im new at python and im making a software with tkinter lib. The program works fine but when i close the program it appears the error presented in the title. Depending on what ive oppened from the software the block shown in the error changes.
Does anyone knows what this error means, and can I ignore it? It only appears when i close the program.
Thanks
Related
It's as simple as that. I've been trying to code something that simply left clicks in a certain position, but no matter what programming language I use, the program fails to do so, freezes, refuses to close, and when trying to terminate it shows "access denied" and the only way to close it through restarting my computer. Please help me.
On Python: pyautogui.moveTo(x,y)
pyautogui.click(x,y)
Alright uh so i fixed it but I'm not sure how. I just downloaded an auto clicker because I was wondering if it would work. https://sourceforge.net/projects/orphamielautoclicker/
Whenever I use the function pylab.plot(), it causes spyder to crash and show an error
This is the code I'm using:
def myplot():
x = ([1,2,3],[2,4,6])
pylab.plot(x)
This is the error message I've got:
Error Message
My friends are running the exact same code without an error - I can't work out what I'm doing wrong?
Every time this happens I have to open a new console to make spyder even function which needless to say is extremely irritating.
I'd appreciate any help, thank you,
Ben
I've been coding in python using tkinter and came across an exception from the tinter library.
Since I don't know exactly what the error means, it is hard for me to debug my program. I was wondering if someone could outline the error and suggest what may have caused it, so that I know what to look for when debugging my program. _tkinter.TclError: invalid command name ".entry#" (The hash represents a number).
I have an image showing the navigation through my program that causes the error if it helps.
Basically, the program will only let me view a sub-menu in the "record" section once, each time I run it, when it should let me enter them as many times as I need to.
You should include the error as text and not as unreadable image.
Based on the error message, you're trying to call .get() on an Entry that doesn't exist anymore. Maybe the parent window has been destroyed/closed and the entry is not there anymore. Or maybe it is just a context thing... hard to tell without the code.
If you can't figure out, please edit your question and add a MCVE, then I will edit my answer with more specific information.
I have recently started to learn Python 3 and have run into an issue while trying to learn how to debug using IDLE. I have created a basic program following a tutorial, which then explains how to use the debugger. However, I keep running into an issue while stepping through the code, which the tutorial does not explain (I have followed the instructions perfectly) nor does hours of searching on the internet. Basically if I step while already inside a function, usually following print() the debugger steps into pyshell.py, specifically, PyShell.py:1285: write() if i step out of pyshell, the debugger will simple step back in as soon as I try to move on, if this is repeated the step, go, etc buttons will grey out.
Any help will be greatly appreciated.
Thanks.
pyshell.py file opens during the debugging process when the function that is under review is found in Python's library - for example print() or input(). If you want to bypass this file/process click Over and it will step over this review of the function in Python's library.
In Python 3.4, I had the same problem. My tutorial is from Invent with Python by Al Sweigart, chapter 7.
New file editor windows such as pyshell.py and random.pyopen when built-in functions are called, such as input(), print(), random.randint(), etc. Then the STEP button starts stepping through the file it opened.
If you click OVER, you will have to click it several times, but if you click OUT, pyshell.py will close immediately and you'll be back in the original file you were trying to debug.
Also, I encountered problems confusing this one--the grayed-out buttons you mentioned--if I forgot to click in the shell and give input when the program asked. I tried Wing IDE and it didn't run the program correctly, although the program has no bugs. So I googled the problem, and there was no indication that IDLE is broken or useless.
Therefore, I kept trying till the OUT button in the IDLE debugger solved the problem.
Can someone help me out please...I'm trying to start my first programming project. It will be implemented in python.
I need to have a textbox (which i am using wxpython for). If the user enters any text into this text box, then I want it to appear as arabic. I wanted to this by automagically changing the users Keyboard to an arabic layout when the cursor lands in the given text box.
So i found this pywin32 module, which has a function LoadKeyboardLayout()
So i am trying to test this in IDLE, to see if I can make it accept arabic text into IDLE, to see if it works. So I enter, into IDLE:
win32api.LoadKeyboardLayout('00000401',1)
This then returns, 67175425, the decimal equivalent of hex:'4010401' whcih I believe is the locale ID for Arabic. SO I think wow! I've done it, but when I try typing after this, in the IDLE window, it continues to type normal english characters.
Can someone please explain my errors and guide me towards a good solution.
UPDATE
Okay, I've been trying to solve this problem ever since posting the damn question.
No luck.
Then, I thought, "ok, screw it, instead of testing it quicly in IDLE, I will just try it out, in situ, in my source code for the project."
WTF - it worked first time, giving exact behaviour that I wanted.
Then I tried it in a different IDE, in the interpreted window, and again, IT WORKED straight away!
So clearly my issue is with IDLE, in its interpreting mode.
Can anyone explain why it doesn't work in the IDLE shell???
Keyboard layout setting in Windows is per-process (and inherited from the parent process)
IDLE runs your Python script in a background process separate from its GUI
So you have successfully changed the keyboard layout of the background Python process that is running your script, but not of IDLE's GUI.