I have already Generated df1 and df2.
df1
df2
Both Dataframes have a common column, df1[TB_DIV] and df2[DIV].
I want to generate a new df3 that contains all the info in df1 filtered by all the df2[DIV] which are NOT IN df1.
I tried to use the .isin function to filter df1 with the df2 info, but wasn't able to get the expected values.
m = DIV_LIST.DIV.isin(DIV_TABLE.TB_DIV)
DIV_LIST1 = DIV_LIST[m]
I obtained a empty df3 and in some cases errors due to a length mismatch.
Try going about it like this:
df1.loc[df1['TB_DIV'].isin(df2['DIV'])]
To get those that are not in, use:
df1.loc[~df1['TB_DIV'].isin(df2['DIV'])]
Related
I got a DF called "df" with 4 numerical columns [frame,id,x,y]
I made a loop that creates two dataframes called df1 and df2. Both df1 and df2 are subseted of the original dataframe.
What I want to do (and I am not understanding how to do it) is this: I want to CHECK if df1 and df2 have same VALUES in the column called "id". If they do, I want to concatenate those rows of df2 (that have the same id values) to df1.
For example: if df1 has rows with different id values (1,6,4,8) and df2 has this id values (12,7,8,10). I want to concatenate df2 rows that have the id value=8 to df1. That is all I need
This is my code:
for i in range(0,max(df['frame']),30):
df1=df[df['frame'].between(i, i+30)]
df2=df[df['frame'].between(i-30, i)]
There are several ways to accomplish what you need.
The simplest one is to get the slice of df2 that contains the values you need with .isin() and concatenate it with df1 in one line.
df3 = pd.concat([df1, df2[df2.id.isin(df1.id)]], axis = 0)
To gain more control and avoid any errors that might stem from updating df1 and df2 elsewhere, you may want to take the apart this one-liner.
look_for_vals = set(df1['id'].tolist())
# do some stuff
need_ix = df2[df2["id"].isin(look_for_vals )].index
# do more stuff
df3 = pd.concat([df1, df2.loc[need_ix,:]], axis=0)
Instead of set() you may also use df1['id'].unique()
I have two dataframes (df1, df2). The columns names and indices are the same (the difference in columns entries). Also, df2 has only 20 entries (which also existed in df1 as i said).
I want to filter df1 by df2 entries, but when i try to do it with isin but nothing happens.
df1.isin(df2) or df1.index.isin(df2.index)
Tell me please what I'm doing wrong and how should I do it..
First of all the isin function in pandas returns a Dataframe of booleans and not the result you want. So it makes sense that the cmds you used did not work.
I am possitive that hte following psot will help
pandas - filter dataframe by another dataframe by row elements
If you want to select the entries in df1 with an index that is also present in df2, you should be able to do it with:
df1.loc[df2.index]
or if you really want to use isin:
df1[df1.index.isin(df2.index)]
I need to concatenate two DataFrames where both dataframes have a column named 'sample ids'. The first dataframe has all the relevant information needed, however the sample ids column in the first dataframe is missing all the sample ids that are within the second dataframe. Is there a way to insert the 'missing' sample ids (IN SEQUENTIAL ORDER) into the first dataframe using the second dataframe?
I have tried the following:
pd.concat([DF1,DF2],axis=1)
this did retain all information from both DataFrames, but the sample ids from both datframes were separated into different columns.
pd.merge(DF1,DF2,how='outer/inner/left/right')
this did not produce the desired outcome in the least...
I have shown the templates of the two dataframes below. Please help my brain is exploding!!!
DataFrame 2
DataFrame 1
If you want to:
insert the 'missing' sample ids (IN SEQUENTIAL ORDER) into the first
dataframe using the second dataframe
you can use an outer join by .merge() with how='outer', as follows:
df_out = df1.merge(df2, on="samp_id", how='outer')
To further ensure the samp_id are IN SEQUENTIAL ORDER, you can further sort on samp_id using .sort_values(), as follows:
df_out = df1.merge(df2, on="samp_id", how='outer').sort_values('samp_id', ignore_index=True)
Try this :
df = df1.merge(df2, on="samp_id")
Hi - I want to merge two python DataFrames, but don't want to bring over ALL of the columns from both dataframes to my new dataframe. In the picture below, if I join df1 and df2 on 'acct' and want to bring back all the columns from df1 and ONLY 'entity' from df2, how would I write that? I don't want to have to drop any columns so doing a normal merge isn't what I'm looking for. Can anyone help? Thanks!
When you perform the merge operation, you can modify a dataframe object that is in your function, which will mean the underlying objects df1 and df2 remain unchanged. An example would look like this:
df_result = df1.merge(df2[ ['acct','entity'] ], on ='acct')
This will let you do your partial merge without modifying either original dataframe.
I am querying AD for a list of machines. I filter this list with pandas by last log on date. When I am done with this data I have one column in
a dataframe.
I have another report that has a list of machines that a product we use is installed. I clean this data and I am left with the devices that I want to use to compare to the AD data. Which is just one column in a dataframe.
I have also tried comparing list to list. I am not sure on the best the method.
I tried the merge but my guess this compares DF1 row 1 to DF2 row 1.
DF1 = comp1,comp2,comp3,comp5
DF2 = comp1,comp2,comp3
How would I check each row in DF1 to make sure that each value in DF2 exist and return true or false?
I am trying to figure out machines in DF1 that don't exist in DF2.
DataFrame.isin
this is a simple check to see if one value is in another, you do this in a multitude of ways, this is probably one of the simpliest.
I'm providing some dummy data but please check out How to make good reproducible pandas examples
machines = ['A','B','C']
machines_to_check = ['A','B']
df = pd.DataFrame({'AD' : machines})
df2 = pd.DataFrame({'AD' : machines_to_check})
now, if we want to check for the machines that exist in df but not in df2 we can use ~ which inverts the .isin function.
non_matching_machines = df.loc[~df['AD'].isin(df2['AD'])]
print(non_matching_machines)
AD
2 C