KEY
j|j|1985-01-01|F|105.0|115144390|fn0r8nVzmDJUihnaQh1SXm1sLOIjzGsPDBskdX4/b+0=|Fh6facONoOiL9hCCA8Q1rtUp9n5h9VBhg2IaX9gjaKI=|NWtnZegpcpgcit2u063zQv3pcEhk4bpKHKFa9hW7LtU=|P3cVOUd6PyYN5tKezdMkVDI62aW8dv+bjIwKtAgX3OM=|cigna_TOKEN_ENCRYPTION_KEY
jh|on|1989-01-01|M|381.0|133794239|PvCWdh+ucgi1WyP5Vr0E6ysTrTZ1gLTQIteXDxZbEJg=|7K3RsfC8ItQtrEQ+MdBGpx6neggYvBvR8nNDMOBTRtU=|nHsF/rJFM/O+HPevTj9cVYwrXS1ou+2/4FelEXTV0Ww=|Jw/nzI/Gu9s6QsgtxTZhTFFBXGLUv06vEewxQbhDyWk=|cigna_TOKEN_ENCRYPTION_KEY
Expected Output:
john|doe|1974-01-01|F|606.0|113955973|cC80fi6kHVjKRNgUnATuE8Nn5x/YyoTUdSDY3sUDis4=|2qalDHguJRO9gR66LZcRLSe2SSQSQAIcT9btvaqLnZk=|eLQ9vYAj0aUfMM9smdpXqIh7QRxLBh6wYl6iYkItz6g=|3ktelRCCKf1CHOVBUdaVbjqltxa70FF+9Lf9MNJ+HDU=|cigna_TOKEN_ENCRYPTION_KEY
jh|on|1989-01-01|M|381.0|133794239|PvCWdh+ucgi1WyP5Vr0E6ysTrTZ1gLTQIteXDxZbEJg=|7K3RsfC8ItQtrEQ+MdBGpx6neggYvBvR8nNDMOBTRtU=|nHsF/rJFM/O+HPevTj9cVYwrXS1ou+2/4FelEXTV0Ww=|Jw/nzI/Gu9s6QsgtxTZhTFFBXGLUv06vEewxQbhDyWk=|cigna_TOKEN_ENCRYPTION_KEY
Any answers/comments will be very much appriciated, thank you

Fastest way to do operations like this on pandas is through numpy.where.
eg for String length:
data = data[np.where((data['cust_last_nm'].str.len()>1) &
(data['cust_frst_nm'].str.len()>1), True, False)]
Note: you can add postal code condition in same way. by default in your data postal codes will read in as floats, so cast them to string first, and then set length limit:
## string length & postal code conditions together
data = data[np.where((data['cust_last_nm'].str.len()>1) &
(data['cust_frst_nm'].str.len()>1) &
(data['cust_postl_cd'].astype('str').str.len()>4) &
(data['cust_postl_cd'].astype('str').str.len()<8)
, True, False)]
EDIT:
Since you working in chunks, change the data to chunk and put this inside your loop. Also, since you don't import headers (headers=0, change column names to their index values. And convert all values to strings before comparison, since otherwise NaN columns will be treated as floats eg:
chunk = chunk[np.where((chunk[0].astype('str').str.len()>1) &
(chunk[1].astype('str').str.len()>1) &
(chunk[5].astype('str').str.len()>4) &
(chunk[5].astype('str').str.len()<8), True, False)]

Create a new column in the dataframe with a value for the length:
df['name_length'] = df.name.str.len()
Index using the new column:
df = df[df.name_length > 1]

pandas - drop row with list of values, if contains from list

I have a huge set of data. Something like 100k lines and I am trying to drop a row from a dataframe if the row, which contains a list, contains a value from another dataframe. Here's a small time example.
has = [['#a'], ['#b'], ['#c, #d, #e, #f'], ['#g']]
use = [1,2,3,5]
z = ['#d','#a']
df = pd.DataFrame({'user': use, 'tweet': has})
df2 = pd.DataFrame({'z': z})
tweet user
0 [#a] 1
1 [#b] 2
2 [#c, #d, #e, #f] 3
3 [#g] 5
z
0 #d
1 #a
The desired outcome would be
tweet user
0 [#b] 2
1 [#g] 5
Things i've tried
#this seems to work for dropping #a but not #d
for a in range(df.tweet.size):
for search in df2.z:
if search in df.loc[a].tweet:
df.drop(a)
#this works for my small scale example but throws an error on my big data
df['tweet'] = df.tweet.apply(', '.join)
test = df[~df.tweet.str.contains('|'.join(df2['z'].astype(str)))]
#the error being "unterminated character set at position 1343770"
#i went to check what was on that line and it returned this
basket.iloc[1343770]
user_id 17060480
tweet [#IfTheyWereBlackOrBrownPeople, #WTF]
Name: 4612505, dtype: object
Any help would be greatly appreciated.

is ['#c, #d, #e, #f'] 1 string or a list like this ['#c', '#d', '#e', '#f'] ?
has = [['#a'], ['#b'], ['#c', '#d', '#e', '#f'], ['#g']]
use = [1,2,3,5]
z = ['#d','#a']
df = pd.DataFrame({'user': use, 'tweet': has})
df2 = pd.DataFrame({'z': z})
simple solution would be
screen = set(df2.z.tolist())
to_delete = list() # this will speed things up doing only 1 delete
for id, row in df.iterrows():
if set(row.tweet).intersection(screen):
to_delete.append(id)
df.drop(to_delete, inplace=True)
speed comparaison (for 10 000 rows):
st = time.time()
screen = set(df2.z.tolist())
to_delete = list()
for id, row in df.iterrows():
if set(row.tweet).intersection(screen):
to_delete.append(id)
df.drop(to_delete, inplace=True)
print(time.time()-st)
2.142000198364258
st = time.time()
for a in df.tweet.index:
for search in df2.z:
if search in df.loc[a].tweet:
df.drop(a, inplace=True)
break
print(time.time()-st)
43.99799990653992

For me, your code works if I make several adjustments.
First, you're missing the last line when putting range(df.tweet.size), either increase this or (more robust, if you don't have an increasing index), use df.tweet.index.
Second, you don't apply your dropping, use inplace=True for that.
Third, you have #d in a string, the following is not a list: '#c, #d, #e, #f' and you have to change it to a list so it works.
So if you change that, the following code works fine:
has = [['#a'], ['#b'], ['#c', '#d', '#e', '#f'], ['#g']]
use = [1,2,3,5]
z = ['#d','#a']
df = pd.DataFrame({'user': use, 'tweet': has})
df2 = pd.DataFrame({'z': z})
for a in df.tweet.index:
for search in df2.z:
if search in df.loc[a].tweet:
df.drop(a, inplace=True)
break # so if we already dropped it we no longer look whether we should drop this line
This will provide the desired result. Be aware of this potentially being not optimal due to missing vectorization.
EDIT:
you can achieve the string being a list with the following:
from itertools import chain
df.tweet = df.tweet.apply(lambda l: list(chain(*map(lambda lelem: lelem.split(","), l))))
This applies a function to each line (assuming each line contains a list with one or more elements): Split each element (should be a string) by comma into a new list and "flatten" all the lists in one line (if there are multiple) together.
EDIT2:
Yes, this is not really performant But basically does what was asked. Keep that in mind and after having it working, try to improve your code (less for iterations, do tricks like collecting the indices and then drop all of them).